Batch .txt reader - batch-file

So, basically I want a Batch file to read a .txt. The problem is that the Batch file needs to update everytime a new line gets written to the .txt
#echo off
set "pc=%1"
FOR /F "delims=:" %%A IN ('findstr /N .* "%pc%"') DO set "zeilen=%%A"
type %pc%
set /A zeilen1=%zeilen%
:loop
if not %zeilen% == %zeilen1% (
set "line="
set zeilen2=%zeilen% - 1
for /f %%a in ('more/e +%zeilen2% ^< %pc%') do (
if not defined line set "line=%%a"
)
echo %line%
set /A zeilen+=1
)
FOR /F "delims=:" %%A IN ('findstr /N .* "%pc%"') DO set "zeilen1=%%A
goto loop
I also can't use the type command (line 9-13) because I don't want to refresh the whole .txt only the last line.
sry for my poor english
Thanks
To start the Batch you need to do something like this call batch.cmd txtname.txt

A basic tail command can be written like so. Credit to #dbenham for his initial solution on DosTips.com
#echo off
call :Loop <"tailme.txt"
exit
:Loop
set "line="
set /p "line="
if defined line (
echo %line%
) else (
pathping -q 1 -p 300 localhost >nul
)
goto :loop

If you don't wish to use third party options and wish to keep it pure batch, it is very possible. From your question, it sounds like you wish to read the last line of a text file and have it update that text each time the text file is edited. Further more, this batch file much be call'ed to when it needs to be used.
To do this, we can compare the date it was last modified using forfiles in an for loop. The reason for this is that if we use the file properties EX: ECHO Last-Modified Date : %%~ta we will not get the properties down to seconds. Thus the file will only compare down to the minutes.
Now that we can grab the last modified properties we can use an IF statement to look for when the file get a new time stamp. From there we can use a modified script that reads only the last line of a text file (Configurable by set /a LINES=LINES+1 LINES+1 - Infin) made by #Patrick Cuff
To call this batch file you will want to use call ReadFile.bat txtname.txt
Call - Command
ReadFile.bat - Name of batch script
txtname.txt - Name of textfile to read
Bellow is the full script.
ReadFile.bat
#ECHO OFF
#GOTO READ
:LOOP
Rem | Look for changes
FOR /f %%a in ('forfiles /M %1 /C "cmd /c echo #fdate-#ftime"') DO (set FileTimeCurrent=%%a)
IF "%FileTimeLoad%"=="%FileTimeCurrent%" (goto LOOP) else (goto READ)
:READ
cls
Rem | Get current date
FOR /f %%a in ('forfiles /M %1 /C "cmd /c echo #fdate-#ftime"') DO (set FileTimeLoad=%%a)
Rem | Get the number of lines in the file
set LINES=0
for /f "delims==" %%I in (%1) do (
set /a LINES=LINES+1
)
Rem | Print the last line
set /a LINES=LINES-1
more +%LINES% < %1
goto LOOP
For help on any of the commands do the following:
call /?
set /?
for /?
if /?
So on.

