Our DNN website is rewriting our product SKU which is part of a Querystring when navigating from a Product Filter Page to a Detailed Product View page.
Unfortunately, some of our products have a forward slash in the SKU for example, BD0002/DSDS
The URL we are navigating to is https://dnndev.me/Product-View/sku/BD0002/DSDS, but DNN would cut off and rewrite the last part of the URL and would result in the following URL: https://dnndev.me/Product-View/sku/BD0002
I did try to add the following Regex code in the SEO settings section of DNN to ignore the re-writing of the page, but it does the same.
sku/(.*)/(.*)
I have also noticed that currently our website writes the sku without the = sign for the querystring. Currently it would be /sku/ and not ?sku= I discovered I can change this when I add |/sku| in the Keep in Querystring Regular Expression.
I have set the URL format to be Advanced in the web.config file. I don't want to change this to HumanFriendly as it breaks our module.
Our product filter page which contains the links to the Product View uses a mustache template with HttpUtility.UrlEncode for QueryStringSKU:
<a href='<%=DetailedPageRedirectLink%>/sku/{{QueryStringSKU}}'>More Info</a>
We then have a Detailed Product View module that listens for the QueryString. I did in the past try to use Encoding and Decoding, but DNN was doing its own thing and ignoring the Encoding and Decoding part so I wrote this crazy part of code that strips out part of the URL that is not part of the SKU.
string rawurlfromrequest = Request.RawUrl;
string checkifquerystringexist = Request.QueryString["sku"];
if(checkifquerystringexist != null)
{
var cleanSKU = rawurlfromrequest.Split(new[] { "sku/" }, StringSplitOptions.None)[1];
decodeprodCode = cleanSKU.Split(new[] { "&" }, StringSplitOptions.None)[0];
decodeprodCode = decodeprodCode.Split(new[] { "/search" }, StringSplitOptions.None)[0];
decodeprodCode = decodeprodCode.Split(new[] { "?fbclid=" }, StringSplitOptions.None)[0];
decodeSKU = HttpUtility.UrlDecode(decodeprodCode);
}
if (!string.IsNullOrWhiteSpace(decodeSKU) && IsEditable == false)
{
LoadProductDetails(decodeSKU);
}
So I would like to know, how can I only allow DNN to rewrite the first part of the URL and not the SKU part of the querystring when it contains a forward slash?
I found these links:
https://www.dnnsoftware.com/answers/disable-friendly-url-for-one-page
https://www.dnnsoftware.com/forums/threadid/542568/scope/posts/how-can-one-turn-off-friendly-urls-url-rewriting-etc-in-dnn-8
I had to escape the query string with uri.EscapedDataString() which will convert the / to %2F as mentioned by VDWWD.
I also discovered that some products contain a space in the SKU which made me decide to use EscapedDataString which will convert a space to %20.
I found this Table with the different Encoding methods on this post useful:
URL Encoding using C#
For some reason Request.Querystring['sku'] fetches the unencoded query string even though it is encoded in the URL. This is why I am using Request.RawUrl and stripping the query string from this.
Related
This is how I use router.query to get hold of the token that I need so that the user can update one's password. But when I e.g. print it to my hidden, it removes e.g. + and / etc.
I have tried to use encodeURIComponent to be able to solve the problem but it seems that it does not help in any way.
Token in url: CfDJ8Pf5H7I0LCJKuxB2jm5JU0EGFK7KC45kBnwAkPgbAO2+kPijFxxb5CW6wyE/ft74if6V5ouwrHE8wK8Vz2ZTlc0s82XwwC9rZD4CvA5UQnv9eyL0UxdCqNEVjlusntVTn4d+41nLwlADsSqhLYajkRHwSHx8DhvJZa9OBGX9iYpR2EXnBOMa1EZcvvKDhEX+9+pgOtW8shPAo4p+F5nG0C+qnK4s5u/rO5vgA7SFhEkWS
When I get it into the content of the page, it looks like this. After it is displayed on the page.
CfDJ8Pf5H7I0LCJKuxB2jm5JU0EGFK7KC45kBnwAkPgbAO2 kPijFxxb5CW6wyE/ft74if6V5ouwrHE8wK8Vz2ZTlc0s82XwwC9rZD4CvA5UQnv9eyL0UxdCqNEVjlusntVTn4d 41nLwlADsSqhLYajkRHwSHx8DhvJZa9OBGX9iYpR2EXnBOMa1EZcvvKDhEX 9 pgOtW8shPAo4p F5nG0C qnK4s5u/rO5vgA7SFhEkWS
I have tried to do this:
encodeURIComponent(String(router.query["token"]))
And i have try
router.query["token"]
How can it be that you change the sign from + to between spaces or something completely different.
