TableA
id Name
--------------------------------
1 Ram Kumar
2 Rajesh A
3 Avinash K Bae
4 Kishore Babu
Try like below
Schema:
CREATE TABLE #TAB(id INT, Name VARCHAR(500))
INSERT INTO #TAB
SELECT 1, 'Ram Kumar'
UNION ALL
SELECT 2, 'Rajesh A'
UNION ALL
SELECT 3, 'Avinash K Bae'
UNION ALL
SELECT 4, 'Kishore Babu'
Now do the trick with Replace
SELECT ID
,REPLACE(REPLACE( REPLACE(Name,' ','><'), '<>',''),'><',' ')
FROM #TAB
Result:
+----+---------------+
| ID | NEW_NAME |
+----+---------------+
| 1 | Ram Kumar |
| 2 | Rajesh A |
| 3 | Avinash K Bae |
| 4 | Kishore Babu |
+----+---------------+
Related
Course
+-----+----------+
| id | c_name |
+-----+----------+
| 1 | course1 |
| 7 | course2 |
+-----+----------+
Chapter
+-----+----------+------------+
| id | Ch_name | c_id |
+-----+----------+------------+
| 3 | Chapter1 | 1 |
| 9 | Chapter2 | 7 |
| 11 | Chapter3 | 1 |
| 17 | Chapter4 | 1 |
+-----+----------+------------+
I'm trying to select all data so that I can generate the following output:
+-----+-- |
|Course |
+-----+-- |
|Course1 |
|Chapter1 |
|Chapter3 |
|Chapter4 |
| |
|Course2 |
|Chapter2 |
I have tried in this way:
select
c.CourseID ,
'Course' as table_name,
c.CourseName as Course,
'' as Chapter
from [MstCourse]c
union
select
s.CourseID,
'Chapter' as table_name,
c.CourseName as Course,
s.ChapterName as Chapter
from [MstCourse] c
inner JOIN [ManageChapter] s ON c.CourseID= s.CourseID
order by Course, Chapter
But I am not getting the results in a single column.
You could achieve this with a group by ... with rollup clause.
Sample data
create table course
(
id int,
name nvarchar(10)
);
insert into course(id, name) values
(1, 'Course1'),
(7, 'Course2');
create table chapter
(
id int,
name nvarchar(10),
c_id int
);
insert into chapter(id, name, c_id) values
(3 , 'Chapter1', 1),
(9 , 'Chapter2', 7),
(11, 'Chapter3', 1),
(17, 'Chapter4', 1);
Solution
select coalesce(ch.Name, co.Name) as [Course]
from course co
join chapter ch
on ch.c_id = co.id
group by co.Name, ch.Name with rollup
having grouping(co.Name) <> 1
order by co.Name, ch.Name;
For some background on how this solution works, have a look at this fiddle.
What is the most efficient method to combine multiple rows of values with the same ID in SQL Server?
Original data table dbo.ProductCategory:
+-----------+----------+------+
| ProductID | CATID | AA |
+-----------+----------+------+
| 1 | 123 | A |
| 1 | 412 | B |
| 2 | 567 | C |
| 2 | 521 | A |
| 3 | 2 | D |
| 3 | 5 | A |
| 4 | 6 | C |
| 4 | 8 | E |
| 4 | 123 | A |
+----+------+----------+------+
And I'm trying to achieve the following result
+-----------+----------+------+
| ProductID | CATID | AA |
+-----------+----------+------+
| 1 | 123,412 | A,B |
| 2 | 567,521 | C,A |
| 3 | 2,5 | D,A |
| 4 | 6,8,123 | C,E,A|
+----+------+----------+------+
In SQL Server 2017+, you can use STRING_AGG
select ProductId, STRING_AGG(CATID, ',') as CATID, STRING_AGG(AA, ',') AA
from PC
GROUP BY ProductID
Sample Data
DECLARE #Temp AS TABLE (ProductID INT, CATID INT, AA CHAR(2))
INSERT INTO #Temp
SELECT 1 , 123 , 'A' UNION ALL
SELECT 1 , 412 , 'B' UNION ALL
SELECT 2 , 567 , 'C' UNION ALL
SELECT 2 , 521 , 'A' UNION ALL
SELECT 3 , 2 , 'D' UNION ALL
SELECT 3 , 5 , 'A' UNION ALL
SELECT 4 , 6 , 'C' UNION ALL
SELECT 4 , 8 , 'E' UNION ALL
SELECT 4 , 123 , 'A'
Using STUFF() In sql server
SELECT ProductID,STUFF((SELECT CONCAT(', ', CATID)
FROM #Temp i
WHERE i.ProductID = o.ProductID
FOR XML PATH ('')),1,1,'') AS CATID
,STUFF((SELECT CONCAT(', ', AA)
FROM #Temp i
WHERE i.ProductID = o.ProductID
FOR XML PATH ('')),1,1,'') AS AA
FROM #Temp o
GROUP BY ProductID
Result
ProductID CATID AA
------------------------------------
1 123, 412 A , B
2 567, 521 C , A
3 2, 5 D , A
4 6, 8, 123 C , E , A
I cannot summarize numbers in the table (SQL-Server) after pivoting and I will be very grateful for your advice.
