I have a calendar table and I want to show each month in a grid, and when I select a month from the table, I have some row with monthday and weekday columns, but I must convert it to multiple rows per week to show the month in the grid.
my select command to get month info is something like this
SELECT Monthday, Weekday FROM Calendar Where Month = 5
that Results to this :
Monthday | Weekday
--------- --------
1 4
2 5
3 6
4 7
5 1
6 2
7 3
8 4
. .
. .
. .
and I Want to Convert it To Something like this
1 | 2 | 3 | 4 | 5 | 6 | 7
-- --- --- --- --- --- --
1 2 3 4
5 6 7 8 . . .
just like a calendar grid.
I think the answer is by Pivot, but I don't know how, Do you know a solution how to convert my select command?
Let's suppose you have a calendar table with the structure mentioned below, which is populated with a query like the following:
CREATE TABLE Calendar (
TheDate DATE PRIMARY KEY,
YearNumber SMALLINT,
MonthNumber SMALLINT,
DayNumber SMALLINT,
WeekdayNumber SMALLINT
)
INSERT INTO dbo.Calendar (TheDate, YearNumber, MonthNumber, DayNumber, WeekdayNumber)
SELECT x.TheDate,
YEAR(x.TheDate) AS YearNumber, MONTH(x.TheDate) AS MonthNumber, DAY(x.TheDate) AS DayNumber,
(DATEPART(WEEKDAY,x.TheDate)+##DATEFIRST-2)%7+1 AS WeekdayNumber
FROM (
SELECT TOP 365 DATEADD(DAY,N-1,'20210101') AS TheDate
FROM (SELECT ROW_NUMBER() OVER (ORDER BY low) AS N FROM master..spt_values) t
ORDER BY N
) x
The formula for WeekdayNumber is written this way to ignore the SET DATEFIRST setting and always consider Monday as the first day of week. If you prefer another day to be the first in the week, adjust -2 to another value.
To display something like a calendar for a particular month, you can use a query like this:
SELECT * FROM (
SELECT DayNumber, WeekdayNumber,
DENSE_RANK() OVER (ORDER BY DayNumber-WeekdayNumber) AS WeekNumber
FROM dbo.Calendar WHERE YearNumber=2021 AND MonthNumber=5
) t
PIVOT (MAX(DayNumber) FOR WeekdayNumber IN ([1],[2],[3],[4],[5],[6],[7])) p
This produces the following result:
WeekNumber 1 2 3 4 5 6 7
-------------------- ------ ------ ------ ------ ------ ------ ------
1 NULL NULL NULL NULL NULL 1 2
2 3 4 5 6 7 8 9
3 10 11 12 13 14 15 16
4 17 18 19 20 21 22 23
5 24 25 26 27 28 29 30
6 31 NULL NULL NULL NULL NULL NULL
I am using just the DayNumber and WeekdayNumber columns to compute a week number and then I am using PIVOT to arrange the values for DayNumber in the desired format.
I have data as below :
Month and then corresponding units sold for 3 different item type
Month Sale1 Sale2 Sale3
1 20
2 12
3 50
1 2
2 17
3 56
1 11
2 35
3 9
I want data to be in below format:
Month Sale1 Sale2 Sale3
1 20 2 11
2 12 17 35
3 50 56 9
Maybe SUM is better then MAX if there can be items from one type across different months:
SELECT [Month]
,SUM(Sale1) AS Sale1
,SUM(Sale2) AS Sale2
,SUM(Sale3) AS Sale3
FROM [table]
GROUP BY [Month]
I have a query that extracts the number of records in 1 minute intervals. I want to compare the average vs last value.
I only get he total which is the count(1) and its valid. The average and the maximum is always returning as 1 which is not accurate.
Is there something that I am missing in this SQL?
