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I have...
ID SKU PRODUCT
=======================
1 FOO-23 Orange
2 BAR-23 Orange
3 FOO-24 Apple
4 FOO-25 Orange
5 FOO-25 null
6 FOO-25 null
expected result:
1 FOO-23 Orange
3 FOO-24 Apple
5 FOO-25 null
6 FOO-25 null
This query isn't getting me there. How can I SELECT DISTINCT on just one column and eliminate null in SELECT DISTINCT?
SELECT *
FROM (SELECT ID, SKU, Product,
ROW_NUMBER() OVER (PARTITION BY PRODUCT ORDER BY ID) AS RowNumber
FROM MyTable
WHERE SKU LIKE 'FOO%') AS a
WHERE a.RowNumber = 1
Perhaps one approach is using the WITH TIES in concert with a conditional PARTITION
Example
Declare #YourTable Table ([ID] int,[SKU] varchar(50),[PRODUCT] varchar(50))
Insert Into #YourTable Values
(1,'FOO-23','Orange')
,(2,'BAR-23','Orange')
,(3,'FOO-24','Apple')
,(4,'FOO-25','Orange')
,(5,'FOO-25',NULL)
,(6,'FOO-25',NULL)
Select top 1 with ties *
From #YourTable
Where SKU Like 'FOO%'
Order By Row_Number() over (Partition By IsNull(Product,NewID()) Order By ID)
Returns
ID SKU PRODUCT
6 FOO-25 NULL
5 FOO-25 NULL
3 FOO-24 Apple
1 FOO-23 Orange
Using John Cappelletti's sample data here is another approach. All you really needed was to add the OR predicate to your where clause.
Declare #YourTable Table ([ID] int,[SKU] varchar(50),[PRODUCT] varchar(50))
Insert Into #YourTable Values
(1,'FOO-23','Orange')
,(2,'BAR-23','Orange')
,(3,'FOO-24','Apple')
,(4,'FOO-25','Orange')
,(5,'FOO-25',NULL)
,(6,'FOO-25',NULL)
SELECT *
FROM
(
SELECT ID
, SKU
, Product
, ROW_NUMBER() OVER (PARTITION BY PRODUCT ORDER BY ID) AS RowNumber
FROM #YourTable
WHERE SKU LIKE 'FOO%'
) AS a
WHERE a.RowNumber = 1
OR a.PRODUCT IS NULL --This was the only part you were missing
I changed your row_number to dense rank:
Declare #YourTable Table ([ID] int,[SKU] varchar(50),[PRODUCT] varchar(50))
Insert Into #YourTable Values
(1,'FOO-23','Orange')
,(2,'BAR-23','Orange')
,(3,'FOO-24','Apple')
,(4,'FOO-25','Orange')
,(5,'FOO-25',NULL)
,(6,'FOO-25',NULL)
SELECT *
FROM (SELECT ID, SKU, Product,
Dense_RANK() OVER (PARTITION BY SKU ORDER BY Product) AS RowNumber
FROM #YourTable
WHERE left(SKU,3) = 'FOO') AS a
WHERE a.RowNumber = 1
Results:
ID SKU Product RowNumber
1 FOO-23 Orange 1
3 FOO-24 Apple 1
5 FOO-25 NULL 1
6 FOO-25 NULL 1
I have below data set in SQL Server and I need to select the data with conditions in order below:
First, check to see if date_end is 1/1/2099, then select the row that has smallest days gap and skill_group is not SWAT for rows have same employee_id, in this case that is row 2.
Second, for rows that do not have 1/1/2099 date_end, select row that has most recent day date_end, in this case it's row 4.
ID employee_id last_name first_name date_start date_end skill_group
---------------------------------------------------------------------------
1 N05E0F Mike Pamela 12/19/2013 1/1/2099 SWAT
2 N05E0F Mike Pamela 9/16/2015 1/1/2099 Welcome Team
3 NSH8A David Smith 12/19/2013 9/16/2016 Unlicensed
4 NSH8A David Smith 8/16/2015 10/16/2016 CMT
There are many ways to do this. Here are some of them:
top with ties version:
select top 1 with ties
*
from tbl
where skill_group != 'SWAT'
order by
row_number() over (
partition by employee_id
order by date_end desc, datediff(day,date_start,date_end) asc
)
with common_table_expression as () using row_number() version:
with cte as (
select *
, rn = row_number() over (
partition by employee_id
order by date_end desc, datediff(day,date_start,date_end) asc
)
from tbl
where skill_group != 'SWAT'
)
select *
from cte
where rn = 1
I have a table like this :
Table1:
[Id] [TDate] [Score]
1 1.1.00 50
1 1.1.00 60
2 1.1.01 50
2 1.1.01 70
2 1.3.01 40
3 1.1.00 80
3 1.1.00 30
3 1.2.00 40
My desired output should be like this:
[ID] [TDate] [Score]
1 1.1.00 60
2 1.1.01 70
2 1.3.01 40
3 1.1.00 80
3 1.2.00 40
So fare, I have written this:
SELECT DISTINCT TOP 2 Id, TDate, Score
FROM
( SELECT Id, TDate, Score, ROW_NUMBER() over(partition by TDate order by Score) Od
FROM Table1
) A
WHERE A.Od = 1
ORDER BY Score
But it gives me :
[ID] [TDate] [Score]
2 1.1.01 70
3 1.1.00 80
of course I can do this:
"select top 2 ...where ID = 1"
and then:
union
`"Select top 2 ... where ID = 2"`
etc..
but I have a 100,000 of this..