Related

Batch File: Assign random line of text file as variable for later use

I'm trying to write a very simple batch file for personal use...It's complete except for one thing I'm stumped on. Hopefully this is an easy fix (I'm effectively illiterate when it comes to code).
Basically what I'm trying to do is have the script choose a random line from a text file, do this a couple times with a couple different text files, then I wish to assign the output from each text file to a variable so that I can easily use them in various combinations...then repeat the process.
Here is what I have right now...
#ECHO OFF
:START
SETLOCAL
SETLOCAL EnableDelayedExpansion EnableExtensions
SET "list1=list1.txt"
FOR /f %%a IN ('type "%list1%"^|find /c /v ""') DO SET /a numlines=%%a
SET /A list1random=(%RANDOM% %% %NumLines%)
IF "%list1random%"=="0" (SET "list1random=") ELSE (SET "list1random=skip=%list1random%")
FOR /F "usebackq tokens=* %list1random% delims=" %%A IN (`TYPE %list1%`) DO (
>> output.txt ECHO %%A
)
:Finish
ENDLOCAL
GOTO START`
This procures the random line, and spits it to a text file. All is well, next step, take that random result and assign it to a variable...
#ECHO OFF
:START
SETLOCAL
SETLOCAL EnableDelayedExpansion EnableExtensions
SET "list1=list1.txt"
FOR /f %%a IN ('type "%list1%"^|find /c /v ""') DO SET /a numlines=%%a
SET /A list1random=(%RANDOM% %% %NumLines%)
IF "%list1random%"=="0" (SET "list1random=") ELSE (SET "list1random=skip=%list1random%")
FOR /F "usebackq tokens=* %list1random% delims=" %%A IN (`TYPE %list1%`) DO (
SET output1=%%A
)
>> output.txt ECHO %output1%
:Finish
ENDLOCAL
GOTO START
Now the output ceases to be random...instead it is always the last line of the referenced text file.
EDIT: The site suggested another question that was similar to mine. However, that person was having trouble getting the script to choose a valid line. I get a valid line every time, and a random one too (when I check it via echo), but a non-random line when proceeding on, assigning the output to a variable. I don't understand because it seems like a post-facto derandomization. I.E. the difference between the two scripts has nothing to do with procuring the random result, only what to do with that result AFTER it has it, right?
I appreciate any help in advance, this is the last step before I know everything I need to finish this, I'm excited!
Sorry, you're right...anyways, I figured out a simple workaround, probably not the quickest in terms of processing time, but whatever. Basically allow the initial part of the script to spit out the random result to a text file (as seemed to work just fine) then reference the text file as a variable.
#ECHO OFF
:START
SET "list1=list1.txt"
FOR /f %%a IN ('type "%list1%"^|find /c /v ""') DO SET /a numlines=%%a
SET /A listchoice=(%RANDOM% %% %NumLines%)
IF "%listchoice%"=="0" (SET "listchoice=") ELSE (SET "listchoice=skip=%listchoice%")
FOR /F "usebackq tokens=* %listchoice% delims=" %%A IN (`TYPE %list1%`) DO (
>> listoutput.txt ECHO %%A
)
Set /p list=<listoutput.txt
>> result.txt ECHO %list%
:Finish
DEL listoutput.txt
GOTO START
This is easy to do in PowerShell using the built-in Get-Random cmdlet.
$line = (Get-Content file.txt | where { $_ } | Get-Random)
Which makes it also easy in batch.
set filename=file.txt
for /f "tokens=*" %%a in ('powershell -ex bypass -c "gc %filename% | ? { $_ } | Get-Random"') do (
set "var=%%a"
)
The where { $_ } clause is only necessary to filter out any blank lines. You can omit it if you know your file has none.

