Paste single strings with an array in Bash - arrays

What would be a bash equivalent of the following R function?
vec=4:9
out=paste0("foo_",vec,"_bar")
out
"foo_4_bar" "foo_5_bar" "foo_6_bar" "foo_7_bar" "foo_8_bar" "foo_9_bar"

You can use declare an array with suffix and prefix and then use brace expansion to populate incrementing numbers:
arr=("foo_" "_bar") # array with suffix and prefix
echo "${arr[0]}"{4..9}"${arr[1]}" # brace expansion
foo_4_bar foo_5_bar foo_6_bar foo_7_bar foo_8_bar foo_9_bar

You can use brace expansion:
$ echo foo_{4..9}_bar
foo_4_bar foo_5_bar foo_6_bar foo_7_bar foo_8_bar foo_9_bar
$ out=( foo_{4..9}_bar )
$ echo "${out[1]}"
foo_5_bar

This works even if your vec is not generated via a brace expansion:
vec=( {4..9} ) # would work even with vec=( *.txt ) or readarray -t vec <file, etc.
out=( "${vec[#]/#/foo_}" ) # add foo_ prefix
out=( "${out[#]/%/_bar}" ) # add _bar suffix
declare -p out # print resulting array definition
See the Parameter Expansion page on the bash-hackers wiki, particularly the "Anchoring" section under "Search and Replace".

Related

Bash shift changes expected value of associative array

I made a simple script, that matches the positional arguments starting with dash, and saves them into an associative array.
declare -A opts
for i; do
[[ "$i" =~ - ]] && opts[$i]=1
done
shift "${#opts[*]}"
echo "opts: ${opts[*]}"
echo "!opts: ${!opts[-d]}"
echo "Query: $*"
For the call ./script -d hello world the output is:
opts: 1
!opts: hello
Query: hello world
Which is unexpected, since the key of ${!opts[-d]} is supposed to be -d itself if defined. This behavior happens because of the shift command, when it is removed from the code, the output is as expected:
opts: 1
!opts: -d
Query: -d hello world
Why does shift interfere with the created associative array?
The associative array isn't being changed; you can verify this by putting a declare -p opts after the shift, which will give
declare -A opts=([-d]="1" )
The problem: ${!opts[-d]} doesn't do what you seem to expect. First, opts[-d] is looked up, which is the value 1. Then the ! means that's used as the name of a variable to substitute - so it's effectively the same as $1, which, after the shift, is hello.
If you want to print out all the keys of the associative array, use ${!opts[#]}. The leading ! has two different meanings in bash paramater expansion depending on if used with an array with # or * in the brackets, or an index/normal variables.

Variable in bash array name

I have this code:
#!/bin/sh
...
for cnumber in `seq $CNUMBER`; do
declare -a CAT$cnumber
let i=0
while IFS=$'\n' read -r line_data; do
CAT$cnumber[i]="${line_data}"
((++i))
done < input_file_$cnumber
done
It works if I use array name without variable $cnumber.
But I want to create multiple arrays (CAT0, CAT1, CAT2 etc.) and to read lines:
from file 'input_file_0' to array 'CAT0'
from file 'input_file_1' to array 'CAT1'
from file 'input_file_2' to array 'CAT2'
etc.
What syntax to use $cnumber variable in array name (CAT1) and in input file_name?
for cnumber in `seq $CNUMBER`; do
declare -a CAT$cnumber
let i=0
while IFS=$'\n' read -r line_data; do
eval CAT$cnumber[i]='"${line_data}"'
((++i))
done < input_file_$cnumber
done
Mainly, that adds the word "eval" which makes bash evaluate the rest of the line. Before that, bash expands variables, thus CAT$number will be something like CAT1 when the line is evaluated. Keep in mind that "${line_date}" would be subject to variable expansion before eval evaluates the line if it would not be protected by single quotes. That might have unexpected effects if the $line_data would contain blank spaces. See this simplified example:
a=b
l="hello date"
eval $a="$l" # executes "date", has no other effect
echo $b # prints an empty line
eval $a='"$l"' # sets b to "hello date"
echo $b # prints that: hello date
In reply to the comment of Etan Reisner below, I add another solution that avoids "eval" and instead uses references, which are available in bash version 4.3 or higher. In that case, using references is preferable for the reason Etan pointed out, and also, for my opinion, because it is more natural:
for cnumber in `seq $CNUMBER`; do
declare -a CAT$cnumber # be sure the array is declared before ...
declare -n ref=CAT$cnumber # ... you declare ref to reference the array
let i=0
while IFS=$'\n' read -r line_data; do
ref[$i]="${line_data}"
((++i))
done < input_file_$cnumber
done
First, your shebang needs to be
#!/bin/bash
since declare is a bash built-in.
Next, use declare to define the array elements
for cnumber in `seq $CNUMBER`; do
declare -a CAT$cnumber
let i=0
while IFS=$'\n' read -r line_data; do
declare "CAT$cnumber[$i]=${line_data}"
((++i))
done < input_file_$cnumber
done

How to expand the elements of an array in zsh?

