SSRS 2005 Previous sum of date and time - sql-server

I have an SSRS report which when I try to calculate the previous value the first line always gives incorrect value since there is no previous number for it to calculate.
=CDec(format(DateDiff("s",previous(Fields!SyncDate.Value),Fields!Date.Value)/60,"0.00"))
The value of the first line comes out 1059831848.62
Is there a way to tell it to skip first line?
Because also i need to sum it all to get total which counts the first line and gives a huge total.
My query consists of the following:
SELECT ToppingCount, DriverName, COUNT(Pizza) AS Count, Date, SyncDate, BranchName, Branch
FROM System
WHERE (Date BETWEEN #datefrom AND #DateTo) AND (Branch IN (#branch)) AND (SystemSource = 'newsys') AND (SystemSource <> 'oldsys')
GROUP BY Pizza, ToppingCount, DriverName, Date, SyncDate, BranchName, Branch
ORDER BY Branch, DriverName, Date
Thanks

You could add a Row_Number column to your query like so..
SELECT ToppingCount,
DriverName,
COUNT(Pizza) AS Count,
Date,
SyncDate,
BranchName,
Branch,
ROW_NUMBER() OVER (ORDER BY Branch,DriverName,Date) Rn
FROM System
WHERE (Date BETWEEN #datefrom AND #DateTo)
AND (Branch IN (#branch))
AND (SystemSource = 'newsys')
AND (SystemSource <> 'oldsys')
GROUP BY Pizza,
ToppingCount,
DriverName,
Date,
SyncDate,
BranchName,
Branch
ORDER BY Branch,
DriverName,
Date
Then just check to see if you are on Rn = 1 before you do your calculation.
=iif(Fields!Rn.Value = 1, "", CDec(format(DateDiff("s",previous(Fields!SyncDate.Value),Fields!Date.Value)/60,"0.00")))
or
=iif(Fields!Rn.Value = 1, 0, CDec(format(DateDiff("s",previous(Fields!SyncDate.Value),Fields!Date.Value)/60,"0.00")))
if you need to reset the Row_Number for groupings, you can add Partition By to reset the number to 1

You can check the value of the previous sync date field and output a 0 or blank if required.
=CDec(iif(IsNothing(previous(Fields!SyncDate.Value)), 0.0, format(DateDiff("s",previous(Fields!SyncDate.Value),Fields!Date.Value)/60,"0.00")))
Without row_number you can use an outer apply to get the last sync date in the query and pre-calculate the 'sync delta':
SELECT
p.ToppingCount,
p.DriverName,
p.Date,
p.SyncDate,
CASE
WHEN i.SynchDate IS NULL THEN 0.0
ELSE DATEDIFF(SS, l.SyncDate, p.Date) / 60.0
END AS SyncTimeDelta,
p.BranchName,
p.Branch,
COUNT(p.Pizza) AS Count
FROM System p
OUTER APPLY
(
-- Join clause depends on how you're grouping
-- in the report.
SELECT TOP 1
i.SyncDate
FROM System i
WHERE
i.SystemSource = 'newsys'
AND i.Branch = p.Branch
AND i.DriverName = p.DriverName
AND i.Date < p.Date
ORDER BY
i.SyncDate DESC
) l
WHERE
(p.Date BETWEEN #datefrom AND #DateTo) AND
(p.Branch IN (#branch)) AND
(p.SystemSource = 'newsys') AND
(p.SystemSource <> 'oldsys') -- This will never be evaluated
GROUP BY
p.Pizza, p.ToppingCount, p.DriverName, p.Date, p.SyncDate, p.BranchName, p.Branch, l.SyncDate
ORDER BY
p.Branch, p.DriverName, p.Date
This way you can just sum the sync delta in the report. I don't know enough about the query but I've made the assumption that:
You want the time between the last sync date before the current [date] column as per your formula for the given branch and driver.
I apologize if there are syntax issues, I'm typing this up without reference.

