Get average and max in 1 minute intervals T-SQL - sql-server

I have a query that extracts the number of records in 1 minute intervals. I want to compare the average vs last value.
I only get he total which is the count(1) and its valid. The average and the maximum is always returning as 1 which is not accurate.
Is there something that I am missing in this SQL?
SELECT
FORMAT(timestamp, 'hh:mm') AS tm,
AVG(1) AS avgOccurances,
MAX(1) AS maxocc,
COUNT(1) AS total
FROM
[history]
WHERE
timestamp BETWEEN '2018-04-16 14:00:00.707' AND '2018-04-18 15:00:00.707'
AND result = 'F'
GROUP BY
FORMAT(timestamp, 'hh:mm')
ORDER BY
tm ASC
Result
01:00 1 1 13
01:01 1 1 10
01:02 1 1 11
01:03 1 1 7
01:04 1 1 13
01:05 1 1 7
01:06 1 1 14
01:07 1 1 11
01:08 1 1 12
01:09 1 1 10
01:10 1 1 5
01:11 1 1 6
01:12 1 1 8
01:13 1 1 13
01:14 1 1 9
01:15 1 1 8
01:16 1 1 2
01:17 1 1 10
01:18 1 1 9
01:19 1 1 13
01:20 1 1 9
01:21 1 1 8
01:22 1 1 14
01:23 1 1 10


The query below assumes each row should have the following:
Count per minute
Count per minute for the previous minute
Count for the minute with the most occurrences
If that's incorrect just let me know. Here's the query:
WITH countbyminute AS (
SELECT
FORMAT(timestamp, 'hh:mm') AS tm,
COUNT(*) AS occurences
FROM history
GROUP BY FORMAT(timestamp, 'hh:mm')
)
SELECT
tm,
occurrences,
LAG(occurrences) OVER (ORDER BY TIMESTAMP) AS priorocc,
MAX(occurrences) OVER () AS maxocc
FROM countbyminute
ORDER BY tm;
And I'd suggest using HH:mm as the format string, which will rerurn the hours using a 24-hour clock (1:00PM as 13:00).

Related

Get output of multiple Counts in one query

Could you help me how to write a query for the following issue:
There are two tables:
Table persons:
P_id Name BirthDate
1 N1 2016-08-02
2 N2 2015-05-02
3 N3 2013-06-01
4 N4 2014-01-09
Table visited:(p_id is foreign key to table persons)
Id. Visitor_id. P_id. Visit_date
1 10 1 2017-03-05
2 11 2 2017-01-01
3 10 2 2017-02-03
4 12 3 2016-05-07
5 11 4 2016-04-09
6 10 1 2017-04-09
We are going to get the count of visited by each Visitor and also count of visited distinct person on filter on for those person who their age are under 1, between 1 and 2, between 2 and 3 at date of visit_date by each visitor_id.
The results should be like :
Under_one Bet_one_two Bet_two_three
Visitor_id VisitedCount/PersonCount VisitedCount/PersonCount VisitedCount/PersonCount
10 2 1 1 1 0 0
11 0 0 1 1 1 1
12 0 0 0 0 1 1
Between 1 and 2 means the result of subtracting visited_date and birthdate (for example : the result of 2013/03/05 - 2011/06/07) is between 1 and 2 years.

I don't know if I can give you the output laid out exactly as you have specified, but this
SELECT
visited.Visitor_id,
visited.P_id,
Int(([Visit_date]-[BirthDate])/365) AS Age,
Count(persons.P_id) AS NumVisits
FROM persons INNER JOIN visited ON persons.P_id = visited.P_id
GROUP BY
visited.Visitor_id,
visited.P_id,
Int((-[BirthDate]+[Visit_date])/365);
returns
Visitor_id P_id Age NumVisits
10 1 0 2
10 2 1 1
11 2 1 1
11 4 2 1
12 3 2 1

