I'm quite new to CakePHP and have an issue. I'm trying to update one field in a row with this:
$options = array('conditions' => array('User.id' => $_POST['userid']));
$user = $this->User->find('first', $options);
$currentpoint = $user['User']['point'];
$correctanswerpoint = Configure::read('CORRECT_SYSTEMANSWER_POINT');
$newpoint = $currentpoint + $correctanswerpoint;
$this->User->updateAll(array('User.point'=>$newpoint), array('User.id'=>$_POST['userid']));
There are no errors, but the field point (bigint(20)) is not being updated. I've changed the field to update to another one in the same row which is of smallint type and the update goes through fine.
My debugging log seems to show that the SQL query is ok too:
[query] => UPDATE `askyoode_askyoo`.`users` AS `User` LEFT JOIN `askyoode_askyoo`.`countries` AS `Country` ON (`User`.`country_id` = `Country`.`id`) LEFT JOIN `askyoode_askyoo`.`accesstypes` AS `Accesstype` ON (`User`.`accesstype_id` = `Accesstype`.`id`) SET `User`.`point` = 57 WHERE `User`.`id` = 124
[params] => Array
(
)
[affected] => 1
[numRows] => 1
[took] => 12
)
And manually running the same SQL statement in MySQL works. Been tearing out my hair for the whole day trying to resolve this. Any help is greatly appreciated. Thanks!!
Related
I am running the following query on my database:-
SELECT COUNT(*) AS COUNT, `Doctor`.`device_type` FROM `doctors` AS `Doctor` WHERE 1 = 1 GROUP BY `Doctor`.`device_type`
and it gives the result:-
count device_type
47 Android
23 iPhone
Whereas when running this query as a CakePHP query it gives the result as '2':-
$this->Doctor->find('count',array('group'=>'Doctor.device_type'));
Can anyone please suggest why this is happening?
The CakePHP result is correct as it is returning a count of the number of results returned by your query. In your case you have 2 rows: 'Android' and 'iPhone'.
find('count') always returns an integer, not an array. What Cake is doing is basically this:-
$data = $this->Doctor->find('all', array('group' => 'Doctor.device_type'));
$count = count($data); // This is what find('count') will return.
You need to do something like the following instead:-
$data = $this->Doctor->find('all', array(
'fields' => array(
'Doctor.device_type',
'COUNT(Doctor.*) AS count'
)
'group' => 'Doctor.device_type'
));
I use form helpers to show drop down select date. My problem is, i can't compare date from ms sql with form data.
My View :
<?php echo $this->Form->input('collect_date', array('label' => 'Collect Date','type'=>'date','dateFormat'=> 'DMY','minYear' => date('Y'),'maxYear' => date('Y')+1));?>
My Controller
$status =array(0,2,4);
$find_date = $this->data['Transaction']['collect_date'];
$field = array('Transaction.status','Catalogue.title', 'Catalogue.author', 'Catalogue.isbn', 'Location.rack');
$condition = array('OR' => array('AND' =>array('Transaction.return_date <'=> $find_date,'Transaction.status '=> '3'),array('Transaction.status'=> $status)));
$data = $this->Catalogue->Transaction->find('count',array('fields' => $field,'conditions'=>$condition,'order'=>array('Transaction.id desc') ));
$this->set('Found', $data);
And the sql dump
SELECT COUNT(*) AS [count] FROM [transactions] AS [Transaction]
LEFT JOIN [catalogues] AS [Catalogue] ON ([Transaction].[catalogue_id] = [Catalogue].[id])
LEFT JOIN [users] AS [User] ON ([Transaction].[user_id] = [User].[id])
WHERE (((([Transaction].[return_date] < ('01', '09', 2013))
AND ([Transaction].[status] = 3))) OR ([Transaction].[status] IN (0, 2, 4)))
As you can see the date format ('01', '09', 2013). But when try to convert use this
'Transaction.return_date <'=> date('Y-m-d', strtotime($find_date))
it show error:
Warning (2): strtotime() expects parameter 1 to be string, array given [APP\Controller\CataloguesController.php, line 66]
and the sql show:
[Transaction].[return_date] < '1970-01-01'
You could use:
$date = DateTime::createFromFormat('d/m/y', implode('/', $find_date));
'Transaction.return_date <'=> $date->format('Y-m-d');
Edit:
I think the way its meant to be 'flattened' is with
$this->Model->deconstruct('find_date', $find_date);
However, last time i tried to use this, i couldn't get it to work properly, so i went with the above.
