I have two tables, table1 has 2 columns as
id name
1 Amal
2 Varun
3 Sari
table2 has 3 columns as
id Subject marks
1 Maths 80
1 Malayalam 75
1 History 45
2 Maths 90
2 Malayalam 85
2 History 50
3 Maths 88
3 Malayalam 75
3 History 80
My question is to find the names who has the maximum mark for each subject (Subject wisw topper) the resultant table have to includes the fields name subject and marks
I tested with the following query
SELECT
table1.Student_Name, (table2.subject), max(table2.Marks_obt)
FROM
table2
INNER JOIN
table1 ON table2.stud_id = table1.Student_ID
GROUP BY
[Student_Name], table2.Subject
HAVING
MAX(Marks_obt) IN (SELECT MAX(Marks_obt) AS total_marks
FROM table2
GROUP BY subject)
In SQL Server 2008, but I got the result as
name subject
Sari History 80
Varun Malayalam 85
Amal Maths 80
Varun Maths 90
how I get the topper of three subject with these manner?
You can use ROW_NUMBER() :
SELECT s.subject,s.name,s.marks
FROM(
SELECT t1.*,t2.subject,t2.marks,
ROW_NUMBER() OVER(PARTITION BY t2.subject ORDER BY t2.marks DESC) as rnk
FROM Table1
JOIN Table2
ON table2.stud_id = table1.Student_ID) s
WHERE s.rnk = 1
Use Rank You will not miss any people for example like two people will get same highest marks in same subject. And if you want query to find 2nd highest marks or 3rd highest use Dense_Rank() function even dense_rank() also works for finding 1st highest. For More cilck here
SELECT NAME,
SUBJECT,
MARKS
FROM (SELECT NAME,
SUBJECT,
MARKS,
rank()
OVER(
PARTITION BY [SUBJECT]
ORDER BY MARKS DESC) RNO
FROM #TABLE1 T
JOIN #TABLE2 T2
ON T.ID = T2.ID) A
WHERE RNO = 1
CREATE TABLE #table1
(Student_ID INT,
Student_Name VARCHAR(20))
INSERT INTO #table1
SELECT 1,'Amal'
UNION
SELECT 2,'Varun'
UNION
SELECT 3,'Sari'
CREATE TABLE #table2
(
stud_id INT,
[subject] VARCHAR(20),
Marks_obt INT
)
INSERT INTO #table2
SELECT 1,'Maths',80
UNION
SELECT 1,'Malayalam',75
UNION
SELECT 1,'History',45
UNION
SELECT 2,'Maths',90
UNION
SELECT 2,'Malayalam',85
UNION
SELECT 2,'History',80
UNION
SELECT 3,'Maths',88
UNION
SELECT 3,'Malayalam',75
UNION
SELECT 3,'History',80
/*Table 1*/
SELECT * FROM #table1
/*Table 2*/
SELECT * FROM #table2
/*Top Mark*/
SELECT [subject],
Student_Name,
Marks_obt
FROM(SELECT Student_Name,
[subject],
Marks_obt,
RANK()
OVER(
PARTITION BY [subject]
ORDER BY Marks_obt DESC) RowNum
FROM #table1 T1
JOIN #table2 T2
ON T1.Student_ID= T2.stud_id) AS data
WHERE data.RowNum = 1
DROP TABLE #table1,#table2
you can use a cross apply too like this
with maxi as (
select Subject, max(marks) maximark from table2
group by Subject
)
select * from maxi f1
cross apply
(
select top 1 f2.name from table1 f2 inner join table2 f3 on f2.id=f3.id
where f1.maximark=f3.marks and f1.subject=f3.subject
) f3
if multiple users are possible for a maxi mark, remove "top 1"
other solution with imbication:
with maxi as (
select Subject, max(marks) maximark from table2
group by Subject
)
select (select top 1 f2.name from table1 f2 inner join table2 f3 on f2.id=f3.id where f1.maximark=f3.marks and f1.Subject=f3.Subject) as Name, f1.*
from maxi f1
Related
I have a query the following works as expected
If((Select count(*) from table1 where product = 'carrot')< 5)
Begin
Select Top (5 - (Select count(*) from table1 where product = 'carrot'))
id, product From table2
WHere id NOT IN
(Select id from table1) AND product = 'carrot'
Order by newid()
END
What i want to do is Union or Union all say another product potatoes
If((Select count(*) from table1 where product = 'potato')< 5)
Begin
Select Top (5 - (Select count(*) from table1 where product = 'potato'))
id, product From table2
WHere id NOT IN
(Select id from table1) AND product = 'potato'
Order by newid()
END
I keep getting a syntax error, when i add UNION between IF or after END. Is this possible or another way is better....
What i am doing is trying to select a random sample of carrots, first i want to check if i have the 5 carrots in table1. if i do don't run sample.