How to count number of months in T-SQL

I've got a problem in SQL Server.
"Whate'er is well conceived is clearly said, And the words to say it flow with ease", Nicolas Boileau-Despreaux
Well, I don't think I'll be able to make it clear but I'll try ! And I'd like to apologize for my bad english !
I've got this table :
id ind lvl result date
1 1 a 3 2017-01-31
2 1 a 3 2017-02-28
3 1 a 1 2017-03-31
4 1 a 1 2017-04-30
5 1 a 1 2017-05-31
6 1 b 1 2017-01-31
7 1 b 3 2017-02-28
8 1 b 3 2017-03-31
9 1 b 1 2017-04-30
10 1 b 1 2017-05-31
11 2 a 3 2017-01-31
12 2 a 1 2017-02-28
13 2 a 3 2017-03-31
14 2 a 1 2017-04-30
15 2 a 3 2017-05-31
I'd like to count the number of month the combo {ind, lvl} remain in the result 1 before re-initializing the number of month to 0 if the result is not 1.
Clearly, I need to get something like that :
id ind lvl result date BadResultRemainsFor%Months
1 1 a 3 2017-01-31 0
2 1 a 3 2017-02-28 0
3 1 a 1 2017-03-31 1
4 1 a 1 2017-04-30 2
5 1 a 1 2017-05-31 3
6 1 b 1 2017-01-31 1
7 1 b 3 2017-02-28 0
8 1 b 3 2017-03-31 0
9 1 b 1 2017-04-30 1
10 1 b 1 2017-05-31 2
11 2 a 3 2017-01-31 0
12 2 a 1 2017-02-28 1
13 2 a 3 2017-03-31 0
14 2 a 1 2017-04-30 1
15 2 a 3 2017-05-31 0
So that if I was looking for the number of months the result was 1 for the date 2017-05-31 with the id 1 and the lvl a, I know it's been 3 months.

Assume all the date the the end day of month:
;WITH tb(id,ind,lvl,result,date) AS(
select 1,1,'a',3,'2017-01-31' UNION
select 2,1,'a',3,'2017-02-28' UNION
select 3,1,'a',1,'2017-03-31' UNION
select 4,1,'a',1,'2017-04-30' UNION
select 5,1,'a',1,'2017-05-31' UNION
select 6,1,'b',1,'2017-01-31' UNION
select 7,1,'b',3,'2017-02-28' UNION
select 8,1,'b',3,'2017-03-31' UNION
select 9,1,'b',1,'2017-04-30' UNION
select 10,1,'b',1,'2017-05-31' UNION
select 11,2,'a',3,'2017-01-31' UNION
select 12,2,'a',1,'2017-02-28' UNION
select 13,2,'a',3,'2017-03-31' UNION
select 14,2,'a',1,'2017-04-30' UNION
select 15,2,'a',3,'2017-05-31'
)
SELECT t.id,t.ind,t.lvl,t.result,t.date
,CASE WHEN t.isMatched=1 THEN ROW_NUMBER()OVER(PARTITION BY t.ind,t.lvl,t.id-t.rn ORDER BY t.id) ELSE 0 END
FROM (
SELECT t1.*,c.MonthDiff,CASE WHEN c.MonthDiff=t1.result THEN 1 ELSE 0 END AS isMatched
,CASE WHEN c.MonthDiff=t1.result THEN ROW_NUMBER()OVER(PARTITION BY t1.ind,t1.lvl,CASE WHEN c.MonthDiff=t1.result THEN 1 ELSE 0 END ORDER BY t1.id) ELSE null END AS rn
FROM tb AS t1
LEFT JOIN tb AS t2 ON t1.ind=t2.ind AND t1.lvl=t2.lvl AND t2.id=t1.id-1
CROSS APPLY(VALUES(ISNULL(DATEDIFF(MONTH,t2.date,t1.date),1))) c(MonthDiff)
) AS t
ORDER BY t.id
id ind lvl result date
----------- ----------- ---- ----------- ---------- --------------------
1 1 a 3 2017-01-31 0
2 1 a 3 2017-02-28 0
3 1 a 1 2017-03-31 1
4 1 a 1 2017-04-30 2
5 1 a 1 2017-05-31 3
6 1 b 1 2017-01-31 1
7 1 b 3 2017-02-28 0
8 1 b 3 2017-03-31 0
9 1 b 1 2017-04-30 1
10 1 b 1 2017-05-31 2
11 2 a 3 2017-01-31 0
12 2 a 1 2017-02-28 1
13 2 a 3 2017-03-31 0
14 2 a 1 2017-04-30 1
15 2 a 3 2017-05-31 0

