I need to select the rows with the minimum distance by grouping on the OrganisationID. Here is my data in a single table:
ID OrganisationID Distance
0 10 100
1 10 200
3 10 50
4 20 80
5 20 300
This is the result I want:
ID OrganisationID Distance
3 10 50
4 20 80
This will accomplish that:
SELECT t1.*
FROM yourTable t1
LEFT JOIN yourTable t2
ON (t1.OrganisationID = t2.OrganisationID AND t1.Distance > t2.Distance)
WHERE t2.OrganisationID IS NULL;
sqlfiddle demo
Note that if there are multiple rows with the lowest distance duplicate, this returns them both
EDIT:
If, as you say in the comments, only want one column and the MIN distance you can do it easily with MIN and GROUP BY:
SELECT city, MIN(distance)
FROM table2
GROUP BY city;
sqlfiddle demo
p.s. i saw your previous question that you deleted, and was answering it with a different thing than this (was going to tell you that since you had the organisationID in the WHERE clause, you could just do: SELECT TOP 1 ... order by Distance DESC), but if you need more it for more than one organisationID, this is something that can get you there)
This is the solution:
SELECT ID ,D.*
FROM <TABLE> INNER JOIN( SELECT OrganisationID 'OR',MIN(Distance) DI
FROM <TABLE>
GROUP BY OrganisationID) D
ON D.DI=<TABLE>.Distance
Test :
CREATE TABLE #T
(
ID INT,
OrganisationID INT,
Distance INT
)
INSERT INTO #T
SELECT 0,10,100
UNION ALL
SELECT 1,10,200
UNION ALL
SELECT 3,10,50
UNION ALL
SELECT 4,20,80
UNION ALL
SELECT 5,20,300
SELECT ID ,D.*
FROM #T INNER JOIN( SELECT OrganisationID 'OR',MIN(Distance) DI
FROM #T
GROUP BY OrganisationID) D
ON D.DI=#T.Distance
DROP TABLE #T
Related
i had this problem where i got two tables with different values.
TABLE 1:
Description Qty Amount
Proc 1 1 100
Proc 2 1 50
Proc 3 1 60
TABLE 2:
Description Payment
Proc 1 60
Proc 1 30
Proc 2 20
Proc 3 60
Proc 2 20
So, the result should be like:
Description Balance
Proc 1 10
Proc 2 40
Proc 3 0
How will i do this with select query? thanks.
I Already tried this code but it should first get the distinct rows of TABLE1 and sum distinct values from TABLE2 before subtracting the two tables.
SELECT FEESList.[Fee Description], sum(StudentBILLING.Quantity* StudentBILLING.Total- isnull(StudReceipts.Amount,0)) as Balance
FROM StudentBILLING INNER JOIN FEESList ON StudentBILLING.FeeID = FEESList.FeeID INNER JOIN SREGStudentInformation ON StudentBILLING.StudentID = SREGStudentInformation.ID INNER JOIN
SemesterList ON StudentBILLING.SemesterID = SemesterList.SemID INNER JOIN SchoolYear ON StudentBILLING.SYid = SchoolYear.[SY ID] FULL JOIN StudReceipts ON FEESList.FeeID = StudReceipts.FeeID
WHERE (SREGStudentInformation.[Student ID] = #StudentNumber) AND (SemesterList.[Sem.] = #Sem) AND (SchoolYear.[School Year] = #SchoolYear) AND
(FEESList.[Type of Fee] = 2) AND (StudentBILLING.Quantity* StudentBILLING.Total- ISNULL(StudReceipts.Amount,0))>0
GROUP BY FEESList.[Fee Description]
The result is from this;
Description Amount Payments
Proc 1 100 60
Proc 1 100 30
Proc 2 50 20
Proc 2 50 20
Proc 3 60 60
To this result which is not supposed to be.
Description Amount
Proc 1 100
Proc 2 50
Can you help me with this?
