Please help how to achieve data as per shown in attached image
Highlighted rows actually group on Item Number field
Thanks in advance
Following should work:
SELECT distinct ItemNumber,SUBSTRING(
(SELECT ';' + TotalItem+' x '+ItemName
FROM YourTable
where ItemNumber=c.ItemNumber
ORDER BY ItemNumber
FOR XML PATH('')),2,200000 ) AS NewDescription from YourTable c
GO
Here's one way:
SELECT
it.[Item Number]
, Values1 = STUFF(CAST((
SELECT [text()] = ', ' + CAST(it2.TotalItem AS varchar) + ' x ' + it2.ItemName
FROM dbo.Items it2
WHERE it2.[Item Number] = it.[Item Number]
FOR XML PATH(''), TYPE) AS VARCHAR(100)), 1, 2, '')
FROM (
SELECT DISTINCT [Item Number]
FROM dbo.Items
) it
You could use STRING_AGG
SELECT [Item Number], STRING_AGG (CONCAT(TotalItem,'x',ItemName), ';') as tags
FROM dbo.TableName
GROUP BY [Item Number];
SELECT t2.ItemNumber ,
STUFF(( SELECT ',' + CAST(TotalItem AS VARCHAR) + ' x ' + ItemName
FROM #MyTable t1
WHERE t1.ItemNumber = t2.ItemNumber
FOR
XML PATH('')
), 1, 1, '') AS NewDescription
FROM #MyTable t2
GROUP BY t2.ItemNumber
DEMO
Related
I have the following query:
SELECT
p.ID,
p.DESCRIPTION,
STUFF((SELECT '; ' + col.CUST_ORDER_ID
FROM CUST_ORDER_LINE col
WHERE col.PART_ID = p.ID
ORDER BY col.CUST_ORDER_ID
FOR XML PATH('')), 1, 1, '') [Customer Orders],
STUFF((SELECT '; ' + ql.QUOTE_ID
FROM QUOTE_LINE ql
WHERE ql.PART_ID = p.ID
ORDER BY ql.QUOTE_ID
FOR XML PATH('')), 1, 1, '') As Quotes
FROM
PART p
GROUP BY
p.ID, p.DESCRIPTION
I end up with many duplicate "Customer Orders". I tried adding "DISTINCT" i.e. "Stuff((Select DISTINCT" but I get the error "ORDER BY items must appear in the select list if SELECT DISTINCT is specified". There's already an "Order By col.CUST_ORDER_ID" in the statement so I guess I don't understand. Can anyone provide me with a suggestion and possibly and explanation? Using SQL Server 2012.
Select p.ID,
p.DESCRIPTION,
Stuff((Select distinct '; ' + col.CUST_ORDER_ID From CUST_ORDER_LINE col
Where col.PART_ID = p.ID Order By '; ' + col.CUST_ORDER_ID For Xml Path('')), 1, 1,
'') [Customer Orders],
Stuff((Select distinct '; ' + ql.QUOTE_ID From QUOTE_LINE ql
Where ql.PART_ID = p.ID Order By '; ' + ql.QUOTE_ID For Xml Path('')), 1, 1,
'') As Quotes
From PART p
Group By p.ID,
p.DESCRIPTION
Simpy use ';'+ use in order by column with distinct clause.order by column and selected column data must be same.
Actually i have three columns. ID, MedID, Name. With my query i am getting a result look like the below.
ID MedID Name
1 101 TestData1
1 124 TestData2
Query
select
cmd.ID, mm.MedID,mm.Name as Name
from
tbl1 mm
inner join
tbl2 cmd on cmd.medID= mm.MedID
where
cmd.ID= 1
Actually i am expecting a result like the below
ID MedID Name
1 101,124 TestData1,TestData2
So, how can get a result like this, Where i need to do changes in my query?
Any help appreciated. Thanks in advance !!!