Say I have an array in zsh
a=(1 2 3)
I want to append .txt to each element
echo ${a}.txt # this doesn't work
So the output is
1.txt 2.txt 3.txt
UPDATE:
I guess I can do this, but I think there's a more idiomatic way:
for i in $a; do
echo $i.txt
done
You need to set RC_EXPAND_PARAM option:
$ setopt RC_EXPAND_PARAM
$ echo ${a}.txt
1.txt 2.txt 3.txt
From zsh manual:
RC_EXPAND_PARAM (-P)
Array expansions of the form `foo${xx}bar', where the parameter xx is set to
(a b c), are substituted with `fooabar foobbar foocbar' instead of the
default `fooa b cbar'. Note that an empty array will therefore cause all
arguments to be removed.
You can also set this option just for for one array expansion using ^ flag:
$ echo ${^a}.txt
1.txt 2.txt 3.txt
$ echo ${^^a}.txt
1 2 3.txt
Again citing zsh manual:
${^spec}
Turn on the RC_EXPAND_PARAM option for the evaluation of spec; if the `^' is
doubled, turn it off. When this option is set, array expansions of the form
foo${xx}bar, where the parameter xx is set to (a b c), are substituted with
`fooabar foobbar foocbar' instead of the default `fooa b cbar'. Note that an
empty array will therefore cause all arguments to be removed.

How to return an array in bash without using globals?