You could try below with sample data which you have provided
First, it will generated row numbers by using row_number() function partition by Description and Payment column which has duplicate payment made & sum() if have duplicate payments made
;WITH cte AS (
SELECT *,
ROW_NUMBER() OVER(PARTITION BY [Description],
Payment ORDER BY [Description]) rn
FROM <TABLE 2>)
SELECT t.[Description],
CASE
WHEN COUNT(DISTINCT c.rn) > 1 THEN SUM(c.Payment)
ELSE MAX(t.amount) - SUM(c.Payment)
END [Balance]
FROM cte c
JOIN <TABLE 1> t ON t.[Description] = c.[Description]
GROUP BY t.[Description];
Result :
Description Balance
Proc 1 10
Proc 2 40
Proc 3 0
Note, But you could also check with your sample data what if one Description has both Payments made one is duplicate and other is unique ??
You're maths isn't correct
Proc 2 = Tabl1 50, Tab2 20+ 20 = balance = 10
DECLARE #tab1 TABLE ([Description] NVARCHAR(15), Qty INT, Amount INT )
INSERT INTO #tab1
([Description], Qty, Amount)
SELECT 'Proc 1',1,100 UNION ALL
SELECT 'Proc 2',1,50 UNION ALL
SELECT 'Proc 3',1,60
DECLARE #tab2 TABLE ([Description] NVARCHAR(15), Payment INT)
INSERT INTO #tab2
([Description], Payment)
SELECT 'Proc 1', 60 UNION ALL
SELECT 'Proc 1', 30 UNION ALL
SELECT 'Proc 2', 20 UNION ALL
SELECT 'Proc 3', 60 UNION ALL
SELECT 'Proc 2', 20
SELECT
T.[Description]
, Balance = (T.Qty * T.Amount) - X.Payment
FROM #tab1 T
INNER JOIN
(
SELECT
T.[Description]
, Payment = SUM(T.Payment)
FROM #tab2 T
GROUP BY T.[Description]
) X ON X.[Description] = T.[Description]
Left joining from a derived table will solve your issue. Alternatively you could have done it the slightly longer route by doing aggregation in a cte and then a join
select t1.description
,t1.amount - t2.sum as balance
from table1 t1
left join
(select description
,sum(payment) as sum
from table2
group by description) t2 on t1.description = t2.description
Just some food for thought:
You want to use a left join instead of an inner join. Left join says if it's in this first table and not second, show null. Inner join says show it only if it is in BOTH tables. And I'm guessing you want to show the balance even if a payment hasn't been made (just a guess but that's up to your report).
Here's the rextester sample you can play with.
I have a large table (130 columns). It is a monthly dataset that is separated by month (jan,feb,mar,...). every month I get a small set of duplicate rows. I would like to remove one of the rows, it does not matter which row to be deleted.
This query seems to work ok when I only select the ID that I want to filter the dups on, but when I select everything "*" from the table I end up with all of the rows, dups included. My goal is to filter out the dups and insert the result set into a new table.
SELECT DISTINCT a.[ID]
FROM MonthlyLoan a
JOIN (SELECT COUNT(*) as Count, b.[ID]
FROM MonthlyLoan b
GROUP BY b.[ID])
AS b ON a.[ID] = b.[ID]
WHERE b.Count > 1
and effectiveDate = '01/31/2017'
Any help will be appreciated.
This will show you all duplicates per ID:
;WITH Duplicates AS
(
SELECT ID
rn = ROW_NUMBER() OVER (PARTITION BY ID ORDER BY ID)
FROM MonthlyLoan
)
SELECT ID,
rn
FROM Duplicates
WHERE rn > 1
Alternatively, you can set rn = 2 to find the immediate duplicate per ID.
Since your ID is dupped (A DUPPED ID!!!!)
all you need it to use the HAVING clause in your aggregate.