Any way to generalize it to any Id?
Thank you.
WITH TOPTWO AS (
SELECT Id, TDate, Score, ROW_NUMBER()
over (
PARTITION BY TDate
order by SCORE
) AS RowNo
FROM [table_name]
)
SELECT * FROM TOPTWO WHERE RowNo <= 2
Your output doesn't make sense. Let me assume you want two rows per id. Then the query would look like:
SELECT TOP 2 Id, TDate, Score
FROM (SELECT Id, TDate, Score,
ROW_NUMBER() over (partition by id order by Score DESC) as seqnum
FROM Table1
) t
WHERE seqnum <= 2
ORDER BY Score;
Notes:
This assumes that you want two rows per id. Hence, id is in the PARTITION BY.
The WHERE now selects two rows per group in the PARTITION BY.
There is no need for SELECT DISTINCT in the outer query -- at least for this question.
Try this : Make partition by ID and TDate and sort by score in descending order
ROW_NUMBER() over(partition by ID,TDate order by Score DESC) Od
Complete script
WITH CTE AS(
SELECT *,
ROW_NUMBER() over(partition by ID,TDate order by Score DESC) RN
FROM TableName
)
SELECT *
FROM CTE
WHERE RN = 1
Unless I am missing something this can be done with a simple group by
First I prepare a temp table for testing :
declare #table table (ID int, TDate varchar(10), Score int)
insert into #Table values(1, '1.1.00', 50)
insert into #Table values(1, '1.1.00', 60)
insert into #Table values(2, '1.1.01', 50)
insert into #Table values(2, '1.1.01', 70)
insert into #Table values(2, '1.3.01', 40)
insert into #Table values(3, '1.1.00', 80)
insert into #Table values(3, '1.1.00', 30)
insert into #Table values(3, '1.2.00', 40)
Now lets do a select on this table
select ID, TDate, max(Score) as Score
from #table
group by ID, TDate
order by ID, TDate
The result is this :
ID TDate Score
1 1.1.00 60
2 1.1.01 70
2 1.3.01 40
3 1.1.00 80
3 1.2.00 40
So all you need to do is change #table to your table name and you are done
I have table like this:
id_Seq_No emp_name Current_Property_value
-----------------------------------------------
1 John 100
2 Peter 200
3 Pollard 50
4 John 500
I want the max record value of particular employee.
For example, John has 2 records seq_no 1, 4. I want 4th seq_no Current_Property_Value in single query.
Select
max(id_Seq_No)
from
t1
where
emp_name = 'John'
To get the Current_Property_value, just order the results by id_Seq_No and get the first one:
SELECT
TOP 1 Current_Property_value
FROM
table
WHERE
emp_name = 'John'
ORDER BY
id_Seq_No DESC
this will give highest for all tied employees
select top 1 with ties
id_Seq_No,emp_name,Current_Property_value
from
table
order by
row_number() over (partition by emp_name order by Current_Property_value desc)
You can use ROW_NUMBER with CTE.
Query
;WITH CTE AS(
SELECT rn = ROW_NUMBER() OVER(
PARTITION BY emp_name
ORDER BY id_Seq_No DESC
), *
FROM your_table_name
WHERE emp_name = 'John'
)
SELECT * FROM CTE
WHERE rn = 1;
I have a problem using RANK() in SQL Server.
Here’s my code:
SELECT contendernum,
totals,
RANK() OVER (PARTITION BY ContenderNum ORDER BY totals ASC) AS xRank
FROM (
SELECT ContenderNum,
SUM(Criteria1+Criteria2+Criteria3+Criteria4) AS totals
FROM Cat1GroupImpersonation
GROUP BY ContenderNum
) AS a
The results for that query are:
contendernum totals xRank
1 196 1
2 181 1
3 192 1
4 181 1
5 179 1
What my desired result is:
contendernum totals xRank
1 196 1
2 181 3
3 192 2
4 181 3
5 179 4
I want to rank the result based on totals. If there are same value like 181, then two numbers will have the same xRank.
