I would like to insert to Clients table data from two different tables (Surname and name). Moreover I would like to have a third column (email) that is a concatination from the first two. when i try the code hereunder it gives me the following error: "Subquery returned more than 1 value".
insert into CLIENTS (LastName,Firstname, EMAIL)
select (select top 150 Surname from Surname order by NEWID()),
(select top 150 Name from Name order by Newid()),
(select concat(concat(FisrtName, LastName),'#novaims.com') from clients);
Could you please help me understand where is the problem?
The error message is obvious your sub-query can result more than one record. Try this
;WITH cte
AS (SELECT 1 AS val
UNION ALL
SELECT val + 1
FROM cte
WHERE val < 150)
SELECT FisrtName,
LastName,
Concat(FisrtName, LastName, '#novaims.com')
FROM cte
OUTER apply (SELECT TOP 1 Surname FROM Surname ORDER BY Newid()) s (FisrtName)
OUTER apply (SELECT TOP 1 NAME FROM NAME ORDER BY Newid()) n (LastName)
Option (Maxrecursion 0)
You need to move the table references to the from clause. I think this does what you want:
insert into CLIENTS (LastName, Firstname, EMAIL)
select surname, name, concat(name, surname, '#novaims.com')
from (select Surname, row_number() over (order by newid()) as seqnum
from Surname
) s join
(select Name, row_number() over (order by newid()) as seqnum
from Name
)
on n.seqnum = s.seqnum;
Another method uses apply:
insert into CLIENTS (LastName, Firstname, EMAIL)
select top 150 s.surname, n.name, concat(n.name, s.surname, '#novaims.com')
from surname s cross apply
(select top 1 n.*
from names n
order by newid()
) n
order by newid();
This is more similar to your original idea. Do note, though, that the same name can appear more than once. And the performance should be better for the first version (because the sort is only happening once on each table).
Related
I have a table that Tracks Employees and the days they have spent in a policy. I don't generate this Data, it is dumped to our Server Daily.
The table looks like this:
My Goal is to get rid of the duplicates by keeping only the most recent Date.
In this example, if I run the query, I would like it to keep Rows 11 for Nicholas Morris and 14 for Tiana Sullivan.
Assumption: First name and Last Name combo are unique
So far,
This is what I have been doing:
select *
from
Employees IN(
Select ID
from Employees
group by FirstName, lastName
Having count(*) > 1)
This returns to me the rows that have duplicates and I have to manually search them and remove the ones I don't want to keep.
I am sure there is a better way of doing this
Thanks for your help
You can use a CTE and ROW_NUMBER() function to do it.
The query to get the data is:
SELECT ID, FirstName, LastName, ROW_NUMBER()
OVER (PARTITION BY FirstName, LastName ORDER BY DaysInPolicy DESC) AS Identifier
FROM
Employees
The query to remove duplicates is:
;WITH CTE AS (
SELECT ID, ROW_NUMBER()
OVER (PARTITION BY FirstName, LastName ORDER BY DaysInPolicy DESC) AS Identifier
FROM
Employees
)
DELETE E
FROM
Employees E
INNER JOIN CTE C ON C.ID = E.ID
WHERE
C.Identifier > 1
You could delete using an exists operator where you remove any row that has the same first and last name, but with a newer date:
DELETE FROM employees e1
WHERE EXISTS (SELECT *
FROM employees e2
WHERE e1.FirstName = e2.FirstName AND
e1.LastName = e2.LastName AND
e1.DaysInPolicy < e2.DaysInPolicy)
Try this:
SELECT * FROM
(
SELECT *, ROW_NUMBER() OVER (PARTITION BY Last_Name, First_Nmae ORDER BY DaysInPolicy DESC) AS RowNum
FROM Employees
) AS Emp
WHERE Emp.RowNum > 1
How to use DISTINCT keyword in SQL Server? I mean if it can work for given field.
select id, name, age
from dbo.XXX
There are multiple row returned by the query. I would like to get how many kinds of id or name or age.
select **distinct** id, name, age from dbo.XXX or
select id, **distinct** name, age from dbo.XXX or
select id, name, **distinct** age from dbo.XXX
To sum up, I would like to use a single SQL to get the distinct count of each fields, like select π±πΆπππΆπ»π°π id, π±πΆπππΆπ»π°π name, π±πΆπππΆπ»π°π age from dbo.XXX
Dense_Rank can be used to calculate a distinct count for any column and multiple columns:
Select col1, col2, col3,
dense_rank() over (partition by [col1] order by [Unique ID]) + dense_rank() over (partition by [col1] order by [Unique ID] desc) - 1 as DistCountCol1,
dense_rank() over (partition by [col2] order by [Unique ID]) + dense_rank() over (partition by [col2] order by [Unique ID] desc) - 1 as DistCountCol2,
dense_rank() over (partition by [col3] order by [Unique ID]) + dense_rank() over (partition by [col3] order by [Unique ID] desc) - 1 as DistCountCol3
from [table]
select distinct ID
from dbo.XXX
Select distinct name
from dbo.XXX
Select distinct age
from dbo.XXX
If you want to know how many rows you have for each distinct ID or Name or Age, you can use the following:
Select ID, count(id) as [ID_Recurrence]
from dbo.XXX
group by ID
Select Age, count(age) as [Age_Recurrence]
from dbo.XXX
group by Age
Select Name, count(name) as [Name_Recurrence]
from dbo.XXX
group by Name
The DISTINCT keyword return a unique row like the Following
SELECT DISTINCT ID FROM SomeTable
SELECT DISTINCT ID , SCORE FROM SomeTable
If you want to get unique value from row try the following code.
