I have below set of data.
LLimit ULimit Col C
1 3 a
3 5 b
5 11 c
11 15 d
15 17 e
17 20 f
in col D if i enter 3.5 i need result in col E as "b" (corrosponding value to lowerlimit and upper limit). I have used If or statement, However is there a way i can do this using Index, Match or array. I tried and it works absolutely fine with the limit numbers (like 5, 11, 17, 3 etc) but not working with between numbers like 14 (between 11 and 14).
Below is what i used
{=INDEX(F5:F10,MATCH(1,(((D5:D10)>=H4)*((E5:E10)>=H4))*1,0))}
Was trying to attach workbook, but don't know how to do it.
Try this
Assuming D2=3.5 then
In E2
=INDEX(C2:C7,SUMPRODUCT((A2:A7<=D2)*(B2:B7>=D2)*(ROW(C2:C7)-ROW(C2)+1)))
Edit:
To exclude the lower boundary, try this
=INDEX(C2:C7,SUMPRODUCT((A2:A7<D2)*(B2:B7>=D2)*(ROW(C2:C7)-ROW(C2)+1)))
Use Vlookup as follow:
=VLOOKUP(D2,$A$2:$C$7,3)
$A$2:$C$7 is your initial table LLimit ULimit Col C
Vlookup will look in the first column for the value <= D2 and return the corresponding value in column 3
Update
For non sorted column A your Formula needs a modification:
={INDEX($C$2:$C$7,MATCH(1,($A$2:$A$7<=D2)*($B$2:$B$7>=D2),0),1)}
You wrote the same condition >= for both limit
{=INDEX($F$5:$F$10,MATCH(1,((($D$5:$D$10)<=H4)*(($E$5:$E$10)>=H4))*1,0))}
Related
I need to extract data from one tab (extracted data) to another tab and validate the data in the following way:
if 0% assign 3
if from 0 till -10% assign 2
if from -10% and more assign 1
if from 0% till 10% assign 4
if from 10% and more assign 5
here is the link to the file https://docs.google.com/spreadsheets/d/1f8SFi2hNP6Anav7G7BYWyK-fasPk1pT1A2HFJblT-FI/edit?usp=sharing
I suggest you use two vlookups.
If you have a tab called 'Ranges' with the following two columns:
Percentage Result
-1000% 1
-10% 2
0% 3
10% 4
11% 5
Then the formula in cell B1 on the 'calculations' tab would be something like:
=arrayformula({"Con Potential";iferror(vlookup(vlookup(A2:A,'Extracted data'!A:D,4,0),Ranges!A:B,2,1),)})
Delete all data below cell B1 for the arrayformula to work correctly.
The second vlookup references col D on the 'Extracted data' tab because that is the percentage I think you are comparing? If not, alter 4 in the vlookup to another column.
If it helps, please see:
https://stackoverflow.com/help/someone-answers
NB: In place of Ranges!A:B you could use a fixed array:
=arrayformula({"Con Potential";iferror(vlookup(vlookup(A2:A,'Extracted data'!A:D,4,0),{-10,1;-0.1,2;0,3;0.1,4;0.11,5},2,1),)})
If you want to temporarily see the fixed array in case you want to edit any values, place this in a cell somewhere out of the way:
={-10,1;-0.1,2;0,3;0.1,4;0.11,5}
, is used to bump to a new column, ; is used as a return.
Relevance
Looking at 'Relevance' lookup from 'Position Delta' and this table in your sheet:
Since a 'position delta' value of 10 cannot both have a relevance of 5 and 4, I've made the assumption that 10 gets 5. If that is incorrect, then I'll adjust the boundaries.
Add this to cell C1 on the 'calculations' tab (clearing all cells below):
=arrayformula({"Relevance";iferror(vlookup(vlookup(calculations!A2:A,'Extracted data'!A:D,3,0),{0,5;11,4;21,3;31,2;41,1;51,0},2,1),)})
The fixed array {0,5;11,4;21,3;31,2;41,1;51,0} has these values:
0 5
11 4
21 3
31 2
41 1
51 0
If you need to change the boundaries so 10 is a 4, not 5, then change the vlookup to use this fixed range {0,5;10,4;20,3;30,2;40,1;50,0}:
0 5
10 4
20 3
30 2
40 1
50 0
vlookup is incremental and anything up to 11 will get 5, then 11 to 20 will get 4, 21 to 30 will get 3 and so on.
