I have a string called Dats which is either of the general appearence xxxx-nnnnn (where x is a character, and n is a number) or nnn-nnnnnn.
I want to return only the numbers.
For this I've tried:
SELECT Distinct dats,
Left(SubString(artikelnr, PatIndex('%[0-9.-]%', artikelnr), 8000), PatIndex('%[^0-9.-]%', SubString(artikelnr, PatIndex('%[0-9.-]%', artikelnr), 8000) + 'X')-1)
FROM ThatDatabase
It is almost what I want. It removes the regular characters x, but it does not remove the unicode character -. How can I remove this as well? And also, it seems rather ineffective to have two PatIndex functions for every row, is there a way to avoid this? (This will be used on a big database where the result of this Query will be used as keys).
EDIT: Updated as a new database sometimes contained additional -'s or . together with -.
DECLARE #T as table
(
dats nvarchar(10)
)
INSERT INTO #T VALUES
('111BWA30'),
('115-200-11')
('115-22.4-1')
('10.000.22')
('600F-FFF200')
I wasn't sure if you wanted the numbers before the - char as well, but if you do, here is one way to do it:
Create and populate sample table (Please save us this step in your future questions)
DECLARE #T as table
(
dats nvarchar(10)
)
INSERT INTO #T VALUES
('abcde-1234'),
('23-343')
The query:
SELECT dats,
case when patindex('%[^0-9]-[0-9]%', dats) > 0 then
right(dats, len(dats) - patindex('%-[0-9]%', dats))
else
stuff(dats, charindex('-', dats), 1, '')
end As NumbersOnly
FROM #T
Results:
dats NumbersOnly
abcde-1234 1234
23-343 23343
If you want the only the numbers to the right of the - char, it's simpler:
SELECT dats,
right(dats, len(dats) - patindex('%-[0-9]%', dats)) As RightNumbersOnly
FROM #T
Results:
dats RightNumbersOnly
abcde-1234 1234
23-343 343
If you know which characters you need to remove then use REPLACE function
DECLARE #T as table
(
dats nvarchar(100)
)
INSERT INTO #T
VALUES
('111BWA30'),
('115-200-11'),
('115-22.4-1'),
('10.000.22'),
('600F-FFF200')
SELECT REPLACE(REPLACE(dats, '.', ''), '-', '')
FROM #T
Related
Heads!
In my database, I have a column that contains the following data (examples):
H-01-01-02-01
BLE-01-03-01
H-02-05-1.1-03
The task is to get the second to last element of the array if you would split that using the "-" character. The strings are of different length.
So this would be the result using the above mentioned data:
02
03
1.1
Basically I'm searching for an equivalent of the following ruby-statement for use in a Select-Statement in SQL-Server:
"BLE-01-03-01".split("-")[-2]
Is this possible in any way in SQL Server? After spending some time searching for a solution, I only found ones that work for the last or first element.
Thanks very much for any clues or solutions!
PS: Version of SQL Server is Microsoft SQL Server 2012
As an alternative you can try this:.
--A mockup table with some test data to simulate your issue
DECLARE #mockupTable TABLE (ID INT IDENTITY, YourColumn VARCHAR(50));
INSERT INTO #mockupTable VALUES
('H-01-01-02-01')
,('BLE-01-03-01')
,('H-02-05-1.1-03');
--The query
SELECT CastedToXml.value('/x[sql:column("CountOfFragments")-1][1]','nvarchar(10)') AS TheWantedFragment
FROM #mockupTable t
CROSS APPLY(SELECT CAST('<x>' + REPLACE(t.YourColumn,'-','</x><x>') + '</x>' AS XML))A(CastedToXml)
CROSS APPLY(SELECT CastedToXml.value('count(/x)','int')) B(CountOfFragments);
The idea in short:
The first APPLY will transform the string to a XML like this
<x>H</x>
<x>01</x>
<x>01</x>
<x>02</x>
<x>01</x>
The second APPLY will xquery into this XML to get the count of fragments. As APPLY will add this as a column to the result set, we can use the value using sql:column() to get the wanted fragment by its position.
As I wrote in my comment - using charindex with reverse.
