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#include <stdio.h>
int main(){
char c;
while((c = getchar()) != EOF){
if(c >= 'A' && c <= 'Z')
c = c - 'A' + 'a';
putchar(c);
}
return 0;
}
Came across this C code in MIT's Practical Programming in C. Can anyone explain how this program works?
The program converts any input into lower case output.
You would have recognized this yourself, if you ran it, debugged it, or just made a paper test for this.
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Code:
#include <stdio.h>
#define puts "%s C preprocessor"
int main()
{
printf(puts, puts);
return 0;
}
Output:
%s C preprocessor C preprocessor
See also...
Can anyone explain me the logic behind this output?
I tried to solve it,but I didn't get the proper explanation through my friends. If anyone can explain me ,it'll be very helpful.
The macro let to (code after linker):
int main
{
printf("%s C preprocessor", "%s C preprocessor");
return 0;
}
printf works like:
The output is then
%s C preprocessor C preprocessor
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151A codeforces link
Here is my code written in C language. It has some problem
#include<stdio.h>
#include<conio.h>
int main ()
{
int n,k,l,c,d,p,nl,np,mm,per,tl,to,sum;
scanf("%d%d%d%d%d%d%d%d",&n,&k,&l,&c,&d,&p,&nl,&np);
mm = k*l;
per = mm/nl;
tl = c*d;
to = p/np;
sum=(per,tl,to)/n;
printf("%d",sum);
return 0;
}
You have to find the minimum value among per, tl, and to and divide that with n instead of just calculating to/n, which you are currently calculating with sum=(per,tl,to)/n;. (per and tl are ignored according to the definition of the comma operator)
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Code written in c language trying to get desired output but else condition is not running
#include<stdio.h>
int main()
{
int i;
if (i <= 10)
{
for (scanf("%d", &i);i<=10;i++)
{
printf("%d\n",i);
}
}
else
{
printf("Please enter a valid number");
}
}
You are not initialized your variable named i. You must have to initialize it before using.
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Can anyone please provide me the code in c programming language of problem in which we enter "ABCD" as an input in run time and we get "ZYXW" as output and I tried to solve this using ASCII Code
Hope this will help you . Read about ascii code of character . Also you have to gain knowledge of pointer and string .
#include<stdio.h>
int main(){
char ch[20];
scanf("%s",ch);
for(const char *s = ch; *s; ++s)
putchar('Z'-(*s-'A'));
return 0;
}
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Closed 9 years ago.
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I have following C program and I am not understanding some point of this program
#include <stdio.h>
int main()
{
char ara[100];
while(NULL != gets(ara))
{
printf("%s\n", ara);
}
return 0;
}
If I input some string like Hello World, this code return me the output same as input. But, what is NULL and gets?? Are they from C library? Why their colour not changed when I compile them?
Please read description of function gets()!
This function reads string from stdin. It returns NULL if found end of line or end of file before any characters.