I have 3 arrays. The first one contains strings considered as "forbidden".
The second one contains random words (initially a message) where some of these words can be referenced in the first array.
And the third array contains numbers.
What I want to do is first to compare the two first arrays to check what words in my message (second array) are "forbidden" words (first array), and then, adding to a variable the numbers of the third array that actually correspond to the forbidden words as follows:
array1: dog cat horse
array3: 40 60 10
array2: I like my dog
I think I managed to achieve the first step with this piece of script:
array1=(dog cat horse)
array2=(I like my dog)
array3=(40 60 10)
myarray=()
for item1 in "${array1[#]}"; do
for item2 in "${array2[#]}"; do
if [[ $item1 == $item2 ]]; then
myarray+=( $item1 )
break
fi
done
done
echo ${myarray[#]}
Result:
dog
But I still can't find a way to include my third array and extract the numbers that have the same indice as the forbidden words in the first array concerned by the message.
You want to iterate over the indices of the array, not the array elements:
sum=0
for i in "${!array1[#]}"; do # note the `!` there
forbidden=${array[i]}
for word in "${array2[#]}"; do
if [[ "$word" == "$forbidden" ]]; then
(( sum += ${array3[i]} ))
fi
done
done
echo $sum
Another approach is to use an associative array: That maps the animal to the value quite directly as opposed to 2 separate arrays. As a bonus, it does not require nested loops.
declare -A forbidden=([dog]=40 [cat]=60 [horse]=10)
message=(I like my dog)
sum=0
for word in "${message[#]}"; do
if [[ -n "${forbidden[$word]}" ]]; then
(( sum += ${forbidden[$word]} ))
fi
done
You should try to use more descriptive variable names than array1 etc
I need to remove an element from an array in bash shell.
Generally I'd simply do:
array=("${(#)array:#<element to remove>}")
Unfortunately the element I want to remove is a variable so I can't use the previous command.
Down here an example:
array+=(pluto)
array+=(pippo)
delete=(pluto)
array( ${array[#]/$delete} ) -> but clearly doesn't work because of {}
Any idea?
The following works as you would like in bash and zsh:
$ array=(pluto pippo)
$ delete=pluto
$ echo ${array[#]/$delete}
pippo
$ array=( "${array[#]/$delete}" ) #Quotes when working with strings
If need to delete more than one element:
...
$ delete=(pluto pippo)
for del in ${delete[#]}
do
array=("${array[#]/$del}") #Quotes when working with strings
done
Caveat
This technique actually removes prefixes matching $delete from the elements, not necessarily whole elements.
Update
To really remove an exact item, you need to walk through the array, comparing the target to each element, and using unset to delete an exact match.
array=(pluto pippo bob)
delete=(pippo)
for target in "${delete[#]}"; do
for i in "${!array[#]}"; do
if [[ ${array[i]} = $target ]]; then
unset 'array[i]'
fi
done
done
Note that if you do this, and one or more elements is removed, the indices will no longer be a continuous sequence of integers.
$ declare -p array
declare -a array=([0]="pluto" [2]="bob")
The simple fact is, arrays were not designed for use as mutable data structures. They are primarily used for storing lists of items in a single variable without needing to waste a character as a delimiter (e.g., to store a list of strings which can contain whitespace).
If gaps are a problem, then you need to rebuild the array to fill the gaps:
for i in "${!array[#]}"; do
new_array+=( "${array[i]}" )
done
array=("${new_array[#]}")
unset new_array
You could build up a new array without the undesired element, then assign it back to the old array. This works in bash:
array=(pluto pippo)
new_array=()
for value in "${array[#]}"
do
[[ $value != pluto ]] && new_array+=($value)
done
array=("${new_array[#]}")
unset new_array
This yields:
echo "${array[#]}"
pippo
This is the most direct way to unset a value if you know it's position.
$ array=(one two three)
$ echo ${#array[#]}
3
$ unset 'array[1]'
$ echo ${array[#]}
one three
$ echo ${#array[#]}
2
This answer is specific to the case of deleting multiple values from large arrays, where performance is important.
The most voted solutions are (1) pattern substitution on an array, or (2) iterating over the array elements. The first is fast, but can only deal with elements that have distinct prefix, the second has O(n*k), n=array size, k=elements to remove. Associative array are relative new feature, and might not have been common when the question was originally posted.