The Below code is copied from here
select t.id, t.player_name, t.team
from tablename t
join (select team, min(id) as minid from tablename group by team) x
on x.team = t.team and x.minid = t.id
select COUNT(distinct id) uniqueIDCount
from dbo.XXX
would count distinct values of id field, if you want to count distinct values for field combination you must concat fields, assuming your id is integer and name is nvarchar:
select COUNT(distinct CONVERT(nvarchar, id) + name) uniqueIDCount
from dbo.XXX
note that even this way looks nice it is probably not the most efficient one, here you have more efficient, but also more complicated method way:
with c as (
select distinct id, name
from dbo.XXX
)select COUNT(1)
from c
Not sure why it's complicated. U can have 3 different queries and u can union to return single set if u want .
I have 36 Sales tables each referred to one store:
st1.dbo.Sales
st2.dbo.Sales
...
st35.dbo.Sales
st36.dbo.Sales
Each record has the following key columns:
UserName, PostalCode, Location, Country, InvoiceAmount, ItemsCount, StoreID
Here is SQLFiddle
I need to copy into Customers table all Username (and their details) that are not already present into Customers
in case of duplicated it is required to use the fields of record where InvoiceAmount is MAX
I tried to build a query but looks too complicated and it is also wrong because in CROSS APPLY should consider the full list of Sales Tables
INSERT INTO Customers (.....)
SELECT distinct
d.UserName,
w.postalCode,
w.location,
W.country,
max(w.invoiceamount) invoiceamount,
max(w.itemscount) itemscount,
w.storeID
FROM
(SELECT * FROM st1.dbo.Sales
UNION
SELECT * FROM st2.dbo.Sales
UNION
...
SELECT * FROM st36.dbo.Sales) d
LEFT JOIN
G.dbo.Customers s ON d.Username = s.UserName
CROSS APPLY
(SELECT TOP (1) *
FROM s.dbo.[Sales]
WHERE d.Username=w.Username
ORDER BY InvoiceAmount DESC) w
WHERE
s.UserName IS NULL
AND d.username IS NOT NULL
GROUP BY
d.UserName, w.postalCode, w.location,
w.country, w.storeID
Can somebody please give some hints?
As a basic SQL query, I'd create a row_number in the inner subquery and then join to customers and then isolated the max invoice number for each customer not in the customer table.
INSERT INTO Customers (.....)
SELECT w.UserName,
w.postalCode,
w.location,
w.country,
w.invoiceamount,
w.itemscount,
w.storeID
FROM (select d.*,
row_number() over(partition by d.Username order by d.invoiceamount desc) rownumber
from (SELECT *
FROM st1.dbo.Sales
UNION
SELECT *
FROM st2.dbo.Sales
UNION
...
SELECT *
FROM st36.dbo.Sales
) d
LEFT JOIN G.dbo.Customers s
ON d.Username = s.UserName
WHERE s.UserName IS NULL
AND d.username IS NOT NULL
) w
where w.rownumber = 1
Using your fiddle this will select distinct usernames rows with max invoiceamount
with d as(
SELECT * FROM Sales
UNION
SELECT * FROM Sales2
)
select *
from ( select *,
rn = row_number() over(partition by Username order by invoiceamount desc)
from d) dd
where rn=1;
step 1 - use cte .
select username , invoiceamount ,itemscount from Sales
UNION all
select user name , invoiceamount ,itemscount from Sales
.....
...
step 2
next cte use group by and get max invoiceamount ,itemscount for user of last result set.
,cte2 as (
select user name , max (invoiceamount) as invoiceamount ,max(itemscount) as itemscount from cte)
step3
use left join with user table and find missing record and itemscount invoiceamount
I want to find the recent duplicate records from SQL Server 2012. Here is the table structure I have.
I have table name called UserRegistration which contains the duplicate of UserID(GUID) and in same table, I have CreatedDate Column as well (Date). Now I want to find the recent duplicate records from this table.