First, create and populate sample table (Please save us this step in your future questions):
DECLARE #T AS TABLE
(
Col Varchar(100)
);
INSERT INTO #T (Col) VALUES
('H-01-01-02-01'),
('BLE-01-03-01'),
('H-02-05-1.1-03');
The query:
SELECT Col,
LEFT(RIGHT(Col, AlmostLastDelimiter-1), AlmostLastDelimiter - LastDelimiter - 1) As SecondToLast
FROM #T
CROSS APPLY (SELECT CharIndex('-', Reverse(Col)) As LastDelimiter) As A
CROSS APPLY (SELECT CharIndex('-', Reverse(Col), LastDelimiter+1) As AlmostLastDelimiter) As B
Results:
Col SecondToLast
H-01-01-02-01 02
BLE-01-03-01 03
H-02-05-1.1-03 1.1
Similar to Zohar's solution, but using CTEs instead of CROSS APPLY to prevent redundancy. I personally find this easier to follow, as you can see what happens in each step. Doesn't make it a better solution though ;)
DECLARE #strings TABLE (data VARCHAR(50));
INSERT INTO #strings VALUES ('H-01-01-02-01') , ('BLE-01-03-01'), ('H-02-05-1.1-03');
WITH rev AS (
SELECT
data,
REVERSE(data) AS reversed
FROM
#strings),
first_hyphen AS (
SELECT
data,
reversed,
CHARINDEX('-', reversed) + 1 AS first_pos
FROM
rev),
second_hyphen AS (
SELECT
data,
reversed,
first_pos,
CHARINDEX('-', reversed, first_pos) AS second_pos
FROM
first_hyphen)
SELECT
data,
REVERSE(SUBSTRING(reversed, first_pos, second_pos - first_pos)) AS result
FROM
second_hyphen;
Results:
data result
H-01-01-02-01 02
BLE-01-03-01 03
H-02-05-1.1-03 1.1
Try this
declare #input NVARCHAR(100)
declare #dlmt NVARCHAR(3);
declare #pos INT = 2
SET #input=REVERSE(N'H-02-05-1.1-03');
SET #dlmt=N'-';
SELECT
CAST(N'<x>'
+ REPLACE(
(SELECT REPLACE(#input,#dlmt,'#DLMT#') AS [*] FOR XML PATH(''))
,N'#DLMT#',N'</x><x>'
) + N'</x>' AS XML).value('/x[sql:variable("#pos")][1]','nvarchar(max)');
I have a situation where I have created script to select data in our company's environment. In doing so, I decided to use functions for some pattern matching and stripping of characters in a CASE WHEN.
However, one of our clients doesn't want to let us put their data in our local environment, so I now have the requirement of massaging the script to be able to run on their environment--essentially meaning I need to remove the functions, and I am having trouble thinking about how I need to move stuff around to do so.
An example of the function call would be:
SELECT ....
CASE WHEN Prp = 'Key Cabinet'
AND SerialNumber IS NOT NULL
AND dbo.fnRemoveNonNumericCharacters(SerialNumber) <> ''
THEN dbo.fnRemoveNonNumericCharacters(SerialNumber)
....
INTO #EmpProperty
FROM ....
Where Prp is a column that contains the property type and SerialNumber is a column that contains a serial number, but also some other random garbage because data entry was sloppy.
The function definition is:
WHILE PATINDEX('%[^0-9]%', #strText) > 0
BEGIN
SET #strText = STUFF(#strText, PATINDEX('%[^0-9]%', #strText), 1, '')
END
RETURN #strText
where #strText is the SerialNumber I am passing in.
I may be stuck in analysis paralysis because I just can't figure out a good way to do this. I don't need a full on solution per-say, perhaps just point me in a direction you know will work. Let me know if you would like some sample DDL/DML to mess around with stuff.
Example 'SerialNumber' values: CA100 (Trash bins), T110, 101B.
There are also a bunch of other types of values such as all text or all numbers, but we are filtering those out. The current patterning matching is good enough.
