Please help me to compile this C program? [Linux] - c

Question

I am using Linux now, and trying to compile this by gcc BUT.......
this is my truly simple code:
#include <stdio.h>
int main(){
printf("Hello world\n");
return 0;
}
and this is so much weird output:
./try.c: line 3: syntax error near unexpected token `('
./try.c: line 3: `int main(){'
why is it?
I have tried the right way to compile it, such:
gcc file_name.c -o file_name and other types of way of compiling
chmod +rwx file_name.c
./file_name.c
but still I got that result, why?

Answer 1

You have to compile the code first.
Follow these steps.
gcc try.c -o try.out
to compile the code. The -o option is given to give a custom name to the executable that will be produced.
Then, you can run it by typing
./try.out
To run the executable.
Be informed though, that there are a number of command line options that you can use to get the information about your code and add more functionality. See this page for more information.

Answer 2

You are trying to execute the .c file, remove the trailing .c from the name of the file you want to execute.
Like this:
gcc -Wall -Wextra -pedantic -Werror -o executable file_name.c
You should not need to make it executable, it should already be executable since the compiler will do that.
./executable
As you see, I've passed some parameters to gcc to let it help in diagnosing problems, sometimes these problems are caused by your lack of knowledge and some other times because you write code quickly and miss some details. So using them is good (although compilation is slower, but that doesn't matter if you have a good and fast machine, wehreas having issues in the code does matter).
The meaning of these flags are as follows
-Wall Enable all warnings. Really some are not enabled, but most are.
-Wextra Enable extra warnings.
-pedantic make the compiler pedantic, i.e. stick strictly to the desired (default for this version of gcc) standard.
-Werror Consider that warnings are errors.
Also, you could have guessed this if you see what the error says
./try.c: line 3: syntax error near unexpected token `('
./try.c: line 3: `int main(){'
as you can see the shell is trying to execute the source code as if it was a shell script, so you can immediately notice that this is not the executable file generated by gcc, and then you would notice the .c in the file name.

Answer 3

Try
gcc try.c
./a.out
Compiles the code and runs it. Please read the manual page for gcc and there are many delights to behold (extra checking etc)