,1) in the vlookup at the far right gets the nearest value match until 'position delta' has reached the next boundary.
This is my table (copied from the similar question Finding minimum value in index(match) array [EXCEL])
A B C D
tasmania 10 3 10
queensland 22 8 10
new south wales 10 12 12
northern territory 8 4 15
south australia 12 2 8
western australia 32 4 15
tasmania 72 6 16
I have criteria for B and C, and I want to retrieve the A with the lowest corresponding value D. Values in B, C and D can be duplicates, values in A can not.
Example:
B >= 8
C >= 4
Should result in "queensland" (lowest matching value is 10), but not "tasmania" (has the same cost)
I am currently trying this array formula:
{ =MIN(IF(B:B>=8;IF(C:C>=4;D;""));1) }
Which returns the correct lowest D, but since I am losing the informaiton about A, I can not retrieve the value for A
This as an array formula should work for you:
=INDEX($A$1:$A$7,MATCH(MIN(IF($B$1:$B$7>=8,IF($C$1:$C$7>=4,$D$1:$D$7))),IF($B$1:$B$7>=8,IF($C$1:$C$7>=4,$D$1:$D$7)),0))
It should be noted that if you have Excel 2016 or Office365, you'll have access to the MINIFS function which is probably better suited for this task (i don't actually have the newest version, so am unable to test)
I think this question might be related to Ms Excel -> 2 columns into a 2 dimensional array but I can't quite make the connection.
I have a VBA script for filling missing missing data. I select two adjacent columns, and it finds any gaps in the second column and linearly interpolates based on (possibly irregular) spacing in the first column. For instance, I could use it on this data:
1 7
2 14
3 21
5 35
5.1
6 42
7
8
9 45
to get this output
1 7
2 14
3 21
5 35
5.1 35.7 <---1/10th the way between 35&42
6 42
7 43 <-- 1/3 the way between 42 & 45
8 44 <-- 2/3 the way between 42 & 45
9 45
This is very useful for me.
My trouble is that it only works on contiguous columns. I would like to be able to select two columns that are not adjacent to each other and have it work the same way. My code starts out like this:
Dim addr As String
addr = Selection.Address
Dim nR As Long
Dim nC As Long
'Reads Selected Cells' Row and Column Information
nR = Range(addr).Rows.Count
nC = Range(addr).Columns.Count
When I run this with contiguous columns selected, addr shows up in the Locals window with a value like "$A$2:$B$8" and nC = 2
When I run this with non-contiguous columns selected, addr shows up in the Locals window with a value like "$A$2:$A$8,$C$2:$C$8" and nC = 1.
Later on in the script, I collect the values in each column into an array. Here's how I deal with the second column, for example:
'Creates a Column 2 (col1) array, determines cells needed to interpolate for, changes font to bold and red, and reads its values
Dim col2() As Double
ReDim col2(0 To nR + 1)
i = 1
Do Until i > nR
If IsEmpty(Selection(i, 2)) Or Selection(i, 2) = 0 Or Selection(i, 2) = -901 Then
Selection(i, 2).Font.Bold = True
Selection(i, 2).Font.Color = RGB(255, 69, 0)
col2(i) = 9999999
Else
col2(i) = Selection(i, 2)
End If
i = i + 1
Loop
This is also busted, because even if my selection is "$A$2:$A$8,$C$2:$C$8" VBA will treat Selection(1,2) as a reference to $B$2, not the desired $C$2.
Anyone have a suggestion for how I can get VBA to treat non-contiguous selection the way it treats contiguous?
You're dealing with "disjoint ranges." Use the Areas collection, e.g., as described here. The first column should be in Selection.Areas(1) and the second column should be in Selection.Areas(2).
