Replace line in config file with batch afterward start exe - batch-file

With a batch file, I want to change a value in a configuration file:
"title.connectionString" : "ServerIP",
ServerIP is the variable to be changed. So the batch file has to give people who use it an option to choose from 4 prefixed IPs. After they selected one of the 4 the IP, the config file has to be saved with new value and the batch file should run an executable.
Has anyone got an idea how I can do this with a batch file?

Easy, try this code:
#echo off
:start
Echo Select Ip:
Echo.
Echo 1. 10.0.0.0
Echo 2. 10.0.0.1
Echo 3. 10.0.0.2
Echo 4. 10.0.0.1
Echo.
Choice /c 1234 /m "Ip: " /n
set choice=%errorlevel%
set ip=
if %choice%==1 set ip=10.0.0.0
if %choice%==2 set ip=10.0.0.1
if %choice%==3 set ip=10.0.0.2
if %choice%==4 set ip=10.0.0.3
if "%ip%"=="" (Echo Error, null variable & goto :start)
ren config.txt config.tmp
setlocal Enabledelayedexpansion
for /f "tokens=*" %%a in (config.tmp) do (
set line=%%a
Echo !line:ServerIP=%ip%! >> config.txt
)
del config.tmp
And that should do what you want.
Mona

#echo off
setlocal enableextensions
call :replaceKeyValue "file.config" "title.connectionString" "123456789"
endlocal
exit /b
:replaceKeyValue file key value
setlocal enableextensions disabledelayedexpansion
ren "%~f1" "%~nx1.tmp" >nul && (
(for /f tokens^=1^,*^ delims^=^:^ eol^= %%k in ('findstr /n "^" ^<"%~f1.tmp"') do (
echo(%%l|findstr /c:"\"%~2\"" >nul && (
for /f "tokens=1 delims=:" %%v in ("%%l") do echo(%%~v : "%~3",
) || (
echo(%%l
)
)) > "%~f1"
del "%~f1.tmp" > nul
)
endlocal
This will handle the replacement of the value in the file. Monacraft answer shows a perfect way of selecting the required ip.
This will rename the file to file.tmp and for each line in the file (findstr /n is used to avoid lost of empty lines) it is tested agains the passed key. When required line is found, it is split using the colon (to keep the indentation) and value replaced with supplied value. All the non matching lines are echoed as is. All the output of the process is send to the original file and at end, the .tmp file is deleted.

Related

How do I substring a dynamic variable value in windows batch scripting

Not able to substring the dynamic variable inside forloop in Windows batch script.
I have the properties file in my git hub in the below format.
"collectionName=TestCollectionRun.json=test"
So I have written the below code to fetch this values.But the requirement is that I need to strip of the '.json' part from collection name.With the below code I am not able to set/echo that value.Can you please help on this!
#ECHO ON
:BEGIN
IF EXIST "test.properties" ECHO Found properties file, reading file..
SET props=test.properties
setlocal EnableDelayedExpansion
For /F "delims== tokens=1,2,3" %%G in (%props%) Do (
if "%%I" EQU "test" if "%%G" EQU "collectionName" SET collName=%%H(
SET finalCollName=%collName%:~0,-5
ECHO %finalCollName%
)
)
:END
We need the ECHO to return "TestCollectionRun".currently its not returning anything.
For /F "delims== tokens=1,2,3" %%G in (%props%) Do (
if "%%I" EQU "test" if "%%G" EQU "collectionName" SET "collName=%%~nH"&echo %%~nH
)
ECHO %CollName%
Note the second ) is now redundant. Your problem has to do with delayedexpansion which you are invoking but not using. call %%collname%% within the for loop would have shown the value after assignment if required.
This code works by interpreting %%H as a filename and assigning simply the name part of %%H (%%~nH)
Given a line content of collectionName=TestCollectionRun.json=test, here's a quick rewrite of what I think you're tring to do:
#Echo Off
Set "props=test.properties"
If Not Exist "%props%" (
Echo Properties file not found!
Echo Exiting..
Timeout /T 3 /NoBreak >NUL
Exit /B
)
Echo Found properties file, reading file..
For /F "UseBackQ Tokens=1-3 Delims==" %%A In ("%props%") Do (
If /I "%%C" == "test" If /I "%%A" == "collectionName" Echo %%~nB
)
Pause
If you wanted to do something with the collection name within the loop then you would probably need to use delayed expansion:
#Echo Off
SetLocal DisableDelayedExpansion
Set "props=test.properties"
If Not Exist "%props%" (
Echo Properties file not found!
Echo Exiting..
Timeout /T 3 /NoBreak >NUL
Exit /B
)
Echo Found properties file, reading file..
For /F "UseBackQ Tokens=1-3 Delims==" %%A In ("%props%") Do (
If /I "%%C" == "test" If /I "%%A" == "collectionName" (
Set "collName=%%B"
SetLocalEnableDelayedExpansion
Echo !collName!
Rem Perform substring task on the variable named collName
Set "finalCollName=!collName%:~0,-5!"
Echo !finalCollName!
EndLocal
)
)
Pause
Note, these answers will not work, as is, if your string is surrounded by doublequotes, (as in your question body), or if the line content differs (e.g. begins with spaces or tabs).
[Edit /]
Looking at your 'after the fact' question in the comments, it is clear that you do not need to substring the variable at all, so should use the first method posted:
Echo Found properties file, reading file..
For /F "UseBackQ Tokens=1-3 Delims==" %%A In ("%props%") Do (
If /I "%%C" == "test" If /I "%%A" == "collectionName" (
newman run "%%B" -e "%envName%" --insecure --reporters cli,htmlextra --reporter-htmlextra-export "newman\%BUILD_NUMBER%\%%~nB.html" --disable-unicode
)
)
Pause
This assumes that both %envName% and %BUILD_NUMBER% have been previously defined correctly.

