Trying to understand Race Conditions/Threads in C - c

For staters, I am a student who wasn't a CS undergrad, but am moving into a CS masters. So I welcome any and all help anyone is willing to give.
The purpose of this was to create N threads between 2-4, then using a randomly generated array of lower case characters, make them uppercase.
This needed to be done using the N threads (defined by the command line when executed), dividing the work up as evenly as possible, using pthread.
My main question I'm trying to ask, is if I avoided race conditions between my threads?
I am also struggling to understand dividing the work among the threads. As I understand (correct me if I'm wrong), in general the threads functioning will be chosen at random during execution. So, I'm assuming I need to do something along the lines of dynamically dividing the array among the N number of threads and setting it so that each thread will perform the uppercasing of a same sized subsection of the array?
I know there are likely a number of other discrepancies I need to get better at within my code, but I haven't coded long and just started using C/C++ about a month ago.
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <pthread.h>
#include <ctype.h>
//Global variable for threads
char randChars[60];
int j=0;
//Used to avoid race conditions
pthread_mutex_t mutex1 = PTHREAD_MUTEX_INITIALIZER;
//Establish the threads
void* upperThread(void* argp)
{
while(randChars[j])
{
pthread_mutex_lock( &mutex1 );
putchar (toupper(randChars[j]));
j++;
pthread_mutex_unlock( &mutex1 );
}
return NULL;
}
int main(int argc, char **argv)
{
//Initializae variables and thread
int N,randNum,t;
long i;
pthread_t pth[N];
pthread_mutex_init(&mutex1, NULL);
char randChar = ' ';
//Check number of command inputs given
if(argc!=2)
{
fprintf(stderr,"usage: %s <enter a value for N>\n", argv[0]);
exit(0);
}
N = atoi(argv[1]);
//Checks command inputs for correct values
if(N<2||N>4){
printf("Please input a value between 2 and 4 for the number of threads.\n");
exit(0);
}
//Seed random to create a randomized value
srand(time(NULL));
printf("original lower case version:\n");
for (i=0; i<61; i++)
{
//Generate a random integer in lower alphabetical range
randNum = rand()%26;
randNum = randNum+97;
//Convert int to char and add to array
randChar = (char) randNum;
randChars[i] = randChar;
printf("%c", randChar);
}
//Create N threads
for (i=0; i<N; i++)
{
pthread_create(pth + i, NULL, upperThread, (void *)i);
}
printf("\n\nupper case version:\n");
//Join the threads
for(t=0; t < N; t++)
{
pthread_join(pth[t], NULL);
}
printf("\n");
pthread_exit(NULL);
return 0;
}

The example you provided is not a good multithreaded program. The reason is that your threads will constantly wait for the one which holds the lock. Which basically makes your program sequential. I would change your upperThread to
void* upperThread(void* argp){
int temp;
while(randChars[j]){
pthread_mutex_lock( &mutex1 );
temp = j;
j++;
pthread_mutex_unlock( &mutex1 );
putchar (toupper(randChars[temp]));
}
return NULL;
}
This way your threads will wait for one that holds the lock until it extracts the value of j , increment it and release the lock and then do the rest of its operations.
The general rule is that you have to acquire the lock only when you deal with critical section or critical data in this case it is an index of your string. Read about critical sections and racing conditions here

Related

Why does my simple counting program take longer to run with multiple threads? (in C)