If i do not have 5 total carrots run the sampler and return 5 carrots. I then filter out if they already exist in table 1 by the id. Then it subtracts the count from the new sample for a total of five.
It works well, now i want to run for other products eg lettuce, potatoes etc...
But i want an UNION or UNION All. hope makes sense.
I'd be interested to see whether this way works-
Select Top (5 - (Select count(*) from table1 where product = 'carrots')< 5)
id
, product
From table2
WHere id NOT IN (Select id from table2)
AND (Select count(*) from table1 where product = 'carrots')< 5)
UNION ALL
Select Top (5 - (Select count(*) from table1 where product = 'potatoes')< 5)
id
, product
From table2
WHere id NOT IN (Select id from table2)
AND (Select count(*) from table1 where product = 'potatoes')< 5)
Your style is interesting, feels procedural rather than set-based.
You can try it this way
If(((Select count(*) from table1 where product = 'carrot'< 5) and (Select count(*) from table1 where product ='potato' <5))
)
Begin
Select Top (5 - (Select count(*) from table1 where product = 'carrot')) id, product
From table2
WHere id NOT IN (Select id from table1) AND product = 'carrot' Order by newid()
Union all
Select Top (5 - (Select count(*) from table1 where product = 'potato')) id, product From table2
WHere id NOT IN (Select id from table1) AND product = 'potato' Order by newid()
END
IF statements in SQL do not behave as sub-queries or row-sets in SQL, as you've found out. They are for branching the flow of control only.
Here is a more set based approach you could take:
SELECT ProdSamples.*
FROM
(
SELECT Table2.*, ROW_NUMBER() OVER (PARTITION BY table2.Product ORDER BY NEWID()) RowNum
FROM Table2
LEFT JOIN Table1
ON Table1.id = Table2.id
WHERE Table1.id IS NULL
) ProdSamples
JOIN
(
SELECT Product, COUNT(*) ProdCount
FROM Table1
GROUP BY Product
) ProdCounts
ON ProdSamples.Product = ProdCounts.Product
AND ProdSamples.RowNum <= (5 - ProdCounts.ProdCount)
The first sub-query ProdSamples returns all the products from Table2 that do not have an id in Table1. The RowNum field ranks them in random order partitioned by Product.
The second sub-query ProdCounts is the count of records for each product in Table1. Then it joins these sub-queries together and only returns the records from ProdSamples where the RowNum is lower or equal to the number of samples you want to return.
I have a select statement in which I am using in clause.
Here is my table : MyTable
Id SKU
1 112
2 223
3 445
4 456
5 678
If I write:
SELECT Id
FROM MyTable
WHERE SKU IN (112,223,445, 456, 678)
I an not getting result as
1
2
3
4
5
Is there any way to get select result based on items order in the in clause.?
For your case ORDER BY id will be sufficient.
SELECT Id
FROM MyTable
WHERE SKU IN (112,223,445, 456, 678)
ORDER BY id
For general approach you could use JOIN with derived table like:
Demo
SELECT m.Id
FROM MyTable m
JOIN (VALUES (1, 112) ,(2,223) ,(3,445), (4,456), (5,678)) AS t(num, SKU)
ON m.SKU = t.SKU
ORDER BY t.num
If you use SQL Server 2008 you can use UNION ALL:
Demo2
;WITH cte AS
(
SELECT 112 AS SKU, 1 AS orderNum
UNION ALL
SELECT 223 AS SKU, 2 AS orderNum
UNION ALL
SELECT 445 AS SKU, 3 AS orderNum
UNION ALL
SELECT 456 AS SKU, 4 AS orderNum
UNION ALL
SELECT 678 AS SKU, 5 AS orderNum
)
SELECT m.Id
FROM #MyTable m
JOIN cte c
ON m.SKU = c.SKU
ORDER BY c.orderNum;
General approach that does not force you to create custom query you could use temp table with IDENTITY column like:
Demo3
CREATE TABLE #mySKU( orderNum INT IDENTITY(1,1), SKU INT);
INSERT INTO #mySKU
VALUES (112),(223),(445), (456), (678);
SELECT m.Id
FROM #MyTable m
JOIN #mySKU c
ON m.SKU = c.SKU
ORDER BY c.orderNum;
"Is there any way to get select result based on items order in the in clause?"
For this particular question the answer is no.
I have a two tables like below
A
Id Name
1 a
2 b
B
Id Name
1 t
6 s
My requirement is to find the maximum id from table and display the name and id for that maximum without using case and if.
i findout the maximum by using below query
SELECT MAX(id)
FROM (SELECT id,name FROM A
UNION
SELECT id,name FROM B) as c
I findout the maximum 6 using the above query.but i can't able to find the name.I tried the below query but it's not working
SELECT MAX(id)
FROM (SELECT id,name FROM A
UNION
SELECT id,name FROM B) as c
How to find the name?
