Full invoice number + comma separated SQL list (TSQL) - sql-server

Question

Does someone perhaps know how to get a comma separated list from SQL that doesn't duplicate - it's a little hard to explain. Let me give an example.
I have a list of invoices + the shipment it belongs to in a table like below:
InvoiceNumber ShipmentNumber
0180376000 1stShipment
0180376005 1stShipment
0180376003 1stShipment
0180375997 1stShipment
0180375993 1stShipment
This list needs to be divided up into main InvoiceNumbers followed by the right 2 digits of the remaining invoice numbers. Result should look similar to the below.
01803760, 00, 05, 03, 01803759, 97, 93
At this point I can get the comma separated list fairly easily but cannot figure out how to position the 2 digit after each respective invoice that it belongs to.
Any suggestion of how to do this would be great!!

Answer 1

Try it like this
DECLARE #tbl TABLE(InvoiceNumber VARCHAR(100));
INSERT INTO #tbl VALUES
('0180376000')
,('0180376005')
,('0180376003')
,('0180375997')
,('0180375993');
WITH CutInTwo AS
(
SELECT LEFT(InvoiceNumber,8) AS Number
,RIGHT(InvoiceNumber,2) AS SubNumber
FROM #tbl
)
,OnlyMainNumbers AS
(
SELECT DISTINCT Number
FROM CutInTwo
)
SELECT y.Number + ' ' + (STUFF((SELECT ', ' + x.SubNumber FROM CutInTwo AS x WHERE x.Number=y.Number FOR XML PATH('')),1,2,''))
FROM OnlyMainNumbers AS y
If you really need this in one single string, you might wrap the final select like this:
SELECT STUFF(
(
SELECT ', ' + y.Number + ', ' + (STUFF((SELECT ', ' + x.SubNumber FROM CutInTwo AS x WHERE x.Number=y.Number FOR XML PATH('')),1,2,''))
FROM OnlyMainNumbers AS y
FOR XML PATH('')
),1,2,'')

Answer 2

Try this
DECLARE #tbl TABLE (InvoceNumber NVARCHAR(50))
INSERT INTO #tbl VALUES ('0180376000')
INSERT INTO #tbl VALUES ('0180376005')
INSERT INTO #tbl VALUES ('0180376003')
INSERT INTO #tbl VALUES ('0180375997')
INSERT INTO #tbl VALUES ('0180375993')
SELECT
(
SELECT
A.InvoceNumber + ', '
FROM
(
SELECT DISTINCT LEFT(InvoceNumber, LEN(InvoceNumber) - 2) InvoceNumber FROM #tbl
UNION ALL
SELECT RIGHT(InvoceNumber, 2) InvoceNumber FROM #tbl
) A
FOR XML PATH ('')
) Invoce
Output:
01803759, 01803760, 00, 05, 03, 97, 93,
If Order is important.
SELECT
(
SELECT
Result.InvoceNumber + ', ' + Result.Invo
FROM
(
SELECT
A.InvoceNumber,
(
SELECT
IA.Invo + ', ' AS [text()]
FROM
(
SELECT DISTINCT LEFT(InvoceNumber, LEN(InvoceNumber) - 2) InvoceNumber, RIGHT(InvoceNumber, 2) AS Invo FROM #tbl
) IA
WHERE
IA.InvoceNumber = A.InvoceNumber
FOR XML PATH ('')
) Invo
FROM
(
SELECT DISTINCT LEFT(InvoceNumber, LEN(InvoceNumber) - 2) AS InvoceNumber FROM #tbl
) A
GROUP BY
A.InvoceNumber
) Result
FOR XML PATH ('')
) S
Output:
01803759, 93, 97, 01803760, 00, 03, 05,