converting back the numerical value to alphabetical letters - batch-file

i found a batch .cmd project here that is able to convert the letters to its numerical value, this is it:
#echo off
:start
cls
color 9a
setlocal enableDelayedExpansion
echo.
set /p text=(your message) =
set "code=!text!"
set "chars=0abcdefghijklmnopqrstuvwxyz"
for /l %%N in (1 1 26) do for /f %%C in ("!chars:~%%N,1!") do set "code=!code:%%C=%%N !"
cls
echo.
echo (your message) = !text!
echo.
echo (numeric value) = !code!
echo.
pause
goto :start
if i type, "i love you" its numerical value will be "9 12 15 22 5 25 15 21"
what i wanted to do is to reverse the action that if i type a numerical value of something, its corresponding letter or word will appear.
how to do that?

Simply go backward for reverse
#echo off
Setlocal enableDelayedExpansion
Set "chars=0abcdefghijklmnopqrstuvwxyz"
set /p code= input code
If "!code:~-1!" neq " " set "code=!code! "
for /L %%N in (26 -1 1) do (
for /f %%C in ("!chars:~%%N, 1!") do set "code=!code:%%N =%%C!"
)
Echo text = !code!
Phil

Related

Batch command to find highest number in set of strings?

For instance:
file.txt contains:
4.3 - random1
5.6 - random2
2.2 - random3
3 - random4
1.8 - random5
I need a command that will output the highest number only, not the preceding text.
Ie.
Output = 5.6
You can give SORTN.bat a try.
Here is the code for it as well.
#ECHO OFF
if "%~1"=="/?" (
echo.Sorts text by handling first number in line as number not text
echo.
echo.%~n0 [n]
echo.
echo. n Specifies the character number, n, to
echo. begin each comparison. 3 indicates that
echo. each comparison should begin at the 3rd
echo. character in each line. Lines with fewer
echo. than n characters collate before other lines.
echo. By default comparisons start at the first
echo. character in each line.
echo.
echo.Description:
echo. 'abc10def3' is bigger than 'abc9def4' because
echo. first number in first string is 10
echo. first number in second string is 9
echo. whereas normal text compare returns
echo. 'abc10def3' smaller than 'abc9def4'
echo.
echo.Example:
echo. To sort a directory pipe the output of the dir
echo. command into %~n0 like this:
echo. dir /b^|%~n0
echo.
echo.Source: http://www.dostips.com
goto:EOF
)
if "%~1" NEQ "~" (
for /f "tokens=1,* delims=," %%a in ('"%~f0 ~ %*|sort"') do echo.%%b
goto:EOF
)
SETLOCAL ENABLEDELAYEDEXPANSION
set /a n=%~2+0
for /f "tokens=1,* delims=]" %%A in ('"find /n /v """') do (
set f=,%%B
(
set f0=!f:~0,%n%!
set f0=!f0:~1!
rem call call set f=,%%%%f:*%%f0%%=%%%%
set f=,!f:~%n%!
)
for /f "delims=1234567890" %%b in ("!f!") do (
set f1=%%b
set f1=!f1:~1!
call set f=0%%f:*%%b=%%
)
for /f "delims=abcdefghijklmnopqrstuwwxyzABCDEFGHIJKLMNOPQRSTUWWXYZ~`##$*_-+=:;',.?/\ " %%b in ("!f!") do (
set f2=00000000000000000000%%b
set f2=!f2:~-20!
call set f=%%f:*%%b=%%
)
echo.!f1!!f2!!f!,%%B
rem echo.-!f0!*!f1!*!f2!*!f!*%%a>&2
)
I gave it a try using this input as an example
4.3 - random1
11.3 - random6
5.6 - random2
2.2 - random3
100.1 - random8
3 - random4
1.8 - random5
11.12 - random7
11.11 - random7
This is how I ran it but you should be able to capture the output as well using a FOR /F command just like Stephan showed you in his answer.
type sortme.txt |sortn.bat
Output
1.8 - random5
2.2 - random3
3 - random4
4.3 - random1
5.6 - random2
11.11 - random7
11.12 - random7
11.3 - random6
100.1 - random8
sort will sort in correct order (Attention: this is sorting strings, not numbers, but will work fine for your example. Note that with string comparison 5 or 6.3 are "bigger" than 15).
Put a for around to process the ouput (Standard tokens is 1 and Space is a standard delimiter, so the for /f gets only the first element - your desired number)
for /f %%a in ('sort t.txt') do set high=%%a
echo %high%
EDIT to also process numbers higher than 10. Note: there is no math involved - it's just clever string manipulation.
#echo off
setlocal enabledelayedexpansion
(
for /f "tokens=1,2 delims=. " %%a in (t.txt) do (
set a=0000%%a
if "%%b"=="-" (echo !a:~-4!) else (echo !a:~-4!.%%b)
)
)>temp.txt
type temp.txt
pause
for /f "tokens=1,2 delims=0" %%a in ('sort temp.txt') do set high=%%a
echo %high%
The following script does proper sorting of fractional numbers with eight digits before and after the decimal separator . at most:
#echo off
setlocal EnableExtensions EnableDelayedExpansion
rem // Define constants here:
set "_FILE=%~1" & rem // (input file; `%~1` means first command line argument)
set /A "_ZPAD=8" & rem // (number of zeroes to be used for temporary padding)
set "_ZERO=" & for /L %%K in (0,1,%_ZPAD%) do set "_ZERO=!_ZERO!0"
for /F "usebackq delims=- " %%L in ("%_FILE%") do (
for /F "tokens=1,2 delims=." %%I in ("%%L.") do (
set "INT=%_ZERO%%%I" & set "FRA=%%J%_ZERO%"
set "$NUM_!INT:~-%_ZPAD%!_!FRA:~,%_ZPAD%!=%%L"
)
)
set "MIN=" & set "MAX="
for /F "tokens=2 delims==" %%L in ('2^> nul set $NUM') do (
if not defined MIN set "MIN=%%L"
set "MAX=%%L"
)
echo Minimum: %MIN%
echo Maximum: %MAX%
endlocal
exit /B