Any help will be greatly appreciated!!!
First combine the tables, since you need to search both. Next, determine the id you need. JOIN the id back with the temporarily created table to retreive the name that belongs to that id:
WITH tmpTable AS (
SELECT id,name FROM A
UNION
SELECT id,name FROM B
)
, max AS (
SELECT MAX(id) id
FROM tmpTable
)
SELECT t.id, t.name
FROM max m
JOIN tmpTable t ON m.id = t.id
You could use ROW_NUMBER(). You have to UNION ALL TableA and TableB first.
WITH TableA(Id, Name) AS(
SELECT 1, 'a' UNION ALL
SELECT 2, 'b'
)
,TableB(Id, Name) AS(
SELECT 1, 't' UNION ALL
SELECT 6, 's'
)
,Combined(Id, Name) AS(
SELECT * FROM TableA UNION ALL
SELECT * FROM TableB
)
,CTE AS(
SELECT *, RN = ROW_NUMBER() OVER(ORDER BY ID DESC) FROM Combined
)
SELECT Id, Name
FROM CTE
WHERE RN = 1
Just order by over the union and take first row:
SELECT TOP 1 * FROM (SELECT * FROM A UNION SELECT * FROM B) x
ORDER BY ID DESC
This won't show ties though.
For you stated that you used SQL Server 2008. Therefore,I used FULL JOIN and NESTED SELECT to get what your looking for. See below:
SELECT
(SELECT
1,
ISNULL(A.Id,B.Id)Id
FROM A FULL JOIN B ON A.Id=B.Id) AS Id,
(SELECT
1,
ISNULL(A.Name,B.Name)Name
FROM A FULL JOIN B ON A.Id=B.Id) AS Name
It's possible to use ROW_NUMBER() or DENSE_RANK() functions to get new numiration by Id, and then select value with newly created orderId equal to 1
Use:
ROW_NUMBER() to get only one value (even if there are some repetitions of max id)
DENSE_RANK() to get all equal max id values
Here is an example:
DECLARE #tb1 AS TABLE
(
Id INT
,[Name] NVARCHAR(255)
)
DECLARE #tb2 AS TABLE
(
Id INT
,[Name] NVARCHAR(255)
)
INSERT INTO #tb1 VALUES (1, 'A');
INSERT INTO #tb1 VALUES (7, 'B');
INSERT INTO #tb2 VALUES (4, 'C');
INSERT INTO #tb1 VALUES (7, 'D');
SELECT * FROM
(SELECT Id, Name, ROW_NUMBER() OVER (ORDER BY Id DESC) AS [orderId]
FROM
(SELECT Id, Name FROM #tb1
UNION
SELECT Id, Name FROM #tb2) as tb3) AS TB
WHERE [orderId] = 1
SELECT * FROM
(SELECT Id, Name, DENSE_RANK() OVER (ORDER BY Id DESC) AS [orderId]
FROM
(SELECT Id, Name FROM #tb1
UNION
SELECT Id, Name FROM #tb2) as tb3) AS TB
WHERE [orderId] = 1
Results are:
I need to select the rows with the minimum distance by grouping on the OrganisationID. Here is my data in a single table:
ID OrganisationID Distance
0 10 100
1 10 200
3 10 50
4 20 80
5 20 300
This is the result I want:
ID OrganisationID Distance
3 10 50
4 20 80
This will accomplish that:
SELECT t1.*
FROM yourTable t1
LEFT JOIN yourTable t2
ON (t1.OrganisationID = t2.OrganisationID AND t1.Distance > t2.Distance)
WHERE t2.OrganisationID IS NULL;
sqlfiddle demo
Note that if there are multiple rows with the lowest distance duplicate, this returns them both
EDIT:
If, as you say in the comments, only want one column and the MIN distance you can do it easily with MIN and GROUP BY:
SELECT city, MIN(distance)
FROM table2
GROUP BY city;
sqlfiddle demo
p.s. i saw your previous question that you deleted, and was answering it with a different thing than this (was going to tell you that since you had the organisationID in the WHERE clause, you could just do: SELECT TOP 1 ... order by Distance DESC), but if you need more it for more than one organisationID, this is something that can get you there)
This is the solution:
SELECT ID ,D.*
FROM <TABLE> INNER JOIN( SELECT OrganisationID 'OR',MIN(Distance) DI
FROM <TABLE>
GROUP BY OrganisationID) D
ON D.DI=<TABLE>.Distance
Test :
CREATE TABLE #T
(
ID INT,
OrganisationID INT,
Distance INT
)
INSERT INTO #T
SELECT 0,10,100
UNION ALL
SELECT 1,10,200
UNION ALL
SELECT 3,10,50
UNION ALL
SELECT 4,20,80
UNION ALL
SELECT 5,20,300
SELECT ID ,D.*
FROM #T INNER JOIN( SELECT OrganisationID 'OR',MIN(Distance) DI
FROM #T
GROUP BY OrganisationID) D
ON D.DI=#T.Distance
DROP TABLE #T
I have a table that has 13 columns, one with type varchar(25) and the rest with type `int (holding values for each month of the year).