Here's my code:
#define COUNT_TO 100000000
#define MAX_CORES 4
static pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER;
long long i = 0;
void* start_counting(void *arg){
for(;;){
pthread_mutex_lock(&mutex);
if(i >= COUNT_TO){
pthread_mutex_unlock(&mutex);
return NULL;
}
i++;
pthread_mutex_unlock(&mutex);
//printf("i = %lld\n", i);
}
}
int main(int argc, char* argv[]){
int i = 0;
pthread_t * thread_group = malloc(sizeof(pthread_t) * MAX_CORES);
for(i = 0; i < MAX_CORES; i++){
pthread_create(&thread_group[i], NULL, start_counting, NULL);
}
for(i = 0; i < MAX_CORES; i++){
pthread_join(thread_group[i], NULL);
}
return 0;
}
This is what your threads do:
Read the value of i.
Increment the value we read.
Write back the incremented value of i.
Go to step 1.
Cleary, another thread cannot read the value of i after a different thread has accomplished step 1 but before it has completed step 3. So there can be no overlap between two threads doing steps 1, 2, or 3.
So all your threads are fighting over access to the same resource -- i (or the mutex that protects it). No thread can make useful forward progress without exclusive access to one or both of those. Given that, there is no benefit to using multiple threads since only one of them can accomplish useful work at a time.

Out of memory in a thread pool in C, Linux

I need to create infinite loop and with a thread pool create for example 200 threads to do the job from infinite loop.
I'm using this thread pool - https://github.com/Pithikos/C-Thread-Pool
In the same time I'm monitoring the server resources (with htop) and see that memory is increasing on 3 megabytes every second until the kernel kills the application.
The code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include <pthread.h>
#include "thpool.h"
#define MAX_IPv4 256
/* Args for thread start function */
typedef struct {
int octet1;
int octet2;
int octet3;
int octet4;
} args_struct;
/* Thread task */
void task1(void *args) {
args_struct *actual_args = args;
printf("%d.%d.%d.%d\n", actual_args->octet1, actual_args->octet2, actual_args->octet3, actual_args->octet4);
/* Do some job */
sleep(1);
/* Free the args */
free(args);
}
/* Main function */
int main( void ) {
int i=0, j=0, n=0, m=0;
/* Making threadpool n threads */
threadpool thpool = thpool_init(200);
/* Infinite loop start from the certain ip*/
while (1) {
for (i=0; i < MAX_IPv4; ++i) {
for (j=0; j < MAX_IPv4; ++j) {
for (n=0; n < MAX_IPv4; ++n) {
for (m=0; m < MAX_IPv4; ++m) {
/* Heap memory for the args different for the every thread */
args_struct *args = malloc(sizeof *args);
args->octet1 = i;
args->octet2 = j;
args->octet3 = n;
args->octet4 = m;
/* Create thread */
thpool_add_work(thpool, (void*)task1, (void*)args);
}
}
}
}
/* Start from 0.0.0.0 */
i=0;
j=0;
n=0;
m=0;
}
/* Wait until the all threads are done */
thpool_wait(thpool);
/* Destroy the threadpool */
thpool_destroy(thpool);
return 0;
}
How to solve this issue?
Looking at issues for your library ( especially this one about memory consumption ).
There is a recommendation to check the job queue length threadpool.jobqueue.len;
Maybe your code could check after adding your job to the queue
Unfortunately the threadpool is an opaque pointer and you could not access the value directly.
I would recommend adding a function for the threadpool in thpool.c :
int thpool_jobqueue_length(thpool_* thpool_p) {
return thpool->jobqueue->len;
}
And don't forget the declaration in thpool.h
int thpool_jobqueue_length(threadpool);
Then modify your code
const int SOME_ARBITRARY_VALUE = 400
...
thpool_add_work(thpool, (void*)task1, (void*)args);
while( ( thpool_jobqueue_length(thpool) > SOME_ARBITRARY_VALUE ) ) {
sleep(1);
}
...
Looking at the code for thpool_add_work there is some memory use per call (allocating a job record to add to a queue), so as your loop runs forever, it is not surprising that it will run out of memory at some point. You are also allocating memory inside your innermost loop, so that too will help use up all your memory.
Essentially inside your inner loop you are allocating 16 bytes (assuming int is 4) for the args_struct, and thpool_add_work is also allocating 12 bytes (possibly rounded to 16 for alignment purposes).
As you can imagine, that adds up to a lot for your 4 nested loops (which are also run infinitely).