Better if I explain the problem on the example:
Existing table:
+-------+-----------+-----------+-------------------+
| # | $$$$$ | Fire | Water |
+-------+-----------+-----------+-------------------+
| 1 | 5 | 1 | 5 |
| 1 | 4 | 1 | 5 |
| 1 | 10 | 1 | 5 |
| 2 | 3 | 3 | 8 |
| 2 | 4 | 3 | 8 |
+-------+-----------+-----------+-------------------+
Desired output:
+-------+-----------+-----------+-------------------+
| # | $$$$$ | Fire | Water |
+-------+-----------+-----------+-------------------+
| 1 | 19 | 1 | 5 |
| 2 | 7 | 3 | 8 |
+-------+-----------+-----------+-------------------+
I tend to believe that I already tried all the solutions I found with summarizing and grouping by, but it was not solved, so I rely on you. Thanks in advance. The code I used to create the table:
WITH Enerc AS
(
SELECT
a1.[#],
a1.[$$$$$],
a2.[cause_of_loss]
FROM
data1 AS a1
LEFT JOIN
data2 AS a2 ON a1.[id] = a2.[id]
)
SELECT *
FROM Enerc
PIVOT
(SUM(gross_claim) FOR [cause_of_loss] IN ([Fire], [Water])) AS PivotTable;
No need to pivot. Your desired result should be got by grouping and using SUM:
SELECT
a1.[#],
SUM(a1.[$$$$$]),
a1.[Fire]
a1.[Water]
from data1 as a1
group by a1.[#], a1.[Fire], a1.[Water]
Let me show an example:
DECLARE #Hello TABLE
(
[#] INT,
[$$$$$] INT,
[Fire] INT,
[Water] INT
)
INSERT INTO #Hello
(
#,
[$$$$$],
Fire,
Water
)
VALUES
( 1, -- # - int
5, -- $$$$$ - int
1, -- Fire - int
5 -- Water - int
)
, (1, 4, 1, 5)
, (1, 10, 1, 5)
, (2, 3, 3, 8)
, (2, 4, 3, 8)
SELECT
h.#,
SUM(h.[$$$$$]),
h.Fire,
h.Water
FROM #Hello h
GROUP BY h.#, h.Fire, h.Water
try group by after the pivot.
With Enerc as
(SELECT
a1.[#],
a1.[$$$$$],
a2.[cause_of_loss]
from data1 as a1
left join data2 as a2
on a1.[id] = a2.[id]
)
select *
into tmp
from Enerc
PIVOT
(sum(gross_claim)
FOR [cause_of_loss] in (
[Fire], [Water]))
as PivotTable
select [#], sum([$$$$$])as [$$$$$], Fire, Water
from #tmp
group by [#],Fire, Water
EDIT: in case of permission denied:
With Enerc as
(SELECT
a1.[#],
a1.[$$$$$],
a2.[cause_of_loss]
from data1 as a1
left join data2 as a2
on a1.[id] = a2.[id]
),phase2 as(
select *
from Enerc
PIVOT
(sum(gross_claim)
FOR [cause_of_loss] in (
[Fire], [Water]))
as PivotTable)
select [#], sum([$$$$$])as [$$$$$], Fire, Water
from phase2
group by [#],Fire, Water
I would like to update multiple colums into one column of an another table:
I am using MS SQl Server
Table 1:
Num | ColumnA | ColumnB |
--------------------------
1 | Peter | Mueller |
1 | Jonny | Corleone |
2 | John | Cohn |
1 | Sarah | Wood |
Now I want to update ColumnA and ColumnB into ColumA of Table2 like this:
Table2:
Num | ColumnC |
----------------------------------------------------
1 | Peter, Mueller, Jonny, Corleone, Sarah, Wood |
2 | John, Cohn |
It is not good practice to store multiple values in a single column. If you need to do this though, then try this:
SELECT adress,
num,
Stuff((SELECT ',' + ColumnA + ',' + ColumnB
FROM table1 a
WHERE a.Num = b.Num
FOR xml path('')), 1, 1, '')
FROM table1 b
GROUP BY num
can i SELECT distinct 2 fields (provfrom, provto) on table AS one column
with condition :
- values of 2 fields is never same in one row
- values in field provfrom can be inside field provto but in different row
- values in field provto can be inside field provfrom but in different row
example :
i have 2 column as below
-------------------------
| provfrom | provto |
-------------------------
| 2 | 4 |
| 3 | 7 |
| 3 | 7 |
| 5 | 2 |
| 5 | 2 |
| 7 | 2 |
| 7 | 2 |
| 1 | 5 |
| 2 | 5 |
| 2 | 8 |
| 5 | 8 |
-------------------------
the result that i want by disticnt is as below
-------------
| prov |
-------------
| 1 |
| 2 |
| 3 |
| 4 |
| 5 |
| 7 |
| 8 |
-------------
Can i do this in sql server?
i try to found out by explore google, but not found it
Thanks
You can use Union keyword which will give distinct elements from Both Tables
select provfrom from mytable
union
select provTo from mytable
You can either do this with a union or by using apply, the apply has less IO so I would go with the apply query.
create table #temp
(
provfrom tinyint,
provto tinyint
);
insert into #temp (provfrom, provto)
values (2,4),(3,7),(3,7),
(5,2),(5,2),(7,2),
(7,2),(1,5),(2,5),
(2,8),(5,8);
set statistics io on;
select distinct
a.provfromto
from #temp as t
cross apply (values (t.provfrom),(t.provto)) as a(provfromto);
select provfrom from #temp
union
select provTo from #temp
set statistics io off;
drop table #temp;
Try this:
select t.prov
from
(select provfrom as prov
from yourtable
union
select provto
from yourtable) as t
order by t.prov
UNION function apply a distinct clause, so you'll get all value per one occurence.
The external query about ordering your result set