SELECT
FORMAT(timestamp, 'hh:mm') AS tm,
AVG(1) AS avgOccurances,
MAX(1) AS maxocc,
COUNT(1) AS total
FROM
[history]
WHERE
timestamp BETWEEN '2018-04-16 14:00:00.707' AND '2018-04-18 15:00:00.707'
AND result = 'F'
GROUP BY
FORMAT(timestamp, 'hh:mm')
ORDER BY
tm ASC
Result
01:00 1 1 13
01:01 1 1 10
01:02 1 1 11
01:03 1 1 7
01:04 1 1 13
01:05 1 1 7
01:06 1 1 14
01:07 1 1 11
01:08 1 1 12
01:09 1 1 10
01:10 1 1 5
01:11 1 1 6
01:12 1 1 8
01:13 1 1 13
01:14 1 1 9
01:15 1 1 8
01:16 1 1 2
01:17 1 1 10
01:18 1 1 9
01:19 1 1 13
01:20 1 1 9
01:21 1 1 8
01:22 1 1 14
01:23 1 1 10
The query below assumes each row should have the following:
Count per minute
Count per minute for the previous minute
Count for the minute with the most occurrences
If that's incorrect just let me know. Here's the query:
WITH countbyminute AS (
SELECT
FORMAT(timestamp, 'hh:mm') AS tm,
COUNT(*) AS occurences
FROM history
GROUP BY FORMAT(timestamp, 'hh:mm')
)
SELECT
tm,
occurrences,
LAG(occurrences) OVER (ORDER BY TIMESTAMP) AS priorocc,
MAX(occurrences) OVER () AS maxocc
FROM countbyminute
ORDER BY tm;
And I'd suggest using HH:mm as the format string, which will rerurn the hours using a 24-hour clock (1:00PM as 13:00).
I did search, but the uniqueness of each question makes it hard for me to "translate" it for my dataset.
I have table A named: CLOGS17
With a sub-set of the data and fields shown:
SERIALNO EVDATE SYSNO AREA USRNO
4 2017-01-01 02:03:48.000 1 4 10
4 2017-01-01 02:09:00.000 1 4 10
4 2017-01-01 02:24:44.997 1 6 10
4 2017-01-01 02:56:50.000 1 2 18
5 2017-08-08 02:03:48.000 1 4 10
5 2017-01-09 02:09:00.000 1 4 10
6 2017-04-03 02:24:44.997 1 6 10
8 2017-05-05 02:56:50.000 1 2 18
My goal is to retrieve all records where the combination of SERIALNO + SYSNO + AREA + USRNO has not been used in the last 30 days (inactive user essentiallY) so I can delete that USRNO.
Desired output from above data would be (newest record for each SERIALNO, SYSNO, AREA, and USRNO distinct combination):
SERIALNO EVDATE SYSNO AREA USRNO
4 2017-01-01 02:09:00.000 1 4 10
4 2017-01-01 02:24:44.997 1 6 10
4 2017-01-01 02:56:50.000 1 2 18
5 2017-08-08 02:03:48.000 1 4 10
6 2017-04-03 02:24:44.997 1 6 10
8 2017-05-05 02:56:50.000 1 2 18
I am then able to get only those within the last 30 days.
Given the table data below ("Table B"), it is a list of all stored users:
SERIALNO CONTID SYSNO AREA USRID
36 001 1 * 1
36 001 1 * 18
36 001 1 * 2
36 001 1 * 29
36 001 1 * 36
36 001 1 1 10
This table contains ALL users in the system.
How can I return all the users from Table B that have not been used for a given CONTID, SYSNO, and AREA?
For the first part of your question it would be as simples as a group by of a select on the desired fields:
SELECT SERIALNO,
SYSNO,
AREA,
USRNO,
MAX(EVDATE)
FROM CLOGS17
GROUP BY SERIALNO,
SYSNO,
AREA,
USRNO
Since you didn't provide enough information about the second part. This query will give you the output you show in your question.
So, to get all users that doesn't meet your 30 days criteria (whatever it are), you just do a left join of you user table with the above query seeking the nulls for the query above, like this:
SELECT *
FROM tableb tb LEFT JOIN
(SELECT SERIALNO,
SYSNO,
AREA,
USRNO,
MAX(EVDATE)
FROM CLOGS17
GROUP BY SERIALNO,
SYSNO,
AREA,
USRNO) a
ON tb.SERIALNO = a.SERIALNO,
AND tb.SYSNO = a.SYSNO
AND tb.USRNO = a.USRNO
WHERE a.AREA is null
friends:
I'm now have a problem about conditional calculation in SQL Server.