Echo Outputs When Writing to File

When I use this code to select a character from my list, it works just fine but when I write it to a file using:
echo %pwd%>>pwd.gen
It will some times put the word "ECHO" randomly in the middle of the strings generated. Here is an example:
jUrkunjcxC
ecRECHOsI5w0T
DmJfat13fT
UWXOysW7Gb
pPmS7138Ve
nFkh32ECHOJd1
You can see it appears in line 2 and 6. This only happens about 20% of the time.
Here is the code:
#echo off
title Password Generator
color f0
:firstRun
set /a cnt=0
cls
setlocal ENABLEEXTENSIONS ENABLEDELAYEDEXPANSION
set /p Len=What length should the password be?
set /a Len=%Len%-1
cls
set /p Amt=How many would you like to generate?
cls
goto start
:start
set alfanum=ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789
set pwd=
FOR /L %%b IN (0, 1, %Len%) DO (
SET /A rnd_num=!RANDOM! * 62 / 32768 + 1
for /F %%c in ('echo %%alfanum:~!rnd_num!^,1%%') do set pwd=!pwd!%%c
)
echo %pwd%>> pwd.gen
set /a cnt=%cnt%+1
if %cnt%==%Amt% goto end
goto start
:end
cls
echo Done!
echo Results have been saved to "pwd.gen"
echo.
choice /c YN /m "Restart?"
if %errorlevel%==1 goto firstRun
:start
set alfanum=ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789
set pwd=
FOR /L %%b IN (0, 1, %Len%) DO (
SET /A rnd_num=!RANDOM! * 62 / 32768 + 1
for /F %%c in ('echo %%alfanum:~!rnd_num!^,1%%') do set pwd=!pwd!%%c
)
alfanum is 26+26+10 = 62 characters long.
RANDOM gives a random number from 0-32,767
When RANDOM is above 32240, rnd_num gets set to 62
string indexing starts at 0 not 1
the for /F %%c command indexes alfanum:~62,1~ which is an empty string
it calls echo with no parameter, which prints ECHO is on. instead of returning a single character
for /F defaults to splitting strings with a space delimiter, which separates out the first word
%%c becomes ECHO
you add ECHO into the password.
This is a combination of a couple of things. While I'm not totally clear about the inner workings of the whole thing, I know what's causing it and how to fix it.
ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789 is 62 characters long. However, substrings in batch start with 0, so valid numbers go from 0 to 61. For whatever reason, an index-out-of-range combined with the ^ in 'echo %%alfanum:~!rnd_num!^,1%%' is causing the word ECHO to be displayed.
To get around this, simply don't add 1 when calculating rnd_num.
SET /A rnd_num=!RANDOM! * 62 / 32768