Here is the same data.
id FirstName LastName CreatedDate UserID
109 FirstNameA LastNameA 28-04-2015 GUID1
110 FirstNameC LastNameD 19-05-2015 GUID2
111 FirstNameE LastNameF 22-05-2015 GUID1
If you notice on above tables, GUID 1 are having the duplicate, Now I want to find the recent one means it should return me only those rows with duplication but recent data. So in above table structure, it should return me 111 because record has been created recently compared to the 109. I believe you understand.
Do let me know if you have any question. I am happy to answer. Thanks. Awaiting for the reply.
Harshal
Try the below query this should do the work based on your i/p data -
create table #UserRegistration (id int,FirstName varchar(20),LastName varchar(20),CreatedDate date,UserID varchar(20))
insert into #UserRegistration
select 109, 'FirstNameA', 'LastNameA', '2015-04-28', 'GUID1' union
select 110, 'FirstNameC', 'LastNameD', '2015-05-19', 'GUID2' union
select 111, 'FirstNameE', 'LastNameF', '2015-05-22', 'GUID1'
select id, FirstName, LastName, CreatedDate, UserID from
(SELECT ur.*,row_number() over(partition by UserID order by CreatedDate) rn
FROM #UserRegistration ur) A
where rn > 1
You could use CTE. Group your records by UserID and give your particular row a rank ordered by CreatedDate.
insert into tab(id, FirstName, LastName, CreatedDate, UserID)
values(109, 'FirstNameA', 'LastNameA', '2015-04-28', 'guid1'),
(110, 'FirstNameC', 'LastNameD', '2015-05-19', 'guid2'),
(111, 'FirstNameE', 'LastNameF', '2015-05-22', 'guid1');
with cte as
(
select id, ROW_NUMBER() over (partition by UserID order by CreatedDate asc) as [Rank],
FirstName, LastName, CreatedDate, UserID
from tab
)
select id, FirstName, LastName, CreatedDate, UserID from cte where Rank > 1
Rank > 1 condition is responsible for retrieving duplicated items.
sqlfiddle link:
http://sqlfiddle.com/#!6/4d1f2/6
Solved this by using tmp-tables:
SELECT a.UserID,
MAX(a.CreatedDate) As CreatedDate
INTO #latest
FROM <your table> a
GROUP BY a.UserID
HAVING COUNT(a.UserID) > 1
SELECT b.id
FROM #latest a
INNER JOIN <your table> b ON a.UserID = b.UserID AND a.CreatedDate = b.CreatedDate
try this,
SELECT * FROM TableName tt WHERE
exists(select MAX(createdDate)
from TableName
where tt.UserID = UserID
group by UserID
having MAX(createdDate)= tt.createdDate)
I think your createddate field is not a date field, then try Format
WITH TempAns (id,UserID,duplicateRecordCount)
AS
(
SELECT id,
UserID,
ROW_NUMBER()OVER(partition by UserID ORDER BY id)
AS duplicateRecordCount
FROM #t
)
select * from #t where id in (
select max(id )
from TempAns
where duplicateRecordCount > 1
group by name )
You'd rank your records with ROW_NUMBER() to give all last records per userid #1. With COUNT() you make sure only to get the userids having more than one record.
select
id, firstname, lastname, createddate, userid
from
(
select
id, firstname, lastname, createddate, userid,
row_number() over (partition by userid oder by createddate desc) as rn,
count(*) over (partition by userid) as cnt
from userregistration
) ranked
where rn = 1 -- only last one
and cnt > 1; -- but only if there is more than one record for the userid
This gets the latest record for every userid that has duplicates.
I've some records in table_3 and I want to insert that record to table_2 but value of first column (Id) will be (NUMBER+1) of table_1. My code is
INSERT INTO TABLE_2(Id,NAME)
SELECT (SELECT MAX(NUMBER) FROM TABLE_1)+1 AS Id,name
FROM TABLE_3
Count of table_1 is 200. and count of TABLE_3 is 10. I want new inserted Ids are like
(201,202,203,204,205,206,207,208,209,210)
but from query am getting is like...
(201,201,201,201,201,201,201,201,201,201)
you can do it simply with only one select using ROW_NUMBER() and a group by
INSERT INTO TABLE_2(Id,NAME)
SELECT MAX(NUMBER) + ROW_NUMBER() OVER (ORDER BY name),name
FROM TABLE_3
group by name
In your query (SELECT MAX(NUMBER) FROM TABLE_1)+1 is always the same, since MAX(NUMBER) is just 200.
If you want to increment by 1 for each new record inserted, starting at (SELECT MAX(NUMBER) FROM TABLE_1)+1, try this:
INSERT INTO TABLE_2 (Id, NAME)
SELECT Id + rn, name
FROM (
SELECT (SELECT MAX(NUMBER) FROM TABLE_1) AS Id, name,
ROW_NUMBER() OVER (ORDER BY name) AS rn
FROM TABLE_3 ) t