http://api21.cakephp.org/class/model#method-Modeldeconstruct
Try converting return date using UNIX_TIMESTAMP in sql query and then comparing it with
strtotime($find_date).
CAKEPHP Group by problem in paginate..
This is my table structure
Friends Table
`id` int(11) NOT NULL AUTO_INCREMENT,
`user1_id` int(11) NOT NULL DEFAULT '0',--> UserFrom
`user2_id` int(11) NOT NULL DEFAULT '0',---> UserTo
I need to get all the unique records of one user and his user1_id = 100
There are lot of duplicate values in user2_id. I need to get the unique values
While i trying this code it returns only first 12 values(according to limit).
If i commented the group by line then all records are displaying (including duplicate values)
$this->paginate = array(
'conditions' => $conditions,
'contain'=>array(
'UserFrom'=>array(
'fields'=>array(
'UserFrom.id',
'UserFrom.first_name',
'UserFrom.last_name',
),
),
'UserTo'=>array(
'fields'=>array(
'UserTo.id',
'UserTo.first_name',
'UserTo.last_name',
)
)
),'limit' => 12,
'order' => array('Friend.id' => 'desc'),
'recursive'=>0,
'fields'=>array('DISTINCT Friend.user2_id','Friend.*'),
'group'=>array('UserTo.id'),
);
This is my sql query on that page
SELECT COUNT(*) AS count FROM friends AS Friend LEFT JOIN users AS UserTo ON (Friend.user2_id = UserTo.id) LEFT JOIN users AS UserFrom ON (Friend.user1_id = UserFrom.id) WHERE UserFrom.nick_name = 'shyam' AND Friend.status = 'friend' GROUP BY UserTo.id
SELECT DISTINCT Friend.user2_id, Friend.*, UserTo.id, UserTo.first_name, UserTo.last_name, UserTo.nick_name, UserTo.name, UserTo.icon_medium, UserTo.icon_big, UserFrom.id, UserFrom.first_name, UserFrom.last_name, UserFrom.nick_name, UserFrom.name FROM friends AS Friend LEFT JOIN users AS UserTo ON (Friend.user2_id = UserTo.id) LEFT JOIN users AS UserFrom ON (Friend.user1_id = UserFrom.id) WHERE UserFrom.nick_name = 'shyam' AND Friend.status = 'friend' GROUP BY UserTo.id ORDER BY Friend.id desc LIMIT 12
1.First count query returning count properly
2.Second query if i put limit it not working properly. i.e there are 144 records in my table i need to display 12 per page.. only first page coming if i use group by and limit
You should have either DISTINCT or GROUP BY, not both - they're duplicating each other and probably causing problems with your query. Remove one of them and retry.
Note: If you want to manually request pages other than 1st with $this->paginate(), add 'page' parameter with page number to your $this->paginate array, like this:
$this->paginate = array_merge($this->paginate, array('page' => $pageNumber);
However, normally you wouldn't want to do this, as paginator does this automatically (passing page variable via URL parameter to your action) as long as you use pagination controls in your view (see http://book.cakephp.org/view/1233/Pagination-in-Views).
Does anybody know how transform this query:
SELECT * from diminventory where partnumber='350964-B22' or partnumber in (SELECT partnumber from dimparts where parentpartnumber='350964-b22')
in a cakephp query
Thanks
I'm not 100% certain what you're asking for as yet, but here's a brief tutorial on cakephp querying.
