Transfer XML file with a languages section to a database table using XSLT - sql-server

Question

below is a part of the xml file I get. I want to transfer this to a single mssql database table. My problem are the different languages of each job-element. The three languages below won't change in time.
I want to create 2 columns for each language in the db-table.
Example: EnglishTitle & EnglishDescription
<jobs>
<job nr="1">
<language name="English">
<title>English title</title>
<description>
<li>English description</li>
<li>English description 2</li>
<li>English description 3</li>
</description>
</language>
<language name="German">
<title>German title</title>
<description>German description</description>
</language>
<language name="Chinese">
<title>Business Mission Chinese</title>
<description>German description</description>
</language>
<general>For all languages</general>
</job>
</jobs>
How can I use XSLT to lookup the language name attribute and create two elements for each language with the content of the name attribute?
UPDATE:
This is what I think the output should look like:
<jobs>
<job nr="1">
<EnglishTitle>English title</EnglishTitle>
<EnglishDescription>
<li>English description</li>
<li>English description 2</li>
<li>English description 3</li>
</EnglishDescription>
<GermanTitle>German title</GermanTitle>
<GermanDescription>German description</GermanDescription>
<ChineseTitle>Business Mission Chinese</ChineseTitle>
<ChineseDescription>Chinese description</ChineseDescription>
<general>For all languages</general>
</job>
</jobs>
Additionally how should I store the <li>-Elements
of a description in the table? Should I replace them with new lines or with a special character?
If there is a better way feel free to tell me.

Answer 1

IMHO, you should have a separate row for each individual description, with columns describing the job number (hopefully unique), the language and the description itself. So something like:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/jobs">
<table>
<xsl:for-each select="job/language/description/text() | job/language/description/li ">
<row>
<col><xsl:value-of select="ancestor::job/#nr"/></col>
<col><xsl:value-of select="ancestor::language/#name"/></col>
<col><xsl:value-of select="."/></col>
</row>
</xsl:for-each>
</table>
</xsl:template>
</xsl:stylesheet>
which in your example would return:
<?xml version="1.0" encoding="utf-8"?>
<table>
<row>
<col>1</col>
<col>English</col>
<col>English description</col>
</row>
<row>
<col>1</col>
<col>English</col>
<col>English description 2</col>
</row>
<row>
<col>1</col>
<col>English</col>
<col>English description 3</col>
</row>
<row>
<col>1</col>
<col>German</col>
<col>German description</col>
</row>
<row>
<col>1</col>
<col>Chinese</col>
<col>German description</col>
</row>
</table>