Batchfile: read last lines from logfiles and copy them to a new file

This is my first posting so if the format is not as it supposed to be please excuse me for this. (Suggestions for
improvement are welcome.)
I am trying to create a batchfile that will read last lines from logfiles and copy them to a new file.
Until now I have found here a way to read the last line.
Code would be something like:
for /f %%i in ('find /v /c "" ^< someFile.txt') do set /a lines=%%i
set /a startLine=%lines% - 1
more /e +%startLine% someFile.txt > lastLines.txt
The above code works for one file at a time. What I need is to read the last line from all files in a known list and add this line to a new .csv file.
I have been using the following code for getting the 4th entry in the logfiles but it returns every line of every logfile:
for /f %%x in (%list%) do for /f "delims=.txt, tokens=4" %%i in (%%x.txt) do echo %%x, %%i >> output.csv
What I would need is a sort of combination of both but I don't know how to combine them and make the complete last line be copied to the .csv file.
===
#Magoo:
Thanx for your reaction.
In every logfile can be 1 to >100 lines with comma separated information. Something like:
"LOGON,6-1-2015,12:43:39,USERNAME,HOSTNAME,,,,192.168.209.242,00:21:5A:2E:64:5E"
The last code with the 4th entry was used to get a list of all accounts that had logged in to the computers. This code gave me a very large list of all logon/logoff events on all computerlogs I checked in %list%.
In %list$ I had all the names of logfiles I wanted to be checked. This returned all lines.
For a new batchfile I need only the last logon/logoff entry and I want the whole last line.
So I have a .txt file with the hostnames of all computers I need to examine.
This .txt file will be read line by line via the variable %list%.
From every logfile I need only the last line copied to an output file.
===
I just tried the solution offered by JosefZ. Unfortunately this does not work for me yet. No lastlines are copied to the resultfile. In the code I removed the extra entry for possible lastlines for there are no empty lines in the logs, I also added an entry for the hostname I want to be available in the result. JosefZ had the filename there:
#ECHO OFF >NUL
#SETLOCAL enableextensions disabledelayedexpansion
type nul>output.csv
set "list=_listing.txt"
for /F "tokens=*" %%x in ('type "%list%"') do (
set "host=%%~x"
for /F "tokens=*" %%G in ('type "%%~x"') do set "lastline=%%G"
call :lline
)
:endlocal
#ENDLOCAL
goto :eof
:lline
set "filename=.\logs\%filename:&=^&%.txt"
echo %host%,%lastline%>>output.csv
goto :eof
The resultfile shows only the hostnames. I'll puzzle some more with this but all tips are welcome!
===
Got it!!!
#ECHO OFF >NUL
#SETLOCAL enableextensions disabledelayedexpansion
type nul>output.csv
set "list=_listing.txt"
for /F "tokens=*" %%x in ('type "%list%"') do (
set filename= :: *empty previous filename*
set lastline= :: *empty previous lastline*
set "host=%%~x"
set "filename=.\logs\%host%.txt" :: *creating the filename from path+hostname+extention*
for /F "tokens=*" %%G in ('type "%filename%"') do set "lastline=%%G"
call :lline
)
:endlocal
#ENDLOCAL
goto :eof
:lline
echo %host%,%lastline%>>output.csv
goto :eof
Your approach with line numbering could fail if a file has more trailing empty lines. Fortunately for /F loop ignores (does not iterate) empty lines; let's put to use this feature: in the script used next practices:
disabledelayedexpansion to allow ! in file names
set "list=_listing.txt" where the _listing.txt contains list of file names (full path and extension .txt including), one file name on one line: got by dir /b /s *.txt>_listing.txt
type nul>files\output.csv to empty the output file (optional)
set "lastline=!!!file empty!!!" to initialize variable %lastline%; could be set "lastline=" as well
call :lline to process variables %filename% and %lastline%
set "filename=%filename:&=^&%" to allow & in file names
The script is as follows:
#ECHO OFF >NUL
#SETLOCAL enableextensions disabledelayedexpansion
type nul>files\output.csv
set "list=_listing.txt"
for /F "tokens=*" %%x in ('type "%list%"') do (
set "filename=%%~x"
set "lastline=!!!file empty!!!"
rem the whole line
for /F "tokens=*" %%G in ('type "%%~x"') do set "lastline=%%G"
rem the fourth token only
rem for /F "tokens=4" %%G in ('type "%%~x"') do set "lastline=%%G"
call :lline
)
:endlocal
#ENDLOCAL
goto :eof
:lline
set "filename=%filename:&=^&%"
echo %filename% %lastline%
rem >>files\output.csv
goto :eof
Sample _listing.txt file:
d:\bat\files\1exclam!ation.txt
d:\bat\files\2exc!lam!ation.txt
d:\bat\files\11per%cent.txt
d:\bat\files\12per%cent%.txt
d:\bat\files\17per%Gcent.txt
d:\bat\files\18per%%Gcent.txt
d:\bat\files\21ampers&nd.txt
d:\bat\files\22ampers&&nd.txt
Output:
d:\bat>lastlines
d:\bat\files\1exclam!ation.txt 0 15.01.2015 1:52:28.48 -15072 20465
d:\bat\files\2exc!lam!ation.txt 6 15.01.2015 1:52:28.50 3250 16741
d:\bat\files\11per%cent.txt -8 15.01.2015 1:52:28.50 -3692 27910
d:\bat\files\12per%cent%.txt !!!file empty!!!
d:\bat\files\17per%Gcent.txt 0 15.01.2015 1:52:28.56 14508 12374
d:\bat\files\18per%%Gcent.txt 1 15.01.2015 1:52:28.56 30540 26959
d:\bat\files\21ampers&nd.txt 15.01.2015 1:22:50.18
d:\bat\files\22ampers&&nd.txt 15.01.2015 1:22:50.18
Honestly, all that ballast is for (possibly) trailing empty lines in files and for (possibly) ! and & in file names only; all could be done with
for /f %%x in (%list%) do for /f "skip=%startLine% tokens=4" %%i in (%%x) do echo %%x, %%i >> output.csv
You should use a simple FOR to iterate a list of values, not FOR /F.
Something like the following should work:
#echo off
setlocal enableDelayedExpansion
>>output.csv (
for %%F in (
"file1.log"
"file2.log"
"file3.log"
etc.
) do (
for /f %%A in ('find /v /c "" <%%F') do set /a skip=%%A-1
more +!skip! %%F
)
)
The quotes around the file names are there in case you get a name with spaces.
You could use your LIST variable if it looks something like
set LIST="file1.log" "file2.log" "file3.log" etc.
#echo off
setlocal enableDelayedExpansion
set LIST="file1.log" "file2.log" "file3.log" etc.
>>output.csv (
for %%F in (%LIST%) do (
for /f %%A in ('find /v /c "" <%%F') do set /a skip=%%A-1
more +!skip! %%F
)
)
If any of your file names contain the ! character, then you must toggle delayed expansion ON and OFF within your loop. Otherwise the delayed expansion will corrupt the names when %%F is expanded.
#echo off
setlocal disableDelayedExpansion
set LIST="file1.log" "file2.log" "file3.log" etc.
>>output.csv (
for %%F in (%LIST%) do (
for /f %%A in ('find /v /c "" <%%F') do set /a skip=%%A-1
setlocal enableDelayedExpansion
more +!skip! %%F
endlocal
)
)