See the below example.
declare #tableA as table
(
ID int not null
)
insert into #tableA
values
(1),(2),(2),(3),(3),(3),(4),(5)
select ID, COUNT(*) as [Count]
from #tableA
group by ID
having COUNT(*) > 1
Result:
ID Count
----------- -----------
2 2
3 3
To insert the result into a #Temporary Table:
select ID, COUNT(*) as [Count]
into #temp
from #tableA
group by ID
having COUNT(*) > 1
select * from #temp
declare #t table
(
id int,
SomeNumt int
)
insert into #t
select 1,10
union
select 2,12
union
select 3,3
union
select 4,15
union
select 5,23
select * from #t
the above select returns me the following.
id SomeNumt
1 10
2 12
3 3
4 15
5 23
How do I get the following:
id srome CumSrome
1 10 10
2 12 22
3 3 25
4 15 40
5 23 63
select t1.id, t1.SomeNumt, SUM(t2.SomeNumt) as sum
from #t t1
inner join #t t2 on t1.id >= t2.id
group by t1.id, t1.SomeNumt
order by t1.id
SQL Fiddle example
Output
| ID | SOMENUMT | SUM |
-----------------------
| 1 | 10 | 10 |
| 2 | 12 | 22 |
| 3 | 3 | 25 |
| 4 | 15 | 40 |
| 5 | 23 | 63 |
Edit: this is a generalized solution that will work across most db platforms. When there is a better solution available for your specific platform (e.g., gareth's), use it!
The latest version of SQL Server (2012) permits the following.
SELECT
RowID,
Col1,
SUM(Col1) OVER(ORDER BY RowId ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS Col2
FROM tablehh
ORDER BY RowId
or
SELECT
GroupID,
RowID,
Col1,
SUM(Col1) OVER(PARTITION BY GroupID ORDER BY RowId ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS Col2
FROM tablehh
ORDER BY RowId
This is even faster. Partitioned version completes in 34 seconds over 5 million rows for me.
Thanks to Peso, who commented on the SQL Team thread referred to in another answer.
For SQL Server 2012 onwards it could be easy:
SELECT id, SomeNumt, sum(SomeNumt) OVER (ORDER BY id) as CumSrome FROM #t
because ORDER BY clause for SUM by default means RANGE UNBOUNDED PRECEDING AND CURRENT ROW for window frame ("General Remarks" at https://msdn.microsoft.com/en-us/library/ms189461.aspx)
Let's first create a table with dummy data:
Create Table CUMULATIVESUM (id tinyint , SomeValue tinyint)
Now let's insert some data into the table;
Insert Into CUMULATIVESUM
Select 1, 10 union
Select 2, 2 union
Select 3, 6 union
Select 4, 10
Here I am joining same table (self joining)
Select c1.ID, c1.SomeValue, c2.SomeValue
From CumulativeSum c1, CumulativeSum c2
Where c1.id >= c2.ID
Order By c1.id Asc
Result:
ID SomeValue SomeValue
-------------------------
1 10 10
2 2 10
2 2 2
3 6 10
3 6 2
3 6 6
4 10 10
4 10 2
4 10 6
4 10 10
Here we go now just sum the Somevalue of t2 and we`ll get the answer:
Select c1.ID, c1.SomeValue, Sum(c2.SomeValue) CumulativeSumValue
From CumulativeSum c1, CumulativeSum c2
Where c1.id >= c2.ID
Group By c1.ID, c1.SomeValue
Order By c1.id Asc
For SQL Server 2012 and above (much better performance):
Select
c1.ID, c1.SomeValue,
Sum (SomeValue) Over (Order By c1.ID )
From CumulativeSum c1
Order By c1.id Asc
Desired result:
ID SomeValue CumlativeSumValue
---------------------------------
1 10 10
2 2 12
3 6 18
4 10 28
Drop Table CumulativeSum
A CTE version, just for fun:
;
WITH abcd
AS ( SELECT id
,SomeNumt
,SomeNumt AS MySum
FROM #t
WHERE id = 1
UNION ALL
SELECT t.id
,t.SomeNumt
,t.SomeNumt + a.MySum AS MySum
FROM #t AS t
JOIN abcd AS a ON a.id = t.id - 1
)
SELECT * FROM abcd
OPTION ( MAXRECURSION 1000 ) -- limit recursion here, or 0 for no limit.