I have a function that creates an array and I want to return the array to the caller:
create_array() {
local my_list=("a", "b", "c")
echo "${my_list[#]}"
}
my_algorithm() {
local result=$(create_array)
}
With this, I only get an expanded string. How can I "return" my_list without using anything global?
With Bash version 4.3 and above, you can make use of a nameref so that the caller can pass in the array name and the callee can use a nameref to populate the named array, indirectly.
#!/usr/bin/env bash
create_array() {
local -n arr=$1 # use nameref for indirection
arr=(one "two three" four)
}
use_array() {
local my_array
create_array my_array # call function to populate the array
echo "inside use_array"
declare -p my_array # test the array
}
use_array # call the main function
Produces the output:
inside use_array
declare -a my_array=([0]="one" [1]="two three" [2]="four")
You could make the function update an existing array as well:
update_array() {
local -n arr=$1 # use nameref for indirection
arr+=("two three" four) # update the array
}
use_array() {
local my_array=(one)
update_array my_array # call function to update the array
}
This is a more elegant and efficient approach since we don't need command substitution $() to grab the standard output of the function being called. It also helps if the function were to return more than one output - we can simply use as many namerefs as the number of outputs.
Here is what the Bash Manual says about nameref:
A variable can be assigned the nameref attribute using the -n option
to the declare or local builtin commands (see Bash Builtins) to create
a nameref, or a reference to another variable. This allows variables
to be manipulated indirectly. Whenever the nameref variable is
referenced, assigned to, unset, or has its attributes modified (other
than using or changing the nameref attribute itself), the operation is
actually performed on the variable specified by the nameref variable’s
value. A nameref is commonly used within shell functions to refer to a
variable whose name is passed as an argument to the function. For
instance, if a variable name is passed to a shell function as its
first argument, running
declare -n ref=$1 inside the function creates a nameref variable ref
whose value is the variable name passed as the first argument.
References and assignments to ref, and changes to its attributes, are
treated as references, assignments, and attribute modifications to the
variable whose name was passed as $1.
What's wrong with globals?
Returning arrays is really not practical. There are lots of pitfalls.
That said, here's one technique that works if it's OK that the variable have the same name:
$ f () { local a; a=(abc 'def ghi' jkl); declare -p a; }
$ g () { local a; eval $(f); declare -p a; }
$ f; declare -p a; echo; g; declare -p a
declare -a a='([0]="abc" [1]="def ghi" [2]="jkl")'
-bash: declare: a: not found
declare -a a='([0]="abc" [1]="def ghi" [2]="jkl")'
-bash: declare: a: not found
The declare -p commands (except for the one in f() are used to display the state of the array for demonstration purposes. In f() it's used as the mechanism to return the array.
If you need the array to have a different name, you can do something like this:
$ g () { local b r; r=$(f); r="declare -a b=${r#*=}"; eval "$r"; declare -p a; declare -p b; }
$ f; declare -p a; echo; g; declare -p a
declare -a a='([0]="abc" [1]="def ghi" [2]="jkl")'
-bash: declare: a: not found
-bash: declare: a: not found
declare -a b='([0]="abc" [1]="def ghi" [2]="jkl")'
-bash: declare: a: not found
Bash can't pass around data structures as return values. A return value must be a numeric exit status between 0-255. However, you can certainly use command or process substitution to pass commands to an eval statement if you're so inclined.
This is rarely worth the trouble, IMHO. If you must pass data structures around in Bash, use a global variable--that's what they're for. If you don't want to do that for some reason, though, think in terms of positional parameters.
Your example could easily be rewritten to use positional parameters instead of global variables:
use_array () {
for idx in "$#"; do
echo "$idx"
done
}
create_array () {
local array=("a" "b" "c")
use_array "${array[#]}"
}
This all creates a certain amount of unnecessary complexity, though. Bash functions generally work best when you treat them more like procedures with side effects, and call them in sequence.
# Gather values and store them in FOO.
get_values_for_array () { :; }
# Do something with the values in FOO.
process_global_array_variable () { :; }
# Call your functions.
get_values_for_array
process_global_array_variable
If all you're worried about is polluting your global namespace, you can also use the unset builtin to remove a global variable after you're done with it. Using your original example, let my_list be global (by removing the local keyword) and add unset my_list to the end of my_algorithm to clean up after yourself.
You were not so far out with your original solution. You had a couple of problems, you used a comma as a separator, and you failed to capture the returned items into a list, try this:
my_algorithm() {
local result=( $(create_array) )
}
create_array() {
local my_list=("a" "b" "c")
echo "${my_list[#]}"
}
Considering the comments about embedded spaces, a few tweaks using IFS can solve that:
my_algorithm() {
oldIFS="$IFS"
IFS=','
local result=( $(create_array) )
IFS="$oldIFS"
echo "Should be 'c d': ${result[1]}"
}
create_array() {
IFS=','
local my_list=("a b" "c d" "e f")
echo "${my_list[*]}"
}
Use the technique developed by Matt McClure:
http://notes-matthewlmcclure.blogspot.com/2009/12/return-array-from-bash-function-v-2.html
Avoiding global variables means you can use the function in a pipe. Here is an example:
#!/bin/bash
makeJunk()
{
echo 'this is junk'
echo '#more junk and "b#d" characters!'
echo '!#$^%^&(*)_^&% ^$##:"<>?/.,\\"'"'"
}
processJunk()
{
local -a arr=()
# read each input and add it to arr
while read -r line
do
arr+=('"'"$line"'" is junk')
done;