Related

SQL SELECT Date based on multiple conditions

I have a set of date in a Table which contains weekly date.
I want to select the following:
If the date is less than 2 months old then i want to select all the date (weekly).
If the date is more than 2 months old then i only want to select the last date of each month (monthly).
I tried the following code:
SELECT DISTINCT(Date) FROM [Table] WHERE Date IN
(CASE
WHEN Date> DATEADD(month, -2, GETDATE())
THEN Date
ELSE MAX(Date) GROUP BY Month(Date),Year(Date)
);
But without success:
Incorrect syntax near the keyword 'GROUP'.
If for instance the current Date is 13/09/2022,
13/09/2022 - 2 months = 13/07/2022
If i have the following Date in my Table:
06/05/2022
13/05/2022
20/05/2022
31/05/2022
07/06/2022
10/06/2022
17/06/2022
24/06/2022
30/06/2022
08/07/2022 (<13/07/2022)
15/07/2022 (>13/07/2022)
22/07/2022
29/07/2022
05/08/2022
12/08/2022
19/08/2022
26/08/2022
Then the final output should be:
31/05/2022
30/06/2022 (<13/07/2022)
15/07/2022 (>13/07/2022)
22/07/2022
29/07/2022
05/08/2022
12/08/2022
19/08/2022
26/08/2022
Your syntax is completely invalid, I'm not going to bother fixing it.
DISTINCT is not a function, it works over the whole set of columns.
You can't use aggregates inside a WHERE, even if they would be window functions (which they're not).
The GROUP BY is inside a CASE which makes no sense.
Instead I'm just going off your requirements
If the date is less than 2 months old then I want to select all the date (weekly).
If the date is more than 2 months old then I only want to select the last date of each month (monthly).
You can use a ROW_NUMBER strategy for this.
SELECT
t.Date
FROM (
SELECT *,
rn = ROW_NUMBER() OVER (PARTITION BY EOMONTH(t.Date) ORDER BY t.Date DESC)
FROM [Table] t
) t
WHERE (
t.Date > DATEADD(month, -2, GETDATE())
OR rn = 1
)
ORDER BY
Date;

Calculating Days Between Dates in Separate Rows For Same UnitID

I am trying to calculate the time a commercial real estate space sits vacant. I have move-in & move-out dates for each tenant that has occupied that unit. It is easy to calculate the occupied time of each tenant as that data is within the same row. However, I want to calculate the vacant time: the time between move-out of the previous tenant and move-in of the next tenant. These dates appear in separate rows.
Here is a sample of what I have currently:
SELECT
uni_vch_UnitNo AS UnitNumber,
uty_vch_Code AS UnitCode,
uty_int_Id AS UnitID, tul_int_FacilityId AS FacilityID,
tul_dtm_MoveInDate AS Move_In_Date,
tul_dtm_MoveOutDate AS Move_Out_Date,
DATEDIFF(day, tul_dtm_MoveInDate, tul_dtm_MoveOutDate) AS Occupancy_Days
FROM TenantUnitLeases
JOIN units
ON tul_int_UnitId = uni_int_UnitId
JOIN UnitTypes
ON uni_int_UnitTypeId = uty_int_Id
WHERE
tul_int_UnitId = '26490'
ORDER BY tul_dtm_MoveInDate ASC
Is there a way to assign an id to each row in chronological, sequential order and find the difference between row 2 move-in date less row 1 move-out date and so on?
Thank you in advance for the help.
I can't really tell which tables provide which columns for your query. Please alias and dot-qualify them in the future.
If you're using SQL 2012 or later, you've got LEAD and LAG functions which do exactly what you want: bring a "leading" or "lagging" row into a current row. See if this works (hopefully it should at least get you started):
SELECT
uni_vch_UnitNo AS UnitNumber,
uty_vch_Code AS UnitCode,
