I'm trying to find a file called mynet1, and I cant located it in my src folder and want to search all the possible files in my system for it. What is a Ubuntu command to find a file given its filename that could be anywhere in my /root and beyond?
To find a file by name, type:
find <path> -name "<query>"
You can learn a lot here: https://www.digitalocean.com/community/tutorials/how-to-use-find-and-locate-to-search-for-files-on-a-linux-vps#finding-by-name
Note that Midnight Commander (mc) can search for file names (and text), run it from the command prompt, navigate to the top directory of interest and press F9 C F.
To install:
sudo aptitude install mc
Related
In the clear case, I want versions of the file in the particular directory with complete file path. By right click on the file and after that going for properties in the file it is possible to take, but in case in the directory 100 files are there, so it will become very huge task. I want to know the clear tool command , which i can execute from the command prompt and after that I can redirect output to some text file
Example of path I am using:
M:\My_Project\Verif_Folder\TP\Functional_TP\ETP\ here
Check the command cleartool find, combined with a cleartool describe and fmt_ccase option:
cd M:\Myproject\...\here
cleartool find . -type f -exec "cleartool describe \"%CLEARCASE_XPN%\" -fmt \"%Xn\""
%Xn: Extended name: Same as default
%n output, but for checked-out versions, append the extension ##\branch-pathname\CHECKEDOUT
The result will be the path of the file, its name, and its extended path including its current selected version.
Say I made and compiled a small program in C to count the bytes of a file, called filebyte. To run it I would use ./filebyte
Now I want to make it universal on bash, like for example to run a php file, I would use bash command php file.php, same way I would like to run my program, filebyte filename.
How do I do this?
Thanks!
I often create a bin/ directory in my home directory, for small custom applications.
You then need to add that directory to your PATH, which is a list of colon-separated paths that your shell searches for executables when you type a name on thr command line.
This is usually accomplished by putting this in your ~/.bashrc file:
PATH="$PATH:~/bin"
Check the environment variable PATH and put the executable in one of the directories listed. You can also put it in a custom directory and then append it to PATH. You can check it by executing printenv PATH
If you want it for your current active shell alone, do
export PATH=$PATH:</path/to/file>
For permanently making the file available add the above line to ~/.bashrc
Why add it in PATH variable, man bash says why,
PATH The search path for commands. It is a colon-separated list of
directories in which the shell looks for commands (see COMMAND
EXECUTION below). A zero-length (null) directory name in the
value of PATH indicates the current directory. A null directory
name may appear as two adjacent colons, or as an initial or
trailing colon. The default path is system-dependent, and is set
by the administrator who installs bash. A common value is
''/usr/gnu/bin:/usr/local/bin:/usr/ucb:/bin:/usr/bin''.
Description:
I am searching a very large server for files that is on a different server. right now I open command prompt and type
DIR [FILE NAME] /S/4
This returns the server location of the file with some other stuff that is not really needed.
Question:
I have a lot of files to search and one by one input into the above command could take forever. Is there a way I could input all of the names of all the files and only search once and the search results would only need to show file name and location?
First, I hope you don't mean DOS, but rather Windows cmd or batch.
You can certainly write a script that will run your DIR command once per file being sought.
But what you most likely want instead is to search once and print the path of each file found. For this you can use PowerShell's FindChildItem or the improved one posted here: http://windows-powershell-scripts.blogspot.in/2009/08/unix-linux-find-equivalent-in.html
It will be something like:
Find-ChildItem -Name "firstfile.txt|secondfile.txt|..."
Another approach is to install msys or cygwin or another Linux tools environment for Windows and use the Linux find command.
I have a bunch of shell scripts that used to run on a Linux machine. Now, we've switched over to Windows, and I need to run these scripts there. I have Cygwin installed, but is there a way to make the script run using Cygwin, but the call is made from Windows batch?
Sure. On my (pretty vanilla) Cygwin setup, bash is in c:\cygwin\bin so I can run a bash script (say testit.sh) from a Windows batch file using a command like:
C:\cygwin\bin\bash testit.sh
... which can be included in a .bat file as easily as it can be typed at the command line, and with the same effect.
