How to compare array to array using VBScript? - arrays

Question

I would like to check a data in my file exist or not in an array data that I have. It will return 1 and 0 if its exit or not. Inside my file is like this:
2j2H4F6d9d0d3hdfasgt.y7
But I cut the last 2 lines. And my array data is like this: [2w fr 5k 2j 0w]. I want to check whether my array data exist inside my file.
Const wbemFlagReturnImmediately = &h10
Const wbemFlagForwardOnly = &h20
XX = 0
Set wshShell = CreateObject("WScript.Shell")
strFBString = wshShell.ExpandEnvironmentStrings("%FB%")
WScript.Echo "==>"
WScript.Echo "strFBString: " & strFBString
Set wshShell = Nothing
For i = 1 To Len(strFBString) Step 2
If StrComp(Mid(strFBString, i, 2), [2w fr 5k 2j 0w]) = 0 Then
XX = 1
End If
Next
WScript.Echo "XX: " & XX
WScript.Quit(XX)

Answer 1

For one thing, [2w fr 5k 2j 0w] is not a valid array definition in VBScript. If you want to define an array with these 5 string elements you need to do it like this:
Array("2w", "fr", "5k", "2j", "0w")
Also, StrComp() is for comparing a string to another string. It does not support comparing a string to an array. For comparing a string to each element of an array you need a loop. How to build that loop depends on the result you want to achieve, though.
Looking at your code it seems you want to find a match in 2j2H4..., but not in w2j2H..., so simply using InStr() probably won't work for you. In that case you could use an inner loop for the comparison:
ref = Array("2w", "fr", "5k", "2j", "0w")
For i = 1 To Len(strFBString) Step 2
For Each s In ref
If Mid(strFBString, i, 2) = s Then
'...
End If
Next
Next
But like I already said, details depend on the desired end result. If you want to check if your input string contains any of the array values you could do something like this:
ref = Array("2w", "fr", "5k", "2j", "0w")
found = False
For i = 1 To Len(strFBString) Step 2
For Each s In ref
If Mid(strFBString, i, 2) = s Then
found = True
Exit For
End If
Next
Next
If on the other hand you wanted to check if your input string contains all of the reference strings you'd probably do something like this instead:
ref = Array("2w", "fr", "5k", "2j", "0w")
For Each s In ref
found = False
For i = 1 To Len(strFBString) Step 2
If Mid(strFBString, i, 2) = s Then
found = True
Exit For
End If
Next
If Not found Then Exit For
Next
You could also use an entirely different approach, like putting your data in a dictionary:
data = CreateObject("Scripting.Dictionary")
For i = 1 To Len(strFBString) Step 2
data(Mid(strFBString, i, 2)) = True
Next
Using that approach you could check if the data contains any of the reference values like this:
found = False
For s In Array("2w", "fr", "5k", "2j", "0w")
If data.Exists(s) Then
found = True
Exit For
End If
Next
or check if the data contains all of the reference values like this:
found = True
For s In Array("2w", "fr", "5k", "2j", "0w")
If Not data.Exists(s) Then
found = False
Exit For
End If
Next