uty_int_Id AS UnitID, tul_int_FacilityId AS FacilityID,
tul_dtm_MoveInDate AS Move_In_Date,
tul_dtm_MoveOutDate AS Move_Out_Date,
DATEDIFF(day, tul_dtm_MoveInDate, tul_dtm_MoveOutDate) AS Occupancy_Days
, LAG(tul_dtm_MoveOutDate) over (partition by uni_vch_UnitNo order by tul_dtm_MoveOutDate) as Previous_Move_Out_Date
, DATEDIFF(day,LAG(tul_dtm_MoveOutDate) over (partition by uni_vch_UnitNo order by tul_dtm_MoveOutDate),tul_dtm_MoveInDate) as Days_Vacant
FROM TenantUnitLeases
JOIN units
ON tul_int_UnitId = uni_int_UnitId
JOIN UnitTypes
ON uni_int_UnitTypeId = uty_int_Id
WHERE
tul_int_UnitId = '26490'
ORDER BY tul_dtm_MoveInDate ASC
Just comparing a value from the current row with a value in the previous row is functionality provided by the lag() function.
Try this in your query:
select...
tul_dtm_MoveInDate AS Move_In_Date,
tul_dtm_MoveOutDate AS Move_Out_Date,
DateDiff(day, Lag(tul_dtm_MoveOutDate,1) over(partition by uty_vch_Code, tul_int_FacilityId order by tul_dtm_MoveInDate), tul_dtm_MoveInDate) DaysVacant,
...
This needs a window function or correlated sub query. The goal is to provide the previous move out date for each row, which is in turn a function of that row. The term 'window' in this context means to apply an aggregate function over a smaller range than the whole set.
If you had a function called GetPreviousMoveOutDate, the parameters would be the key to filter on, and the ranges to search within the filter. So we would pass the UnitID as the key and the MoveInDate for this row, and the function should return the most recent MoveOutDate for the same unit that is before the passed in date. By getting the max date before this one, we will ensure we get only the previous occupancy if it exists.
To use a sub-query in ANSI-SQL you just add the select as a column. This should work on MS-SQL as well as other DB platforms; however, it requires using aliases for the table names so they can be referenced in the query more than once. I've updated your sample SQL with aliases using the AS syntax, although it looks redundant to your table naming convention. I added a uni_dtm_UnitFirstAvailableDate to your units table to handle the first vacancy, but this can be a default:
SELECT
uni.uni_vch_UnitNo AS UnitNumber,
uty.uty_vch_Code AS UnitCode,
uty.uty_int_Id AS UnitID, tul_int_FacilityId AS FacilityID,
tul.tul_dtm_MoveInDate AS Move_In_Date,
tul.tul_dtm_MoveOutDate AS Move_Out_Date,
DATEDIFF(day, tul.tul_dtm_MoveInDate, tul.tul_dtm_MoveOutDate) AS Occupancy_Days,
-- select the date:
(SELECT MAX (prev_tul.tul_dtm_MoveOutDate )
FROM TenantUnitLeases AS prev_tul
WHERE prev_tul.tul_int_UnitId = tul.tul_int_UnitId
AND prev_tul.tul_dtm_MoveOutDate > tul.tul_dtm_MoveInDate
AND prev_tul.tul_dtm_MoveOutDate is not null
) AS previous_moveout,
-- use the date in a function:
DATEDIFF(day, tul.tul_dtm_MoveInDate,
ISNULL(
(SELECT MAX (prev_tul.tul_dtm_MoveOutDate )
FROM TenantUnitLeases AS prev_tul
WHERE prev_tul.tul_int_UnitId = tul.tul_int_UnitId
AND prev_tul.tul_dtm_MoveOutDate > tul.tul_dtm_MoveInDate
AND prev_tul.tul_dtm_MoveOutDate is not null
) , uni.uni_dtm_UnitFirstAvailableDate) -- handle first occupancy
) AS Vacancy_Days
FROM TenantUnitLeases AS tul
JOIN units AS uni
ON tul.tul_int_UnitId = uni.uni_int_UnitId
JOIN UnitTypes AS uty
ON uni.uni_int_UnitTypeId = uty.uty_int_Id
WHERE
tul.tul_int_UnitId = '26490'
ORDER BY tul.tul_dtm_MoveInDate ASC