Change:
RANK() OVER (PARTITION BY ContenderNum ORDER BY totals ASC) AS xRank
to:
RANK() OVER (ORDER BY totals DESC) AS xRank
Have a look at this example:
SQL Fiddle DEMO
You might also want to have a look at the difference between RANK (Transact-SQL) and DENSE_RANK (Transact-SQL):
RANK (Transact-SQL)
If two or more rows tie for a rank, each tied rows receives the same
rank. For example, if the two top salespeople have the same SalesYTD
value, they are both ranked one. The salesperson with the next highest
SalesYTD is ranked number three, because there are two rows that are
ranked higher. Therefore, the RANK function does not always return
consecutive integers.
DENSE_RANK (Transact-SQL)
Returns the rank of rows within the partition of a result set, without
any gaps in the ranking. The rank of a row is one plus the number of
distinct ranks that come before the row in question.
To answer your question title, "How to use Rank() in SQL Server," this is how it works:
I will use this set of data as an example:
create table #tmp
(
column1 varchar(3),
column2 varchar(5),
column3 datetime,
column4 int
)
insert into #tmp values ('AAA', 'SKA', '2013-02-01 00:00:00', 10)
insert into #tmp values ('AAA', 'SKA', '2013-01-31 00:00:00', 15)
insert into #tmp values ('AAA', 'SKB', '2013-01-31 00:00:00', 20)
insert into #tmp values ('AAA', 'SKB', '2013-01-15 00:00:00', 5)
insert into #tmp values ('AAA', 'SKC', '2013-02-01 00:00:00', 25)
You have a partition which basically specifies grouping.
In this example, if you partition by column2, the rank function will create ranks for groups of column2 values. There will be different ranks for rows where column2 = 'SKA' than rows where column2 = 'SKB' and so on.
The ranks are decided like this:
The rank for every record is one plus the number of ranks that come before it in its partition. The rank will only increment when one of the fields you selected (other than the partitioned field(s)) is different than the ones that come before it. If all of the selected fields are the same, then the ranks will tie and both will be assigned the value, one.
Knowing this, if we only wanted to select one value from each group in column two, we could use this query:
with cte as
(
select *,
rank() over (partition by column2
order by column3) rnk
from t
) select * from cte where rnk = 1 order by column3;
Result:
COLUMN1 | COLUMN2 | COLUMN3 |COLUMN4 | RNK
------------------------------------------------------------------------------
AAA | SKB | January, 15 2013 00:00:00+0000 |5 | 1
AAA | SKA | January, 31 2013 00:00:00+0000 |15 | 1
AAA | SKC | February, 01 2013 00:00:00+0000 |25 | 1
SQL DEMO
You have to use DENSE_RANK rather than RANK. The only difference is that it doesn't leave gaps. You also shouldn't partition by contender_num, otherwise you're ranking each contender in a separate group, so each is 1st-ranked in their segregated groups!
SELECT contendernum,totals, DENSE_RANK() OVER (ORDER BY totals desc) AS xRank FROM
(
SELECT ContenderNum ,SUM(Criteria1+Criteria2+Criteria3+Criteria4) AS totals
FROM dbo.Cat1GroupImpersonation
GROUP BY ContenderNum
) AS a
order by contendernum
A hint for using StackOverflow, please post DDL and sample data so people can help you using less of their own time!
create table Cat1GroupImpersonation (
contendernum int,
criteria1 int,
criteria2 int,
criteria3 int,
criteria4 int);
insert Cat1GroupImpersonation select
1,196,0,0,0 union all select
2,181,0,0,0 union all select
3,192,0,0,0 union all select
4,181,0,0,0 union all select
5,179,0,0,0;
DENSE_RANK() is a rank with no gaps, i.e. it is “dense”.
select Name,EmailId,salary,DENSE_RANK() over(order by salary asc) from [dbo].[Employees]
RANK()-It contain gap between the rank.
select Name,EmailId,salary,RANK() over(order by salary asc) from [dbo].[Employees]
You have already grouped by ContenderNum, no need to partition again by it.
Use Dense_rank()and order by totals desc.
In short,
SELECT contendernum,totals, **DENSE_RANK()**
OVER (ORDER BY totals **DESC**)
AS xRank
FROM
(
SELECT ContenderNum ,SUM(Criteria1+Criteria2+Criteria3+Criteria4) AS totals
FROM dbo.Cat1GroupImpersonation
GROUP BY ContenderNum
) AS a
SELECT contendernum,totals, RANK() OVER (ORDER BY totals ASC) AS xRank FROM
(
SELECT ContenderNum ,SUM(Criteria1+Criteria2+Criteria3+Criteria4) AS totals
FROM dbo.Cat1GroupImpersonation
GROUP BY ContenderNum
) AS a
RANK() is good, but it assigns the same rank for equal or similar values. And if you need unique rank, then ROW_NUMBER() solves this problem
ROW_NUMBER() OVER (ORDER BY totals DESC) AS xRank
Select T.Tamil, T.English, T.Maths, T.Total, Dense_Rank()Over(Order by T.Total Desc) as Std_Rank From (select Tamil,English,Maths,(Tamil+English+Maths) as Total From Student) as T
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