Another ? for you. How can I work off of the results of 2 Conditional Formats & have just the results of those conditions highlighted. The 2 Conditional Formats results are in (column C & G) & I need to have the results highlighted in (column A)... A's 3 arguments are as follows:
condition1 cell value equal to 0, No Format
condition2 formula is =$G27>=LARGE($G$27:$G$150,10), Bold Format
condition3 formula is =$C27>=LARGE($C$27:$C$150,10), Colored Red
Another quandry...
This is just like the fizzbuzz programmer test.
So, without writing the code for you: I'll recommend a loop through a 'listobject(table)' followed by setting the range values using '.interior.colorindex' or 'font.colorindex' properties.
OK, without using code...
- Format your table as a table using "Format as Table" function
- In the "Table" menu, select the "Total Row" checkbox
- Set your Total formula for Cols C and G as =LARGE([ColC],10) and =LARGE([ColG],10), respectively.
- In Conditional Formatting, set up two rules as follows:
- =$B28>=$D$[TotalRowlNumber]
- =$B28>=$C$[TotalRowNumber]
- You shouldn't need a condition for =0 since you are not changing any formats.
How does that work?
Here's a sample table:
ID Col A Col C Col G
____________________________
1 50.66 51.33 97.17
2 16.09 83.39 97.37
3 b71.94 69.77 28.06
4 21.60 20.59 21.14
5 33.62 65.58 39.21
6 21.96 34.59 17.99
7 br80.94 93.02 96.84
8 b70.53 37.53 29.60
9 32.06 37.38 0.15
10 br89.81 67.02 6.85
11 br89.76 64.65 74.00
12 47.94 46.06 1.71
13 b61.19 34.19 90.13
14 br79.11 35.77 86.97
15 39.89 79.15 77.88
16 br93.20 8.01 13.99
17 31.84 18.12 95.61
18 br99.78 19.99 3.89
19 38.94 32.12 18.56
20 13.17 22.23 61.82
21 br75.75 51.42 28.32
22 b55.89 49.93 76.30
23 br72.78 82.46 27.07
24 b57.20 31.26 76.90
25 6.46 6.85 2.78
Total 51.33 74.00
Use the LARGE() formula to get the 10th largest value in the TOTAL row.
Then reference this cell in the condition.
So, any number larger than 51.33 will be bold and any number larger than 74.00 will be bold red. (Note, I used random number generator, so the numbers may be good or bad.)
Also, I added a 'b' tag and an 'r' note where cells will be formatted bold and red, respectively.
i am doing very simple Matrix indexing examples . where code is as give below
>> A=[ 1 2 3 4 ; 5 6 7 8 ; 9 10 11 12 ]
A =
1 2 3 4
5 6 7 8
9 10 11 12
>> A(end, end-2)
ans =
10
>> A(2:end, end:-2:1)
ans =
8 6
12 10
here i am bit confused . when i use A(end, end-2) it takes difference of two till first column and when there is just one column left there is no further processing , but when i use A(2:end, end:-2:1) it takes 6 10 but how does it print 8 12 while there is just one column left and we have to take difference of two from right to left , Pleas someone explain this simple point
The selection A(end, end-2) reads: take elements in last row of A that appear in column 4(end)-2=2.
The selection A(2:end, end:-2:1) similarly reads: take elements in rows 2 to 4(end) and starting from last column going backwards in jumps of two, i.e. 4 then 2.
To check the indexing, simply substitute the end with size(A,1) or size(A,2) if respectively found in the row and col position.
First the general stuff: end is just a placeholder for an index, namely the last position in a given array dimension. For instance, for an arbitrary array A(end,1) will pick the last element in column 1, and A(1,end) will pick the last element in the first row.
In your example, A(end, end-2) picks an element in the last row two columns before the last one.
To interpret a statement such as
A(2:end, end:-2:1)
it might help to substitute end with the actual index of the last row/column elements, so this is equivalent to
A(2:3, 4:-2:1)
Furthermore 4:-2:1 is equivalent to the list 4,2 since we are instructing to make the list starting at 4, decreasing in steps of 2, up to (minimum) 1. So this is equivalent to
A([2 3],[4 2])
Finally, the following combination of indices is implied by A([2 3],[4 2]):
A(2,4) A(2,2)
A(3,4) A(3,2)