I can't find an error of the code. minesweeper C - c

Question

I'm trying to make when I put some numbers in scan, and if there's mine(*), print boom and if there's no mine, print the number of mines near to it. I can't find a problem with the code, but there's an error. Please verify it if you find the problem.
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define N 10
int main (void)
{
char minefield [N][N];
int i, j;
int k;
int x, y;
int count;
int mine_number;
count = 0;
mine_number = N*N/10;
srand((long)time(NULL));
for (k=1; 0< k < mine_number; k=k+1) {
i = rand() % N;
j = rand() % N;
minefield [i][j] = '*';
}
for (i=0; i < N; i=i+1) {
for (j=0; j < N; j=j+1) {
count = 0;
if (minefield[i][j] != '*') {
if (i == 0) {
if (j == 0) {
if (minefield [i][j+1] == '*') {
count = count + 1;
}
if (minefield [i+1][j+1] == '*') {
count = count + 1;
}
if (minefield [i+1][j] == '*') {
count = count + 1;
}
}
else if (j == N-1) {
if (minefield [i+1][j] == '*') {
count = count + 1;
}
if (minefield [i+1][j-1] == '*') {
count = count + 1;
}
if (minefield [i][j-1] == '*') {
count = count + 1;
}
}
else {
if (minefield [i][j+1] == '*') {
count = count + 1;
}
if (minefield [i+1][j+1] == '*') {
count = count + 1;
}
if (minefield [i+1][j] == '*') {
count = count + 1;
}
if (minefield [i+1][j-1] == '*') {
count = count + 1;
}
if (minefield [i][j-1] == '*') {
count = count + 1;
}
}
}
else if (i == N-1) {
if (j == 0) {
if (minefield [i-1][j] == '*') {
count = count + 1;
}
if (minefield [i-1][j+1] == '*') {
count = count + 1;
}
if (minefield [i][j+1] == '*') {
count = count + 1;
}
}
else if (j == N-1) {
if (minefield [i-1][j] == '*') {
count = count + 1;
}
if (minefield [i-1][j-1] == '*') {
count = count + 1;
}
if (minefield [i][j-1] == '*') {
count = count + 1;
}
}
else {
if (minefield [i][j+1] == '*') {
count = count + 1;
}
if (minefield [i-1][j+1] == '*') {
count = count + 1;
}
if (minefield [i-1][j] == '*') {
count = count + 1;
}
if (minefield [i-1][j-1] == '*') {
count = count + 1;
}
if (minefield [i][j-1] == '*') {
count = count + 1;
}
}
}
else {
if (j == 0) {
if (minefield [i-1][j] == '*') {
count = count + 1;
}
if (minefield [i-1][j+1] == '*') {
count = count + 1;
}
if (minefield [i][j+1] == '*') {
count = count + 1;
}
if (minefield [i+1][j+1] == '*') {
count = count + 1;
}
if (minefield [i+1][j] == '*') {
count = count + 1;
}
}
else if (j == N-1) {
if (minefield [i-1][j] == '*') {
count = count + 1;
}
if (minefield [i-1][j-1] == '*') {
count = count + 1;
}
if (minefield [i][j-1] == '*') {
count = count + 1;
}
if (minefield [i+1][j-1] == '*') {
count = count + 1;
}
if (minefield [i+1][j] == '*') {
count = count + 1;
}
}
else {
if (minefield [i-1][j-1] == '*') {
count = count + 1;
}
if (minefield [i-1][j] == '*') {
count = count + 1;
}
if (minefield [i-1][j+1] == '*') {
count = count + 1;
}
if (minefield [i][j+1] == '*') {
count = count + 1;
}
if (minefield [i][j-1] == '*') {
count = count + 1;
}
if (minefield [i+1][j-1] == '*') {
count = count + 1;
}
if (minefield [i+1][j] == '*') {
count = count + 1;
}
if (minefield [i+1][j+1] == '*') {
count = count + 1;
}
}
}
}
}
}
scanf("%d %d", &x, &y);
if (minefield[x][y] = '*') {
printf("boom");
}
else {
printf("%d", count);
}
return 0;
}

Answer 1

Your basic problem is that you are counting before you read the input, i.e. before you know what x and y is. In other words, currently you are counting "something" on the whole minefield which isn't what you want.
So the first thing to do is to read x and y before counting.
Further it seems to me that your big if statement is hard to read. You could reorganize it like:
if (scanf("%d %d", &x, &y) != 2 || x < 0 || x >= N || y < 0 || y >= N)
{
// Illegal input
exit(1);
}
if (minefield[x][y] == '*') {
printf("boom");
}
else {
count = 0;
if (x-1 >= 0 && y-1 >= 0) count += (minefield[x-1][y-1] == '*');
if (x-1 >= 0) count += (minefield[x-1][y] == '*');
....
.... Add code to cover all 8 combinations (i.e. add the 5 missing combinations)
....
if (x+1 < N && y+1 < N) count += (minefield[x+1][y+1] == '*');
printf("%d", count);
}