SQL Server XML file with multiple nodes named the same - sql-server

Question

I have this inner XML which I am passing across to a SQL Server stored procedure.
As you can see, it contains multiple root nodes but additionally, it can also contain 1 to 'n' number of LotResults child nodes.
Is there a way I can manipulate this in the stored procedure so that I can retrieve all LotResults/Result nodes for each root node?
So far I have declared the cursor which can deal with the top-level nodes:
DECLARE cur CURSOR FOR
SELECT tab.col.value('ID[1]','NCHAR(10)') as INT_TransactionID,
tab.col.value('ResultDateTime[1]','INT') as DAT_ResultDateTime,
tab.col.value('StandardComment[1]/ID[1]','BIT') as INT_StandardCommentID,
tab.col.value('ReviewComment[1]/ID[1]','BIT') as INT_ReviewCommentID
FROM #XML_Results.nodes('/roots/root') AS tab(col)
OPEN cur
-- loop over nodes within xml document and populate declared variables
FETCH
NEXT
FROM cur
INTO #INT_TransactionID,
#DAT_ResultDateTime,
#INT_StandardCommentID,
#INT_ReviewCommentID
WHILE ##FETCH_STATUS = 0
BEGIN
BEGIN
-- use my values here
END
-- fetch next record
FETCH
NEXT
FROM cur
INTO #INT_TransactionID,
#DAT_ResultDateTime,
#INT_StandardCommentID,
#INT_ReviewCommentID
END
CLOSE cur;
Note: I found a post describing how to extract nodes with the same name and I feel like it is something that can be used to achieve what I want to do here but I need some guidance on how this can be applied to my scenario.

Answer 1

No cursors! Cursor are created by the devil to lead poor little db people away from the light of set-based thinking deep into the dark acres of procedural approaches...
Please (for future questions): Do not paste pictures! Had to type my example in...
And btw: Your use my values here makes it difficult, to advise the correct thing. Depending on what you are doing there, a cursor might be needed actually. But in this case you should create the cursor from a query like I show you...
Try it like this:
DECLARE #xml XML=
'<roots>
<root>
<ID>5</ID>
<LotResults>
<ID>13</ID>
<Result>
<ID>5</ID>
<Count>2</Count>
</Result>
</LotResults>
<LotResults>
<ID>13</ID>
<Result>
<ID>5</ID>
<Count>2</Count>
</Result>
</LotResults>
<StandardComment>
<ID>0</ID>
</StandardComment>
<ReviewComment>
<ID>0</ID>
</ReviewComment>
</root>
<root>
<ID>44</ID>
<LotResults>
<ID>444</ID>
<Result>
<ID>4444</ID>
<Count>2</Count>
</Result>
</LotResults>
<LotResults>
<ID>555</ID>
<Result>
<ID>55</ID>
<Count>2</Count>
</Result>
</LotResults>
<StandardComment>
<ID>5</ID>
</StandardComment>
<ReviewComment>
<ID>5</ID>
</ReviewComment>
</root>
</roots>';
--and here's the query
SELECT r.value('ID[1]','int') AS root_ID
,lr.value('ID[1]','int') AS LotResult_ID
,lr.value('(Result/ID)[1]','int') AS LotResult_Result_ID
,lr.value('(Result/Count)[1]','int') AS LotResult_Result_Count
,r.value('(StandardComment/ID)[1]','int') AS StandardComment_ID
,r.value('(ReviewComment/ID)[1]','int') AS ReviewComment_ID
FROM #xml.nodes('/roots/root') AS A(r)
CROSS APPLY r.nodes('LotResults') AS B(lr)