I have a SQL Server table with numbers in column no:
12345670000115
14245670000116
58492010000118
I need a function that will remove one number 1 from right side of number, so result must be like:
1234567000015
1424567000016
5849201000018
I find some solutions to use charindex() with substring(), but my SQL skills are poor so I really need help.
Thanks
Assuming this is varchar data here is an easy way to accomplish this. BTW, I would suggest you not use column names like 'no'. It is a reserved word and it is horribly ambiguous. Does that mean number or the opposite of yes? If it is number as I assume it would be better to name the column with an indication of what the number is. PartNumber, ItemNumber, CatalogNumber whatever...
LEFT(no, len(no) - 2) + RIGHT(no, 1)
Try to use this query:
declare #charToReplace char = '1'
select REVERSE(stuff(REVERSE(no), charindex(#charToReplace, REVERSE(no)), 1, ''))
from table
or
declare #charToReplace char = '1'
declare #tmp_table TABLE (NO varchar(16))
insert into #tmp_table
select REVERSE(NO)
from yourtable
select REVERSE(stuff(NO, charindex(#charToReplace, NO), 1, ''))
For your particular data, if the numbers fit a BIGINT, one easy way is to treat them like numbers:
Setup
create table #tmp (
number VARCHAR(16)
)
insert into #tmp values ('12345670000115'), ('14245670000116'), ('58492010000118')
GO
Script:
select number, cast( (cast(number AS bigint) - 100) / 100 * 10 + cast(number AS bigint) % 100 as VARCHAR(16))
from #tmp
GO
I resolve problem. There is answer in which I remove one character 1 and update whole table. Thanks all for help!
Update myTableName
set barcode=substring(barcode,1,11)+substring(barcode,13,1)
where len(barcode)>= 14
Related
Hello looking solution to sort sizes inside my column.
Exmaple :
-- CREATE TEMP TABLE
Create Table #MyTempTable (
size varchar(20)
);
-- insert sample data to TEMP TABLE
insert into #MyTempTable
values
('10.5W'),
('10W'),
('11.5W'),
('11W'),
('12W'),
('5.5W'),
('5W'),
('6.5W'),
('6W'),
('7.5W'),
('7W'),
('8.5W'),
('8W'),
('9.5W'),
('9W'),
('4')
select 'BEFORE',* from #MyTempTable
SELECT 'AFTER',size
FROM #MyTempTable
ORDER BY LEN(size)
When i order by LEN there is no good sorting like this :
AFTER 5W
AFTER 6W
AFTER 7W
AFTER 8W
AFTER 9W
AFTER 10W
AFTER 11W
AFTER 12W
AFTER 5.5W
AFTER 7.5W
AFTER 6.5W
AFTER 9.5W
AFTER 8.5W
AFTER 10.5W
AFTER 11.5W
All im' looking for is to sort in proper order. like this :
5W
5.5W
6W
6.5W
7W
7.5W
8W
8.5W
9W
9.5W
10W
10.5W
11W
11.5W
12W
I seearched a lot of stackoverflow and can't find solution for that because there is not only int and also decimal numbers. So don't know how to get it
Assuming each value would always end in just one unit, you may sort on the numeric portion cast to a decimal:
SELECT size
FROM #MyTempTable
ORDER BY CAST(
CASE WHEN size LIKE '%[A-Z]'
THEN LEFT(size, LEN(size) - 1)
ELSE size END AS DECIMAL(10, 2)
);
A couple of other options:
-- if you don't know all of the potential non-numeric characters:
SELECT size FROM #MyTempTable
ORDER BY TRY_CONVERT(decimal(5,2),
SUBSTRING(size,1,COALESCE(NULLIF
(PATINDEX('%[^0-9.]%', size),0),255)-1));
-- if there is a finite set (say, W and D):
DECLARE #KnownChars varchar(32) = 'WD';
SELECT size FROM #MyTempTable
ORDER BY TRY_CONVERT(decimal(5,2),
TRANSLATE(size, #KnownChars, REPLICATE(space(1), LEN(#KnownChars))));
In order by clause first remove W from then cast as NUMERIC data type. Now you can expect sorting like a number.