For the exact match case, with large n and k, possible to improve performance from O(nk) to O(n+klog(k)). In practice, O(n) assuming k much lower than n. Most of the speed up is based on using associative array to identify items to be removed.
Performance (n-array size, k-values to delete). Performance measure seconds of user time
N K New(seconds) Current(seconds) Speedup
1000 10 0.005 0.033 6X
10000 10 0.070 0.348 5X
10000 20 0.070 0.656 9X
10000 1 0.043 0.050 -7%
As expected, the current solution is linear to N*K, and the fast solution is practically linear to K, with much lower constant. The fast solution is slightly slower vs the current solution when k=1, due to additional setup.
The 'Fast' solution: array=list of input, delete=list of values to remove.
declare -A delk
for del in "${delete[#]}" ; do delk[$del]=1 ; done
# Tag items to remove, based on
for k in "${!array[#]}" ; do
[ "${delk[${array[$k]}]-}" ] && unset 'array[k]'
done
# Compaction
array=("${array[#]}")
Benchmarked against current solution, from the most-voted answer.
for target in "${delete[#]}"; do
for i in "${!array[#]}"; do
if [[ ${array[i]} = $target ]]; then
unset 'array[i]'
fi
done
done
array=("${array[#]}")
Here's a one-line solution with mapfile:
$ mapfile -d $'\0' -t arr < <(printf '%s\0' "${arr[#]}" | grep -Pzv "<regexp>")
Example:
$ arr=("Adam" "Bob" "Claire"$'\n'"Smith" "David" "Eve" "Fred")
$ echo "Size: ${#arr[*]} Contents: ${arr[*]}"
Size: 6 Contents: Adam Bob Claire
Smith David Eve Fred
$ mapfile -d $'\0' -t arr < <(printf '%s\0' "${arr[#]}" | grep -Pzv "^Claire\nSmith$")
$ echo "Size: ${#arr[*]} Contents: ${arr[*]}"
Size: 5 Contents: Adam Bob David Eve Fred
This method allows for great flexibility by modifying/exchanging the grep command and doesn't leave any empty strings in the array.
Partial answer only
To delete the first item in the array
unset 'array[0]'
To delete the last item in the array
unset 'array[-1]'
To expand on the above answers, the following can be used to remove multiple elements from an array, without partial matching:
ARRAY=(one two onetwo three four threefour "one six")
TO_REMOVE=(one four)
TEMP_ARRAY=()
for pkg in "${ARRAY[#]}"; do
for remove in "${TO_REMOVE[#]}"; do
KEEP=true
if [[ ${pkg} == ${remove} ]]; then
KEEP=false
break
fi
done
if ${KEEP}; then
TEMP_ARRAY+=(${pkg})
fi
done
ARRAY=("${TEMP_ARRAY[#]}")
unset TEMP_ARRAY
This will result in an array containing:
(two onetwo three threefour "one six")
Here's a (probably very bash-specific) little function involving bash variable indirection and unset; it's a general solution that does not involve text substitution or discarding empty elements and has no problems with quoting/whitespace etc.
delete_ary_elmt() {
local word=$1 # the element to search for & delete
local aryref="$2[#]" # a necessary step since '${!$2[#]}' is a syntax error
local arycopy=("${!aryref}") # create a copy of the input array
local status=1
for (( i = ${#arycopy[#]} - 1; i >= 0; i-- )); do # iterate over indices backwards
elmt=${arycopy[$i]}
[[ $elmt == $word ]] && unset "$2[$i]" && status=0 # unset matching elmts in orig. ary
done
return $status # return 0 if something was deleted; 1 if not
}
array=(a 0 0 b 0 0 0 c 0 d e 0 0 0)
delete_ary_elmt 0 array
for e in "${array[#]}"; do
echo "$e"
done
# prints "a" "b" "c" "d" in lines
Use it like delete_ary_elmt ELEMENT ARRAYNAME without any $ sigil. Switch the == $word for == $word* for prefix matches; use ${elmt,,} == ${word,,} for case-insensitive matches; etc., whatever bash [[ supports.
It works by determining the indices of the input array and iterating over them backwards (so deleting elements doesn't screw up iteration order). To get the indices you need to access the input array by name, which can be done via bash variable indirection x=1; varname=x; echo ${!varname} # prints "1".