So I think you mean you can't use a function... so, perhaps:
declare #table table (SomeCol varchar(4000))
insert into #table values
('1 ab2cdefghijk3lmnopqr4stuvwxyz5 6 !7##$8%^&9*()-10_=11+[]{}12\|;:13></14? 15'),
('CA100 (Trash bins), T110, 101B')
;with cte as (
select top (100)
N=row_number() over (order by ##spid) from sys.all_columns),
Final as (
select SomeCol, Col
from #table
cross apply (
select (select X + ''
from (select N, substring(SomeCol, N, 1) X
from cte
where N<=datalength(SomeCol)) [1]
where X between '0' and '9'
order by N
for xml path(''))
) Z (Col)
where Z.Col is not NULL
)
select
SomeCol
,cast(Col as varchar) CleanCol --change this to BIGINT if it isn't too large
from Final
I have a SQL Server table with numbers in column no:
12345670000115
14245670000116
58492010000118
I need a function that will remove one number 1 from right side of number, so result must be like:
1234567000015
1424567000016
5849201000018
I find some solutions to use charindex() with substring(), but my SQL skills are poor so I really need help.
Thanks
Assuming this is varchar data here is an easy way to accomplish this. BTW, I would suggest you not use column names like 'no'. It is a reserved word and it is horribly ambiguous. Does that mean number or the opposite of yes? If it is number as I assume it would be better to name the column with an indication of what the number is. PartNumber, ItemNumber, CatalogNumber whatever...
LEFT(no, len(no) - 2) + RIGHT(no, 1)
Try to use this query:
declare #charToReplace char = '1'
select REVERSE(stuff(REVERSE(no), charindex(#charToReplace, REVERSE(no)), 1, ''))
from table
or
declare #charToReplace char = '1'
declare #tmp_table TABLE (NO varchar(16))
insert into #tmp_table
select REVERSE(NO)
from yourtable
select REVERSE(stuff(NO, charindex(#charToReplace, NO), 1, ''))
For your particular data, if the numbers fit a BIGINT, one easy way is to treat them like numbers:
Setup
create table #tmp (
number VARCHAR(16)
)
insert into #tmp values ('12345670000115'), ('14245670000116'), ('58492010000118')
GO
Script:
select number, cast( (cast(number AS bigint) - 100) / 100 * 10 + cast(number AS bigint) % 100 as VARCHAR(16))
from #tmp
GO
I resolve problem. There is answer in which I remove one character 1 and update whole table. Thanks all for help!
Update myTableName
set barcode=substring(barcode,1,11)+substring(barcode,13,1)
where len(barcode)>= 14
I have a table with a nvarchar column. This column has values for example:
983
294
a343
a3546f
and so on.
I would like to take MAX of this values, but not as text but like from numerics. So in this example numerics are:
983
294
343
3546
And the MAX value is the last one - 3546. How to do this in TSQL on Microsoft SQL?
First install a regular expression function. This article has code you can cut/paste.
Then with RegexReplace (from that article) you can extract digits from a string:
dbo.RegexReplace( '.*?(\d+).*', myField, '$1' )
Then convert this string to a number:
CAST( dbo.RegexReplace( '.*?(\d+).*', myField, '$1' ) AS INT )
Then use this expression inside a MAX() function in a SELECT.
You can try to keep it simple without using Regular Expression
Here is the source
create table #t ( val varchar(100) )
insert #t select 983
insert #t select 294
insert #t select 'a343'
insert #t select 'a3546f';
GO
;with ValueRange as (
select val,
[from] = patindex('%[0-9]%', val),
[to] = case patindex('%[a-z]', val)
when 0 then len(val)
else patindex('%[a-z]', val) - patindex('%[0-9]%', val)
end
from #t
)
select substring(val, [from], [to]) as val
from ValueRange VR
order by cast(substring(val, [from], [to]) as int) desc
CAST() would do the trick, probably.
SELECT MAX(CAST(yourColumn AS int)) AS maxColumns FROM yourTable
Edit.
I didn't read the whole question, as it seems...