Returns:
id SomeNumt MySum
----------- ----------- -----------
1 10 10
2 12 22
3 3 25
4 15 40
5 23 63
Late answer but showing one more possibility...
Cumulative Sum generation can be more optimized with the CROSS APPLY logic.
Works better than the INNER JOIN & OVER Clause when analyzed the actual query plan ...
/* Create table & populate data */
IF OBJECT_ID('tempdb..#TMP') IS NOT NULL
DROP TABLE #TMP
SELECT * INTO #TMP
FROM (
SELECT 1 AS id
UNION
SELECT 2 AS id
UNION
SELECT 3 AS id
UNION
SELECT 4 AS id
UNION
SELECT 5 AS id
) Tab
/* Using CROSS APPLY
Query cost relative to the batch 17%
*/
SELECT T1.id,
T2.CumSum
FROM #TMP T1
CROSS APPLY (
SELECT SUM(T2.id) AS CumSum
FROM #TMP T2
WHERE T1.id >= T2.id
) T2
/* Using INNER JOIN
Query cost relative to the batch 46%
*/
SELECT T1.id,
SUM(T2.id) CumSum
FROM #TMP T1
INNER JOIN #TMP T2
ON T1.id > = T2.id
GROUP BY T1.id
/* Using OVER clause
Query cost relative to the batch 37%
*/
SELECT T1.id,
SUM(T1.id) OVER( PARTITION BY id)
FROM #TMP T1
Output:-
id CumSum
------- -------
1 1
2 3
3 6
4 10
5 15
Select
*,
(Select Sum(SOMENUMT)
From #t S
Where S.id <= M.id)
From #t M
You can use this simple query for progressive calculation :
select
id
,SomeNumt
,sum(SomeNumt) over(order by id ROWS between UNBOUNDED PRECEDING and CURRENT ROW) as CumSrome
from #t
There is a much faster CTE implementation available in this excellent post:
http://weblogs.sqlteam.com/mladenp/archive/2009/07/28/SQL-Server-2005-Fast-Running-Totals.aspx
The problem in this thread can be expressed like this:
DECLARE #RT INT
SELECT #RT = 0
;
WITH abcd
AS ( SELECT TOP 100 percent
id
,SomeNumt
,MySum
order by id
)
update abcd
set #RT = MySum = #RT + SomeNumt
output inserted.*
For Ex: IF you have a table with two columns one is ID and second is number and wants to find out the cumulative sum.
SELECT ID,Number,SUM(Number)OVER(ORDER BY ID) FROM T
Once the table is created -
select
A.id, A.SomeNumt, SUM(B.SomeNumt) as sum
from #t A, #t B where A.id >= B.id
group by A.id, A.SomeNumt
order by A.id
The SQL solution wich combines "ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW" and "SUM" did exactly what i wanted to achieve.
Thank you so much!
If it can help anyone, here was my case. I wanted to cumulate +1 in a column whenever a maker is found as "Some Maker" (example). If not, no increment but show previous increment result.
So this piece of SQL:
SUM( CASE [rmaker] WHEN 'Some Maker' THEN 1 ELSE 0 END)
OVER
(PARTITION BY UserID ORDER BY UserID,[rrank] ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS Cumul_CNT
Allowed me to get something like this:
User 1 Rank1 MakerA 0
User 1 Rank2 MakerB 0
User 1 Rank3 Some Maker 1
User 1 Rank4 Some Maker 2
User 1 Rank5 MakerC 2
User 1 Rank6 Some Maker 3
User 2 Rank1 MakerA 0
User 2 Rank2 SomeMaker 1
Explanation of above: It starts the count of "some maker" with 0, Some Maker is found and we do +1. For User 1, MakerC is found so we dont do +1 but instead vertical count of Some Maker is stuck to 2 until next row.
Partitioning is by User so when we change user, cumulative count is back to zero.
I am at work, I dont want any merit on this answer, just say thank you and show my example in case someone is in the same situation. I was trying to combine SUM and PARTITION but the amazing syntax "ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW" completed the task.
Thanks!