SELECT *
FROM #MyTempTable AS mtt
ORDER BY CAST(LEFT(mtt.size, LEN(mtt.size) - 1) AS DECIMAL) ASC;
I start to work on old project and there is sql server database column which stores articles numbers for example as follows:
11.1006.45
11.1006.46
11.1006.47
01.10012.11
01.10012.12
2.234.1
2.234.2
2.234.3
657.104324.32
Every number contains 3 parts. First part describe what producent it is and that's something i have to change when user choose diffrent number for specific producent. For example producent number 2 will be now 13 so according to our examples:
2.234.1
2.234.2
2.234.3
has to be done this way right now:
13.234.1
13.234.2
13.234.3
I am looking for sql query which would find all records where producent number is e.g 2.xxxxx and then replace to 13.xxxxx. I would like this query to be secure to avoid any issues with numbers replacments.Hope you understand what i ment.
You could use this for update. '2. and 13.' could be any other string
DECLARE #SampleTable AS TABLE
(
Version varchar(100)
)
INSERT INTO #SampleTable
VALUES
('11.1006.45'),
('11.1006.46'),
('11.1006.47'),
('01.10012.11'),
('01.10012.12'),
('2.234.1'),
('2.234.2'),
('2.234.3'),
('657.104324.32')
UPDATE #SampleTable
SET
Version = '13.' + substring(Version, charindex('.', Version) + 1, len(Version) - charindex('.', Version))
WHERE Version LIKE '2.%'
SELECT * FROM #SampleTable st
Demo link: Rextester
update t
set t.col= replace(yourcol,substring(yourcol,1,charindex('.',yourcol,1),2)
from table t
this finds first character before first dot
substring(yourcol,1,charindex('.',yourcol,1)
then you use replace ,to replace it with whatever you need
You can use this query for multiple updation,
DECLARE #Temp AS TABLE
(
ArtNo VARCHAR(100)
)
INSERT INTO #Temp
VALUES
('11.1006.45'),
('11.1006.46'),
('11.1006.47'),
('01.10012.11'),
('01.10012.12'),
('2.234.1'),
('2.234.2'),
('2.234.3'),
('657.104324.32')
UPDATE #Temp
SET ArtNo = CASE WHEN SUBSTRING(ArtNo,1,CHARINDEX('.',ArtNo)-1) = '2' THEN STUFF(ArtNo,1,CHARINDEX('.',ArtNo)-1,'13')
WHEN SUBSTRING(ArtNo,1,CHARINDEX('.',ArtNo)-1) = '11' THEN STUFF(ArtNo,1,CHARINDEX('.',ArtNo)-1,'15')
ELSE ArtNo
END
SELECT * FROM #Temp
I have a string called Dats which is either of the general appearence xxxx-nnnnn (where x is a character, and n is a number) or nnn-nnnnnn.
I want to return only the numbers.
For this I've tried:
SELECT Distinct dats,
Left(SubString(artikelnr, PatIndex('%[0-9.-]%', artikelnr), 8000), PatIndex('%[^0-9.-]%', SubString(artikelnr, PatIndex('%[0-9.-]%', artikelnr), 8000) + 'X')-1)
FROM ThatDatabase
It is almost what I want. It removes the regular characters x, but it does not remove the unicode character -. How can I remove this as well? And also, it seems rather ineffective to have two PatIndex functions for every row, is there a way to avoid this? (This will be used on a big database where the result of this Query will be used as keys).
EDIT: Updated as a new database sometimes contained additional -'s or . together with -.