– Function to strip out non-numeric chars
ALTER FUNCTION dbo.UDF_ParseNumericChars
(
#string VARCHAR(8000)
)
RETURNS VARCHAR(8000)
AS
BEGIN
DECLARE #IncorrectCharLoc SMALLINT
–SET #IncorrectCharLoc = PATINDEX(’%[^0-9A-Za-z]%’, #string)
SET #IncorrectCharLoc = PATINDEX(’%[^0-9.]%’, #string)
WHILE #IncorrectCharLoc > 0
BEGIN
SET #string = STUFF(#string, #IncorrectCharLoc, 1, ”)
SET #IncorrectCharLoc = PATINDEX(’%[^0-9.]%’, #string)
END
SET #string = #string
RETURN #string
END
GO
I picked it from here. (I voted up the reg exp answer though)
you can write a function something like
create FUNCTION [dbo].[getFirstNumeric](
#s VARCHAR(50)
)
RETURNS int AS
BEGIN
set #s = substring(#s,patindex('%[0-9]%',#s),len(#s)-patindex('%[0-9]%',#s) + 1)
if patindex('%[^0-9]%',#s) = 0
return #s
set #s = substring(#s,1,patindex('%[^0-9]%',#s)-1)
return cast(#s as int)
end
and then call
select max(dbo.getFirstNumeric(yourColumn)) from yourTable
if you are using SQL Server 2005 or never you can also use the solution posted by Sung Meister
As far as I know you would need to create a process (or user defined function) to scrub the column, so that you can actually convert it to an INT or other appropriate datatype, then you can take the max of that.
By using user defined function parse the value to an int and then run the select.
SELECT MAX(dbo.parseVarcharToInt(column)) FROM table
SELECT dbo.RegexReplace('[^0-9]', '','a5453b',1, 1)
and RegexReplace installation like Jason Cohen said
This is an old question, I know - but to add to the knowledge base for others...
Assuming all your values have at least 1 number in them:
Select max(convert(int, SubString(VarName, PATINDEX('%[0-9]%',VarName), Len(VarName))))
from ATable
This is my simple answer. You can try it. But it works for fixed removable string value.
select max(cast(SUBSTRING(T.column,3,len(T.column)) as int)) from tablename T
If I have the following nvarchar variable - BTA200, how can I extract just the BTA from it?
Also, if I have varying lengths such as BTA50, BTA030, how can I extract just the numeric part?
I would recommend a combination of PatIndex and Left. Carefully constructed, you can write a query that always works, no matter what your data looks like.
Ex:
Declare #Temp Table(Data VarChar(20))
Insert Into #Temp Values('BTA200')
Insert Into #Temp Values('BTA50')
Insert Into #Temp Values('BTA030')
Insert Into #Temp Values('BTA')
Insert Into #Temp Values('123')
Insert Into #Temp Values('X999')
Select Data, Left(Data, PatIndex('%[0-9]%', Data + '1') - 1)
From #Temp
PatIndex will look for the first character that falls in the range of 0-9, and return it's character position, which you can use with the LEFT function to extract the correct data. Note that PatIndex is actually using Data + '1'. This protects us from data where there are no numbers found. If there are no numbers, PatIndex would return 0. In this case, the LEFT function would error because we are using Left(Data, PatIndex - 1). When PatIndex returns 0, we would end up with Left(Data, -1) which returns an error.
There are still ways this can fail. For a full explanation, I encourage you to read:
Extracting numbers with SQL Server
That article shows how to get numbers out of a string. In your case, you want to get alpha characters instead. However, the process is similar enough that you can probably learn something useful out of it.
substring(field, 1,3) will work on your examples.
select substring(field, 1,3) from table
Also, if the alphabetic part is of variable length, you can do this to extract the alphabetic part:
select substring(field, 1, PATINDEX('%[1234567890]%', field) -1)
from table
where PATINDEX('%[1234567890]%', field) > 0
LEFT ('BTA200', 3) will work for the examples you have given, as in :
SELECT LEFT(MyField, 3)
FROM MyTable
To extract the numeric part, you can use this code
SELECT RIGHT(MyField, LEN(MyField) - 3)
FROM MyTable
WHERE MyField LIKE 'BTA%'
--Only have this test if your data does not always start with BTA.
declare #data as varchar(50)
set #data='ciao335'
--get text
Select Left(#Data, PatIndex('%[0-9]%', #Data + '1') - 1) ---->>ciao
--get numeric
Select right(#Data, len(#data) - (PatIndex('%[0-9]%', #Data )-1) ) ---->>335