Batch .txt reader

So, basically I want a Batch file to read a .txt. The problem is that the Batch file needs to update everytime a new line gets written to the .txt
#echo off
set "pc=%1"
FOR /F "delims=:" %%A IN ('findstr /N .* "%pc%"') DO set "zeilen=%%A"
type %pc%
set /A zeilen1=%zeilen%
:loop
if not %zeilen% == %zeilen1% (
set "line="
set zeilen2=%zeilen% - 1
for /f %%a in ('more/e +%zeilen2% ^< %pc%') do (
if not defined line set "line=%%a"
)
echo %line%
set /A zeilen+=1
)
FOR /F "delims=:" %%A IN ('findstr /N .* "%pc%"') DO set "zeilen1=%%A
goto loop
I also can't use the type command (line 9-13) because I don't want to refresh the whole .txt only the last line.
sry for my poor english
Thanks
To start the Batch you need to do something like this call batch.cmd txtname.txt
A basic tail command can be written like so. Credit to #dbenham for his initial solution on DosTips.com
#echo off
call :Loop <"tailme.txt"
exit
:Loop
set "line="
set /p "line="
if defined line (
echo %line%
) else (
pathping -q 1 -p 300 localhost >nul
)
goto :loop
If you don't wish to use third party options and wish to keep it pure batch, it is very possible. From your question, it sounds like you wish to read the last line of a text file and have it update that text each time the text file is edited. Further more, this batch file much be call'ed to when it needs to be used.
To do this, we can compare the date it was last modified using forfiles in an for loop. The reason for this is that if we use the file properties EX: ECHO Last-Modified Date : %%~ta we will not get the properties down to seconds. Thus the file will only compare down to the minutes.
Now that we can grab the last modified properties we can use an IF statement to look for when the file get a new time stamp. From there we can use a modified script that reads only the last line of a text file (Configurable by set /a LINES=LINES+1 LINES+1 - Infin) made by #Patrick Cuff
To call this batch file you will want to use call ReadFile.bat txtname.txt
Call - Command
ReadFile.bat - Name of batch script
txtname.txt - Name of textfile to read
Bellow is the full script.
ReadFile.bat
#ECHO OFF
#GOTO READ
:LOOP
Rem | Look for changes
FOR /f %%a in ('forfiles /M %1 /C "cmd /c echo #fdate-#ftime"') DO (set FileTimeCurrent=%%a)
IF "%FileTimeLoad%"=="%FileTimeCurrent%" (goto LOOP) else (goto READ)
:READ
cls
Rem | Get current date
FOR /f %%a in ('forfiles /M %1 /C "cmd /c echo #fdate-#ftime"') DO (set FileTimeLoad=%%a)
Rem | Get the number of lines in the file
set LINES=0
for /f "delims==" %%I in (%1) do (
set /a LINES=LINES+1
)
Rem | Print the last line
set /a LINES=LINES-1
more +%LINES% < %1
goto LOOP
For help on any of the commands do the following:
call /?
set /?
for /?
if /?
So on.