You can't access arrays by name like aryname=a; echo "${$aryname[#]}, this gives you an error. You can't do aryname=a; echo "${!aryname[#]}", this gives you the indices of the variable aryname (although it is not an array). What DOES work is aryref="a[#]"; echo "${!aryref}", which will print the elements of the array a, preserving shell-word quoting and whitespace exactly like echo "${a[#]}". But this only works for printing the elements of an array, not for printing its length or indices (aryref="!a[#]" or aryref="#a[#]" or "${!!aryref}" or "${#!aryref}", they all fail).
So I copy the original array by its name via bash indirection and get the indices from the copy. To iterate over the indices in reverse I use a C-style for loop. I could also do it by accessing the indices via ${!arycopy[#]} and reversing them with tac, which is a cat that turns around the input line order.
A function solution without variable indirection would probably have to involve eval, which may or may not be safe to use in that situation (I can't tell).
Using unset
To remove an element at particular index, we can use unset and then do copy to another array. Only just unset is not required in this case. Because unset does not remove the element it just sets null string to the particular index in array.
declare -a arr=('aa' 'bb' 'cc' 'dd' 'ee')
unset 'arr[1]'
declare -a arr2=()
i=0
for element in "${arr[#]}"
do
arr2[$i]=$element
((++i))
done
echo "${arr[#]}"
echo "1st val is ${arr[1]}, 2nd val is ${arr[2]}"
echo "${arr2[#]}"
echo "1st val is ${arr2[1]}, 2nd val is ${arr2[2]}"
Output is
aa cc dd ee
1st val is , 2nd val is cc
aa cc dd ee
1st val is cc, 2nd val is dd
Using :<idx>
We can remove some set of elements using :<idx> also. For example if we want to remove 1st element we can use :1 as mentioned below.
declare -a arr=('aa' 'bb' 'cc' 'dd' 'ee')
arr2=("${arr[#]:1}")
echo "${arr2[#]}"
echo "1st val is ${arr2[1]}, 2nd val is ${arr2[2]}"
Output is
bb cc dd ee
1st val is cc, 2nd val is dd
http://wiki.bash-hackers.org/syntax/pe#substring_removal
${PARAMETER#PATTERN} # remove from beginning
${PARAMETER##PATTERN} # remove from the beginning, greedy match
${PARAMETER%PATTERN} # remove from the end
${PARAMETER%%PATTERN} # remove from the end, greedy match
In order to do a full remove element, you have to do an unset command with an if statement. If you don't care about removing prefixes from other variables or about supporting whitespace in the array, then you can just drop the quotes and forget about for loops.
See example below for a few different ways to clean up an array.
options=("foo" "bar" "foo" "foobar" "foo bar" "bars" "bar")
# remove bar from the start of each element
options=("${options[#]/#"bar"}")
# options=("foo" "" "foo" "foobar" "foo bar" "s" "")
# remove the complete string "foo" in a for loop
count=${#options[#]}
for ((i = 0; i < count; i++)); do
if [ "${options[i]}" = "foo" ] ; then
unset 'options[i]'
fi
done
# options=( "" "foobar" "foo bar" "s" "")
# remove empty options
# note the count variable can't be recalculated easily on a sparse array
for ((i = 0; i < count; i++)); do
# echo "Element $i: '${options[i]}'"
if [ -z "${options[i]}" ] ; then
unset 'options[i]'
fi
done
# options=("foobar" "foo bar" "s")
# list them with select
echo "Choose an option:"
PS3='Option? '
select i in "${options[#]}" Quit
do
case $i in
Quit) break ;;
*) echo "You selected \"$i\"" ;;
esac
done
Output
Choose an option:
1) foobar
2) foo bar
3) s
4) Quit
Option?
Hope that helps.
There is also this syntax, e.g. if you want to delete the 2nd element :
array=("${array[#]:0:1}" "${array[#]:2}")
which is in fact the concatenation of 2 tabs. The first from the index 0 to the index 1 (exclusive) and the 2nd from the index 2 to the end.
POSIX shell script does not have arrays.
So most probably you are using a specific dialect such as bash, korn shells or zsh.
Therefore, your question as of now cannot be answered.
Maybe this works for you:
unset array[$delete]
What I do is:
array="$(echo $array | tr ' ' '\n' | sed "/itemtodelete/d")"
BAM, that item is removed.