You can decode the encodded string before printing on the page.
const encoddedUri = encodeURI("https://example.com/asdasd asdasd");
console.log(`encoded URI: ${encoddedUri}`);
console.log(`Decoded URI: ${decodeURI(encoddedUri)}`);
I am trying to save category name after convert in slug
So in entity I have used setter for convert my text to slug text
protected function _setName($name)
{
return Text::slug($name);
}
After send post request in input name "আমি তোমায় ভালোবাসি"
Has got in database
ami-tomaya-bhalobasi
After make transliteratorId false
return Text::slug($name,[
'transliteratorId' => false
]);
I got output : আম-ত-ম-য-ভ-ল-ব-স
My expected result is
আমি-তোমায়-ভালোবাসি
How can I get my desire result ?
The whole point of slugs is to obtain a "safe" pure US-ASCII string. If all you seemingly want is to remove white spaces you can use a simple regular expression:
preg_replace('/\s/u', '-', 'আমি তোমায় ভালোবাসি')
However, I recommend you double-check why you think this is necessary in the first place. A properly encoded URL would display spaces as %20 anyway, which is "ugly" in a Latin script text but will get unnoticed in other scripts:
var_dump(rawurlencode('আমি তোমায় ভালোবাসি'));
string(159) "%E0%A6%86%E0%A6%AE%E0%A6%BF%20%E0%A6%A4%E0%A7%8B%E0%A6%AE%E0%A6%BE%E0%A6%AF%E0%A6%BC%20%E0%A6%AD%E0%A6%BE%E0%A6%B2%E0%A7%8B%E0%A6%AC%E0%A6%BE%E0%A6%B8%E0%A6%BF"
Tried to find a solution, but I got always stuck a the docs or at answers include other bundles. In the documentation of the dynamic router you can find the hint:
"Of course you can also have several parameters, as with normal Symfony routes. The semantics and rules for patterns, defaults and requirements are exactly the same as in core routes."
Thats it.
...
/foo/{id}/bar
I tried (seems not) everything to get it done.
Same for all tries:
I tried it to apply a variable pattern and a child route.
use Symfony\Cmf\Bundle\RoutingBundle\Doctrine\Phpcr\Route as PhpcrRoute;
$dm = $this->get('cmf_routing.route_provider');
$route = new PhpcrRoute();
$route->setPosition( $dm->find( null, '/cms/routes' ), 'foo' );
$route->setVariablePattern('/{id}');
$dm->persist( $route );
$child = new PhpcrRoute();
$child->setPosition( $route, 'bar' );
$dm->persist( $child );
$dm->flush();
With or without default value and requirement only '/foo/bar' and '/foo/*' return matches, but '/foo/1/bar' prompts me with a 'No route found for "GET /foo/1/bar"'.
...
Just now I nearly got it done.
use Symfony\Cmf\Bundle\RoutingBundle\Doctrine\Phpcr\Route as PhpcrRoute;
$dm = $this->get('cmf_routing.route_provider');
$route = new PhpcrRoute();
$route->setPosition( $dm->find( null, '/cms/routes' ), 'example_route' );
$dm->persist( $route );
$route->setPrefix( '/cms/routes/example_route' );
$route->setPath( '/foo/{id}/bar' );
$dm->flush();
If prefix is '/cms/routes' and name is 'foo' everything works fine. But now that I got this far, assigning a speaking name would round it up.
Thanks in advice!
You got quite close to the solution, actually!
When using PHPCR-ODM, the route document id is its path in the repository. PHPCR stores all content in a tree, so every document needs to be in a specific place in the tree. We then use the prefix to get a URL to match. If the prefix is configured as /cms/routes and the request is for /foo, the router looks in /cms/routes/foo. To allow parameters, you can use setVariablePattern as you correctly assumed. For the use case of /foo/{id}/bar, you need to do setVariablePattern('/{id}/bar'). You could also have setVariablePattern('/{context}/{id}') (this is what the doc paragraph you quoted meant - i will look into adding an example there as its indeed not helpful to say "you can do this" but not explain how to).
Calling setPath is not recommended as its just less explicit - but as you noticed, it would get the job done. See the phpdoc and implementation of Model\Route::setPattern:
/**
* It is recommended to use setVariablePattern to just set the part after
* the static part. If you use this method, it will ensure that the
* static part is not changed and only change the variable part.