# output the array as a string in the "declare" representation
declare -p arr | sed -e 's/^declare -a [^=]*=//'
}
# processJunk returns the array in a flattened string ready for "declare"
# Note that because of the pipe processJunk cannot return anything using
# a global variable
returned_string="$(makeJunk | processJunk)"
# convert the returned string to an array named returned_array
# declare correctly manages spaces and bad characters
eval "declare -a returned_array=${returned_string}"
for junk in "${returned_array[#]}"
do
echo "$junk"
done
Output is:
"this is junk" is junk
"#more junk and "b#d" characters!" is junk
"!#$^%^&(*)_^&% ^$##:"<>?/.,\\"'" is junk
A pure bash, minimal and robust solution based on the 'declare -p' builtin — without insane global variables
This approach involves the following three steps:
Convert the array with 'declare -p' and save the output in a variable.
myVar="$( declare -p myArray )"
The output of the declare -p statement can be used to recreate the array.
For instance the output of declare -p myVar might look like this:
declare -a myVar='([0]="1st field" [1]="2nd field" [2]="3rd field")'
Use the echo builtin to pass the variable to a function or to pass it back from there.
In order to preserve whitspaces in array fields when echoing the variable, IFS is temporarly set to a control character (e.g. a vertical tab).
Only the right-hand-side of the declare statement in the variable is to be echoed - this can be achieved by parameter expansion of the form ${parameter#word}. As for the example above: ${myVar#*=}
Finally, recreate the array where it is passed to using the eval and the 'declare -a' builtins.
Example 1 - return an array from a function
#!/bin/bash
# Example 1 - return an array from a function
function my-fun () {
# set up a new array with 3 fields - note the whitespaces in the
# 2nd (2 spaces) and 3rd (2 tabs) field
local myFunArray=( "1st field" "2nd field" "3rd field" )
# show its contents on stderr (must not be output to stdout!)
echo "now in $FUNCNAME () - showing contents of myFunArray" >&2
echo "by the help of the 'declare -p' builtin:" >&2
declare -p myFunArray >&2
# return the array
local myVar="$( declare -p myFunArray )"
local IFS=$'\v';
echo "${myVar#*=}"
# if the function would continue at this point, then IFS should be
# restored to its default value: <space><tab><newline>
IFS=' '$'\t'$'\n';
}
# main
# call the function and recreate the array that was originally
# set up in the function
eval declare -a myMainArray="$( my-fun )"
# show the array contents
echo ""
echo "now in main part of the script - showing contents of myMainArray"
echo "by the help of the 'declare -p' builtin:"
declare -p myMainArray
# end-of-file
Output of Example 1:
now in my-fun () - showing contents of myFunArray
by the help of the 'declare -p' builtin:
declare -a myFunArray='([0]="1st field" [1]="2nd field" [2]="3rd field")'
now in main part of the script - showing contents of myMainArray
by the help of the 'declare -p' builtin:
declare -a myMainArray='([0]="1st field" [1]="2nd field" [2]="3rd field")'
Example 2 - pass an array to a function
#!/bin/bash
# Example 2 - pass an array to a function
function my-fun () {
# recreate the array that was originally set up in the main part of
# the script
eval declare -a myFunArray="$( echo "$1" )"
# note that myFunArray is local - from the bash(1) man page: when used
# in a function, declare makes each name local, as with the local
# command, unless the ‘-g’ option is used.
# IFS has been changed in the main part of this script - now that we
# have recreated the array it's better to restore it to the its (local)
# default value: <space><tab><newline>
local IFS=' '$'\t'$'\n';
# show contents of the array
echo ""
echo "now in $FUNCNAME () - showing contents of myFunArray"
echo "by the help of the 'declare -p' builtin:"
declare -p myFunArray
}
# main
# set up a new array with 3 fields - note the whitespaces in the
# 2nd (2 spaces) and 3rd (2 tabs) field
myMainArray=( "1st field" "2nd field" "3rd field" )
# show the array contents
echo "now in the main part of the script - showing contents of myMainArray"
echo "by the help of the 'declare -p' builtin:"
declare -p myMainArray
# call the function and pass the array to it
myVar="$( declare -p myMainArray )"
IFS=$'\v';
my-fun $( echo "${myVar#*=}" )
# if the script would continue at this point, then IFS should be restored
# to its default value: <space><tab><newline>
IFS=' '$'\t'$'\n';
# end-of-file
Output of Example 2:
now in the main part of the script - showing contents of myMainArray
by the help of the 'declare -p' builtin:
declare -a myMainArray='([0]="1st field" [1]="2nd field" [2]="3rd field")'
now in my-fun () - showing contents of myFunArray
by the help of the 'declare -p' builtin:
declare -a myFunArray='([0]="1st field" [1]="2nd field" [2]="3rd field")'
I recently discovered a quirk in BASH in that a function has direct access to the variables declared in the functions higher in the call stack. I've only just started to contemplate how to exploit this feature (it promises both benefits and dangers), but one obvious application is a solution to the spirit of this problem.
I would also prefer to get a return value rather than using a global variable when delegating the creation of an array. There are several reasons for my preference, among which are to avoid possibly disturbing an preexisting value and to avoid leaving a value that may be invalid when later accessed. While there are workarounds to these problems, the easiest is have the variable go out of scope when the code is finished with it.
My solution ensures that the array is available when needed and discarded when the function returns, and leaves undisturbed a global variable with the same name.
#!/bin/bash
myarr=(global array elements)
get_an_array()
{
myarr=( $( date +"%Y %m %d" ) )
}
request_array()
{
declare -a myarr
get_an_array "myarr"
echo "New contents of local variable myarr:"
printf "%s\n" "${myarr[#]}"
}
echo "Original contents of global variable myarr:"
printf "%s\n" "${myarr[#]}"
echo
request_array
echo
echo "Confirm the global myarr was not touched:"