Only accept numeric characters in batch file input

I am making a game from a batch file and one of the inputs can accept any character (~!##$%^&*()`) and any other. Is there any way to look for any character other than numbers and use the GOTO command? This is my script so far:
set /p guess=
echo "%guess%"|findstr /L "[a-z][A-Z]~`!##$%^&*()-_=+\^|^^;:"',<.>/?*"
if %errorlevel% == 0 goto Invalid_Number
if %guess% == %number% goto Correct
... everything else here ...
:Invalid_Number
echo Invalid Number. Input must be a number
pause
Is there any way to make this work, all it says is Access Denied, I am testing this on a school computer though, it might not work.
Put this at the bottom of your script:
:isInt <str>
for /f "delims=0123456789" %%a in ("%1") do exit /b 1
exit /b 0
Then to invoke it, do
call :isInt %guess% && success || fail
Here's a more complete example:
#echo off
setlocal
set /a rand = %RANDOM% %% 10 + 1
:begin
set /P "guess=Guess a number between 1 and 10: "
call :isInt %guess% || goto invalid
if %guess% gtr 0 if %guess% lss 11 (
if %guess% equ %rand% (
echo Lucky guess!
exit /b
) else (
echo Oooh, so close. Try again.
goto begin
)
)
:invalid
echo Please enter a valid integer between 1 and 10.
goto begin
:isInt <str>
for /f "delims=0123456789" %%a in ("%1") do exit /b 1
exit /b 0
This is the same basic idea as MC ND's solution, but instead of using the for statement to unset %guess%, it sets %errorlevel% and stops looping at the first non-numeric character. This makes it infinitesimally more efficient. :)
And with either success or fail, I like to use conditional execution (the && and || stuff).
:ask
set /p "guess=?" || goto :ask
setlocal enabledelayedexpansion
for /f "delims=0123456789" %%a in ("!guess!") do set "guess="
endlocal & set "guess=%guess%"
if not defined guess (
echo invalid input
goto ask
)
echo valid input
The basic idea behind the test is to use the numbers as delimiters in a for /f command, so they are removed from the input. If anything remains it is not a number and the code in the do clause is executed.
The delayedexpansion is enabled/disabled to handle problematic characters (specially double quotes) that could be typed in the input field.
May I suggest you a different, better approach? Instead of read any line and then check if it contains a number, your program may directly read a number, so the checking is not necessary. The way to do that is emulating SET /P command via a subroutine. This way, you may add additional constraints to the input, like read a maximum number of digits, for example.
#echo off
rem Read a number emulating SET /P command
rem Antonio Perez Ayala
setlocal
rem Define the following variable before call InputNumber subroutine
set "thisFile=%~F0"
call :InputNumber number="Enter a number of up to 5 digits: " 5
echo Number read: %number%
goto :EOF
:InputNumber var="prompt" [digits]
setlocal EnableDelayedExpansion
rem Initialize variables
if "%~3" equ "" (set numDigits=9) else set "numDigits=%3"
set "digits=0123456789"
for /F %%a in ('copy /Z "%thisFile%" NUL') do set "CR=%%a"
for /F %%a in ('echo prompt $H ^| cmd') do set "BS=%%a"
rem Show the prompt and start reading
set /P "=%~2" < NUL
set "input="
set i=0
:nextKey
set "key="
for /F "delims=" %%a in ('xcopy /W "%thisFile%" "%thisFile%" 2^>NUL') do if not defined key set "key=%%a"
rem If key is CR: terminate input
if "!key:~-1!" equ "!CR!" goto endRead
rem If key is BS: delete last char, if any
set "key=!key:~-1!"
if "!key!" equ "!BS!" (
if %i% gtr 0 (
set /P "=!BS! !BS!" < NUL
set "input=%input:~0,-1%"
set /A i-=1
)
goto nextKey
)
rem If key is not a digit: ignore it
if "!digits:%key%=!" equ "%digits%" goto nextKey
rem If can not accept more digits: ignore it
if %i% equ %numDigits% goto nextKey
rem Else: show and accept the digit
set /P "=%key%" < NUL
set "input=%input%%key%"
set /A i+=1
goto nextKey
:endRead
echo/
endlocal & set "%~1=%input%"
exit /B
You may also add any other processing to the input line, like show asterisks instead of digits, etc. For a large example on this topic, see this post