DECLARE #T as table
(
dats nvarchar(10)
)
INSERT INTO #T VALUES
('111BWA30'),
('115-200-11')
('115-22.4-1')
('10.000.22')
('600F-FFF200')
I wasn't sure if you wanted the numbers before the - char as well, but if you do, here is one way to do it:
Create and populate sample table (Please save us this step in your future questions)
DECLARE #T as table
(
dats nvarchar(10)
)
INSERT INTO #T VALUES
('abcde-1234'),
('23-343')
The query:
SELECT dats,
case when patindex('%[^0-9]-[0-9]%', dats) > 0 then
right(dats, len(dats) - patindex('%-[0-9]%', dats))
else
stuff(dats, charindex('-', dats), 1, '')
end As NumbersOnly
FROM #T
Results:
dats NumbersOnly
abcde-1234 1234
23-343 23343
If you want the only the numbers to the right of the - char, it's simpler:
SELECT dats,
right(dats, len(dats) - patindex('%-[0-9]%', dats)) As RightNumbersOnly
FROM #T
Results:
dats RightNumbersOnly
abcde-1234 1234
23-343 343
If you know which characters you need to remove then use REPLACE function
DECLARE #T as table
(
dats nvarchar(100)
)
INSERT INTO #T
VALUES
('111BWA30'),
('115-200-11'),
('115-22.4-1'),
('10.000.22'),
('600F-FFF200')
SELECT REPLACE(REPLACE(dats, '.', ''), '-', '')
FROM #T
I am stuck on converting a varchar column UserID to INT. I know, please don't ask why this UserID column was not created as INT initially, long story.
So I tried this, but it doesn't work. and give me an error:
select CAST(userID AS int) from audit
Error:
Conversion failed when converting the varchar value
'1581............................................................................................................................' to data type int.
I did select len(userID) from audit and it returns 128 characters, which are not spaces.
I tried to detect ASCII characters for those trailing after the ID number and ASCII value = 0.
I have also tried LTRIM, RTRIM, and replace char(0) with '', but does not work.
The only way it works when I tell the fixed number of character like this below, but UserID is not always 4 characters.
select CAST(LEFT(userID, 4) AS int) from audit
You could try updating the table to get rid of these characters:
UPDATE dbo.[audit]
SET UserID = REPLACE(UserID, CHAR(0), '')
WHERE CHARINDEX(CHAR(0), UserID) > 0;
But then you'll also need to fix whatever is putting this bad data into the table in the first place. In the meantime perhaps try:
SELECT CONVERT(INT, REPLACE(UserID, CHAR(0), ''))
FROM dbo.[audit];
But that is not a long term solution. Fix the data (and the data type while you're at it). If you can't fix the data type immediately, then you can quickly find the culprit by adding a check constraint:
ALTER TABLE dbo.[audit]
ADD CONSTRAINT do_not_allow_stupid_data
CHECK (CHARINDEX(CHAR(0), UserID) = 0);
EDIT
Ok, so that is definitely a 4-digit integer followed by six instances of CHAR(0). And the workaround I posted definitely works for me:
DECLARE #foo TABLE(UserID VARCHAR(32));
INSERT #foo SELECT 0x31353831000000000000;
-- this succeeds:
SELECT CONVERT(INT, REPLACE(UserID, CHAR(0), '')) FROM #foo;
-- this fails:
SELECT CONVERT(INT, UserID) FROM #foo;
Please confirm that this code on its own (well, the first SELECT, anyway) works for you. If it does then the error you are getting is from a different non-numeric character in a different row (and if it doesn't then perhaps you have a build where a particular bug hasn't been fixed). To try and narrow it down you can take random values from the following query and then loop through the characters:
SELECT UserID, CONVERT(VARBINARY(32), UserID)
FROM dbo.[audit]
WHERE UserID LIKE '%[^0-9]%';
So take a random row, and then paste the output into a query like this:
DECLARE #x VARCHAR(32), #i INT;
SET #x = CONVERT(VARCHAR(32), 0x...); -- paste the value here
SET #i = 1;
WHILE #i <= LEN(#x)
BEGIN
PRINT RTRIM(#i) + ' = ' + RTRIM(ASCII(SUBSTRING(#x, #i, 1)))
SET #i = #i + 1;
END
This may take some trial and error before you encounter a row that fails for some other reason than CHAR(0) - since you can't really filter out the rows that contain CHAR(0) because they could contain CHAR(0) and CHAR(something else). For all we know you have values in the table like:
SELECT '15' + CHAR(9) + '23' + CHAR(0);
...which also can't be converted to an integer, whether you've replaced CHAR(0) or not.
I know you don't want to hear it, but I am really glad this is painful for people, because now they have more war stories to push back when people make very poor decisions about data types.