For each row, I would like to pick the top 6 int values from the 12 columns and calculate the average of those values.
I know how to select the top n from a given column, but how do you do it across multiple columns?
select ID,
(
select avg(C)
from (
select top(6) C
from (values(C1),(C2),(C3),(C4),(C5),(C6),(C7),
(C8),(C9),(C10),(C11),(C12)) as T(C)
order by C desc
) as T
) as C
from YourTable
SQL Fiddle
For SQL Server 2005 it would look like this since you can't use the Table Value Constructor
select ID,
(
select avg(C)
from (
select top(6) C
from (select C1 union all
select C2 union all
select C3 union all
select C4 union all
select C5 union all
select C6 union all
select C7 union all
select C8 union all
select C9 union all
select C10 union all
select C11 union all
select C12) as T(C)
order by C desc
) as T
) as C
from YourTable
SQL Fiddle
And for SQL Server 2000 this could work for you.
select T1.ID,
avg(C) as C
from (
select ID, C1 as C from YourTable union all
select ID, C2 from YourTable union all
select ID, C3 from YourTable union all
select ID, C4 from YourTable union all
select ID, C5 from YourTable union all
select ID, C6 from YourTable union all
select ID, C7 from YourTable union all
select ID, C8 from YourTable union all
select ID, C9 from YourTable union all
select ID, C10 from YourTable union all
select ID, C11 from YourTable union all
select ID, C12 from YourTable
) as T1
where (
select count(*)
from (
select ID, C1 as C from YourTable union all
select ID, C2 from YourTable union all
select ID, C3 from YourTable union all
select ID, C4 from YourTable union all
select ID, C5 from YourTable union all
select ID, C6 from YourTable union all
select ID, C7 from YourTable union all
select ID, C8 from YourTable union all
select ID, C9 from YourTable union all
select ID, C10 from YourTable union all
select ID, C11 from YourTable union all
select ID, C12 from YourTable
) as T2
where T1.ID = T2.ID and
T1.C <= T2.C
) <= 6
group by T1.ID
SQL Fiddle
I would not expect this to be particularly fast. Perhaps a better option is to store an intermediate result in a temp table.
create table #T
(
ID varchar(25),
C int
)
insert into #T
select ID, C1 as C from YourTable union all
select ID, C2 from YourTable union all
select ID, C3 from YourTable union all
select ID, C4 from YourTable union all
select ID, C5 from YourTable union all
select ID, C6 from YourTable union all
select ID, C7 from YourTable union all
select ID, C8 from YourTable union all
select ID, C9 from YourTable union all
select ID, C10 from YourTable union all
select ID, C11 from YourTable union all
select ID, C12 from YourTable
select T1.ID,
avg(C) as C
from #T as T1
where (
select count(*)
from #T as T2
where T1.ID = T2.ID and
T1.C <= T2.C
) <= 6
group by T1.ID
drop table #T
Firstly, it is important to understand that using TOP in conjunction with aggregates will not limit the aggregation but rather the result set. Look at this example:
SELECT TOP 2 SUM(col) FROM
(SELECT 1 AS col
UNION
SELECT 2
UNION
SELECT 3)sq
The result is still "6".
Secondly, aggregation does NOT work across columns, only rows. You would need to evaluate them manually. Probably the most efficient way would be to create a table from the row like this:
SELECT
(SELECT MAX(myval) FROM (values (col1), (col2), (col3), (col4)) as all_values(myval))
FROM (SELECT 1 as col1, 2 as col2, 3 as col3, 4 as col4)sq
If you are using SQL Server 2005 or later you can unpivot the table, then rank the values, and last calculate the averages the for the top 6 values per identifier.
something like this:
;WITH UnPivoted AS (
SELECT pk, MonthID, MonthNumber, MonthValue
FROM
(SELECT pk, Month1, Month2, Month3, Month4, Month5, Month6, Month7, Month8, Month9, Month10, Month11, Month12
FROM pvt) p
UNPIVOT
(pk FOR MonthNumber IN
(Month1, Month2, Month3, Month4, Month5, Month6, Month7, Month8, Month9, Month10, Month11, Month12)
)AS unpvt
),
UnPivotedRanked AS (
SELECT pk, MonthValue, RANK() OVER(PARTITION BY pk ORDER BY MonthValue DESC) AS pkRanked
FROM UnPivoted
GROUP BY pk
)
SELECT pk, AVG(MonthValue) AS Top6Average
FROM UnPivotedRanked
WHERE pkRanked < 6
GROUP BY pk