This is a quick-and-dirty solution that will work in simple cases but will break if (a) there are regex special characters in $delete, or (b) there are any spaces at all in any items. Starting with:
array+=(pluto)
array+=(pippo)
delete=(pluto)
Delete all entries exactly matching $delete:
array=(`echo $array | fmt -1 | grep -v "^${delete}$" | fmt -999999`)
resulting in
echo $array -> pippo, and making sure it's an array:
echo $array[1] -> pippo
fmt is a little obscure: fmt -1 wraps at the first column (to put each item on its own line. That's where the problem arises with items in spaces.) fmt -999999 unwraps it back to one line, putting back the spaces between items. There are other ways to do that, such as xargs.
Addendum: If you want to delete just the first match, use sed, as described here:
array=(`echo $array | fmt -1 | sed "0,/^${delete}$/{//d;}" | fmt -999999`)
Actually, I just noticed that the shell syntax somewhat has a behavior built-in that allows for easy reconstruction of the array when, as posed in the question, an item should be removed.
# let's set up an array of items to consume:
x=()
for (( i=0; i<10; i++ )); do
x+=("$i")
done
# here, we consume that array:
while (( ${#x[#]} )); do
i=$(( $RANDOM % ${#x[#]} ))
echo "${x[i]} / ${x[#]}"
x=("${x[#]:0:i}" "${x[#]:i+1}")
done
Notice how we constructed the array using bash's x+=() syntax?
You could actually add more than one item with that, the content of a whole other array at once.
In ZSH this is dead easy (note this uses more bash compatible syntax than necessary where possible for ease of understanding):
# I always include an edge case to make sure each element
# is not being word split.
start=(one two three 'four 4' five)
work=(${(#)start})
idx=2
val=${work[idx]}
# How to remove a single element easily.
# Also works for associative arrays (at least in zsh)
work[$idx]=()
echo "Array size went down by one: "
[[ $#work -eq $(($#start - 1)) ]] && echo "OK"
echo "Array item "$val" is now gone: "
[[ -z ${work[(r)$val]} ]] && echo OK
echo "Array contents are as expected: "
wanted=("${start[#]:0:1}" "${start[#]:2}")
[[ "${(j.:.)wanted[#]}" == "${(j.:.)work[#]}" ]] && echo "OK"
echo "-- array contents: start --"
print -l -r -- "-- $#start elements" ${(#)start}
echo "-- array contents: work --"
print -l -r -- "-- $#work elements" "${work[#]}"
Results:
Array size went down by one:
OK
Array item two is now gone:
OK
Array contents are as expected:
OK
-- array contents: start --
-- 5 elements
one
two
three
four 4
five
-- array contents: work --
-- 4 elements
one
three
four 4
five
To avoid conflicts with array index using unset - see https://stackoverflow.com/a/49626928/3223785 and https://stackoverflow.com/a/47798640/3223785 for more information - reassign the array to itself: ARRAY_VAR=(${ARRAY_VAR[#]}).
#!/bin/bash
ARRAY_VAR=(0 1 2 3 4 5 6 7 8 9)
unset ARRAY_VAR[5]
unset ARRAY_VAR[4]
ARRAY_VAR=(${ARRAY_VAR[#]})
echo ${ARRAY_VAR[#]}
A_LENGTH=${#ARRAY_VAR[*]}
for (( i=0; i<=$(( $A_LENGTH -1 )); i++ )) ; do
echo ""
echo "INDEX - $i"
echo "VALUE - ${ARRAY_VAR[$i]}"
done
exit 0
[Ref.: https://tecadmin.net/working-with-array-bash-script/ ]
How about something like:
array=(one two three)
array_t=" ${array[#]} "
delete=one
array=(${array_t// $delete / })
unset array_t
#/bin/bash
echo "# define array with six elements"
arr=(zero one two three 'four 4' five)
echo "# unset by index: 0"
unset -v 'arr[0]'
for i in ${!arr[*]}; do echo "arr[$i]=${arr[$i]}"; done
arr_delete_by_content() { # value to delete
for i in ${!arr[*]}; do
[ "${arr[$i]}" = "$1" ] && unset -v 'arr[$i]'
done
}
echo "# unset in global variable where value: three"
arr_delete_by_content three
for i in ${!arr[*]}; do echo "arr[$i]=${arr[$i]}"; done
echo "# rearrange indices"
arr=( "${arr[#]}" )
for i in ${!arr[*]}; do echo "arr[$i]=${arr[$i]}"; done
delete_value() { # value arrayelements..., returns array decl.
