bash - pulling content from array via index - arrays

Question

I am having trouble with a script that prints out the index and items of the array and then allows the user to input an index that will print out that specific item of the array.
array=(abc def ghi)
i=0
while [ $i -lt ${#array[*]} ]; do
echo "[$i] ${array[$i]}"
i=$(($i+1));
done
echo -e "select an index: "; read answer
#this is the part that is troubling me
for index in ${!array[*]}; do
if [[ $answer == $index ]]; then
echo ${array[$index]}
break
else
echo "invalid"
break
fi
done
so if the user enters 0, it should print abc. 1 would be def etc. It currently only works for index 0.

Answer 1

Couple of problems in there that I can find:
you need a space right after $item to separate from the ]
$item should probably be $index
most importantly, remove the break after the "echo invalid" which is the reason the loop exits right after testing against '0' and doesn't check for the next array indexes. Using a flag then you should control if the answer matched any of the valid indexes, otherwise print the "invalid" message. I used a very explicit string test there for clarity.
A running code should look like:
array=(abc def ghi)
i=0
while [ $i -lt ${#array[*]} ]; do
echo "[$i] ${array[$i]}"
i=$(($i+1));
done
echo -e "select an index: "; read answer
for index in ${!array[*]}; do
found="FALSE"
if [[ "$answer" == "$index" ]]; then
found="TRUE"
echo "${array[$index]}"
break
fi
done
if [ "$found" == "FALSE" ]; then
echo "Invalid input $answer"
fi