*
* When using PHPCR-ODM, make sure to persist the route before calling this
* to have the id field initialized.
*/
public function setPath($pattern)
{
$len = strlen($this->getStaticPrefix());
if (strncmp($this->getStaticPrefix(), $pattern, $len)) {
throw new \InvalidArgumentException('You can not set a pattern for the route that does not start with its current static prefix. First update the static prefix or directly use setVariablePattern.');
}
return $this->setVariablePattern(substr($pattern, $len));
}
About explicit names: The repository path is also the name of the route, in the example /cms/routes/foo. But it is not a good idea to use a route name of a dynamic route in your code, as those routes are supposed to be editable (and deletable) by an admin. If you have a route that exists for sure and is at a specific path, use the configured symfony routes (the routing.yml file). If its dynamic routes, have a look at the CMF Resource Bundle. It allows to define a role for a document and a way to look up documents by role. If you have a route with a specific role that you want to link to from your controller / template, this is the way to go. If you have a content document that is linked with a route document and have that content document available, your third and best option is to generate the URL from the content document. The CMF dynamic router can do that, just use the content object where you normally specify the route name.
Using ui-router, is there a way to capture a path that contains forward slashes and query parameters?
Let's say there's the catch-all rule in the state configuration:
var exState = {
url: '/example/*path',
...
};
$stateProvider.state(exState);
and then point my browser to
/example/test1?var1=a&var2=b/test2?var3=c&var4=d/
I now see that the forward slashes get encoded:
test1?var1=a&var2=b%2Ftest2%3Fvar3&var4=d%2F
and $stateParams.path is test1 - not what I wanted. Is it possible to get the actual 'raw' path for further processing while avoiding the automatic query parameter capturing which ui-router is doing here?
You can accomplish this but you'll need to use Regex with your URL state, this is from the UI-Router Guide (https://github.com/angular-ui/ui-router/wiki/URL-Routing):
Regex Parameters
A bonus to using curly brackets is the ability to set a Regular Expression rule for the parameter:
// will only match a contactId of one to eight number characters
url: "/contacts/{contactId:[0-9]{1,8}}"
Examples:
'/user/{id:[^/]*}' - Same as '/user/{id}' from the previous example.
'/user/{id:[0-9a-fA-F]{1,8}}' - Similar to the previous example, but only matches if the id parameter consists of 1 to 8 hex digits.
'/files/{path:.*}' - Matches any URL starting with '/files/' and captures the rest of the path into the parameter 'path'.
'/files/*path' - Ditto. Special syntax for catch all.`
This one should catch your url and the parameter string: '/files/{path:.*}' - Matches any URL starting with '/files/' and captures the rest of the path into the parameter 'path'.
EDIT: After capturing the the rest of the URL in the path parameter you'll need to URL decode in order to regain the / & ? and anything else encoded. You can use decodeURIComponent()
I'm working on a data migration task, where I have to export a somewhat large Lotus Notes application into a blogging platform. My first task was to export the articles from Lotus Notes into CSV files.
I created a Agent in LotusScript to export the data into CSV files. I use a modified version of this IBM DeveloperWorks forum post. And it basically does the job. But the contents of the Rich Text field is stripped of any formatting. And this is not what I want, I want the Rich Text field rendered as HTML.
The documentation for the GetItemValue method explicitly states that the text is rendered into plain text. So I began to research for something that would retrieve the HTML. I found the NotesMIMEEntity class and some sample code in the IBM article How To Access HTML in a Rich Text Field Using LotusScript.
But for the technique described in the above article to work, the Rich Text field need to have the property "Store Contents as HTML and MIME". And this is not the case with my Lotus Notes database. I tried to set the property on the fields in question, but it didn't do the trick.
Is it possible to use the NotesMIMEEntity and set the "Store Contents as HTML and MIME" property after the content has been added, to export the field rendered as HTML?
Or what are my options for exporting the Notes database Rich Text fields as HTML?
Bonus information: I'm using IBM Lotus Domino Designer version 8.5
There is this fairly unknown command that does exactly what you want: retrieve the URL using the command OpenField.