Groaker
Above (Pre-SQL12) we see examples like this:-
SELECT
T1.id, SUM(T2.id) AS CumSum
FROM
#TMP T1
JOIN #TMP T2 ON T2.id < = T1.id
GROUP BY
T1.id
More efficient...
SELECT
T1.id, SUM(T2.id) + T1.id AS CumSum
FROM
#TMP T1
JOIN #TMP T2 ON T2.id < T1.id
GROUP BY
T1.id
Try this
select
t.id,
t.SomeNumt,
sum(t.SomeNumt) Over (Order by t.id asc Rows Between Unbounded Preceding and Current Row) as cum
from
#t t
group by
t.id,
t.SomeNumt
order by
t.id asc;
Try this:
CREATE TABLE #t(
[name] varchar NULL,
[val] [int] NULL,
[ID] [int] NULL
) ON [PRIMARY]
insert into #t (id,name,val) values
(1,'A',10), (2,'B',20), (3,'C',30)
select t1.id, t1.val, SUM(t2.val) as cumSum
from #t t1 inner join #t t2 on t1.id >= t2.id
group by t1.id, t1.val order by t1.id
Without using any type of JOIN cumulative salary for a person fetch by using follow query:
SELECT * , (
SELECT SUM( salary )
FROM `abc` AS table1
WHERE table1.ID <= `abc`.ID
AND table1.name = `abc`.Name
) AS cum
FROM `abc`
ORDER BY Name
I have a table that gets rewritten each night. I have two columns that need to be populated with a random number from a set list of values. Angle column needs to be populated with 15,30,45,60,90 and Distance needs to populated with 9,15,21. The insert statements may process up to 700 records.
I have tried creating a temp table (#MyRandomVal1) with
select 15 union
select 30 union
select 45 etc...
Then use (select top 1 val from #MyRandomVal1 order by newid()). This populates the column with the same random number for all rows. It seems that I might need to loop through the inserted rows so it runs (select top 1 val from #MyRandomVal1 order by newid()) for each row, however in my research I have read that Loops are not recommended. Is there another method for populating 700+ rows with a random sampling from a set list during an insert?
Below is my existing code (for angle only). SQL Server 2012.
DECLARE #MyRandomVal1 Table (
id int identity (1,1),
val int not null)
INSERT INTO #MyRandomVal1 (val)
SELECT 15
union
SELECT 30
union
SELECT 45
union
SELECT 60
union
SELECT 90
INSERT INTO MyTable (AUTO_KEY,E3_KEY,EMPID,ENAME,COLOR,ANGLE)
SELECT dbo.getautokey(),dbo.GetAutoKey(),[EMPID],[ENAME],abs(checksum(NewId()) % 256),(select top 1 val from #MyRandomVal1 order by newid())
FROM MyTable2 WHERE [JOBLEVEL]='SVP'
Thanks.
One way to do it is with a cte. Join your #MyRandomVal1 to MyTable2 on true. Add a row number that is ordered by newid(). Then get all the rownumber 1's. You'll want to check the logic in the PARTITION BY. I didn't know if there was a column that was unique. If not you may have to partition by all columns since we are joining each row to every row in the random value table.
DECLARE #MyRandomVal1 Table (
id int identity (1,1),
val int not null)
INSERT INTO #MyRandomVal1 (val)
SELECT 15
union
SELECT 30
union
SELECT 45
union
SELECT 60
union
SELECT 90
;WITH cte AS (
SELECT
dbo.getautokey() AS AUTO_KEY
, dbo.GetAutoKey() AS E3_KEY
, [EMPID]
, [ENAME]
, ABS(checksum(NewId()) % 256) AS COLOR
, a.val
, ROW_NUMBER() OVER (PARTITION BY empid ORDER BY NEWID()) AS rn
FROM MyTable2
JOIN #MyRandomVal1 a ON 1 = 1
WHERE [JOBLEVEL]='SVP')
INSERT INTO MyTable (AUTO_KEY, E3_KEY, EMPID,ENAME, COLOR, ANGLE)
SELECT * FROM cte
WHERE rn = 1
Here's a simple DEMO since we don't have example data.