Use STUFF and FOR XML PATH like this:
select id,
stuff((
select ',' + cast(MedId as varchar(30))
from t t1
where t1.id = t.id
order by MedID
for xml path('')
), 1, 1, '') MedID,
stuff((
select ',' + Name
from t t1
where t1.id = t.id
order by MedID
for xml path('')
), 1, 1, '') Name
from t
group by id;
Demo
DECLARE #TABLE TABLE (ID int, MedID varchar(10), Name varchar(10))
INSERT INTO #TABLE VALUES
(1, '101' , 'TestData1'),
(1, '124' , 'TestData2')
SELECT t.ID
, STUFF(( SELECT ', ' + MedID
FROM #TABLE
WHERE ID = t.ID
FOR XML PATH(''),TYPE)
.value('.','NVARCHAR(MAX)'),1,2,'') AS MedID
, STUFF(( SELECT ', ' + Name
FROM #TABLE
WHERE ID = t.ID
FOR XML PATH(''),TYPE)
.value('.','NVARCHAR(MAX)'),1,2,'') AS Name
FROM #TABLE t
GROUP BY t.ID
stuff(( select distinct ',',Convert(varchar(256),y.RoomPlanID)
from(
select x.RoomPlanID ,x.RoomPlanHierarchy from (select utblConfigDestRoomRates.RoomPlanID,utblMstRoomPlans.RoomPlanHierarchy
FROM utblConfigDestRoomRates inner
JOIN utblMstRoomPlans on utblConfigDestRoomRates.RoomPlanID=utblMstRoomPlans.RoomPlanId
WHERE PropertyTypeID=1
AND BusinessID='AAAA'
AND('25-Aug-2015' BETWEEN DateEffective AND DateEnd)
AND StarRank=3 group by RoomPlanHierarchy order by RoomPlanHierarchy asc
) x
--order by
-- x.RoomPlanHierarchy
)y
FOR XML PATH('')), 1, 1, '')
You can use ROW_NUMBER (Transact-SQL) function. I assume that order to x.RoomPlanHierarchy like this
stuff(( select distinct ',',Convert(varchar(256),y.RoomPlanID)
from(
select x.RoomPlanID ,x.RoomPlanHierarchy,ROW_NUMBER() OVER(ORDER BY x.RoomPlanHierarchy asc) AS Row from (select utblConfigDestRoomRates.RoomPlanID,utblMstRoomPlans.RoomPlanHierarchy
FROM utblConfigDestRoomRates inner
JOIN utblMstRoomPlans on utblConfigDestRoomRates.RoomPlanID=utblMstRoomPlans.RoomPlanId
WHERE PropertyTypeID=1
AND BusinessID='AAAA'
AND('25-Aug-2015' BETWEEN DateEffective AND DateEnd)
AND StarRank=3 group by RoomPlanHierarchy
) x
--order by
-- x.RoomPlanHierarchy
)y
FOR XML PATH('')), 1, 1, '')
--Format it in SQL
(
SELECT
stuff(
(
SELECT
'' + a.col_name ,
'' + Replace(CAST(a.pos as VARCHAR), a.pos, '') + '"'
FROM
(
SELECT
CAST (',' + db_column_name + ' AS "' + REPLACE(label_tag, '.', '_') AS nvarchar (4000) ) AS col_name,
row_number() over (partition BY RIGHT(entity, CHARINDEX('.', (REVERSE(entity)) ) - 1) ORDER BY db_column_name) AS pos
FROM
table1 AS ex
JOIN
table2 AS ef
ON
ef.col1 = ex.col1
WHERE
entity LIKE '%string%')a FOR xml path('')) , 1, 1, '' ) )
I have the following code which will create a comma delimited list for my results:
DECLARE #listStr VARCHAR(MAX)
SELECT #listStr = COALESCE(#listStr+', ' ,'') + INSTITUTIONNAME
FROM EDUCATION
WHERE STUDENTNUMBER= '111'
SELECT #listStr
The problem is its creating one massive comma delimited line. I need it to return a comma separated list per row.
So if Simon has been part of 2 institutions, then i expect:
"INSTITUTION1, INSTITUTION2"
As i didnt supply a where clause i expect my results to show up like this for each row in the database.
Update (As suggested by #Aaron in the comment)
STRING_AGG is the preferred way of doing this in the modern versions of SQL Server (2017 or later). It also supports easy ordering.