local e val=$1; new=(); shift
for e in "${#}"; do [ "$val" != "$e" ] && new+=("$e"); done
declare -p new|sed 's,^[^=]*=,,'
}
echo "# new array without value: two"
declare -a arr="$(delete_value two "${arr[#]}")"
for i in ${!arr[*]}; do echo "arr[$i]=${arr[$i]}"; done
delete_values() { # arraydecl values..., returns array decl. (keeps indices)
declare -a arr="$1"; local i v; shift
for v in "${#}"; do
for i in ${!arr[*]}; do
[ "$v" = "${arr[$i]}" ] && unset -v 'arr[$i]'
done
done
declare -p arr|sed 's,^[^=]*=,,'
}
echo "# new array without values: one five (keep indices)"
declare -a arr="$(delete_values "$(declare -p arr|sed 's,^[^=]*=,,')" one five)"
for i in ${!arr[*]}; do echo "arr[$i]=${arr[$i]}"; done
# new array without multiple values and rearranged indices is left to the reader
Imagine I created an array like this:
IFS="|" read -ra ARR <<< "zero|one|||four"
now
echo ${#ARR[#]}
> 5
echo "${ARR[#]}"
> zero one four
echo "${ARR[0]}"
> zero
echo "${ARR[2]}"
> # Nothing, because it is empty
The question is how can I replace the empty elements with another string?
I have tried
${ARR[#]///other}
${ARR[#]//""/other}
none of them worked.
I want this as output:
zero one other other four
To have the shell expansion behave, you need to loop through its elements and perform the replacement on each one of them:
$ IFS="|" read -ra ARR <<< "zero|one|||four"
$ for i in "${ARR[#]}"; do echo "${i:-other}"; done
zero
one
other
other
four
Where:
${parameter:-word}
If parameter is unset or null, the expansion of word is substituted. Otherwise, the value of parameter is substituted.
To store them in a new array, just do so by appending with +=( element ):
$ new=()
$ for i in "${ARR[#]}"; do new+=("${i:-other}"); done
$ printf "%s\n" "${new[#]}"
zero
one
other
other
four
If you want to replace all empty values (actually modifying the list), you could do this :
for i in "${!ARR[#]}" ; do ARR[$i]="${ARR[$i]:-other}"; done
Which looks like this when indented (more readable I would say) :
for i in "${!ARR[#]}"
do
ARR[$i]="${ARR[$i]:-other}"
done
# Temporary array initialization
NEW=()
# Loop over the array, add only non-empty values to the new array
for i in "${ARR[#]}"; do
# Skip null items
if [ -z "$i" ]; then
continue
fi
# Add the rest of the elements to an array
NEW+=("${i}")
done
# Reinitialize your array
ARR=(${NEW[#]})
I am looking to append each element of a bash array with | except the last one.
array=("element1" "element2" "element3")
My desired output would be
array=("element1"|"element2"|"element3")
What I have done
for i in ${!array[#]};
do
array1+=( "${array[$i]}|" )
done
Followed by
array=echo ${array1[#]}|sed 's/|$//'
Is there any other looping approach I can use that only appends the character until the last but one element?
For your special case, where only one single character has to be inserted between each array member, the simplest solution is probably to use array expansion (and changing the separation character IFS according to your need beforehand):
$ array=("element1" "element2" "element3")
$ array=( $( IFS="|" ; echo "${array[*]}") )
$ echo "\$array[0] is '${array[0]}'"
$array[0] is 'element1|element2|element3'
You can use:
# append | all except last element
read -ra array < <( printf "%s|" "${array[#]:0:$((${#array[#]} - 1))}"; echo "${array[#]: -1}"; )
# Check array content now
declare -p array
declare -a array='([0]="element1|element2|element3")'
"${array[#]:0:$((${#array[#]} - 1))}" will get all but last element of array
"${array[#]: -1}" will get the last element of array
printf "%s|" will append | in front of all the arguments
< <(...) is process substitution to read output of any command from stdin
read -ra will read the input in an array
$ array=("element1" "element2" "element3")
$ printf -v str "|%s" "${array[#]}"
$ array=("${str:1}")
$ declare -p array
declare -a array='([0]="element1|element2|element3")'
The printf statement creates a string str that contains |element1|element2|element3, i.e., one more | than we want (at the beginning).