One more thing - if You edited the shell script in some Windows text editor, which produces the \r\n line-endings, cygwin's bash wouldn't accept those \r. Just run dos2unix testit.sh before executing the script:
C:\cygwin\bin\dos2unix testit.sh
C:\cygwin\bin\bash testit.sh
If you have access to the Notepad++ editor on Windows there is a feature that allows you to easily get around this problem:
Open the file that's giving the error in Notepad++.
Go under the "Edit" Menu and choose "EOL Conversion"
There is an option there for "UNIX/OSX Format." Choose that option.
Re-save the file.
I did this and it solved my problems.
Hope this helps!
Read more at http://danieladeniji.wordpress.com/2013/03/07/microsoft-windows-cygwin-error-r-command-not-found/
Just wanted to add that you can do this to apply dos2unix fix for all files under a directory, as it saved me heaps of time when we had to 'fix' a bunch of our scripts.
find . -type f -exec dos2unix.exe {} \;
I'd do it as a comment to Roman's answer, but I don't have access to commenting yet.
The existing answers all seem to run this script in a DOS console window.
This may be acceptable, but for example means that colour codes (changing text colour) don't work but instead get printed out as they are:
there is no item "[032mGroovy[0m"
I found this solution some time ago, so I'm not sure whether mintty.exe is a standard Cygwin utility or whether you have to run the setup program to get it, but I run like this:
D:\apps\cygwin64\bin\mintty.exe -i /Cygwin-Terminal.ico bash.exe .\myShellScript.sh
... this causes the script to run in a Cygwin BASH console instead of a Windows DOS console.
If you don't mind always including .sh on the script file name, then you can keep the same script for Cygwin and Unix (Macbook).
To illustrate:
1. Always include .sh to your script file name, e.g., test1.sh
2. test1.sh looks like the following as an example:
#!/bin/bash
echo '$0 = ' $0
echo '$1 = ' $1
filepath=$1
3. On Windows with Cygwin, you type "test1.sh" to run
4. On a Unix, you also type "test1.sh" to run
Note: On Windows, you need to use the file explorer to do following once:
1. Open the file explorer
2. Right-click on a file with .sh extension, like test1.sh
3. Open with... -> Select sh.exe
After this, your Windows 10 remembers to execute all .sh files with sh.exe.
Note: Using this method, you do not need to prepend your script file name with bash to run
So I'm writing a script at work where I have to go through all the projects in a ClearCase vob, look for a file and parse some info from said file.
Naturally, I wouldn't want to load every single project so I'm using cleartool to retrieve the unloaded files.
First, I'm using the find command to locate the files. This was my first attempt:
root>cleartool find C:/viewpath -name file.txt -version "lbtype(Version-label)" -print -nr
Viewpath is the path to the project where I'm currently looking for the file. The file I'm looking for is file.txt on the version specified by Version-label.
This gave me no result whatsoever, even though I knew file.txt existed on that version.
I figured out it was looking through an old version of the directory, the latest on the main-branch, which was before file.txt was added to the directory. I tried this instead:
root>cleartool find C:/viewpath##/Version-label -name file.txt -version "lbtype(Version-label)" -print -nr
And got this result, which was what I was looking for
C:/viewpath\file.txt##\main\branch\41
So now that I knew where I could find the file I tried to get it.
root>cleartool get -to savepath C:/viewpath\file.txt##\main\branch\41
Which gave me this result
cleartool: Error: "C:/viewpath\file.txt##\main\branch\41" does not exist, or is not a ClearCase version, or is a checked out version which was removed.
Also tried
root>cleartool get -to savepath C:/viewpath\file.txt##/Version-label
With the same result
I can get files added to the directory when it was still on the main-branch, so it is still searching through the directory on the main-branch, where file.txt is nowhere to be found.
How do I tell it to look through a version of the directory from after it was branched from main?
I would really recommend for you to try those same commands in a dynamic view.
As illustrated here, a dynamic view gives you access to extended path (the file##/branch/version syntax), which means command like get will work.
You have in this question an example of search (cleartool find) using extended paths.
As explained in "In ClearCase, how can I view old version of a file in a static view, from the command line?", you can browse (as in 'change directory to') the various extended paths of a file in a dynamic view.