Batchfile: read last lines from logfiles and copy them to a new file

This is my first posting so if the format is not as it supposed to be please excuse me for this. (Suggestions for
improvement are welcome.)
I am trying to create a batchfile that will read last lines from logfiles and copy them to a new file.
Until now I have found here a way to read the last line.
Code would be something like:
for /f %%i in ('find /v /c "" ^< someFile.txt') do set /a lines=%%i
set /a startLine=%lines% - 1
more /e +%startLine% someFile.txt > lastLines.txt
The above code works for one file at a time. What I need is to read the last line from all files in a known list and add this line to a new .csv file.
I have been using the following code for getting the 4th entry in the logfiles but it returns every line of every logfile:
for /f %%x in (%list%) do for /f "delims=.txt, tokens=4" %%i in (%%x.txt) do echo %%x, %%i >> output.csv
What I would need is a sort of combination of both but I don't know how to combine them and make the complete last line be copied to the .csv file.
===
#Magoo:
Thanx for your reaction.
In every logfile can be 1 to >100 lines with comma separated information. Something like:
"LOGON,6-1-2015,12:43:39,USERNAME,HOSTNAME,,,,192.168.209.242,00:21:5A:2E:64:5E"
The last code with the 4th entry was used to get a list of all accounts that had logged in to the computers. This code gave me a very large list of all logon/logoff events on all computerlogs I checked in %list%.
In %list$ I had all the names of logfiles I wanted to be checked. This returned all lines.
For a new batchfile I need only the last logon/logoff entry and I want the whole last line.
So I have a .txt file with the hostnames of all computers I need to examine.
This .txt file will be read line by line via the variable %list%.
From every logfile I need only the last line copied to an output file.
===
I just tried the solution offered by JosefZ. Unfortunately this does not work for me yet. No lastlines are copied to the resultfile. In the code I removed the extra entry for possible lastlines for there are no empty lines in the logs, I also added an entry for the hostname I want to be available in the result. JosefZ had the filename there:
#ECHO OFF >NUL
#SETLOCAL enableextensions disabledelayedexpansion
type nul>output.csv
set "list=_listing.txt"
for /F "tokens=*" %%x in ('type "%list%"') do (
set "host=%%~x"
for /F "tokens=*" %%G in ('type "%%~x"') do set "lastline=%%G"
call :lline
)
:endlocal
#ENDLOCAL
goto :eof
:lline
set "filename=.\logs\%filename:&=^&%.txt"
echo %host%,%lastline%>>output.csv
goto :eof
The resultfile shows only the hostnames. I'll puzzle some more with this but all tips are welcome!
===
Got it!!!
#ECHO OFF >NUL
#SETLOCAL enableextensions disabledelayedexpansion
type nul>output.csv
set "list=_listing.txt"
for /F "tokens=*" %%x in ('type "%list%"') do (
set filename= :: *empty previous filename*
set lastline= :: *empty previous lastline*
set "host=%%~x"
set "filename=.\logs\%host%.txt" :: *creating the filename from path+hostname+extention*
for /F "tokens=*" %%G in ('type "%filename%"') do set "lastline=%%G"
call :lline
)
:endlocal
#ENDLOCAL
goto :eof
:lline
echo %host%,%lastline%>>output.csv
goto :eof
Your approach with line numbering could fail if a file has more trailing empty lines. Fortunately for /F loop ignores (does not iterate) empty lines; let's put to use this feature: in the script used next practices:
disabledelayedexpansion to allow ! in file names
set "list=_listing.txt" where the _listing.txt contains list of file names (full path and extension .txt including), one file name on one line: got by dir /b /s *.txt>_listing.txt
type nul>files\output.csv to empty the output file (optional)
set "lastline=!!!file empty!!!" to initialize variable %lastline%; could be set "lastline=" as well
call :lline to process variables %filename% and %lastline%
set "filename=%filename:&=^&%" to allow & in file names
The script is as follows:
#ECHO OFF >NUL
#SETLOCAL enableextensions disabledelayedexpansion
type nul>files\output.csv
set "list=_listing.txt"
for /F "tokens=*" %%x in ('type "%list%"') do (
set "filename=%%~x"
set "lastline=!!!file empty!!!"
rem the whole line
for /F "tokens=*" %%G in ('type "%%~x"') do set "lastline=%%G"
rem the fourth token only
rem for /F "tokens=4" %%G in ('type "%%~x"') do set "lastline=%%G"
call :lline
)
:endlocal
#ENDLOCAL
goto :eof
:lline
set "filename=%filename:&=^&%"
echo %filename% %lastline%
rem >>files\output.csv
goto :eof
Sample _listing.txt file:
d:\bat\files\1exclam!ation.txt
d:\bat\files\2exc!lam!ation.txt
d:\bat\files\11per%cent.txt
d:\bat\files\12per%cent%.txt
d:\bat\files\17per%Gcent.txt
d:\bat\files\18per%%Gcent.txt
d:\bat\files\21ampers&nd.txt
d:\bat\files\22ampers&&nd.txt
Output:
d:\bat>lastlines
d:\bat\files\1exclam!ation.txt 0 15.01.2015 1:52:28.48 -15072 20465
d:\bat\files\2exc!lam!ation.txt 6 15.01.2015 1:52:28.50 3250 16741
d:\bat\files\11per%cent.txt -8 15.01.2015 1:52:28.50 -3692 27910
d:\bat\files\12per%cent%.txt !!!file empty!!!
d:\bat\files\17per%Gcent.txt 0 15.01.2015 1:52:28.56 14508 12374
d:\bat\files\18per%%Gcent.txt 1 15.01.2015 1:52:28.56 30540 26959
d:\bat\files\21ampers&nd.txt 15.01.2015 1:22:50.18
d:\bat\files\22ampers&&nd.txt 15.01.2015 1:22:50.18
Honestly, all that ballast is for (possibly) trailing empty lines in files and for (possibly) ! and & in file names only; all could be done with
for /f %%x in (%list%) do for /f "skip=%startLine% tokens=4" %%i in (%%x) do echo %%x, %%i >> output.csv
You should use a simple FOR to iterate a list of values, not FOR /F.
Something like the following should work:
#echo off
setlocal enableDelayedExpansion
>>output.csv (
for %%F in (
"file1.log"
"file2.log"
"file3.log"
etc.
) do (
for /f %%A in ('find /v /c "" <%%F') do set /a skip=%%A-1
more +!skip! %%F
)
)
The quotes around the file names are there in case you get a name with spaces.
You could use your LIST variable if it looks something like
set LIST="file1.log" "file2.log" "file3.log" etc.
#echo off
setlocal enableDelayedExpansion
set LIST="file1.log" "file2.log" "file3.log" etc.
>>output.csv (
for %%F in (%LIST%) do (
for /f %%A in ('find /v /c "" <%%F') do set /a skip=%%A-1
more +!skip! %%F
)
)
If any of your file names contain the ! character, then you must toggle delayed expansion ON and OFF within your loop. Otherwise the delayed expansion will corrupt the names when %%F is expanded.
#echo off
setlocal disableDelayedExpansion
set LIST="file1.log" "file2.log" "file3.log" etc.
>>output.csv (
for %%F in (%LIST%) do (
for /f %%A in ('find /v /c "" <%%F') do set /a skip=%%A-1
setlocal enableDelayedExpansion
more +!skip! %%F
endlocal
)
)

