I have a script starting with a shebang stored in a string. I would like to execute this script without writing it in a temporary file.
I saw that execve takes a filename as argument. Is it possible to do the same with a script in memory.
A script is not directly executable, when executing a script, the kernel identify which interpreter to launch then pass the file name as an argument to the interpreter, in your case a shell.
Should you want to execute a script stored in a string, you might directly launch the shell of your choice and pass your string as its standard input through a pipe.
Here is way to do it using popen:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, char *argv[])
{
FILE *fp;
char *prefix="/bin/bash <<'%EOF%'\n";
char *script="#!/bin/bash\necho foo\ndate\n";
char *suffix="%EOF%\n";
char *command;
char buf[1024];
command=malloc(strlen(prefix)+strlen(script)+strlen(suffix)+1);
sprintf(command,"%s%s%s",prefix,script,suffix);
fp=popen(command, "r");
if(fp == NULL) {
perror("Error\n");
exit(1);
}
while(fgets(buf, sizeof(buf), fp) != NULL) {
printf("%s", buf);
}
pclose(fp);
return 0;
}
As you say that the script starts with a shebang string, you cannot directly pipe it into the standard input of a shell. But you can mimic what a shell would have done:
extract the shell command from the shebang line
start it with a pipe as standard input
pipe the remaining of the script into that shell command
A more generalist version would control whether the script string starts with a #!. If it does, use the above way, else just pipe the whole string into an instance of /bin/sh (or whatever shell you are used to)
Related
I am using MS visual studio 2008, for C coding.
I know we can use
"int system(const char *command)" to execute commands.
Is there any other method to execute system commands in C program.
Also I need to store output of executed command in a variable.
system() function execute command and send output to stdout , is there any way to read from stdout and store in variable.
So my ultimate goal is to execute system command in C program for windows (using visual studio) and store output of that command in a variable.
Any suggestions ?
Standard C libraries give you only one way to execute external command in OS, so use int system(const char *command).
You can save output of this command to text file, and then read this file from you program.
For example:
#include <stdio.h>
#include <stdlib.h>
#define TMP_FILE_NAME "TMP_FOLDER_CONTENT.txt"
int main(int argc, char *argv[])
{
system("dir C:\* > "TMP_FILE_NAME);
FILE * fdir = fopen(TMP_FILE_NAME, "r");
char buff[100];
if (fdir)
{
while (1) {
if (fgets(buff, 100, fdir) == NULL) break;
printf("%s", buff);
}
}
fclose(fdir);
remove(TMP_FILE_NAME);
return 0;
}
Where dir is a program to be executed, C:\* - argument of the program, and > - redirection of standard output for that command after which filename TMP_FOLDER_CONTENT.txt will be substituted.
Also you can check returned value, as:
int errorcode = system("dir C:\* > "TMP_FILE_NAME);
printf("Command executed and returned a value %d\n", errorcode);
or taking into account command you use, change the logic of your program, e.g.:
int errorcode = system("dir C:\* > "TMP_FILE_NAME);
if( errorcode )
{
return errorcode;
}
UPDATE:
Alternatively, you could use pipes in C++, for example as shown in the answer to question How to execute a command and get output of command within C++ using POSIX?
you can do as #VolAnd said or also if you don't care about/don't want the output of the command to be in stdout and you also don't want anything else to be printed to stdout you can use freopen to set stdout to a file of your choice.
I have the following code to find the release of the Linux distribution that I am using.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
return print_osinfo();
}
int print_osinfo()
{
FILE *fp;
extern FILE* popen();
char buffer[128];
int index = 0;
memset(buffer,0,sizeof(buffer));
fp = popen("/etc/centos-release", "r");
if(!fp)
{
pclose(fp);
fp = popen("/etc/redhat-release", "r");
if(!fp)
{
pclose(fp);
return 1;
}
}
while(fgets(buffer, sizeof(buffer), fp)!= NULL)
{
printf("%s\n",buffer);
}
pclose(fp);
return 0;
}
If I run the above code on Ubuntu 14.04 I get the following error.
sh: 1: /etc/centos-release: not found
I fail to understand why it is not trying to open redhat-release and then return -1. Also, is there a way to prevent the above error from being displayed on the screen?
popen is a function more suited for accessing the output of a subprocess than for simply accessing the contents of a file. For that, you should use fopen. fopen takes a file path and a mode as arguments, so all you would need to do is replace your popens with fopens and it should work perfectly.
If you really want to use popen, it takes a shell command as it's first argument, not a filename. Try popen("cat /etc/centos-release","r"); instead.
Now, you might be a bit confused, because both of these functions return a FILE pointer. fopen returns a pointer to the file you passed as an argument. popen, however, returns a pipe pointing to the output of the command you passed to it, which C sees as a FILE pointer. This is because, in C, all i/o is file access; C's only connection to the outside world is through files. So, in order to pass the output of some shell command, popen creates what C sees as a FILE in memory, containing the output of said shell command. Since it is rather absurd to run a whole other program (the shell command) just to do what fopen does perfectly well, it makes far more sense to just use fopen to read from files that already exist on disk.
