Replace XML Span Element with Inner text of Span Tag in SQL Server - sql-server

Question

Replace span Element with its inner text whose class is "TAGGED_ITEM " in multiple rows with a column of type XML
<Item title="1234" xmlns="http://www.imsglobal.org/xsd/imsqti_v2p2">
<ItemBody>
<div class="item_text">
<div>
<span class="TAGGED_ITEM " id="c1_ae1">This is a map on a grid.</span>
<span class="TAGGED_ITEM " id="c1_ae2"> It shows a car.</span>
</div>
<span class="TAGGED_ITEM " id="c1_ae3"> It shows a car on Road.</span>
</div>
</ItemBody>
</Item>
Once Element is updated it should looks as below.
<Item title="1234" xmlns="http://www.imsglobal.org/xsd/imsqti_v2p2">
<ItemBody>
<div class="item_text">
<div>
This is a map on a grid.
It shows a car.
</div>
It shows a car on Road.
</div>
</ItemBody>
</Item>

Answer 1

This question had a particular namespace problem which, probably, had aroused the question. Eliminating namespaces on the match= does solve the problem. So an identity transform and a namespace-neutral matching gives the desired result:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[local-name() = 'span']">
<xsl:value-of select="text()" />
</xsl:template>
</xsl:stylesheet>
Result:
<?xml version="1.0"?>
<Item xmlns="http://www.imsglobal.org/xsd/imsqti_v2p2" title="1234">
<ItemBody>
<div class="item_text">
<div>
This is a map on a grid.
It shows a car.
</div>
</div>
</ItemBody>
</Item>