I have set some data from SQL Server as an example in excel like this:
No Employee Month Commission1 Commission2
1 A Jan 10 5
2 A Jan 10 4
3 B Jan 15 3
4 B Jan 15 4
5 C Jan 10 3
6 C Jan 10 4
7 D Jan 13 3
8 D Jan 13 4
9 DM Jan 0 6
10 DM Jan 0 8
11 A Feb 15 4
12 A Feb 15 5
13 B Feb 20 5
14 B Feb 20 4
15 C Feb 9 3
16 C Feb 9 4
17 D Feb 14 5
18 D Feb 14 6
19 DM Feb 0 13
20 DM Feb 0 10
And the result I want is like this:
Employee Jan No# Feb No#
A 20 2 30 2
B 30 2 40 2
C 20 2 18 2
D 26 2 28 2
DM 44 10 59 10
For every sales,Employee A,B,C,D only have commission1 as payment,the commission2 is for DM. So , in Jan , DM's commission is SUM(E2:E9)
I can do it easy in excel , but how can I do this in sql server?
I make my try code like this:
select [Month],Employee,SUM(Commission1) Commission,count(distinct([No])) No#
from table1
WHERE Employee IN ('A','B','C','D')
group by [Month],Employee
union
select 'DM' as Employee,[Month],SUM(Commission2) Commission,count(distinct([No])) No#
from table1
WHERE Employee IN ('A','B','C','D','DM')
group by [Month],Employee
And I get the result
Employee Month Commission No#
A Jan 20 2
B Jan 30 2
C Jan 20 2
D Jan 26 2
DM Jan 44 10
A Feb 30 2
B Feb 40 2
C Feb 18 2
D Feb 28 2
DM Feb 59 10
The result format is not what I want.I tried pivot after this query,but failed,it seems I only can pivot one state?
Another question: If I want the month growth automatic (In actual data , there's not only Jan and Feb) in the result ,not write [Jan],[Feb],[Mar]... in pivot code, how to do it?
Who can help me?
Thanks!
Here is a PIVOT solution:
Test data:
DECLARE #t table(Employee varchar(2), Month char(3), Commission1 int, Commission2 int)
INSERT #t values
('A','Jan',10,5 ),('A','Jan',10,4),('B','Jan',15,3),
('B','Jan',15,4 ),('C','Jan',10,3),('C','Jan',10,4),
('D','Jan',13,3 ),('D','Jan',13,4),('DM','Jan',0,6),
('DM','Jan',0,8 ),('A','Feb',15,4),('A','Feb',15,5),
('B','Feb',20,5 ),('B','Feb',20,4),('C','Feb',9,3),
('C','Feb',9,4 ),('D','Feb',14,5),('D','Feb',14,6),
('DM','Feb',0,13),('DM','Feb',0,10)
Query:
;WITH CTE as
(
SELECT
Employee, Month,
CASE WHEN Employee = 'DM' THEN
SUM(Commission2) over (partition by [Month])
ELSE Commission1 END com,
CASE WHEN Employee = 'DM'
THEN row_number() over
(PARTITION BY Employee, [Month] ORDER BY (SELECT 1)) ELSE 1 END rn
FROM #t
)
SELECT Employee, [Jan], [Feb], [Mar] -- add more months
FROM
CTE
PIVOT
(SUM(com)
FOR [Month] IN ([Jan], [Feb], [Mar])) AS pvt -- add more months
WHERE rn = 1
Result:
Employee Jan Feb Mar
A 20 30 NULL
B 30 40 NULL
C 20 18 NULL
D 26 28 NULL
DM 44 59 NULL
In SqlServer you can do so using PIVOT operator as like below:
Please refer PIVOT syntax
select tmp.employee,pv.[jan] as Jan_Commission, pv.[feb] as Feb_Commission from
(
select employee,month,commission1 from table_name
)tmp
pivot (
sum(commission1)
for [month] in ([jan],[feb])
)pv;