The next statement uses substring parameter expansion, ${str:1}, to skip the first character and reassigns to array, which now consists of a single element.
A simple solution (if you don't mind changing IFS) is:
$ array=("element1" "element2" "element3")
$ IFS="|"; printf "%s\n" "${array[*]}"
And to re-assign to the variable array (which doesn't change IFS):
$ array=("$(IFS="|"; printf "%s\n" "${array[*]}")")
$ printf '%s\n' "${array[#]}"
element1|element2|element3
An alternative solution is:
$ array=($(printf '%s|' "${array[#]}")); array="${array%?}"
$ printf '%s\n' "${array}"
A more complex solution (script) is:
array=("element1" "element2" "element3")
delimiter='|'
unset newarr
for val in "${array[#]}"
do newarr=$newarr${newarr+"$delimiter"}$val
done
array=("$newarr")
echo "array=($array)"
How do I create an array in unix shell scripting?
The following code creates and prints an array of strings in shell:
#!/bin/bash
array=("A" "B" "ElementC" "ElementE")
for element in "${array[#]}"
do
echo "$element"
done
echo
echo "Number of elements: ${#array[#]}"
echo
echo "${array[#]}"
Result:
A
B
ElementC
ElementE
Number of elements: 4
A B ElementC ElementE
in bash, you create array like this
arr=(one two three)
to call the elements
$ echo "${arr[0]}"
one
$ echo "${arr[2]}"
three
to ask for user input, you can use read
read -p "Enter your choice: " choice
Bourne shell doesn't support arrays. However, there are two ways to handle the issue.
Use positional shell parameters $1, $2, etc.:
$ set one two three
$ echo $*
one two three
$ echo $#
3
$ echo $2
two
Use variable evaluations:
$ n=1 ; eval a$n="one"
$ n=2 ; eval a$n="two"
$ n=3 ; eval a$n="three"
$ n=2
$ eval echo \$a$n
two
#!/bin/bash
# define a array, space to separate every item
foo=(foo1 foo2)
# access
echo "${foo[1]}"
# add or changes
foo[0]=bar
foo[2]=cat
foo[1000]=also_OK
You can read the ABS "Advanced Bash-Scripting Guide"
The Bourne shell and C shell don't have arrays, IIRC.
In addition to what others have said, in Bash you can get the number of elements in an array as follows:
elements=${#arrayname[#]}
and do slice-style operations:
arrayname=(apple banana cherry)
echo ${arrayname[#]:1} # yields "banana cherry"
echo ${arrayname[#]: -1} # yields "cherry"
echo ${arrayname[${#arrayname[#]}-1]} # yields "cherry"
echo ${arrayname[#]:0:2} # yields "apple banana"
echo ${arrayname[#]:1:1} # yields "banana"
Try this :
echo "Find the Largest Number and Smallest Number of a given number"
echo "---------------------------------------------------------------------------------"
echo "Enter the number"
read n
i=0
while [ $n -gt 0 ] #For Seperating digits and Stored into array "x"
do
x[$i]=`expr $n % 10`
n=`expr $n / 10`
i=`expr $i + 1`
done
echo "Array values ${x[#]}" # For displaying array elements
len=${#x[*]} # it returns the array length
for (( i=0; i<len; i++ )) # For Sorting array elements using Bubble sort
do
for (( j=i+1; j<len; j++ ))
do
if [ `echo "${x[$i]} > ${x[$j]}"|bc` ]
then
t=${x[$i]}
t=${x[$i]}
x[$i]=${x[$j]}
x[$j]=$t
fi
done
done
echo "Array values ${x[*]}" # Displaying of Sorted Array
for (( i=len-1; i>=0; i-- )) # Form largest number
do
a=`echo $a \* 10 + ${x[$i]}|bc`
done
echo "Largest Number is : $a"
l=$a #Largest number
s=0
while [ $a -gt 0 ] # Reversing of number, We get Smallest number
do
r=`expr $a % 10`
s=`echo "$s * 10 + $r"|bc`
a=`expr $a / 10`
done
echo "Smallest Number is : $s" #Smallest Number
echo "Difference between Largest number and Smallest number"
echo "=========================================="
Diff=`expr $l - $s`
echo "Result is : $Diff"
echo "If you try it, We can get it"
Your question asks about "unix shell scripting", but is tagged bash. Those are two different answers.