Need help writing a batch file to process multiple files into comma delimited text files

I have a million old text files that I need to convert the format on. I have been desperately trying to do this myself but I really could use help. I am trying to convert data that looks like this:
text
11111.111
22222.222
33333.333
text2
44444.444
55555.555
66666.666
77777.777
88888.888
99999.999
(each number is on a seperate line and there are some blank lines, but I need them to go into the output file as a place keeper)
Into a .txt file that looks like this:
**I also need to add an increment number at the beginning of each line to number the lines.
1,11111.111,22222.222,33333.333,text
2,44444.444,55555.555,66666.666,text2
3,77777.777,88888.888,99999.999,
the files that I have are in separate folders in a directory and have no file extension but they behave exactly like a standard text file.
I have tried all sorts of stuff but I am just not that well versed in programming. Here is the little bit of code that I havent deleted for the 100th time. gettting frustrated
:REFORMAT
FOR %%F IN (*) DO IF NOT %%~XF==.BAT (
SETLOCAL DISABLEDELAYEDEXPANSION
(
SET /P LINE1=
SET /P LINE2=
SET /P LINE3=
SET /P LINE4=
)<"%%F"
ECHO %LINE2%,%LINE3%,%LINE4%,%LINE1%>>"%%F".TXT
PAUSE >NUL
:END
I am using windows I have access to dos6 dos7 winxp 32 and win7 64
the text and text2 are text strings within the file, they are descriptors telling me what the numbers below mean and some of the descriptors are left out. I also need it to process more than the first four lines. Some files have up to 200 lines inside of them. Thank you so much for helping me. thank you so much dbenham here is the final result:
#echo off
setlocal enableDelayedExpansion
for /R %%F in (*.) do (
set /a ln=0
for /f %%N in ('type "%%F"^|find /c /v ""') do set /a cnt=%%N/4
for /l %%N in (1 1 !cnt!) do (
for %%A in (1 2 3 4) do (
set "ln%%A="
set /p "ln%%A="
)
set /a ln+=1
echo !ln!,!ln2!,!ln3!,!ln4!,!ln1!
)
) <"%%F" >"%%F.CSV"
Using nothing but pure native batch:
#echo off
setlocal enableDelayedExpansion
for %%F in (*.) do (
set /a ln=0
for /f %%N in ('type "%%F"^|find /c /v ""') do set /a cnt=%%N/4
for /l %%N in (1 1 !cnt!) do (
for %%A in (1 2 3 4) do (
set "ln%%A="
set /p "ln%%A="
)
set /a ln+=1
echo !ln!,!ln2!,!ln3!,!ln4!,!ln1!
)
) <"%%F" >"%%F.txt"
The above will process all files that have no extension in the current folder. If you want to recursively include all sub-folders, then add the /R option to the outer FOR statement.
The whole thing can be done quite simply using my REPL.BAT utility:
#echo off
for %%F in (*.) do (
<"%%F" repl "([^\r\n]*)\r?\n([^\r\n]*)\r?\n([^\r\n]*)\r?\n([^\r\n]*)\r?\n?" "$2,$3,$4,$1\r\n" mx|findstr /n "^"|repl "^(.*):" "$1," >"%%F.txt"
)
just a few modifications:
set /p doesnt delete a variable if input is empty, so you have to delete it before.
You missed a closing paranthese )
You have to use delayed expansion to use a changed variable inside parantheses
the counter.
#echo off
SETLOCAL ENABLEDELAYEDEXPANSION
set count=0
FOR %%F IN (*.) DO IF NOT %%~XF==.BAT (
set "LINE1="
set "LINE2="
set "LINE3="
set "LINE4="
set count+=1
(
SET /P LINE1=
SET /P LINE2=
SET /P LINE3=
SET /P LINE4=
)<"%%F"
ECHO !count!,!LINE2!,!LINE3!,!LINE4!,!LINE1!>>"%%F.txt"
)
PAUSE >NUL
:END