This question has got 91,000 views so perhaps many people are looking for a more generic solution to the issue in the title "error converting varchar to INT"
If you are on SQL Server 2012+ one way of handling this invalid data is to use TRY_CAST
SELECT TRY_CAST (userID AS INT)
FROM audit
On previous versions you could use
SELECT CASE
WHEN ISNUMERIC(RTRIM(userID) + '.0e0') = 1
AND LEN(userID) <= 11
THEN CAST(userID AS INT)
END
FROM audit
Both return NULL if the value cannot be cast.
In the specific case that you have in your question with known bad values I would use the following however.
CAST(REPLACE(userID COLLATE Latin1_General_Bin, CHAR(0),'') AS INT)
Trying to replace the null character is often problematic except if using a binary collation.
This is more for someone Searching for a result, than the original post-er. This worked for me...
declare #value varchar(max) = 'sad';
select sum(cast(iif(isnumeric(#value) = 1, #value, 0) as bigint));
returns 0
declare #value varchar(max) = '3';
select sum(cast(iif(isnumeric(#value) = 1, #value, 0) as bigint));
returns 3
I would try triming the number to see what you get:
select len(rtrim(ltrim(userid))) from audit
if that return the correct value then just do:
select convert(int, rtrim(ltrim(userid))) from audit
if that doesn't return the correct value then I would do a replace to remove the empty space:
select convert(int, replace(userid, char(0), '')) from audit
This is how I solved the problem in my case:
First of all I made sure the column I need to convert to integer doesn't contain any spaces:
update data set col1 = TRIM(col1)
I also checked whether the column only contains numeric digits.
You can check it by:
select * from data where col1 like '%[^0-9]%' order by col1
If any nonnumeric values are present, you can save them to another table and remove them from the table you are working on.
select * into nonnumeric_data from data where col1 like '%[^0-9]%'
delete from data where col1 like '%[^0-9]%'
Problems with my data were the cases above. So after fixing them, I created a bigint variable and set the values of the varchar column to the integer column I created.
alter table data add int_col1 bigint
update data set int_col1 = CAST(col1 AS VARCHAR)
This worked for me, hope you find it useful as well.
If I have the following nvarchar variable - BTA200, how can I extract just the BTA from it?
Also, if I have varying lengths such as BTA50, BTA030, how can I extract just the numeric part?
I would recommend a combination of PatIndex and Left. Carefully constructed, you can write a query that always works, no matter what your data looks like.
Ex:
Declare #Temp Table(Data VarChar(20))
Insert Into #Temp Values('BTA200')
Insert Into #Temp Values('BTA50')
Insert Into #Temp Values('BTA030')
Insert Into #Temp Values('BTA')
Insert Into #Temp Values('123')
Insert Into #Temp Values('X999')
Select Data, Left(Data, PatIndex('%[0-9]%', Data + '1') - 1)
From #Temp
PatIndex will look for the first character that falls in the range of 0-9, and return it's character position, which you can use with the LEFT function to extract the correct data. Note that PatIndex is actually using Data + '1'. This protects us from data where there are no numbers found. If there are no numbers, PatIndex would return 0. In this case, the LEFT function would error because we are using Left(Data, PatIndex - 1). When PatIndex returns 0, we would end up with Left(Data, -1) which returns an error.
There are still ways this can fail. For a full explanation, I encourage you to read:
Extracting numbers with SQL Server
That article shows how to get numbers out of a string. In your case, you want to get alpha characters instead. However, the process is similar enough that you can probably learn something useful out of it.
substring(field, 1,3) will work on your examples.
select substring(field, 1,3) from table
Also, if the alphabetic part is of variable length, you can do this to extract the alphabetic part:
select substring(field, 1, PATINDEX('%[1234567890]%', field) -1)
from table
where PATINDEX('%[1234567890]%', field) > 0
LEFT ('BTA200', 3) will work for the examples you have given, as in :
SELECT LEFT(MyField, 3)
FROM MyTable
To extract the numeric part, you can use this code
SELECT RIGHT(MyField, LEN(MyField) - 3)
FROM MyTable
WHERE MyField LIKE 'BTA%'
--Only have this test if your data does not always start with BTA.
declare #data as varchar(50)
set #data='ciao335'
--get text
Select Left(#Data, PatIndex('%[0-9]%', #Data + '1') - 1) ---->>ciao
--get numeric
Select right(#Data, len(#data) - (PatIndex('%[0-9]%', #Data )-1) ) ---->>335