Changing parts of arrays/structs/.. in threads without blocking the whole thing, in pure c

I want to modify some (not all) fields of an array (or structs) in multiple threads, with out blocking the rest of the array as the rest of it is being modified in other threads. How is this achieved? I found some answers, but they are for C++ and I want to do it in C.
Here is the code I got so far:
#define _GNU_SOURCE
#include <pthread.h>
#include <stdio.h>
#include <semaphore.h>
#include <stdlib.h>
#include <time.h>
#include <unistd.h>
#define ARRAYLENGTH 5
#define TARGET 10000
int target;
typedef struct zstr{
int* array;
int place;
int run;
pthread_mutex_t* locks;
}zstr;
void *countup(void *);
int main(int argc, char** args){
int al;
if(argc>2){
al=atoi(args[1]);
target=atoi(args[2]);
}else{
al=ARRAYLENGTH;
target=TARGET;
}
printf("%d %d\n", al, target);
zstr* t=malloc(sizeof(zstr));
t->array=calloc(al, sizeof(int));
t->locks=calloc(al, sizeof(pthread_mutex_t));
int* rua=calloc(al, sizeof(int));
pthread_t id[4*al];
for(int i=0; i<al; i++)
pthread_mutex_init(&(t->locks[i]), NULL);
for(int j=0; j<4*al; j++){
int st=j%al;
t->run=rua[st]++;
t->place=st;
pthread_create(&id[j], NULL, &countup, t);
}
for(int k=0; k<4*al; k++){
pthread_join(id[k], NULL);
}
for(int u=0; u<al; u++)
printf("%d\n", t->array[u]);
free(rua);
free(t->locks);
free(t->array);
return 0;
}
void *countup(void* table){
zstr* nu=table;
if(!nu->run){
pthread_mutex_lock(nu->locks + nu->place);
}else{
pthread_mutex_trylock(nu->locks + nu->place);
}
while(nu->array[nu->place]<target)
nu->array[nu->place]++;
pthread_mutex_unlock(nu->locks + nu->place);
return NULL;
}
Sometimes this works just fine, but then calculates wrong values and for quiet sort problems (like the default values), it takes super long (strangely it worked once when I handed them in as parameters).
There isn't anything special about part of an array or structure. What matters is that the mutex or other synchronization you apply to a given value is used correctly.
In this case, it seems like you're not checking your locking function results.
The design of the countup function only allows a single thread to ever access the object, running the value all the way up to target before releasing the lock, but you don't check the trylock result.
So what's probably happening is the first thread gets the lock, and subsequent threads on the same mutex call trylock and fail to get the lock, but the code doesn't check the result. Then you get multiple threads incrementing the same value without synchronization. Given all the pointer dereferences the index and increment operations are not guaranteed to be atomic, leading to problems where the values grow well beyond target.
The moral of the story is to check function results and handle errors.
Sorry, don't have enough reputation to comment, yet.
Adding to Brad's comment of not checking the result of pthread_mutex_trylock, there's a misconception that shows many times with Pthreads:
You assume, that pthread_create will start immediately, and receive the values passed (here pointer t to your struct) and it's content read atomically. That is not true. The thread might start any time later and will find the contents, like t->run and t->place already changed by the next iteration of the j-loop in main.
Moreover, you might want to read David Butenhof's book "Programming with Posix Threads" (old, but still a good reference) and check on synchronization and condition variables.