printf "%s\n" "${myarr[#]}"
Here is the output of this code:
When function request_array calls get_an_array, get_an_array can directly set the myarr variable that is local to request_array. Since myarr is created with declare, it is local to request_array and thus goes out of scope when request_array returns.
Although this solution does not literally return a value, I suggest that taken as a whole, it satisfies the promises of a true function return value.
Useful example: return an array from function
function Query() {
local _tmp=`echo -n "$*" | mysql 2>> zz.err`;
echo -e "$_tmp";
}
function StrToArray() {
IFS=$'\t'; set $1; for item; do echo $item; done; IFS=$oIFS;
}
sql="SELECT codi, bloc, requisit FROM requisits ORDER BY codi";
qry=$(Query $sql0);
IFS=$'\n';
for row in $qry; do
r=( $(StrToArray $row) );
echo ${r[0]} - ${r[1]} - ${r[2]};
done
I tried various implementations, and none preserved arrays that had elements with spaces ... because they all had to use echo.
# These implementations only work if no array items contain spaces.
use_array() { eval echo '(' \"\${${1}\[\#\]}\" ')'; }
use_array() { local _array="${1}[#]"; echo '(' "${!_array}" ')'; }
Solution
Then I came across Dennis Williamson's answer. I incorporated his method into the following functions so they can a) accept an arbitrary array and b) be used to pass, duplicate and append arrays.
# Print array definition to use with assignments, for loops, etc.
# varname: the name of an array variable.
use_array() {
local r=$( declare -p $1 )
r=${r#declare\ -a\ *=}
# Strip keys so printed definition will be a simple list (like when using
# "${array[#]}"). One side effect of having keys in the definition is
# that when appending arrays (i.e. `a1+=$( use_array a2 )`), values at
# matching indices merge instead of pushing all items onto array.
echo ${r//\[[0-9]\]=}
}
# Same as use_array() but preserves keys.
use_array_assoc() {
local r=$( declare -p $1 )
echo ${r#declare\ -a\ *=}
}
Then, other functions can return an array using catchable output or indirect arguments.
# catchable output
return_array_by_printing() {
local returnme=( "one" "two" "two and a half" )
use_array returnme
}
eval test1=$( return_array_by_printing )
# indirect argument
return_array_to_referenced_variable() {
local returnme=( "one" "two" "two and a half" )
eval $1=$( use_array returnme )
}
return_array_to_referenced_variable test2
# Now both test1 and test2 are arrays with three elements
I needed a similar functionality recently, so the following is a mix of the suggestions made by RashaMatt and Steve Zobell.
echo each array/list element as separate line from within a function
use mapfile to read all array/list elements echoed by a function.
As far as I can see, strings are kept intact and whitespaces are preserved.
#!bin/bash
function create-array() {
local somearray=("aaa" "bbb ccc" "d" "e f g h")
for elem in "${somearray[#]}"
do
echo "${elem}"
done
}
mapfile -t resa <<< "$(create-array)"
# quick output check
declare -p resa
Some more variations…
#!/bin/bash
function create-array-from-ls() {
local somearray=("$(ls -1)")
for elem in "${somearray[#]}"
do
echo "${elem}"
done
}
function create-array-from-args() {
local somearray=("$#")
for elem in "${somearray[#]}"
do
echo "${elem}"
done
}
mapfile -t resb <<< "$(create-array-from-ls)"
mapfile -t resc <<< "$(create-array-from-args 'xxx' 'yy zz' 't s u' )"
sentenceA="create array from this sentence"
sentenceB="keep this sentence"
mapfile -t resd <<< "$(create-array-from-args ${sentenceA} )"
mapfile -t rese <<< "$(create-array-from-args "$sentenceB" )"
mapfile -t resf <<< "$(create-array-from-args "$sentenceB" "and" "this words" )"
# quick output check
declare -p resb
declare -p resc
declare -p resd
declare -p rese
declare -p resf
Here is a solution with no external array references and no IFS manipulation:
# add one level of single quotes to args, eval to remove
squote () {
local a=("$#")
a=("${a[#]//\'/\'\\\'\'}") # "'" => "'\''"
a=("${a[#]/#/\'}") # add "'" prefix to each word
a=("${a[#]/%/\'}") # add "'" suffix to each word
echo "${a[#]}"
}
create_array () {
local my_list=(a "b 'c'" "\\\"d
")
squote "${my_list[#]}"
}
my_algorithm () {
eval "local result=($(create_array))"
# result=([0]="a" [1]="b 'c'" [2]=$'\\"d\n')
}
[Note: the following was rejected as an edit of this answer for reasons that make no sense to me (since the edit was not intended to address the author of the post!), so I'm taking the suggestion to make it a separate answer.]
A simpler implementation of Steve Zobell's adaptation of Matt McClure's technique uses the bash built-in (since version == 4) readarray as suggested by RastaMatt to create a representation of an array that can be converted into an array at runtime. (Note that both readarray and mapfile name the same code.) It still avoids globals (allowing use of the function in a pipe), and still handles nasty characters.
For some more-fully-developed (e.g., more modularization) but still-kinda-toy examples, see bash_pass_arrays_between_functions. Following are a few easily-executable examples, provided here to avoid moderators b!tching about external links.
Cut the following block and paste it into a bash terminal to create /tmp/source.sh and /tmp/junk1.sh:
FP='/tmp/source.sh' # path to file to be created for `source`ing
cat << 'EOF' > "${FP}" # suppress interpretation of variables in heredoc
function make_junk {
echo 'this is junk'
echo '#more junk and "b#d" characters!'
echo '!#$^%^&(*)_^&% ^$##:"<>?/.,\\"'"'"
}
### Use 'readarray' (aka 'mapfile', bash built-in) to read lines into an array.
### Handles blank lines, whitespace and even nastier characters.
function lines_to_array_representation {
local -a arr=()
readarray -t arr
# output array as string using 'declare's representation (minus header)
declare -p arr | sed -e 's/^declare -a [^=]*=//'
}
EOF
FP1='/tmp/junk1.sh' # path to script to run
cat << 'EOF' > "${FP1}" # suppress interpretation of variables in heredoc
#!/usr/bin/env bash
source '/tmp/source.sh' # to reuse its functions
returned_string="$(make_junk | lines_to_array_representation)"