I have two tables, table1 has 2 columns as
id name
1 Amal
2 Varun
3 Sari
table2 has 3 columns as
id Subject marks
1 Maths 80
1 Malayalam 75
1 History 45
2 Maths 90
2 Malayalam 85
2 History 50
3 Maths 88
3 Malayalam 75
3 History 80
My question is to find the names who has the maximum mark for each subject (Subject wisw topper) the resultant table have to includes the fields name subject and marks
I tested with the following query
SELECT
table1.Student_Name, (table2.subject), max(table2.Marks_obt)
FROM
table2
INNER JOIN
table1 ON table2.stud_id = table1.Student_ID
GROUP BY
[Student_Name], table2.Subject
HAVING
MAX(Marks_obt) IN (SELECT MAX(Marks_obt) AS total_marks
FROM table2
GROUP BY subject)
In SQL Server 2008, but I got the result as
name subject
Sari History 80
Varun Malayalam 85
Amal Maths 80
Varun Maths 90
how I get the topper of three subject with these manner?
You can use ROW_NUMBER() :
SELECT s.subject,s.name,s.marks
FROM(
SELECT t1.*,t2.subject,t2.marks,
ROW_NUMBER() OVER(PARTITION BY t2.subject ORDER BY t2.marks DESC) as rnk
FROM Table1
JOIN Table2
ON table2.stud_id = table1.Student_ID) s
WHERE s.rnk = 1
Use Rank You will not miss any people for example like two people will get same highest marks in same subject. And if you want query to find 2nd highest marks or 3rd highest use Dense_Rank() function even dense_rank() also works for finding 1st highest. For More cilck here
SELECT NAME,
SUBJECT,
MARKS
FROM (SELECT NAME,
SUBJECT,
MARKS,
rank()
OVER(
PARTITION BY [SUBJECT]
ORDER BY MARKS DESC) RNO
FROM #TABLE1 T
JOIN #TABLE2 T2
ON T.ID = T2.ID) A
WHERE RNO = 1
CREATE TABLE #table1
(Student_ID INT,
Student_Name VARCHAR(20))
INSERT INTO #table1
SELECT 1,'Amal'
UNION
SELECT 2,'Varun'
UNION
SELECT 3,'Sari'
CREATE TABLE #table2
(
stud_id INT,
[subject] VARCHAR(20),
Marks_obt INT
)
INSERT INTO #table2
SELECT 1,'Maths',80
UNION
SELECT 1,'Malayalam',75
UNION
SELECT 1,'History',45
UNION
SELECT 2,'Maths',90
UNION
SELECT 2,'Malayalam',85
UNION
SELECT 2,'History',80
UNION
SELECT 3,'Maths',88
UNION
SELECT 3,'Malayalam',75
UNION
SELECT 3,'History',80
/*Table 1*/
SELECT * FROM #table1
/*Table 2*/
SELECT * FROM #table2
/*Top Mark*/
SELECT [subject],
Student_Name,
Marks_obt
FROM(SELECT Student_Name,
[subject],
Marks_obt,
RANK()
OVER(
PARTITION BY [subject]
ORDER BY Marks_obt DESC) RowNum
FROM #table1 T1
JOIN #table2 T2
ON T1.Student_ID= T2.stud_id) AS data
WHERE data.RowNum = 1
DROP TABLE #table1,#table2
you can use a cross apply too like this
with maxi as (
select Subject, max(marks) maximark from table2
group by Subject
)
select * from maxi f1
cross apply
(
select top 1 f2.name from table1 f2 inner join table2 f3 on f2.id=f3.id
where f1.maximark=f3.marks and f1.subject=f3.subject
) f3
if multiple users are possible for a maxi mark, remove "top 1"
other solution with imbication:
with maxi as (
select Subject, max(marks) maximark from table2
group by Subject
)
select (select top 1 f2.name from table1 f2 inner join table2 f3 on f2.id=f3.id where f1.maximark=f3.marks and f1.Subject=f3.Subject) as Name, f1.*
from maxi f1