'findstr' with multiple search results (BATCH)

This is based on my last question's script:, Directory mapout is not working (BATCH)
(For the whole script, click the link. However, you may only click the link if the following snip of code from "directory mapout is not working" does not really make sense to you)
<code>
cd temporary
set odir=%dir%
set /p cdir="DIRECTORY: "
set domap=%cdir%
title SONOROUS FILE SEARCHER: Mapping out...
echo PLEASE WAIT, MAPPING OUT DIRECTORY.
dir %domap% /a-d /b /s > "tempres.rsm"
echo Directory Mapout done
echo -----------------------------
echo DIRECTORY MAPOUT
set dirmapout=<tempres.rsm
echo %dirmapout%
echo -----------------------------
title SONOROUS FILE SEARCHER: Mapout done.
set /p "searchinput=Search Term: "
title SONOROUS FILE SEARCHER (Copyright 2013 by Sonorous)
for /f "delims=" %%a in ('findstr /i /L /c:"%searchinput%" "tempres.rsm" ') do set "found=%%a"
set proin=%found%
echo "%found%"
cd temporary
del "tempres.rsm"
</code>
I want the "for /f" command to output MANY search results from one search term.
Is the code not correctly formatted? Please message / comment on this question.
If you simply want to display the matching lines, then ditch the FOR /F altogether
title SONOROUS FILE SEARCHER (Copyright 2013 by Sonorous)
findstr /i /L /c:"%searchinput%" "tempres.rsm"
cd temporary
del "tempres.rsm"
If you need an "array" of matching lines, then:
:: Define the array of matching lines
set "foundCount=0"
for /f delims^=^ eol^= %%a in ('findstr /i /L /c:"%searchinput%" "tempres.rsm" ') do (
set /a "foundCount+=1"
setlocal enableDelayedExpansion
for %%N in (!foundCount!) do (
endlocal
set "found%%N=%%a"
)
)
:: Display the array values
setlocal enableDelayedExpansion
for /l %%N in (1 1 %foundCount%) do echo match %%N = !found%%N!