Example that converts only the Body-field:
http://SERVER/your%5Fdatabase%5Fpath.nsf/NEW%5FVIEW/docid/Body?OpenField
Here is how I did it, using the OpenField command, see D.Bugger's post above
Function GetHtmlFromField(doc As NotesDocument, fieldname As String) As String
Dim obj
Set obj = CreateObject("Microsoft.XMLHTTP")
obj.open "GET", "http://www.mydomain.dk/database.nsf/0/" + doc.Universalid + "/" + fieldname + "?openfield&charset=utf-8", False, "", ""
obj.send("")
Dim html As String
html = Trim$(obj.responseText)
GetHtmlFromField = html
End Function
I'd suggest looking at Midas' Rich Text LSX (http://www.geniisoft.com/showcase.nsf/MidasLSX)
I haven't used the personally, but I remember them from years ago being the best option for working with Rich Text. I'd bet it saves you a lot of headaches.
As for the NotesMIMEEntity class, I don't believe there is a way to convert RichText to MIME, only MIME to RichText (or retain the MIME within the document for emailing purposes).
If you upgrade to Notes Domino 8.5.1 then you can use the new ConvertToMIME method of the NotesDocument class. See the docs. This should do what you want.
Alternativly the easiest way to get the Domino server to render the RichText will be to actually retrieve it via a url call. Set up a simple form that just has the RichText field and then use your favourite HTTP api to pull in the page. It should then be pretty straight forward to pull out the body.
Keep it simple.
Change the BODY field to Store contents as HTML and MIME
Open the doc in editmode.
Save.
Close.
You can now use the NotesMIMEEntity to get what you need from script.
You can use the NotesDXLExporter class to export the Rich Text and use an XSLT to transform the output to what you need.
I know you mentioned using LotusScript, but if you don't mind writing a small Java agent (in the Notes client), this can be done fairly easily - and there is no need to modify the existing form design.
The basic idea is to have your Java code open a particular document through a localhost http request (which is simple in Java) and to have your code capture that html output and save it back to that document. You basically allow the Domino rendering engine to do the heavy lifting.
You would want do this:
Create a form which contains only the rich-text field you want to convert, and with Content Type of HTML
Create a view with a selection formula for all of the documents you want to convert, and with a form formula which computes to the new form
Create the Java agent which just walks your view, and for each document gets its docid, opens a URL in the form http://SERVER/your_database_path.nsf/NEW_VIEW/docid?openDocument, grabs the http response and saves it.
I put up some sample code in a similar SO post here:
How to convert text and rich text fields in a document to html using lotusscript?
Works in Domino 10 (have not tested with 9)
HTMLStrings$ = NotesRichTextItem .Converttohtml([options] ) As String
See documentation :
https://help.hcltechsw.com/dom_designer/10.0.1/basic/H_CONVERTOHTML_METHOD_NOTESRICHTEXTITEM.html
UPDATE (2022)
HCL no longer support this method since version 11. The documentation does not include any info about the method.
I have made some tests and it still works in v12 but HCL recommended to not use it.
Casper's recommendation above works well, but make sure the ACL is such to allow Anonymous Access otherwise your HTML will be the HTML from your login form
If you do not need to get the Richtext from the items specifically, you can use ?OpenDocument, which is documented (at least) here: https://www.ibm.com/developerworks/lotus/library/ls-Domino_URL_cheat_sheet/
https://www.ibm.com/support/knowledgecenter/SSVRGU_9.0.1/com.ibm.designer.domino.main.doc/H_ABOUT_URL_COMMANDS_FOR_OPENING_DOCUMENTS_BY_KEY.html
OpenDocument also allows you to expand sections (I am unsure if OpenField does)
Syntax is:
http://Host/Database/View/DocumentUniversalID?OpenDocument
But be sure to include the charset parameter as well - Japanese documents were unreadable without specifying utf-8 as the charset.
Here is the method I use that takes a NotesDocument and returns the HTML for the doc as a string.
private string ConvertDocumentToHml(Domino.NotesDocument doc, string sectionList = null)
{
var server = doc.ParentDatabase.Server.Split('/')[0];
var dbPath = doc.ParentDatabase.FilePath;
string viewName = "0";
string documentId = doc.UniversalID.ToUpper();
var ub = new UriBuilder();
ub.Host = server;
ub.Path = dbPath.Replace("\\", "/") + "/" + viewName + "/" + documentId;
if (string.IsNullOrEmpty(sectionList))
{
ub.Query = "OpenDocument&charset=utf-8";
}
else
{
ub.Query = "OpenDocument&charset=utf-8&ExpandSection=" + sectionList;
}
var url = ub.ToString();
var req = HttpWebRequest.CreateHttp(url);
try
{
var resp = req.GetResponse();
string respText = null;
using (var sr = new StreamReader(resp.GetResponseStream()))
{
respText = sr.ReadToEnd();
}
return respText;
}
catch (WebException ex)
{
return "";
}
}