eval "declare -a returned_array=${returned_string}"
for elem in "${returned_array[#]}" ; do
echo "${elem}"
done
EOF
chmod u+x "${FP1}"
# newline here ... just hit Enter ...
Run /tmp/junk1.sh: output should be
this is junk
#more junk and "b#d" characters!
!#$^%^&(*)_^&% ^$##:"<>?/.,\\"'
Note lines_to_array_representation also handles blank lines. Try pasting the following block into your bash terminal:
FP2='/tmp/junk2.sh' # path to script to run
cat << 'EOF' > "${FP2}" # suppress interpretation of variables in heredoc
#!/usr/bin/env bash
source '/tmp/source.sh' # to reuse its functions
echo '`bash --version` the normal way:'
echo '--------------------------------'
bash --version
echo # newline
echo '`bash --version` via `lines_to_array_representation`:'
echo '-----------------------------------------------------'
bash_version="$(bash --version | lines_to_array_representation)"
eval "declare -a returned_array=${bash_version}"
for elem in "${returned_array[#]}" ; do
echo "${elem}"
done
echo # newline
echo 'But are they *really* the same? Ask `diff`:'
echo '-------------------------------------------'
echo 'You already know how to capture normal output (from `bash --version`):'
declare -r PATH_TO_NORMAL_OUTPUT="$(mktemp)"
bash --version > "${PATH_TO_NORMAL_OUTPUT}"
echo "normal output captured to file # ${PATH_TO_NORMAL_OUTPUT}"
ls -al "${PATH_TO_NORMAL_OUTPUT}"
echo # newline
echo 'Capturing L2AR takes a bit more work, but is not onerous.'
echo "Look # contents of the file you're about to run to see how it's done."
declare -r RAW_L2AR_OUTPUT="$(bash --version | lines_to_array_representation)"
declare -r PATH_TO_COOKED_L2AR_OUTPUT="$(mktemp)"
eval "declare -a returned_array=${RAW_L2AR_OUTPUT}"
for elem in "${returned_array[#]}" ; do
echo "${elem}" >> "${PATH_TO_COOKED_L2AR_OUTPUT}"
done
echo "output from lines_to_array_representation captured to file # ${PATH_TO_COOKED_L2AR_OUTPUT}"
ls -al "${PATH_TO_COOKED_L2AR_OUTPUT}"
echo # newline
echo 'So are they really the same? Per'
echo "\`diff -uwB "${PATH_TO_NORMAL_OUTPUT}" "${PATH_TO_COOKED_L2AR_OUTPUT}" | wc -l\`"
diff -uwB "${PATH_TO_NORMAL_OUTPUT}" "${PATH_TO_COOKED_L2AR_OUTPUT}" | wc -l
echo '... they are the same!'
EOF
chmod u+x "${FP2}"
# newline here ... just hit Enter ...
Run /tmp/junk2.sh # commandline. Your output should be similar to mine:
`bash --version` the normal way:
--------------------------------
GNU bash, version 4.3.30(1)-release (x86_64-pc-linux-gnu)
Copyright (C) 2013 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>
This is free software; you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.
`bash --version` via `lines_to_array_representation`:
-----------------------------------------------------
GNU bash, version 4.3.30(1)-release (x86_64-pc-linux-gnu)
Copyright (C) 2013 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>
This is free software; you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.
But are they *really* the same? Ask `diff`:
-------------------------------------------
You already know how to capture normal output (from `bash --version`):
normal output captured to file # /tmp/tmp.Ni1bgyPPEw
-rw------- 1 me me 308 Jun 18 16:27 /tmp/tmp.Ni1bgyPPEw
Capturing L2AR takes a bit more work, but is not onerous.
Look # contents of the file you're about to run to see how it's done.
output from lines_to_array_representation captured to file # /tmp/tmp.1D6O2vckGz
-rw------- 1 me me 308 Jun 18 16:27 /tmp/tmp.1D6O2vckGz
So are they really the same? Per
`diff -uwB /tmp/tmp.Ni1bgyPPEw /tmp/tmp.1D6O2vckGz | wc -l`
0
... they are the same!
There's no need to use eval or to change IFS to \n. There are at least 2 good ways to do this.
1) Using echo and mapfile
You can simply echo each item of the array in the function, then use mapfile to turn it into an array:
outputArray()
{
for i
{
echo "$i"
}
}
declare -a arr=( 'qq' 'www' 'ee rr' )
mapfile -t array < <(outputArray "${arr[#]}")
for i in "${array[#]}"
do
echo "i=$i"
done
To make it work using pipes, add (( $# == 0 )) && readarray -t temp && set "${temp[#]}" && unset temp to the top of output array. It converts stdin to parameters.
2) Using declare -p and sed
This can also be done using declare -p and sed instead of mapfile.
outputArray()
{
(( $# == 0 )) && readarray -t temp && set "${temp[#]}" && unset temp
for i; { echo "$i"; }
}
returnArray()
{
local -a arr=()
(( $# == 0 )) && readarray -t arr || for i; { arr+=("$i"); }
declare -p arr | sed -e 's/^declare -a [^=]*=//'
}
declare -a arr=( 'qq' 'www' 'ee rr' )
declare -a array=$(returnArray "${arr[#]}")
for i in "${array[#]}"
do
echo "i=$i"
done
declare -a array=$(outputArray "${arr[#]}" | returnArray)
echo
for i in "${array[#]}"
do
echo "i=$i"
done
declare -a array < <(outputArray "${arr[#]}" | returnArray)
echo
for i in "${array[#]}"
do
echo "i=$i"
done
This can also be done by simply passing array variable to the function and assign array values to this var then use this var outside of function. For example.
create_array() {
local __resultArgArray=$1
local my_list=("a" "b" "c")
eval $__resultArgArray="("${my_list[#]}")"
}
my_algorithm() {
create_array result
echo "Total elements in the array: ${#result[#]}"
for i in "${result[#]}"
do
echo $i
done
}
my_algorithm
The easest way y found
my_function()
{
array=(one two three)
echo ${array[#]}
}
result=($(my_function))
echo ${result[0]}
echo ${result[1]}
echo ${result[2]}
You can also use the declare -p method more easily by taking advantage of declare -a's double-evaluation when the value is a string (no true parens outside the string):
# return_array_value returns the value of array whose name is passed in.
# It turns the array into a declaration statement, then echos the value
# part of that statement with parentheses intact. You can use that
# result in a "declare -a" statement to create your own array with the
# same value. Also works for associative arrays with "declare -A".
return_array_value () {
declare Array_name=$1 # namespace locals with caps to prevent name collision
declare Result
Result=$(declare -p $Array_name) # dehydrate the array into a declaration