It's not that good style to start that many threads in the first place ;)
As this has come up a few times and might come up again, I have restructured that a bit to issue work_items to the started threads. The code below might be amended by a function, that maps the index into array to always the same area_lock, or by adding a queue to feed the running threads with further work-item...
#include <assert.h>
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <unistd.h>
#include <pthread.h>
/*
* Macros for default values. To make it more interesting, set:
* ARRAYLENGTH != THREADS
* INCREMENTS != TARGET
* NUM_AREAS != THREADS
* Please note, that NUM_AREAS must be <= ARRAY_LENGTH.
*/
#define ARRAYLENGTH 10
#define TARGET 100
#define INCREMENTS 10
#define NUM_AREAS 2
#define THREADS 5
/* These variables are initialized once in main, then only read... */
int array_len;
int target;
int num_areas;
int threads;
int increments;
/**
* A long array that is going to be equally split into number of areas.
* Each area is covered by a lock. The number of areas do not have to
* equal the length of the array, but must be smaller...
*/
typedef struct shared_array {
int * array;
int num_areas;
pthread_mutex_t * area_locks;
} shared_array;
/**
* A work-item a thread is assigned to upon startup (or later on).
* Then a value of { 0, any } might signal the ending of this thread.
* The thread is working on index within zstr->array, counting up increments
* (or up until the target is reached).
*/
typedef struct work_item {
shared_array * zstr;
int work_on_index;
int increments;
} work_item;
/* Local function declarations */
void * countup(void *);
int main(int argc, char * argv[]) {
int i;
shared_array * zstr;
if (argc == 1) {
array_len = ARRAYLENGTH;
target = TARGET;
num_areas = NUM_AREAS;
threads = THREADS;
increments = INCREMENTS;
} else if (argc == 6) {
array_len = atoi(argv[1]);
target = atoi(argv[2]);
num_areas = atoi(argv[3]);
threads = atoi(argv[4]);
increments = atoi(argv[5]);
} else {
fprintf(stderr, "USAGE: %s len target areas threads increments", argv[0]);
exit(-1);
}
assert(array_len >= num_areas);
zstr = malloc(sizeof (shared_array));
zstr->array = calloc(array_len, sizeof (int));
zstr->num_areas = num_areas;
zstr->area_locks = calloc(num_areas, sizeof (pthread_mutex_t));
for (i = 0; i < num_areas; i++)
pthread_mutex_init(&(zstr->area_locks[i]), NULL);
pthread_t * id = calloc(threads, sizeof (pthread_t));
work_item * work_items = calloc(threads, sizeof (work_item));
for (i = 0; i < threads; i++) {
work_items[i].zstr = zstr;
work_items[i].work_on_index = i % array_len;
work_items[i].increments = increments;
pthread_create(&(id[i]), NULL, &countup, &(work_items[i]));
}
// Let's just do this one work-item.
for (i = 0; i < threads; i++) {
pthread_join(id[i], NULL);
}
printf("Array: ");
for (i = 0; i < array_len; i++)
printf("%d ", zstr->array[i]);
printf("\n");
free(id);
free(work_items);
free(zstr->area_locks);
free(zstr->array);
return 0;
}
void *countup(void* first_work_item) {
work_item * wi = first_work_item;
int inc;
// Extract the information from this work-item.
int idx = wi->work_on_index;
int area = idx % wi->zstr->num_areas;
pthread_mutex_t * lock = &(wi->zstr->area_locks[area]);
pthread_mutex_lock(lock);
for (inc = wi->increments; inc > 0 && wi->zstr->array[idx] < target; inc--)
wi->zstr->array[idx]++;
pthread_mutex_unlock(lock);
return NULL;
}

