until item does not exists in array do in bash - arrays

Question

I have below part of the code
jmsPort=61015
jmsPorts=(61018 61016 61017)
until [ $jmsPorts -ne $jmsPort ]; do
jmsPort=$(expr $jmsPort + 1)
done
The iteration of the loop is only once in this case, how can use do this
until the jmsPorts array does not contain the jmsPort do (jmsPort + 1)
the goal that I want to achieve is
If the jmsPort matches an element in the array:
It should do + 1 to the jmsPort until the jmsPort does not match an element in the jmsPorts array
If the jmsPort is not in the array:
it should choose the jmsPort
I have done this using PowerShell but can't do it in Bash.
the syntax in PowerShell is
$jmsPort = 61016
$jmsPorts = #(61018, 61016, 61017)
do
{
$jmsPort = $jmsPort + 1
}
until ($jmsPorts -notcontains $jmsPort )

Answer 1

Remember that
jmsPorts=() # jmsPorts is an array
To update the array, initially(before the edit) you've put
jmsPorts+=$(echo $i | grep -oP '\d+') # Wrong
It should've been
jmsPorts+=( "$(echo $i | grep -oP '\d+')" ) #mind the outer brackets.
Now to check if jmsPort doesn't match any element in jmsPorts array do
validator(){
flag=0 # Assuming the element is not present
for i in "${jmsPorts[#]}"
do
if [ "$1" -eq "$i" ]
then
flag=1 # Element is present
fi
done
}
while validator "$jmsPort" && [ "$flag" -eq 1 ]
do
((jmsPort++))
done
echo "Port Chosen : $jmsPort"
# This port doesn't match any value in the array.
Warning : Ports 1-65535 are available, and ports in range 1-1023 are the privileged ones. On more complicated scenatios an extra check [ $jmsPort -lt 65535 ] might be necessary.