Add Column to CSV file Using Other CSV file - arrays

Question

I am working with two CSV files. One holds the name of users and the other one holds their corresponding email address. What I want to do is to combine them both so that users is column 1 and email is column 2 and output it to one file. So far, I've managed to add a second column from the email csv file to the user csv file, but with blank row data. Below is the code that I am using:
$emailCol= import-csv "C:\files\temp\emailOnly.csv" | Select-Object -skip 1
$emailArr=#{}
$i=0
$nameCol = import-csv "C:\files\temp\nameOnly.csv"
foreach ($item in $emailCol){
$nameCol | Select *, #{
Name="email";Expression=
{$emailArr[$i]}
} | Export-Csv -path
C:\files\temp\revised.csv -NoTypeInformation
}
Updated: Below is what worked for me. Thanks BenH!
function combineData {
#This function will combine the user CSV file and
#email CSV file into a single file
$emailCol = Get-Content "C:\files\temp\emailOnly.csv"
| Select-Object -skip 1
$nameCol = Get-Content "C:\files\temp\nameOnly.csv" |
Select-Object -skip 1
# Max function to find the larger count of the two
#csvs to use as the boundary for the counter.
$count = [math]::Max($emailCol.count,$nameCol.count)
$CombinedArray = for ($i = 0; $i -lt $count; $i++) {
[PSCustomObject]#{
fullName = $nameCol[$i]
email = $emailCol[$i]
}
}
$CombinedArray | Export-Csv C:\files\temp\revised.csv
-NoTypeInformation
}

Answer 1

To prevent some additional questions about this theme let me show you alternative approach. If your both CSV files have same number of lines and each line of the first file corresponds to the first line of the second file and etc. then you can do next. For example, users.csv:
User
Name1
Name2
Name3
Name4
Name5
and email.csv:
Email
mail1#gmail.com
mail2#gmail.com
mail3#gmail.com
mail5#gmail.com
Our purpose:
"User","Email"
"Name1","mail1#gmail.com"
"Name2","mail2#gmail.com"
"Name3","mail3#gmail.com"
"Name4",
"Name5","mail5#gmail.com"
What we do?
$c1 = 'C:\path\to\user.csv'
$c2 = 'C:\path\to\email.csv'
[Linq.Enumerable]::Zip(
(Get-Content $c1), (Get-Content $c2),[Func[Object, Object, Object[]]]{$args -join ','}
) | ConvertFrom-Csv | Export-Csv C:\path\to\output.csv
If our purpose is:
"User","Email"
"Name1","mail1#gmail.com"
"Name2","mail2#gmail.com"
"Name3","mail3#gmail.com"
"Name5","mail5#gmail.com"
then:
$c1 = 'C:\path\to\user.csv'
$c2 = 'C:\path\to\email.csv'
([Linq.Enumerable]::Zip(
(Get-Content $c1), (Get-Content $c2),[Func[Object, Object, Object[]]]{$args -join ','}
) | ConvertFrom-Csv).Where{$_.Email} | Export-Csv C:\path\to\output.csv
Hope this helps you in the future.

Answer 2

A for loop would be better suited for your loop. Then use the counter as the index for each of the arrays to build your new object.
$emailCol = Get-Content "C:\files\temp\emailOnly.csv" | Select-Object -Skip 2
$nameCol = Get-Content "C:\files\temp\nameOnly.csv" | Select-Object -Skip 1
# Max function to find the larger count of the two csvs to use as the boundary for the counter.
$count = [math]::Max($emailCol.count,$nameCol.count)
$CombinedArray = for ($i = 0; $i -lt $count; $i++) {
[PSCustomObject]#{
Name = $nameCol[$i]
Email = $emailCol[$i]
}
}
$CombinedArray | Export-Csv C:\files\temp\revised.csv -NoTypeInformation
Answer edited to use Get-Content with an extra skip added to skip the header line in order to handle blank lines.