echo "${Result#*=}" # trim "declare -a ...=" from the front
}
# now use it. test for robustness by skipping an index and putting a
# space in an entry.
declare -a src=([0]=one [2]="two three")
declare -a dst="$(return_array_value src)" # rehydrate with double-eval
declare -p dst
> declare -a dst=([0]="one" [2]="two three") # result matches original
Verifying the result, declare -p dst yields declare -a dst=([0]="one" [2]="two three")", demonstrating that this method correctly deals with both sparse arrays as well as entries with an IFS character (space).
The first thing is to dehydrate the source array by using declare -p to generate a valid bash declaration of it. Because the declaration is a full statement, including "declare" and the variable name, we strip that part from the front with ${Result#*=}, leaving the parentheses with the indices and values inside: ([0]="one" [2]="two three").
It then rehydrates the array by feeding that value to your own declare statement, one where you choose the array name. It relies on the fact that the right side of the dst array declaration is a string with parentheses that are inside the string, rather than true parentheses in the declare itself, e.g. not declare -a dst=( "true parens outside string" ). This triggers declare to evaluate the string twice, once into a valid statement with parentheses (and quotes in the value preserved), and another for the actual assignment. I.e. it evaluates first to declare -a dst=([0]="one" [2]="two three"), then evaluates that as a statement.
Note that this double evaluation behavior is specific to the -a and -A options of declare.
Oh, and this method works with associative arrays as well, just change -a to -A.
Because this method relies on stdout, it works across subshell boundaries like pipelines, as others have noted.
I discuss this method in more detail in my blog post
If your source data is formatted with each list element on a separate line, then the mapfile builtin is a simple and elegant way to read a list into an array:
$ list=$(ls -1 /usr/local) # one item per line
$ mapfile -t arrayVar <<<"$list" # -t trims trailing newlines
$ declare -p arrayVar | sed 's#\[#\n[#g'
declare -a arrayVar='(
[0]="bin"
[1]="etc"
[2]="games"
[3]="include"
[4]="lib"
[5]="man"
[6]="sbin"
[7]="share"
[8]="src")'
Note that, as with the read builtin, you would not ordinarily* use mapfile in a pipeline (or subshell) because the assigned array variable would be unavailable to subsequent statements (* unless bash job control is disabled and shopt -s lastpipe is set).
$ help mapfile
mapfile: mapfile [-n count] [-O origin] [-s count] [-t] [-u fd] [-C callback] [-c quantum] [array]
Read lines from the standard input into an indexed array variable.
Read lines from the standard input into the indexed array variable ARRAY, or
from file descriptor FD if the -u option is supplied. The variable MAPFILE
is the default ARRAY.
Options:
-n count Copy at most COUNT lines. If COUNT is 0, all lines are copied.
-O origin Begin assigning to ARRAY at index ORIGIN. The default index is 0.
-s count Discard the first COUNT lines read.
-t Remove a trailing newline from each line read.
-u fd Read lines from file descriptor FD instead of the standard input.
-C callback Evaluate CALLBACK each time QUANTUM lines are read.
-c quantum Specify the number of lines read between each call to CALLBACK.
Arguments:
ARRAY Array variable name to use for file data.
If -C is supplied without -c, the default quantum is 5000. When
CALLBACK is evaluated, it is supplied the index of the next array
element to be assigned and the line to be assigned to that element
as additional arguments.
If not supplied with an explicit origin, mapfile will clear ARRAY before
assigning to it.
Exit Status:
Returns success unless an invalid option is given or ARRAY is readonly or
not an indexed array.
You can try this
my_algorithm() {
create_array list
for element in "${list[#]}"
do
echo "${element}"
done
}
create_array() {
local my_list=("1st one" "2nd two" "3rd three")
eval "${1}=()"
for element in "${my_list[#]}"
do
eval "${1}+=(\"${element}\")"
done
}
my_algorithm
The output is
1st one
2nd two
3rd three
I'd suggest piping to a code block to set values of an array. The strategy is POSIX compatible, so you get both Bash and Zsh, and doesn't run the risk of side effects like the posted solutions.
i=0 # index for our new array
declare -a arr # our new array
# pipe from a function that produces output by line
ls -l | { while read data; do i=$i+1; arr[$i]="$data"; done }
# example of reading that new array
for row in "${arr[#]}"; do echo "$row"; done
This will work for zsh and bash, and won't be affected by spaces or special characters. In the case of the OP, the output is transformed by echo, so it is not actually outputting an array, but printing it (as others mentioned shell functions return status not values). We can change it to a pipeline ready mechanism:
create_array() {
local my_list=("a", "b", "c")
for row in "${my_list[#]}"; do
echo "$row"
done
}
my_algorithm() {
i=0
declare -a result
create_array | { while read data; do i=$i+1; result[$i]="$data"; done }
}
If so inclined, one could remove the create_array pipeline process from my_algorithm and chain the two functions together
create_array | my_algorithm
A modern Bash implementation using #Q to safely output array elements:
#!/usr/bin/env bash
return_array_elements() {
local -a foo_array=('1st one' '2nd two' '3rd three')
printf '%s\n' "${foo_array[#]#Q}"
}
use_array_elements() {
local -a bar_array="($(return_array_elements))"
# Display declareation of bar_array
# which is local to this function, but whose elements
# hahaves been returned by the return_array_elements function
declare -p bar_array
}
use_array_elements
Output:
declare -a bar_array=([0]="1st one" [1]="2nd two" [2]="3rd three")
While the declare -p approach is elegant indeed, you can still create a global array using declare -g within a function and have it visible outside the scope of the function:
create_array() {
declare -ag result=("a", "b", "c")
}
my_algorithm() {
create_array
echo "${result[#]}"
}