Replace line in config file with batch afterward start exe

With a batch file, I want to change a value in a configuration file:
"title.connectionString" : "ServerIP",
ServerIP is the variable to be changed. So the batch file has to give people who use it an option to choose from 4 prefixed IPs. After they selected one of the 4 the IP, the config file has to be saved with new value and the batch file should run an executable.
Has anyone got an idea how I can do this with a batch file?
Easy, try this code:
#echo off
:start
Echo Select Ip:
Echo.
Echo 1. 10.0.0.0
Echo 2. 10.0.0.1
Echo 3. 10.0.0.2
Echo 4. 10.0.0.1
Echo.
Choice /c 1234 /m "Ip: " /n
set choice=%errorlevel%
set ip=
if %choice%==1 set ip=10.0.0.0
if %choice%==2 set ip=10.0.0.1
if %choice%==3 set ip=10.0.0.2
if %choice%==4 set ip=10.0.0.3
if "%ip%"=="" (Echo Error, null variable & goto :start)
ren config.txt config.tmp
setlocal Enabledelayedexpansion
for /f "tokens=*" %%a in (config.tmp) do (
set line=%%a
Echo !line:ServerIP=%ip%! >> config.txt
)
del config.tmp
And that should do what you want.
Mona
#echo off
setlocal enableextensions
call :replaceKeyValue "file.config" "title.connectionString" "123456789"
endlocal
exit /b
:replaceKeyValue file key value
setlocal enableextensions disabledelayedexpansion
ren "%~f1" "%~nx1.tmp" >nul && (
(for /f tokens^=1^,*^ delims^=^:^ eol^= %%k in ('findstr /n "^" ^<"%~f1.tmp"') do (
echo(%%l|findstr /c:"\"%~2\"" >nul && (
for /f "tokens=1 delims=:" %%v in ("%%l") do echo(%%~v : "%~3",
) || (
echo(%%l
)
)) > "%~f1"
del "%~f1.tmp" > nul
)
endlocal
This will handle the replacement of the value in the file. Monacraft answer shows a perfect way of selecting the required ip.
This will rename the file to file.tmp and for each line in the file (findstr /n is used to avoid lost of empty lines) it is tested agains the passed key. When required line is found, it is split using the colon (to keep the indentation) and value replaced with supplied value. All the non matching lines are echoed as is. All the output of the process is send to the original file and at end, the .tmp file is deleted.