By slightly tweaking your input data and slightly tweaking how we define the requirement, it becomes quite simple to produce the expected results.
First, we tweak your date values so that the only thing that varies is the month and year - the days are all the same. I've chosen to do that my adding 1 day to each value1. The fact that this produces results which are one month advanced doesn't matter here, since all values are similarly transformed, and so the monthly relationships stay the same.
Then, we introduce a numbers table - here, I've assumed a small fixed table is adequate. If it doesn't fit your needs, you can easily locate examples online for creating a large fixed numbers table that you can use for this query.
And, finally, we recast the problem statement. Instead of trying to count months, we instead ask "what's the smallest number of months, greater of equal to zero, that I need to go back from the current row, to locate a row with a non-1 result?". And so, we produce this query:
declare #t table (id int not null,ind int not null,lvl varchar(13) not null,
result int not null,date date not null)
insert into #t(id,ind,lvl,result,date) values
(1 ,1,'a',3,'20170131'), (2 ,1,'a',3,'20170228'), (3 ,1,'a',1,'20170331'),
(4 ,1,'a',1,'20170430'), (5 ,1,'a',1,'20170531'), (6 ,1,'b',1,'20170131'),
(7 ,1,'b',3,'20170228'), (8 ,1,'b',3,'20170331'), (9 ,1,'b',1,'20170430'),
(10,1,'b',1,'20170531'), (11,2,'a',3,'20170131'), (12,2,'a',1,'20170228'),
(13,2,'a',3,'20170331'), (14,2,'a',1,'20170430'), (15,2,'a',3,'20170531')
;With Tweaked as (
select
*,
DATEADD(day,1,date) as dp1d
from
#t
), Numbers(n) as (
select 0 union all select 1 union all select 2 union all select 3 union all select 4
union all
select 5 union all select 6 union all select 7 union all select 8 union all select 9
)
select
id, ind, lvl, result, date,
COALESCE(
(select MIN(n) from Numbers n1
inner join Tweaked t2
on
t2.ind = t1.ind and
t2.lvl = t1.lvl and
t2.dp1d = DATEADD(month,-n,t1.dp1d)
where
t2.result != 1
),
1) as [BadResultRemainsFor%Months]
from
Tweaked t1
The COALESCE is just there to deal with the edge case, such as for your 1,b data, where there is no previous row with a non-1 result.
Results:
id ind lvl result date BadResultRemainsFor%Months
----------- ----------- ------------- ----------- ---------- --------------------------
1 1 a 3 2017-01-31 0
2 1 a 3 2017-02-28 0
3 1 a 1 2017-03-31 1
4 1 a 1 2017-04-30 2
5 1 a 1 2017-05-31 3
6 1 b 1 2017-01-31 1
7 1 b 3 2017-02-28 0
8 1 b 3 2017-03-31 0
9 1 b 1 2017-04-30 1
10 1 b 1 2017-05-31 2
11 2 a 3 2017-01-31 0
12 2 a 1 2017-02-28 1
13 2 a 3 2017-03-31 0
14 2 a 1 2017-04-30 1
15 2 a 3 2017-05-31 0
1An alternative way to perform the adjustment is to use a DATEADD/DATEDIFF pair to perform a "floor" operation against the dates:
DATEADD(month,DATEDIFF(month,0,date),0) as dp1d
Which resets all of the date values to be the first of their own month rather than the following month. This may fell more "natural" to you, or you may already have such values available in your original data.

Assuming the dates are continously increasing in month, you can use window function like so:
select
t.id, ind, lvl, result, dat,
case when result = 1 then row_number() over (partition by grp order by id) else 0 end x
from (
select t.*,
dense_rank() over (order by e, result) grp
from (
select
t.*,
row_number() over (order by id) - row_number() over (partition by ind, lvl, result order by id) e
from your_table t
order by id) t ) t;

Reset a sum in a query when a date field changes month

I am currently executing the following query:
Select *, Balance = SUM(DailyReAdmits)
OVER (ORDER BY Date_Total ROWS UNBOUNDED PRECEDING)
From #AllReadmits
Which returns these results:
Date_Total DailyReAdmits Balance
2015-08-25 4 4
2015-08-26 8 12
2015-08-27 9 21
2015-08-28 3 24
2015-08-29 1 25
2015-08-30 4 29
2015-08-31 3 32
2015-09-01 5 37
However, when a new month starts, I would like the balance to start over again and look like this:
Date_Total DailyReAdmits Balance
2015-08-25 4 4
2015-08-26 8 12
2015-08-27 9 21
2015-08-28 3 24
2015-08-29 1 25
2015-08-30 4 29
2015-08-31 3 32
2015-09-01 5 5
How can I achieve this?