Multithreaded search in c

I'm supposed to have two threads that search for the minimum element in an array: the first one searches the first half, and the second thread searches the other half. However, when I run my code, it seems that it chooses a thread randomly. I'm not sure what I'm doing wrong, but it probably has to do with the "mid" part. I tried dividing an array into two, finding the midpoint and then writing the conditions from there, but I probably went wrong somewhere. I also tried putting array[i] in the conditions, but in that case only thread2 executes.
EDIT: I'm really trying my best here, but I'm not getting anywhere. I edited the code in a way that made sense to me, and I probably typecasted "min" wrong but now it doesn't even execute it just gives me an error, even though it compiles just fine. I'm just a beginner, and while I do understand everything you guys are talking about, I have a hard time implementing the ideas, so really, any help with fixing this is appreciated!
EDIT2: Okay so the previous code made no sense at all, I do apologize but I was exhausted while writing it. Anyway, I came up with something else that works partially! I split the array into two halves, however only the first element is accessible when using the pointer. But would it work if the whole array was being accessed and if so how can I fix that then?
#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
#include <string.h>
#define size 20
void *smallest(void *arg);
pthread_t th, th2;
int array[size], i, min;
int main(int argc, char *argv[]) {
srand ( time(NULL) );
for(i = 0; i < size; i++)
{
array[i] = (rand() % 100)+1;
printf("%d ", array[i]);
}
int *array1 = malloc(10 * sizeof(int));
int *array2 = malloc(10 * sizeof(int));
memcpy(array1, array, 10 * sizeof(int));
memcpy(array2, array + 10, 10 * sizeof(int));
printf("\nFirst half gives %d \n", *array1);
printf("Second half gives %d \n", *array2);
pthread_create(&th, NULL, smallest, (void*) array1);
pthread_create(&th2, NULL, smallest, (void*) array2);
pthread_join(th, NULL);
pthread_join(th2, NULL);
//printf("\nFirst half gives %d\n", array1);
//printf("Second half gives %d\n", array2);
if (*array1 < *array2) {
printf("\nThread1 finds the number\n");
printf("The smallest element is %i\n", *array1);
}
else {
printf("\nThread2 finds the number\n");
printf("The smallest element is %i\n", *array2);
}
return 0;
}
void *smallest(void* arg){
int *array = (int*)arg;
min = array[0];
for (i = 0; i < size; i++) {
if (array[i] < min) {
min = array[i];
}
}
pthread_exit(NULL);
}
The code you've set up never runs more than one thread. Notice that if you run the first branch of the if statement, you fire off one thread to search half the array, wait for it to finish, then continue onward, and if the else branch executes, the same thing happens in the second half of the array. Fundamentally, you probably want to rethink your strategy here by having the code always launch two threads and join each of them only after both threads have started running.
The condition within your if statement also seems like it's mistaken. You're asking whether the middle element of the array is greater than its index. I assume this isn't what you're trying to do.
Finally, the code you have in each thread always looks at the entire array, not just a half of it. I would recommend rewriting the thread routine so that its argument represents the start and end indices of the range to take the minimum of. You would then update the code in main so that when you fire off the thread, you specify which range to search.
I would structure things like this:
Fire off a thread to find the minimum of the first half of the array.
Fire off a thread to find the minimum of the second half of the array.
Join both threads.
Use the results from each thread to find the minimum.
As one final note, since you'll have two different threads each running at the same time, you'll need to watch for data races as both threads try to read or write the minimum value. Consider having each thread use its exit code to signal where the minimum is and then resolving the true minimum back in main. This eliminates the race condition. Alternatively, have one global minimum value, but guard it with a mutex.