Deleting last n lines from file using batch file

How to delete last n lines from file using batch script
I don't have any idea about batch files, I am writing batch file for the first time.
How should I write this batch file?
For Windows7
Try it for
<Project_Name>
<Noter>
<Common>
<File>D:\Project_Name\Util.jar</File>
<File>D:\Project_Name\Noter.bat</File>
<File>D:Project_Name\Noter.xml</File>
<File>D:Project_Name\Noter.jar</File>
</Common>
<Project_Name>
<File>D:\Util.bat</File>
<File>D:\Util.xml</File>
<File>D:\log.bat</File>
</Project_Name>
</Noter>
<CCNET>
This the complete script for remove last N line
count the total line
set Line = Line - N , remain just processing lines number
#echo OFF
setlocal EnableDelayedExpansion
set LINES=0
for /f "delims==" %%I in (infile.txt) do (
set /a LINES=LINES+1
)
echo Total Lines : %LINES%
echo.
:: n = 5 , last 5 line will ignore
set /a LINES=LINES-5
call:PrintFirstNLine > output.txt
goto EOF
:PrintFirstNLine
set cur=0
for /f "delims==" %%I in (infile.txt) do (
echo %%I
::echo !cur! : %%I
set /a cur=cur+1
if "!cur!"=="%LINES%" goto EOF
)
:EOF
exit /b
Here call:PrintFirstNLine > output.txt will give the output in an external file name as output.txt
Output for sample Input
<Project_Name>
<CBA_Notifier>
<Common>
<File>D:\CBA\CBA_Notifier\Project_Name\IPS-Util.jar</File>
<File>D:\CBA\CBA_Notifier\Project_Name\Notifier.bat</File>
<File>D:\CBA\CBA_Notifier\Project_Name\Notifier.xml</File>
<File>D:\CBA\CBA_Notifier\Project_Name\Notifier.jar</File>
</Common>
<Project_Name>
<File>D:\CBA\CBA_Notifier\IPS-Util.bat</File>
remove last 5 line
Update
:PrintFirstNLine
set cur=0
for /F "tokens=1* delims=]" %%I in ('type "infile.txt" ^| find /V /N ""') do (
if "%%J"=="" (echo.) else (
echo.%%J
set /a cur=cur+1
)
if "!cur!"=="%LINES%" goto EOF
)
This script will takes 1 arguement, the file to be trunkated, creates a temporary file and then replaces the original file with the shorter one.
#echo off
setlocal enabledelayedexpansion
set count=
for /f %%x in ('type %1 ^| find /c /v ""') do set /a lines=%%x-5
copy /y nul %tmp%\tmp.zzz > nul
for /f "tokens=*" %%x in ('type %1 ^| find /v ""') do (
set /a count=count+1
if !count! leq %lines% echo %%x>>%tmp%\tmp.zzz
)
move /y %tmp%\tmp.zzz %1 > nul
If the original file is 5 or less lines, the main output routine will noT create a file. To combat this, I use the copy /y null to create a zero byte file.
If you would rather not have an empty file, just remove the copy /y nul line, and replace it with the following line:
if %lines% leq 0 del %1
You should use one method or the other, otherwise source files with 5 or less lines will remain untouched. (Neither replaced or deleted.)
to delete last lines from your file,
1 copy starting lines that are needed from file like from- e:\original.txt
2 paste them in new file like- e:\new\newfile1.txt
code is thanks to the person giving me this code:
remember all may be done if you have motive and even blood hb =6. but help of nature is required always as you are a part of it
#echo off & setLocal enableDELAYedeXpansion
set N=
for /f "tokens=* delims= " %%a in (e:\4.txt) do (
set /a N+=1
if !N! gtr 264 goto :did
e:\new4.txt echo.%%a
)
:did
if you have 800 files then use excel to make code for 800 and then copy it to notepad and using Ctrl+h replace space with no space. then rename file as haha.bat . run in folder with files numbered 1.txt 2.txt 3.txt etc. any enquirers welcome Erkamaldev#gmail.com " Long Live Bharata"
A slow method with less coding:
set input=file.txt
set remove=7
for /f "delims=" %i in ('find /c /v "" ^< "%cd%\%input%"') do set lines=%i
set /a lines-=remove
for /l %i in (1,1,!lines!) do findstr /n . log.txt | findstr /b %i:
May be redirected to a file.
Each line is prefixed with the line number; may be removed with extra coding.
A faster version with /g flag in my answer at:
How to split large text file in windows?
Tested in Win 10 CMD, on 577KB file, 7669 lines.

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