SQL Server contiguous dates - summarizing multiple rows into contiguous start and end date rows without CTE's, loops,...s

Is it possible to write an sql query that will summarize rows with start and end dates into rows that have contiguous start and end dates?
The constraint is that it has to be regular sql, i.e. no CTE's, loops and the like as a third party tool is used that only allows an sql statement to start with Select.
e.g.:
ID StartDate EndDate
1001, Jan-1-2018, Jan-04-2018
1002, Jan-5-2018, Jan-13-2018
1003, Jan-14-2018, Jan-18-2018
1004, Jan-25-2018, Feb-05-2018
The required output needs to be:
Jan-1-2018, Jan-18-2018
Jan-25-2018, Feb-05-2018
Thank you
You can take advantage of both window functions and the use of a concept called gaps-and-islands. In your case, contiguous dates would be the island, and the the gaps are self explanatory.
I wrote the answer below in a verbose way to help make it clear what the query is doing, but it could most likely be written in a different way that is more concise. Please see my comments in the answer explaining what each step (sub-query) does.
--Determine Final output
select min(c.StartDate) as StartDate
, max(c.EndDate) as EndDate
from (
--Assign a number to each group of Contiguous Records
select b.ID
, b.StartDate
, b.EndDate
, b.EndDatePrev
, b.IslandBegin
, sum(b.IslandBegin) over (order by b.ID asc) as IslandNbr
from (
--Determine if its Contiguous (IslandBegin = 1, means its not Contiguous with previous record)
select a.ID
, a.StartDate
, a.EndDate
, a.EndDatePrev
, case when a.EndDatePrev is NULL then 1
when datediff(d, a.EndDatePrev, a.StartDate) > 1 then 1
else 0
end as IslandBegin
from (
--Determine Prev End Date
select tt.ID
, tt.StartDate
, tt.EndDate
, lag(tt.EndDate, 1, NULL) over (order by tt.ID asc) as EndDatePrev
from dbo.Table_Name as tt
) as a
) as b
) as c
group by c.IslandNbr
order by c.IslandNbr
I hope following SQL query can help you to identify gaps and covered dates for given case
I did not use a CTE expression of a dates table function, etc
On the other hand, I used a numbers table using master..spt_values to generate the dates table as the main table of a LEFT join
You can create a numbers table or a dates table if it does not fit to your requirements
In the query, to catch changes between borders I used SQL LAG() function which enables me to compare with previous value of a column in a sorted list
select
max(startdate) as startdate,
max(enddate) as enddate
from (
select
date,
case when exist = 1 then date else null end as startdate,
case when exist = 0 then dateadd(d,-1,date) else null end as enddate,
( row_number() over (order by date) + 1) / 2 as rn
from (
select date, exist, case when exist <> (lag(exist,1,'') over (order by date)) then 1 else 0 end as changed
from (
select
d.date,
case when exists (select * from Periods where d.date between startdate and enddate) then 1 else 0 end as exist
from (
SELECT dateadd(dd,number,'20180101') date
FROM master..spt_values
WHERE Type = 'P' and dateadd(dd,number,'20180101') <= '20180228'
) d
) cte
) tbl
where changed = 1
) dates
group by rn
Here is the result

T-SQL - get only latest row for selected condition

I have table with measurement with column SERIAL_NBR, DATE_TIME, VALUE.
There is a lot of data so when I need them to get the last 48 hours for 2000 devices
Select * from MY_TABLE where [TIME]> = DATEADD (hh, -48, #TimeNow)
takes a very long time.
Is there a way not to receive all the rows for each device, but only the latest entry? Would this speed up the query execution time?
Assuming that there is column named deviceId(change as per your needs), you can use top 1 with ties with window function row_number:
Select top 1 with ties *
from MY_TABLE
where [TIME]> = DATEADD (hh, -48, #TimeNow)
Order by row_number() over (
partition by deviceId
order by Time desc
);
You can simply create Common Table Expression that sorts and groups the entries and then pick the latest one from there.
;WITH numbered
AS ( SELECT [SERIAL_NBR], [TIME], [VALUE], row_nr = ROW_NUMBER() OVER (PARTITION BY [SERIAL_NBR] ORDER BY [TIME] DESC)
FROM MY_TABLE
WHERE [TIME]> = DATEADD (hh, -48, #TimeNow) )
SELECT [SERIAL_NBR], [TIME], [VALUE]
FROM numbered
WHERE row_nr = 1 -- we want the latest record only
Depending on the amount of data and the indexes available this might or might not be faster than Anthony Hancock's answer.
Similar to his answer you might also try the following:
(from MSSQL's point of view, the below query and Anthony's query are pretty much identical and they'll probably end up with the same query plan)
SELECT [SERIAL_NBR] , [TIME], [VALUE]
FROM MY_TABLE AS M
JOIN (SELECT [SERIAL_NBR] , max_time = MAX([TIME])
FROM MY_TABLE
GROUP BY [SERIAL_NBR]) AS L -- latest
ON L.[SERIAL_NBR] = M.[SERIAL_NBR]
AND L.max_time = M.[TIME]
WHERE M.DATE_TIME >= DATEADD(hh,-48,#TimeNow)
Your listed column values and your code don't quite match up so you'll probably have to change this code a little, but it sounds like for each SERIAL_NBR you want the record with the highest DATE_TIME in the last 48 hours. This should achieve that result for you.
SELECT SERIAL_NBR,DATE_TIME,VALUE
FROM MY_TABLE AS M
WHERE M.DATE_TIME >= DATEADD(hh,-48,#TimeNow)
AND M.DATE_TIME = (SELECT MAX(_M.DATE_TIME) FROM MY_TABLE AS _M WHERE M.SERIAL_NBR = _M.SERIAL_NBR)
This will get you details of the latest record per serial number:
Select t.SERIAL_NBR, q.FieldsYouWant
from MY_TABLE t
outer apply
(
selct top 1 t2.FieldsYouWant
from MY_TABLE t2
where t2.SERIAL_NBR = t.SERIAL_NBR
order by t2.[TIME] desc
)q
where t.[TIME]> = DATEADD (hh, -48, #TimeNow)
Also, worth sticking DATEADD (hh, -48, #TimeNow) into a variable rather than calculating inline.