Deleting last n lines from file using batch file

How to delete last n lines from file using batch script
I don't have any idea about batch files, I am writing batch file for the first time.
How should I write this batch file?
For Windows7
Try it for
<Project_Name>
<Noter>
<Common>
<File>D:\Project_Name\Util.jar</File>
<File>D:\Project_Name\Noter.bat</File>
<File>D:Project_Name\Noter.xml</File>
<File>D:Project_Name\Noter.jar</File>
</Common>
<Project_Name>
<File>D:\Util.bat</File>
<File>D:\Util.xml</File>
<File>D:\log.bat</File>
</Project_Name>
</Noter>
<CCNET>
This the complete script for remove last N line
count the total line
set Line = Line - N , remain just processing lines number
#echo OFF
setlocal EnableDelayedExpansion
set LINES=0
for /f "delims==" %%I in (infile.txt) do (
set /a LINES=LINES+1
)
echo Total Lines : %LINES%
echo.
:: n = 5 , last 5 line will ignore
set /a LINES=LINES-5
call:PrintFirstNLine > output.txt
goto EOF
:PrintFirstNLine
set cur=0
for /f "delims==" %%I in (infile.txt) do (
echo %%I
::echo !cur! : %%I
set /a cur=cur+1
if "!cur!"=="%LINES%" goto EOF
)
:EOF
exit /b
Here call:PrintFirstNLine > output.txt will give the output in an external file name as output.txt
Output for sample Input
<Project_Name>
<CBA_Notifier>
<Common>
<File>D:\CBA\CBA_Notifier\Project_Name\IPS-Util.jar</File>
<File>D:\CBA\CBA_Notifier\Project_Name\Notifier.bat</File>
<File>D:\CBA\CBA_Notifier\Project_Name\Notifier.xml</File>
<File>D:\CBA\CBA_Notifier\Project_Name\Notifier.jar</File>
</Common>
<Project_Name>
<File>D:\CBA\CBA_Notifier\IPS-Util.bat</File>
remove last 5 line
Update
:PrintFirstNLine
set cur=0
for /F "tokens=1* delims=]" %%I in ('type "infile.txt" ^| find /V /N ""') do (
if "%%J"=="" (echo.) else (
echo.%%J
set /a cur=cur+1
)
if "!cur!"=="%LINES%" goto EOF
)
This script will takes 1 arguement, the file to be trunkated, creates a temporary file and then replaces the original file with the shorter one.
#echo off
setlocal enabledelayedexpansion
set count=
for /f %%x in ('type %1 ^| find /c /v ""') do set /a lines=%%x-5
copy /y nul %tmp%\tmp.zzz > nul
for /f "tokens=*" %%x in ('type %1 ^| find /v ""') do (
set /a count=count+1
if !count! leq %lines% echo %%x>>%tmp%\tmp.zzz
)
move /y %tmp%\tmp.zzz %1 > nul
If the original file is 5 or less lines, the main output routine will noT create a file. To combat this, I use the copy /y null to create a zero byte file.
If you would rather not have an empty file, just remove the copy /y nul line, and replace it with the following line:
if %lines% leq 0 del %1
You should use one method or the other, otherwise source files with 5 or less lines will remain untouched. (Neither replaced or deleted.)
to delete last lines from your file,
1 copy starting lines that are needed from file like from- e:\original.txt
2 paste them in new file like- e:\new\newfile1.txt
code is thanks to the person giving me this code:
remember all may be done if you have motive and even blood hb =6. but help of nature is required always as you are a part of it
#echo off & setLocal enableDELAYedeXpansion
set N=
for /f "tokens=* delims= " %%a in (e:\4.txt) do (
set /a N+=1
if !N! gtr 264 goto :did
e:\new4.txt echo.%%a
)
:did
if you have 800 files then use excel to make code for 800 and then copy it to notepad and using Ctrl+h replace space with no space. then rename file as haha.bat . run in folder with files numbered 1.txt 2.txt 3.txt etc. any enquirers welcome Erkamaldev#gmail.com " Long Live Bharata"
A slow method with less coding:
set input=file.txt
set remove=7
for /f "delims=" %i in ('find /c /v "" ^< "%cd%\%input%"') do set lines=%i
set /a lines-=remove
for /l %i in (1,1,!lines!) do findstr /n . log.txt | findstr /b %i:
May be redirected to a file.
Each line is prefixed with the line number; may be removed with extra coding.
A faster version with /g flag in my answer at:
How to split large text file in windows?
Tested in Win 10 CMD, on 577KB file, 7669 lines.

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