I supposed that you want partition by month, so try this:
SELECT *, Balance = SUM(DailyReAdmits)
OVER (PARTITION BY DATEPART(MM,Date_Total) ORDER BY Date_Total ROWS UNBOUNDED PRECEDING)
FROM #AllReadmits

Azure SQL - Calculate stock level based on previous date

I have transactions table that looks like below. I need to create a stored procedure that will calculate the StockLevel column.
The dates are consecutive (always 1 day gap) and the formula is :
StockLevel = yesterdayStockLevel + AIn - AOut
Sample data:
Date | ArticleId | AOut | AIn | StockLevel
Aug 1 1 1 10 10 - 1 = 9
Aug 2 1 2 0 9 - 2 = 7
Aug 3 1 1 0 7 - 1 = 6
Aug 4 1 2 0 6 - 2 = 4
Aug 5 1 3 5 4 - 3 + 5 = 6
Aug 6 1 0 0 6 - 0 = 6
I prefer to run it on SQL (if possible) and not use cursor (if possible).
THANKS!!

Try this :
Select Date, ArticleID, AOut, AIn, AInSum-AOutSum as StockLevel
From (
Select *,
sum(AOut)over (Partition by ArticleId Order by Date) AOutSum,
sum(AIn)over (Partition by ArticleId Order by Date) AInSum
From yourTabble
) X

SQL Query multiple values of a column as multiple columns (SQL 2005)

When I run a SQL query on a single table and here is the data (this is just a sample, error column might be more than 10)
time total Error
00:16 6 10000(E)
00:20 4 10000(E)
00:46 2 10000(E)
01:01 2 10000(E)
01:40 2 10000(E)
02:07 2 10000(E)
02:52 1 10000(E)
04:27 2 10000(E)
04:29 6 10000(E)
04:32 4 10000(E)
04:49 2 10000(E)
04:50 2 10000(E)
06:18 2 10000(E)
09:04 1 10000(E)
10:57 4 10000(E)
10:58 4 10000(E)
00:36 1 9401(E)
00:37 1 9401(E)
00:57 1 9401(E)
00:58 1 9401(E)
01:32 1 9401(E)
01:33 1 9401(E)
02:36 2 9401(E)
03:05 1 9401(E)
03:06 1 9401(E)
09:53 2 9401(E)
12:11 2 9401(E)
12:12 4 9401(E)
12:41 1 9401(E)
I want to write a SQL query so that I want to get the above data like this
time 10000(E) 9401(E)
---------------------------
00:16 6 0
00:20 4 0
00:36 0 1
00:37 0 1
00:46 2 0
00:57 0 1
00:58 0 1
01:01 2 0
01:32 0 1
01:33 0 1
01:40 2 0
02:07 2 0
02:36 0 2
02:52 1 0
03:05 0 1
03:06 0 1
04:27 2 0
04:29 6 0
04:32 4 0
04:49 2 0
04:50 2 0
06:18 2 0
09:04 1 0
09:53 0 1
10:57 4 0
10:58 4 0
12:11 0 2
12:12 0 4
12:41 0 1
is this possible??

Does this meet your requirement?
select e.time
, e.[10000(E)]
, e.[9401(E)]
from (
select time
, SUM(case when Error LIKE N'10000(E)' then Total else NULL end) as [10000(E)]
, null as [9401(E)]
from MyTable
where Error LIKE N'10000(E)'
group by time
union
select time
, null as [10000(E)]
, SUM(case when Error LIKE N'9401' then Total else NULL end) as [9401(E)]
from MyTable
where Error LIKE N'9401(E)'
group by time
) e
order by e.time
If no, please tell me about the result so that I can bring the righteous corrections.
The SUM function only comes to group the number of occurences of a same error into one given time, which seems to be what you have in your table, actually. So, it shouldn't modify any data. On the other hand, if you had two different records of the same error by the same time, then they should be grouped by this time and the total of occurences of this error will be additioned.

For your given in- and output it could be as simple as this.
SELECT *
FROM (
SELECT time
, [10000(E)] = Total
, [9401(E)] = 0
FROM YourTable
WHERE Error = '10000(E)'
UNION ALL
SELECT time
, [10000(E)] = 0
, [9401(E)] = Total
FROM YourTable
WHERE Error = '9401(E)'
) q
ORDER BY
time

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