Batch script - Assign variable in FOR-IF

I have a file with this output:
ANS8000I Server command: 'ru FailedReport'
Unnamed[1]
------------
9
Unnamed[1]
------------
110
Unnamed[1]
------------
101
I need to take those numbers, and assign it to three different variables. I made this script, but I can't make it to work... I always got "0" as result.
#echo off
setlocal enableextensions enabledelayedexpansion
set /A counter=0
SET /A failed=0
SET /A completed=0
SET /A total=0
for /F "tokens=1 skip=4" %%a in (C:\Users\Desktop\Aux.txt) do (
if "%counter%" EQU 5 (set /A failed=%%a)
if "%counter%" EQU 9 (set /A completed=%%a)
if "%counter%" EQU 13 (set /A total=%%a)
set /A counter+=1
)
echo "Failed: " %failed% >> C:\Users\Desktop\Result.txt
echo "Completed: " %completed% >> C:\Users\Desktop\Result.txt
echo "Total: " %total% >> C:\Users\Desktop\Result.txt
Could anyone help me with this? I tried a lot of combinations (variables with !, %, %%), but I still got the same result.
Thanks!!!
#ECHO OFF
setlocal enableextensions enabledelayedexpansion
set /A counter=0
SET /A failed=0
SET /A completed=0
SET /A total=0
for /F "tokens=1" %%a in (q24152955.txt) do (
ECHO !counter! %%a
if !counter! EQU 3 (set /A failed=%%a)
if !counter! EQU 9 (set /A completed=%%a)
if !counter! EQU 6 (set /A total=%%a)
set /A counter+=1
)
echo "Failed: " %failed%
echo "Completed: " %completed%
echo "Total: " %total%
GOTO :eof
I used a file named q24152955.txt containing your data for my testing.
In delayedexpansion mode, %var% refers to the original value of var - before the loop began execution and !var! is the dynamic value - as it changes.
"something" is never going to be equal to something because the quotes are significant. Quoted values are often used in this context in case the value itself is empty or contains special characters (especially spaces) - "" is a non-empty string.
for /f ignores empty lines. I've included a superfluous echo command to show which lines the for processes. Note that the value of counter is thus the sequential number of non-empty lines in the file, not the actual line number. Note also that a line containing just one (or more) spaces is not an empty line!
#ECHO off&cls
setlocal enabledelayedexpansion
set "$count=1"
for /f "delims=" %%a in (C:\Users\Desktop\Aux.txt) do (
if !$count!==4 set failed=%%a
if !$count!==7 set completed=%%a
if !$count!==10 set total=%%a
set /a $count+=1
)
(echo Failed : %failed: =%
echo Completed : %completed: =%
echo Total : %total: =%)> C:\Users\Desktop\Result.txt

How to do math in batch-file

I have been having troubles with batch-codes that I would expect to work, but don't...
Below is what I have written...
#echo off
cls
:loop
set /p "input=Input a number: "
set /a "number=%input%" 2>nul
REM check if input valid
if "%input%" NEQ "%number%" (
cls
Echo Please Enter a valid number! &Echo.&Echo.
goto :loop
)
Set /a Even=number%%2
if %Even% EQU 0 (
Echo Substituting Even Number in: x / 2
Echo set /p"=(%number%) / 2 = "
set /a answer=number/2
) Else (
Echo Substituting Odd Number in: 3x - 1
<nul set /p"=3(%number%)-1 = "
set /a answer=number*3
set /a answer=answer-1
)
Echo %answer%
Echo.
Echo.
goto :loop
Echo Unexpected Error . . .
pause
Exit
Whenever I input a number into the console, it does the math, like I want it to, but prints the number -1, and every time i input another number, the number goes to -2, -3, -4, so on.
Put a setlocal enableextensions at the beginning after the #echo off, e.g.
#echo off
setlocal enableextensions
cls
Also, I think you would also need to use delayed variable expansion (usually denoted by !var!), which would change your script above to something like this:
#echo off
setlocal enableextensions enabledelayedexpansion
cls
:loop
set /p "input=Input a number: "
set /a number=!input! 2>nul
REM check if input valid
if "!input!" NEQ "!number!" (
cls
Echo Please Enter a valid number!
Echo.
Echo.
goto :loop
)
REM Make sure that it is an integer put in (just in case)
set /a int=!number! %% 1
if "!input!" NEQ "!int!" (
cls
Echo Please Enter a valid number!
Echo.
Echo.
goto :loop
)
Set /a Even=!number! %% 2
if !Even! EQU 0 (
Echo Substituting Even Number in: x / 2
set /a answer=!number! / 2
) Else (
Echo Substituting Odd Number in: 3x - 1
set /a answer=!number! * 3 - 1
)
Echo !answer!
Echo.
Echo.
goto :loop
I also would like to point out that I also fixed a few other bugs (set /p isn't of any use in this script at all, especially in where it is used, and also you need the modulus to find even/odd).

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