1) You´re redeclaring the global variables in the main function, so there´s actually no point in declaring i, low, high, min:
int array[size], i, low, high, min;
The problem you´re having is with the scope of the variables when you redeclare the variables in the main function, the global ones with the same name become "invisible"
int *low = array;
int *high = array + (size/2);
int mid = (*low + *high) / 2;
So when you run the threads all the values of your variables(low, high, min;
) are 0, this is because they are never actually modified by the main and because they start in 0 default(startup code,etc).
Anyways I wouldn´t really recommend(it´s really frowned upon) using global variables unless it´s a really small proyect for personal use.
2) Another crucial problem is that you´re ignorning the main idea behind threads which is running both simultaneously
if (array[mid] > mid) {
pthread_create(&th, NULL, &smallest, NULL);
pthread_join(th, NULL);
printf("\nThread1 finds the number\n");
}
else if (array[mid] < mid) {
pthread_create(&th2, NULL, &smallest, NULL);
pthread_join(th2, NULL);
printf("\nThread2 finds the number\n");
}
You´re actually only running one thread when executing.
Try something like this:
pthread_create(&th, NULL, &smallest, NULL);
pthread_create(&th2, NULL, &smallest, NULL);
pthread_join(th2, NULL);
pthread_join(th, NULL);
3) You are trying to have two threads access the same variable this can result in undefined behaviour, you MUST use a muthex to avoid a number from not actually being stored.
This guide is pretty complete regarding mutexes but if you need anyhelp please let me know.
This is a single threaded version of what you are asking.
#include <stdio.h>
#include <stdlib.h>
/*
I can not run pthread on my system.
So this is some code that should kind of work the same way
*/
typedef int pthread_t;
typedef int pthread_attr_t;
typedef void*(*threadfunc)(void*);
int pthread_create(pthread_t *thread, const pthread_attr_t *attr, void *(*start_routine)(void*), void *arg)
{
start_routine(arg);
return 0;
}
int pthread_join(pthread_t thread, void **value_ptr)
{
return 0;
}
struct context
{
int* begin;
int* end;
int* result;
};
//the function has to be castable to the threadfunction type
//that way you do not have to worry about casting the argument.
//be careful though - if something does not match these errors may be hard to track
void * smallest(context * c) //signature needet for start routine
{
c->result = c->begin;
for (int* current = c->begin; current < c->end; ++current)
{
if (*current < *c->result)
{
c->result = current;
}
}
return 0; // not needet with the way the argument is set up.
}
int main(int argc, char *argv[])
{
pthread_t t1, t2;
#define size 20
int array[size];
srand(0);
for (int i = 0; i < size; ++i)
{
array[i] = (rand() % 100) + 1;
printf("%d ", array[i]);
}
//prepare data
//one surefire way of messing up in multithreading is sharing data between threads.
//even a simple approach like storing in a variable who is accessing will not solve the issues
//to properly lock data you would have to dive into the memory model.
//either lock with mutexes or memory barriers or just don' t share data between threads.
context c1;
context c2;
c1.begin = array;
c1.end = array + (size / 2);
c2.begin = c1.end + 1;
c2.end = array + size;
//start threads - here your threads would go
//note the casting - you may wnt to wrap this in its own function
//there is error potential here, especially due to maintainance etc...
pthread_create(&t1, 0, (void*(*)(void*))smallest, &c1); //without typedef
pthread_create(&t2, 0, (threadfunc)smallest, &c2); //without typedef
pthread_join(t1, 0);//instead of zero you could have a return value here
pthread_join(t1, 0);//as far as i read 0 throws the return value away
//return value could be useful for error handling
//evaluate
if (*c1.result < *c2.result)
{
printf("\nThread1 finds the number\n");
printf("The smallest element is %i\n", *c1.result);
}
else
{
printf("\nThread2 finds the number\n");
printf("The smallest element is %i\n", *c2.result);
}
return 0;
}
Edit:
I edited some stubs in to give you an idea of how to use multithreading.
I never used pthread but this should likely work.
I used this source for prototype information.