$this->ModelName->query("SELECT * FROM tablename LIMIT 2;");
You query from the model, but you use the literal tablename. You use the SQL "AS" keyword to rename the keys of the resultant array.
Sample results:
Array
(
[0] => Array
(
[tablename] => Array
(
[id] => 1304
[user_id] => 759
)
)
[1] => Array
(
[tablename] => Array
(
[id] => 1305
[user_id] => 759
)
)
)
He is asking for Cakephp query not custom SQL query. In the controller:
$partnumber = $this->diminventory->find('all',array('conditions' => array('diminventory.partnumber' => '350964-B22')));
$this->set('partnumber',$partnumber);
set function passes a variable as $partnumber to the view. Then int view (which is .ctp file) you need to output the array.
foreach($partnumber as $partnumbers){
echo $partnumbers;
}
Make sure that diminventory table has 's' after the name otherwise it won't work as this is part of Cakephp's strict naming conventions.
Tutorial for find function:
http://book.cakephp.org/view/1018/find
To do it fully Cake'ish, you need to use CakePHP subquery:
$dbo = $this->User->getDataSource();
$subQuery = $dbo->buildStatement(
array(
'fields' => array('`Dimpart`.`partnumber`'),
'table' => $dbo->fullTableName($this->Dimpart),
'alias' => 'Dimpart',
'conditions' => array('`Dimpart`.`parentpartnumber`' => '350964-b22'),
),
$this->Dimpart
);
$subQuery = ' `DiminventoryEntry`.`partnumber` IN (' . $subQuery . ') ';
$subQueryExpression = $dbo->expression($subQuery);
$conditions[] = $subQueryExpression;
$conditions['DiminventoryEntry.partnumber'] = '350964-B22';
$result = $this->DiminventoryEntry->find('all', compact('conditions'));
Where Dimpart is your model for table dimparts, and DiminventoryEntry is your model for table diminventory (which is not actually Cake'ish, you should've renamed your table according to conventions).
I'm having a problem with data integrity when using find() in my controller in conjunction with beforeFind() in a behavior callback. The WHERE Submissions.site_id is not being added in the WHERE clause like it should be. I get different result sets depending on where the WHERE clause is set.
in my SubmissionsController:
public function index()
{
$query = $this->Submissions->find('all')
->where(['user_id' => $this->Auth->user('id')])
->contain(['Users', 'Categories']);
$this->set('submissions', $this->paginate($query));
}
In my beforeFind() Model callback (attached as a 'TenantBehavior' to
$query->where([$this->_table->alias().'.'.'site_id' => 3]);
The problem is that with the above, the SQL generated puts the "WHERE" clause as an AND on the JOIN condition like so, and NOT on the actual WHERE:
...
FROM
submissions Submissions
INNER JOIN users Users ON (
Users.id = (Submissions.user_id)
AND Users.site_id = 3
)
INNER JOIN categories Categories ON (
Categories.id = (Submissions.category_id)
AND Categories.site_id = 3
)
WHERE
user_id = 315
If I remove the beforeFind() ->where and instead place it on the controller ->where I get the expected SQL and result set like so:
...
FROM
submissions Submissions
INNER JOIN users Users ON (
Users.id = (Submissions.user_id)
AND Users.site_id = 3
)
INNER JOIN categories Categories ON (
Categories.id = (Submissions.category_id)
AND Categories.site_id = 3
)
WHERE
(
user_id = 315
AND Submissions.site_id = 3
)
Thoughts? Suggestions?
EDIT
As #ndm's suggestion, I began to update and provide much more context. In doing so I discovered (like an idiot) that I was missing the $this->addBehavior('Tenant'); on my 'SubmissionsTable' model. Adding this of course solved the issue.
$query = $this->Submissions->find('all', [
'conditions' => [
'user_id' => $this->Auth->user('id')
],
'contain' => [
'Users',
'Categories',
]
]);
Passing conditions as inline array will solve your issue and append beforeFind() where conditions properly.