I have a binary called TEST which spawns a bash shell, I was hoping to write a C program that runs TEST and then passes commands to the bash shell that it spawns - I have tried the following - can someone indicate if this is possible. I can run the file using, but don't know how to then pass commands to shell it spawns:
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
int main()
{
system("/var/testfolder/TEST"); #run the test file
return 0;
}
The UNIX styled popen() function is what you want to use.
See the man page for specifics.
It runs your command in a subprocess and gives you a pipe to interact with it. It returns a FILE handle like fopen() does, but you close it with pclose() rather than fclose(). Otherwise you can interact with the pipe the same way as for a file stream. Very easy to use and useful.
Here's a link to a use case example
Also check out this example illustrating a way to do what you are trying to do:
#include <stdio.h>
int main(void) {
FILE *in;
extern FILE *popen();
char buf[512];
if (!(in = popen("ls -sail", "r")))
exit(1);
while (fgets(buf, sizeof(buf), in) != NULL)
printf("%s", buf);
pclose(in);
}
Basically what I want to do is have a program with int main(argc, *argv[]) and instead of writing chars into command line, I want to have my program read those words from a file. How could I accomplish this? Is there a special command in Linux for that?
You can use standard redirect operations in a *nix shell to pass files as input:
./myprogram < inputfile.txt
This statement executes your program (myprogram) and pumps the data inside of inputfile.txt to your program
You can also redirect the output of program to a file in a similar fashion:
./myprogram > outputfile.txt
Instead of doing
for(int i = 1; i < argc; i++)
{
insert(&trie, argv[i]);
}
you could doing something like
FILE *input;
char *line;
....
while (fscanf(input, "%ms", &line) != EOF) {
insert(&trie, line);
/* If you make a copy of line in `insert()`, you should
* free `line` at here; if you do not, free it later. */
free(line);
}
Use redirection
yourprogram < youtextfile
will offer the content of yourtextfile as standard input (stdin) to yourprogram. Likewise
yourprogram > yourothertextfile
will send everything the program writes to standard output (stdout) to yourothertextfile
You'll notice when reading man pages that most system calls have a version that works directly with stdin or stdout
For example consider the printf family:
printf ("hello world\n");
is a shorter version of
fprintf (stdout,"hello world\n");
and the same goes for scanf and stdin.
This is only the most basic usage of redirection, which in my opinion is one of the key aspects of "the unix way of doing things". As such, you'll find lots of articles and tutorials that show examples that are a lot more advanced than what I wrote here. Have a look at this Linux Documentation Project page on redirection to get started.
EDIT: getting fed input via redirection ior interactively "looks" the same to the program, so it will react the same to redirected input as it does to console input. This means that if your program expects data line-wise (eg because it uses gets() to read lines), the input text file should be organized in lines.
By default, every program you execute on POSIX-compliant systems has three file descriptors open (see <unistd.h> for the macros' definition): the standard input (STDOUT_FILENO), the standard output (STDOUT_FILENO), and the error output (STDERR_FILENO), which is tied to the console.
Since you said you want read lines, I believe the ssize_t getline(char **lineptr, size_t *n, FILE *stream) function can do the job. It takes a stream (FILE pointer) as a third argument, so you must either use fopen(3) to open a file, or a combination of open(2) and fdopen(3).
Getting inspiration from man 3 getline, here is a program demonstrating what you want:
#define _GNU_SOURCE
#include <stddef.h>
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char *argv[])
{
FILE *fp;
size_t len;
char *line;
ssize_t bytes_read;
len = 0;
line = NULL;
if (argc > 1)
{
fp = fopen(argv[1], "r");
if (fp == NULL)
{
perror(*argv);
exit(EXIT_FAILURE);
}
}
else
fp = stdin;
while ((bytes_read = getline(&line, &len, fp)) != -1)
printf("[%2zi] %s", bytes_read, line);
free(line);
exit(EXIT_SUCCESS);
}
Without arguments, this program reads lines from the standard input: you can either feed it lines like echo "This is a line of 31 characters" | ./a.out or execute it directly and write your input from there (finish with ^D).
With a file as an argument, it will output every line from the file, and then exit.
You can have your executable read its arguments on the command line and use xargs, the special Linux command for passing the contents of a file to a command as arguments.
An alternative to xargs is parallel.
Automating diskpart commands in windows requires pointing to a .txt file that contains the sequence of commands you want to execute. I am writing a C program that needs to use this automated feature. I want to have it run completely independent of the working directory. How would I do this?
Either use a fully qualified name for the file, or, with a bit more work, pass the commands from the C program to diskpart through an anonymous pipe using popen.
Example added:
#include <stdio.h>
int main ( int argc, char *argv[] )
{
char buffer[MAXBUF];
FILE *fp = popen("gzip -dc data.gz","r");
while (fgets(buffer,MAXBUF,fp)) {
/* Process line of data, here just print it out… */
fputs(buffer,stdout);
}
printf ("Command exit status %d\n", pclose(fp));
}