Compute the summation of a given interval using multiple threads

For my homework, I need to compute the squares of integers in the interval (0,N) (e.g. (0,50) in a way that the load is distributed equally among threads (e.g. 5 threads). I have been advised to use small chunks from the interval and assign it to the thread. For that, I am using a queue. Here's my code:
#include <stdio.h>
#include <pthread.h>
#define QUEUE_SIZE 50
typedef struct {
int q[QUEUE_SIZE];
int first,last;
int count;
} queue;
void init_queue(queue *q)
{
q->first = 0;
q->last = QUEUE_SIZE - 1;
q->count = 0;
}
void enqueue(queue *q,int x)
{
q->last = (q->last + 1) % QUEUE_SIZE;
q->q[ q->last ] = x;
q->count = q->count + 1;
}
int dequeue(queue *q)
{
int x = q->q[ q->first ];
q->first = (q->first + 1) % QUEUE_SIZE;
q->count = q->count - 1;
return x;
}
queue q; //declare the queue data structure
void* threadFunc(void* data)
{
int my_data = (int)data; /* data received by thread */
int sum=0, tmp;
while (q.count)
{
tmp = dequeue(&q);
sum = sum + tmp*tmp;
usleep(1);
}
printf("SUM = %d\n", sum);
printf("Hello from new thread %u - I was created in iteration %d\n",pthread_self(), my_data);
pthread_exit(NULL); /* terminate the thread */
}
int main(int argc, char* argv[])
{
init_queue(&q);
int i;
for (i=0; i<50; i++)
{
enqueue(&q, i);
}
pthread_t *tid = malloc(5 * sizeof(pthread_t) );
int rc; //return value
for(i=0; i<5; i++)
{
rc = pthread_create(&tid[i], NULL, threadFunc, (void*)i);
if(rc) /* could not create thread */
{
printf("\n ERROR: return code from pthread_create is %u \n", rc);
return(-1);
}
}
for(i=0; i<5; i++)
{
pthread_join(tid[i], NULL);
}
}
The output is not always correct. Most of the time it is correct, 40425, but sometimes, the value is bigger. Is it because of the threads are running in parallel and accessing the queue at the same time (the processor on my laptop is is intel i7)? I would appreciate the feedback on my concerns.
I think contrary to what some of the other people here suggested, you don't need any synchronization primitives like semaphores or mutexes at all. Something like this:
Given some array like
int values[50];
I'd create a couple of threads (say: 5), each of which getting a pointer to a struct with the offset into the values array and a number of squares to compute, like
typedef struct ThreadArgs {
int *values;
size_t numSquares;
} ThreadArgs;
You can then start your threads, each of which being told to process 10 numbers:
for ( i = 0; i < 5; ++i ) {
ThreadArgs *args = malloc( sizeof( ThreadArgs ) );
args->values = values + 10 * i;
args->numSquares = 10;
pthread_create( ...., threadFunc, args );
}
Each thread then simply computes the squares it was assigned, like:
void *threadFunc( void *data )
{
ThreadArgs *args = data;
int i;
for ( i = 0; i < args->numSquares; ++i ) {
args->values[i] = args->values[i] * args->values[i];
}
free( args );
}
At the end, you'd just use a pthread_join to wait for all threads to finish, after which you have your squares in the values array.
All your threads read from the same queue. This leads to a race condition. For instance, if the number 10 was read simultaneously by two threads, your result will be offset by 100. You should protect your queue with a mutex. Put the following print in deque function to know which numbers are repeated:
printf("Dequeing %d in thread %d\n", x, pthread_self());
Your code doesn't show where the results are accumulated to a single variable. You should protect that variable with a mutex as well.
Alternatively, you can pass the start number as the input parameter to each thread from the loop so that each thread can work on its set of numbers. First thread will work on 1-10, the second one on 11-20 and so on. In this approach, you have to use mutex only the part where the threads update the global sum variable at the end of their execution.
First you need to define what it means to be "distributed equally among threads." If you mean that each thread does the same amount of work as the other threads, then I would create a single queue, put all the numbers in the queue, and start all threads (which are the same code.) Each thread tries to get a value from the queue which must be protected by a mutex unless it is thread safe, calculates the partial answer from the value taken from the thread, and adds the result to the total which must also be protected by a mutex. If you mean that each thread will execute an equal amount of times as each of the other threads, then you need to make a priority queue and put all the numbers in the queue along with the thread number that should compute on it. Each thread then tries to get a value from the queue that matches its thread number. From the thread point of view, it should try to get a value from the queue, do the work, then try to get another value. If there are no more values to get, then the thread should exit. The main program does a join on all threads and the program exits when all threads have exited.

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