SELECT
STUDENTNUMBER
, STRING_AGG(INSTITUTIONNAME, ', ') AS StringAggList
, STRING_AGG(INSTITUTIONNAME, ', ') WITHIN GROUP (ORDER BY INSTITUTIONNAME DESC) AS StringAggListDesc
FROM Education E
GROUP BY E.STUDENTNUMBER;
Original Answer:
Use FOR XML PATH('') - which is converting the entries to a comma separated string and STUFF() -which is to trim the first comma- as follows Which gives you the same comma separated result
SELECT
STUFF((SELECT ',' + INSTITUTIONNAME
FROM EDUCATION EE
WHERE EE.STUDENTNUMBER = E.STUDENTNUMBER
ORDER BY sortOrder
FOR XML PATH(''), TYPE).value('text()[1]', 'nvarchar(max)')
, 1, LEN(','), '') AS XmlPathList
FROM EDUCATION E
GROUP BY E.STUDENTNUMBER
Here is the FIDDLE showing results for both STRING_AGG and FOR XML PATH('').
For Sql Server 2017 and later you can use the new STRING_AGG function
https://learn.microsoft.com/en-us/sql/t-sql/functions/string-agg-transact-sql
The following example replaces null values with 'N/A' and returns the
names separated by commas in a single result cell.
SELECT STRING_AGG ( ISNULL(FirstName,'N/A'), ',') AS csv
FROM Person.Person;
Here is the result set.
John,N/A,Mike,Peter,N/A,N/A,Alice,Bob
Perhaps a more common use case is to group together and then aggregate, just like you would with SUM, COUNT or AVG.
SELECT a.articleId, title, STRING_AGG (tag, ',') AS tags
FROM dbo.Article AS a
LEFT JOIN dbo.ArticleTag AS t
ON a.ArticleId = t.ArticleId
GROUP BY a.articleId, title;
this works in sql server 2016
USE AdventureWorks
GO
DECLARE #listStr VARCHAR(MAX)
SELECT #listStr = COALESCE(#listStr+',' ,'') + Name
FROM Production.Product
SELECT #listStr
GO
If you're stuck with SQL Server <2017, you can use GroupConcat. The syntax and the performance is far better than the FOR XML PATH sollution.
Installation:
-- https://codeplexarchive.blob.core.windows.net/archive/projects/groupconcat/groupconcat.zip
create assembly [GroupConcat] from 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with permission_set = safe;
create aggregate [dbo].[GROUP_CONCAT] (#VALUE [nvarchar](4000)) returns[nvarchar](max) external name [GroupConcat].[GroupConcat.GROUP_CONCAT];
create aggregate [dbo].[GROUP_CONCAT_D] (#VALUE [nvarchar](4000), #DELIMITER [nvarchar](4)) returns[nvarchar](max) external name [GroupConcat].[GroupConcat.GROUP_CONCAT_D];
create aggregate [dbo].[GROUP_CONCAT_DS] (#VALUE [nvarchar](4000), #DELIMITER [nvarchar](4), #SORT_ORDER [tinyint]) returns[nvarchar](max) external name [GroupConcat].[GroupConcat.GROUP_CONCAT_DS];
create aggregate [dbo].[GROUP_CONCAT_S] (#VALUE [nvarchar](4000), #SORT_ORDER [tinyint]) returns[nvarchar](max) external name [GroupConcat].[GroupConcat.GROUP_CONCAT_S];
go
Usage:
declare #liststr varchar(max)
select #liststr = dbo.group_concat_d(institutionname, ',')
from education
where studentnumber = '111'
group by studentnumber;
select #liststr
GroupConcat does not support ordering, though. You could use PIVOT, CTE's and windows functions if you need ordering:
drop table if exists #students;
create table #students (
name varchar(20),
institution varchar(20),
year int -- order by year
)
go
insert into #students(name, institution, year)
values
('Simon', 'INSTITUTION1', 2005),
('Simon', 'INSTITUTION2', 2008);
with cte as (
select name,
institution,
rn = row_number() over (partition by name order by year)
from #students
)
select name,
[1] +
isnull((',' + [2]), '') +
isnull((',' + [3]), '') +
isnull((',' + [4]), '') +
isnull((',' + [5]), '') +
isnull((',' + [6]), '') +
isnull((',' + [7]), '') +
isnull((',' + [8]), '') +
isnull((',' + [9]), '') +
isnull((',' + [10]), '') +
isnull((',' + [11]), '') +
isnull((',' + [12]), '') +
isnull((',' + [13]), '') +
isnull((',' + [14]), '') +
isnull((',' + [15]), '') +
isnull((',' + [16]), '') +
isnull((',' + [17]), '') +
isnull((',' + [18]), '') +
isnull((',' + [19]), '') +
isnull((',' + [20]), '')
from cte
pivot (
max(institution)
for rn in ([1], [2], [3], [4],[5],[6],[7],[8],[9],[10],[11],[12],[13],[14],[15],[16],[17],[18],[19],[20])
) as piv
I just saw another question very similar to this!