T-SQL - Get last as-at date SUM(Quantity) was not negative

I am trying to find a way to get the last date by location and product a sum was positive. The only way i can think to do it is with a cursor, and if that's the case I may as well just do it in code. Before i go down that route, i was hoping someone may have a better idea?
Table:
Product, Date, Location, Quantity
The scenario is; I find the quantity by location and product at a particular date, if it is negative i need to get the sum and date when the group was last positive.
select
Product,
Location,
SUM(Quantity) Qty,
SUM(Value) Value
from
ProductTransactions PT
where
Date <= #AsAtDate
group by
Product,
Location
i am looking for the last date where the sum of the transactions previous to and including it are positive
Based on your revised question and your comment, here another solution I hope answers your question.
select Product, Location, max(Date) as Date
from (
select a.Product, a.Location, a.Date from ProductTransactions as a
join ProductTransactions as b
on a.Product = b.Product and a.Location = b.Location
where b.Date <= a.Date
group by a.Product, a.Location, a.Date
having sum(b.Value) >= 0
) as T
group by Product, Location
The subquery (table T) produces a list of {product, location, date} rows for which the sum of the values prior (and inclusive) is positive. From that set, we select the last date for each {product, location} pair.
This can be done in a set based way using windowed aggregates in order to construct the running total. Depending on the number of rows in the table this could be a bit slow but you can't really limit the time range going backwards as the last positive date is an unknown quantity.
I've used a CTE for convenience to construct the aggregated data set but converting that to a temp table should be faster. (CTEs get executed each time they are called whereas a temp table will only execute once.)
The basic theory is to construct the running totals for all of the previous days using the OVER clause to partition and order the SUM aggregates. This data set is then used and filtered to the expected date. When a row in that table has a quantity less than zero it is joined back to the aggregate data set for all previous days for that product and location where the quantity was greater than zero.
Since this may return multiple positive date rows the ROW_NUMBER() function is used to order the rows based on the date of the positive quantity day. This is done in descending order so that row number 1 is the most recent positive day. It isn't possible to use a simple MIN() here because the MIN([Date]) may not correspond to the MIN(Quantity).
WITH x AS (
SELECT [Date],
Product,
[Location],
SUM(Quantity) OVER (PARTITION BY Product, [Location] ORDER BY [Date] ASC) AS Quantity,
SUM([Value]) OVER(PARTITION BY Product, [Location] ORDER BY [Date] ASC) AS [Value]
FROM ProductTransactions
WHERE [Date] <= #AsAtDate
)
SELECT [Date], Product, [Location], Quantity, [Value], Positive_date, Positive_date_quantity
FROM (
SELECT x1.[Date], x1.Product, x1.[Location], x1.Quantity, x1.[Value],
x2.[Date] AS Positive_date, x2.[Quantity] AS Positive_date_quantity,
ROW_NUMBER() OVER (PARTITION BY x1.Product, x1.[Location] ORDER BY x2.[Date] DESC) AS Positive_date_row
FROM x AS x1
LEFT JOIN x AS x2 ON x1.Product=x2.Product AND x1.[Location]=x2.[Location]
AND x2.[Date]<x1.[Date] AND x1.Quantity<0 AND x2.Quantity>0
WHERE x1.[Date] = #AsAtDate
) AS y
WHERE Positive_date_row=1
Do you mean that you want to get the last date of positive quantity come to positive in group?
For example, If you are using SQL Server 2012+:
In following scenario, when the date going to 01/03/2017 the summary of quantity come to 1(-10+5+6).
Is it possible the quantity of following date come to negative again?
;WITH tb(Product, Location,[Date],Quantity) AS(
SELECT 'A','B',CONVERT(DATETIME,'01/01/2017'),-10 UNION ALL
SELECT 'A','B','01/02/2017',5 UNION ALL
SELECT 'A','B','01/03/2017',6 UNION ALL
SELECT 'A','B','01/04/2017',2
)
SELECT t.Product,t.Location,SUM(t.Quantity) AS Qty,MIN(CASE WHEN t.CurrentSum>0 THEN t.Date ELSE NULL END ) AS LastPositiveDate
FROM (
SELECT *,SUM(tb.Quantity)OVER(ORDER BY [Date]) AS CurrentSum FROM tb
) AS t GROUP BY t.Product,t.Location
Product Location Qty LastPositiveDate
------- -------- ----------- -----------------------
A B 3 2017-01-03 00:00:00.000

Resources