Disable queueing execute in C - c

Question

I have problem with my sleep function in C.
When i use in this code sleep function like this:
while(1) {
XNextEvent(display, &xevent);
switch (xevent.type) {
case MotionNotify:
break;
case ButtonPress:
printf("Button click: [%d, %d]\n", xevent.xmotion.x_root, xevent.xmotion.y_root);
sleep(5);
break;
case ButtonRelease:
break;
}
It doesn't works well for me because printf("button click") is executing all time but slower.
How to print "button click x y" once and stop listening for click for 5 second?

Answer 1

I think you're looking for something like:
/* ignore_click is the time until mouse click is ignored */
time_t ignore_click = 0;
while(1) {
XNextEvent(display, &xevent);
switch (xevent.type) {
case MotionNotify:
break;
case ButtonPress:
{
time_t now;
/* we read current time */
time(&now);
if (now > ignore_click)
{
/* now is after ignore_click, mous click is processed */
printf("Button click: [%d, %d]\n", xevent.xmotion.x_root, xevent.xmotion.y_root);
/* and we set ignore_click to ignore clicks for 5 seconds */
ignore_click = now + 5;
}
else
{
/* click is ignored */
}
}
break;
case ButtonRelease:
break;
}
}
The code written above will ignore clicks for 4 to 5 seconds: the time_t type is a second precision structure...
To get more acurate time, you could use struct timeval or struct timespec structure. I do not use them in my example to keep it clear.