Here is the canonical NORTHWIND (spelled just slightly different for some reason) database example.
SELECT *
FROM [NORTHWND].[dbo].[Products]
SELECT CategoryId,
MAX( CASE seq WHEN 1 THEN ProductName ELSE '' END ) + ', ' +
MAX( CASE seq WHEN 2 THEN ProductName ELSE '' END ) + ', ' +
MAX( CASE seq WHEN 3 THEN ProductName ELSE '' END ) + ', ' +
MAX( CASE seq WHEN 4 THEN ProductName ELSE '' END )
FROM ( SELECT p1.CategoryId, p1.ProductName,
( SELECT COUNT(*)
FROM NORTHWND.dbo.Products p2
WHERE p2.CategoryId = p1.CategoryId
AND p2.ProductName <= p1.ProductName )
FROM NORTHWND.dbo.Products p1 ) D ( CategoryId, ProductName, seq )
GROUP BY CategoryId ;
I have a table such as:
|Date |Name|
--------------------
|'20-May-2011'|Bob |
|'20-May-2011'|Fred|
|'20-May-2011'|Jim |
|'21-May-2011'|Bob |
|'21-May-2011'|Ed |
|'22-May-2011'|Bill|
I need a query to return:
|Date |Count|Names |
--------------------------------------
|'20-May-2011'| 3|'Bob, Fred, Jim'|
|'21-May-2011'| 2|'Bob, Ed' |
|'22-May-2011'| 1|'Bill' |
In other words, I want a list and a count of the names by date.
The best I can come up with is:
SELECT list.[Date], [Count], [Names]
FROM (
SELECT [Date],
STUFF((
SELECT ', ' + [Name]
FROM #table t2
WHERE t2.[Date] = t.[Date]
ORDER BY [Name]
FOR XML PATH('')
), 1, 2, '') AS [Names]
FROM #table t
GROUP BY [Date]
) [list]
INNER JOIN (
SELECT [Date],
COUNT(*) AS [Count]
FROM #table t
GROUP BY [Date]
) [count]
ON list.[Date] = count.[Date]
ORDER BY [Count] DESC, list.[Date]
Is there a more elegant query?
SELECT [Date],
COUNT(*) AS [Count],
STUFF((
SELECT ', ' + [Name]
FROM #table t2
WHERE t2.[Date] = t.[Date]
ORDER BY [Name]
FOR XML PATH('')
), 1, 2, '') AS [Names]
FROM #table t
GROUP BY [Date]
If you think that the Name column might contain <>'"& you should do like this instead:
SELECT [Date],
COUNT(*) AS [Count],
STUFF((
SELECT ', ' + [Name]
FROM #table t2
WHERE t2.[Date] = t.[Date]
ORDER BY [Name]
FOR XML PATH(''), TYPE
).value('.', 'varchar(max)'), 1, 2, '') AS [Names]
FROM #table t
GROUP BY [Date]
Not a whole lot better - but maybe using a single CTE to "encapsulate" the XML-PATH-stuffing into a more presentable way would work??
;WITH ConsolidatedData AS
(
SELECT
[Date],
STUFF((
SELECT ', ' + [Name]
FROM #table t2
WHERE t2.[Date] = t.[Date]
ORDER BY [Name]
FOR XML PATH('')
), 1, 2, '') AS [Names]
FROM #table t
)
SELECT
[Date], Names, COUNT(*)
FROM
ConsolidatedData
GROUP BY
[Date], Names
Not sure if you'd count this as one "compound" statement, or two.... :-)
One word of advice: try not to use SQL Server identifiers and reserved words (like Date or Order) as your own column and/or table names.... it's always rather messy....