The POSIX specification for shells does not have anything to say about arrays, as the original Bourne shell did not support them. Even today, on FreeBSD, Ubuntu Linux, and many other systems, /bin/sh does not have array support. So if you want your script to work in different Bourne-compatible shells, you shouldn't use them. Alternatively, if you are assuming a specific shell, then be sure to put its full name in the shebang line, e.g. #!/usr/bin/env bash.
If you are using bash or zsh, or a modern version of ksh, you can create an array like this:
myArray=(first "second element" 3rd)
and access elements like this
$ echo "${myArray[1]}" # for bash/ksh; for zsh, echo $myArray[2]
second element
You can get all the elements via "${myArray[#]}". You can use the slice notation ${array[#]:start:length} to restrict the portion of the array referenced, e.g. "${myArray[#]:1}" to leave off the first element.
The length of the array is ${#myArray[#]}. You can get a new array containing all the indexes from an existing array with "${!myArray[#]}".
Older versions of ksh before ksh93 also had arrays, but not the parenthesis-based notation, nor did they support slicing. You could create an array like this, though:
set -A myArray -- first "second element" 3rd
You can try of the following type :
#!/bin/bash
declare -a arr
i=0
j=0
for dir in $(find /home/rmajeti/programs -type d)
do
arr[i]=$dir
i=$((i+1))
done
while [ $j -lt $i ]
do
echo ${arr[$j]}
j=$((j+1))
done
An array can be loaded in twoways.
set -A TEST_ARRAY alpha beta gamma
or
X=0 # Initialize counter to zero.
-- Load the array with the strings alpha, beta, and gamma
for ELEMENT in alpha gamma beta
do
TEST_ARRAY[$X]=$ELEMENT
((X = X + 1))
done
Also, I think below information may help:
The shell supports one-dimensional arrays. The maximum number of array
elements is 1,024. When an array is defined, it is automatically
dimensioned to 1,024 elements. A one-dimensional array contains a
sequence of array elements, which are like the boxcars connected
together on a train track.
In case you want to access the array:
echo ${MY_ARRAY[2] # Show the third array element
gamma
echo ${MY_ARRAY[*] # Show all array elements
- alpha beta gamma
echo ${MY_ARRAY[#] # Show all array elements
- alpha beta gamma
echo ${#MY_ARRAY[*]} # Show the total number of array elements
- 3
echo ${#MY_ARRAY[#]} # Show the total number of array elements
- 3
echo ${MY_ARRAY} # Show array element 0 (the first element)
- alpha
If you want a key value store with support for spaces use the -A parameter:
declare -A programCollection
programCollection["xwininfo"]="to aquire information about the target window."
for program in ${!programCollection[#]}
do
echo "The program ${program} is used ${programCollection[${program}]}"
done
http://linux.die.net/man/1/bash "Associative arrays are created using declare -A name. "
There are multiple ways to create an array in shell.
ARR[0]="ABC"
ARR[1]="BCD"
echo ${ARR[*]}
${ARR[*]} prints all elements in the array.
Second way is:
ARR=("A" "B" "C" "D" 5 7 "J")
echo ${#ARR[#]}
echo ${ARR[0]}
${#ARR[#]} is used to count length of the array.
To read the values from keybord and insert element into array
# enter 0 when exit the insert element
echo "Enter the numbers"
read n
while [ $n -ne 0 ]
do
x[$i]=`expr $n`
read n
let i++
done
#display the all array elements
echo "Array values ${x[#]}"
echo "Array values ${x[*]}"
# To find the array length
length=${#x[*]}
echo $length
A Simple way :
arr=("sharlock" "bomkesh" "feluda" ) ##declare array
len=${#arr[*]} #determine length of array
# iterate with for loop
for (( i=0; i<len; i++ ))
do
echo ${arr[$i]}
done
In ksh you do it:
set -A array element1 element2 elementn
# view the first element
echo ${array[0]}
# Amount elements (You have to substitute 1)
echo ${#array[*]}
# show last element
echo ${array[ $(( ${#array[*]} - 1 )) ]}