Bash array with spaces in elements

I'm trying to construct an array in bash of the filenames from my camera:
FILES=(2011-09-04 21.43.02.jpg
2011-09-05 10.23.14.jpg
2011-09-09 12.31.16.jpg
2011-09-11 08.43.12.jpg)
As you can see, there is a space in the middle of each filename.
I've tried wrapping each name in quotes, and escaping the space with a backslash, neither of which works.
When I try to access the array elements, it continues to treat the space as the elementdelimiter.
How can I properly capture the filenames with a space inside the name?
I think the issue might be partly with how you're accessing the elements. If I do a simple for elem in $FILES, I experience the same issue as you. However, if I access the array through its indices, like so, it works if I add the elements either numerically or with escapes:
for ((i = 0; i < ${#FILES[#]}; i++))
do
echo "${FILES[$i]}"
done
Any of these declarations of $FILES should work:
FILES=(2011-09-04\ 21.43.02.jpg
2011-09-05\ 10.23.14.jpg
2011-09-09\ 12.31.16.jpg
2011-09-11\ 08.43.12.jpg)
or
FILES=("2011-09-04 21.43.02.jpg"
"2011-09-05 10.23.14.jpg"
"2011-09-09 12.31.16.jpg"
"2011-09-11 08.43.12.jpg")
or
FILES[0]="2011-09-04 21.43.02.jpg"
FILES[1]="2011-09-05 10.23.14.jpg"
FILES[2]="2011-09-09 12.31.16.jpg"
FILES[3]="2011-09-11 08.43.12.jpg"
There must be something wrong with the way you access the array's items. Here's how it's done:
for elem in "${files[#]}"
...
From the bash manpage:
Any element of an array may be referenced using ${name[subscript]}. ... If subscript is # or *, the word expands to all members of name. These subscripts differ only when the word appears within double quotes. If the word is double-quoted, ${name[*]} expands to a single word with the value of each array member separated by the first character of the IFS special variable, and ${name[#]} expands each element of name to a separate word.
Of course, you should also use double quotes when accessing a single member
cp "${files[0]}" /tmp
You need to use IFS to stop space as element delimiter.
FILES=("2011-09-04 21.43.02.jpg"
"2011-09-05 10.23.14.jpg"
"2011-09-09 12.31.16.jpg"
"2011-09-11 08.43.12.jpg")
IFS=""
for jpg in ${FILES[*]}
do
echo "${jpg}"
done
If you want to separate on basis of . then just do IFS="."
Hope it helps you:)
I agree with others that it's likely how you're accessing the elements that is the problem. Quoting the file names in the array assignment is correct:
FILES=(
"2011-09-04 21.43.02.jpg"
"2011-09-05 10.23.14.jpg"
"2011-09-09 12.31.16.jpg"
"2011-09-11 08.43.12.jpg"
)
for f in "${FILES[#]}"
do
echo "$f"
done
Using double quotes around any array of the form "${FILES[#]}" splits the array into one word per array element. It doesn't do any word-splitting beyond that.
Using "${FILES[*]}" also has a special meaning, but it joins the array elements with the first character of $IFS, resulting in one word, which is probably not what you want.
Using a bare ${array[#]} or ${array[*]} subjects the result of that expansion to further word-splitting, so you'll end up with words split on spaces (and anything else in $IFS) instead of one word per array element.
Using a C-style for loop is also fine and avoids worrying about word-splitting if you're not clear on it:
for (( i = 0; i < ${#FILES[#]}; i++ ))
do
echo "${FILES[$i]}"
done
If you had your array like this:
#!/bin/bash
Unix[0]='Debian'
Unix[1]="Red Hat"
Unix[2]='Ubuntu'
Unix[3]='Suse'
for i in $(echo ${Unix[#]});
do echo $i;
done
You would get:
Debian
Red
Hat
Ubuntu
Suse
I don't know why but the loop breaks down the spaces and puts them as an individual item, even you surround it with quotes.
To get around this, instead of calling the elements in the array, you call the indexes, which takes the full string thats wrapped in quotes.
It must be wrapped in quotes!
#!/bin/bash
Unix[0]='Debian'
Unix[1]='Red Hat'
Unix[2]='Ubuntu'
Unix[3]='Suse'
for i in $(echo ${!Unix[#]});
do echo ${Unix[$i]};
done
Then you'll get:
Debian
Red Hat
Ubuntu
Suse
This was already answered above, but that answer was a bit terse and the man page excerpt is a bit cryptic. I wanted to provide a fully worked example to demonstrate how this works in practice.
If not quoted, an array just expands to strings separated by spaces, so that
for file in ${FILES[#]}; do
expands to
for file in 2011-09-04 21.43.02.jpg 2011-09-05 10.23.14.jpg 2011-09-09 12.31.16.jpg 2011-09-11 08.43.12.jpg ; do
But if you quote the expansion, bash adds double quotes around each term, so that:
for file in "${FILES[#]}"; do
expands to
for file in "2011-09-04 21.43.02.jpg" "2011-09-05 10.23.14.jpg" "2011-09-09 12.31.16.jpg" "2011-09-11 08.43.12.jpg" ; do
The simple rule of thumb is to always use [#] instead of [*] and quote array expansions if you want spaces preserved.
To elaborate on this a little further, the man page in the other answer is explaining that if unquoted, $* an $# behave the same way, but they are different when quoted. So, given
array=(a b c)
Then $* and $# both expand to
a b c
and "$*" expands to
"a b c"
and "$#" expands to
"a" "b" "c"
Not exactly an answer to the quoting/escaping problem of the original question but probably something that would actually have been more useful for the op:
unset FILES
for f in 2011-*.jpg; do FILES+=("$f"); done
echo "${FILES[#]}"
Where of course the expression would have to be adopted to the specific requirement (e.g. *.jpg for all or 2001-09-11*.jpg for only the pictures of a certain day).
For those who prefer set array in oneline mode, instead of using for loop
Changing IFS temporarily to new line could save you from escaping.
OLD_IFS="$IFS"
IFS=$'\n'
array=( $(ls *.jpg) ) #save the hassle to construct filename
IFS="$OLD_IFS"
Escaping works.
#!/bin/bash
FILES=(2011-09-04\ 21.43.02.jpg
2011-09-05\ 10.23.14.jpg
2011-09-09\ 12.31.16.jpg
2011-09-11\ 08.43.12.jpg)
echo ${FILES[0]}
echo ${FILES[1]}
echo ${FILES[2]}
echo ${FILES[3]}
Output:
$ ./test.sh
2011-09-04 21.43.02.jpg
2011-09-05 10.23.14.jpg
2011-09-09 12.31.16.jpg
2011-09-11 08.43.12.jpg
Quoting the strings also produces the same output.
#! /bin/bash
renditions=(
"640x360 80k 60k"
"1280x720 320k 128k"
"1280x720 320k 128k"
)
for z in "${renditions[#]}"; do
echo "$z"
done
OUTPUT
640x360 80k 60k
1280x720 320k 128k
1280x720 320k 128k
`
Another solution is using a "while" loop instead a "for" loop:
index=0
while [ ${index} -lt ${#Array[#]} ]
do
echo ${Array[${index}]}
index=$(( $index + 1 ))
done
If you aren't stuck on using bash, different handling of spaces in file names is one of the benefits of the fish shell. Consider a directory which contains two files: "a b.txt" and "b c.txt". Here's a reasonable guess at processing a list of files generated from another command with bash, but it fails due to spaces in file names you experienced:
# bash
$ for f in $(ls *.txt); { echo $f; }
a
b.txt
b
c.txt
With fish, the syntax is nearly identical, but the result is what you'd expect:
# fish
for f in (ls *.txt); echo $f; end
a b.txt
b c.txt
It works differently because fish splits the output of commands on newlines, not spaces.
If you have a case where you do want to split on spaces instead of newlines, fish has a very readable syntax for that:
for f in (ls *.txt | string split " "); echo $f; end
If the elements of FILES come from another file whose file names are line-separated like this:
2011-09-04 21.43.02.jpg
2011-09-05 10.23.14.jpg
2011-09-09 12.31.16.jpg
2011-09-11 08.43.12.jpg
then try this so that the whitespaces in the file names aren't regarded as delimiters:
while read -r line; do
FILES+=("$line")
done < ./files.txt
If they come from another command, you need to rewrite the last line like this:
while read -r line; do
FILES+=("$line")
done < <(./output-files.sh)
I used to reset the IFS value and rollback when done.
# backup IFS value
O_IFS=$IFS
# reset IFS value
IFS=""
FILES=(
"2011-09-04 21.43.02.jpg"
"2011-09-05 10.23.14.jpg"
"2011-09-09 12.31.16.jpg"
"2011-09-11 08.43.12.jpg"
)
for file in ${FILES[#]}; do
echo ${file}
done
# rollback IFS value
IFS=${O_IFS}
Possible output from the loop:
2011-09-04 21.43.02.jpg
2011-09-05 10.23.14.jpg
2011-09-09 12.31.16.jpg
2011-09-11 08.43.12.jpg

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