Calculating total number of adjacent integers - c

Question

I want to calculate the number of integers excluding repeats line by line from the file.
The output I desire is:
Duplicates : 9
Duplicates : 4
Duplicates : 5
Duplicates : 5
Duplicates : 1
Duplicates : 1
Duplicates : 8
For further explanation of the concept:
Take the second line of the file:
1 2 3 4 5 6 5 4 5
At this line there is a 1 so increment the counter because 1 was found first.
Next comes a 2, 2 is not 1 so increment the counter. Next comes a 3, 3 is not a 2 so increment the counter. Next comes a 4, 4 is not a 3 so increment the counter. Next comes a 5, 5 is not a 4 so increment the counter. Next comes a 6, 6 is not a 5 so increment the counter. Next comes a 5, 5 is not a 6 so increment the counter. Next comes a 4, 4 is not a 5 so increment the counter. Next comes a 5, 5 is not a 4 so increment the counter. The number of integers excluding repeats is 9.
Another example:
Take a look a line 8 of the file:
34 34 34 34 34
At this line there is a 34 so increment the counter. Next comes a 34, 34 is 34 so do not increment the counter. Next comes 34, 34 is 34 so do not increment the counter. Next comes a 34, 34 is 34 so do not increment the counter. Next comes a 34, 34 is 34 so do not increment the counter. The number of integers excluding repeats is 1.
EDIT:
I took the suggestion of a user on here and looked at a few link related to adjacent strings and integers. The output is almost completely correct now when compared to the desired output that I listed above. I will only put the pertain code below:
Output:
check1:1
check1:1
check1:2
Duplicates : 6 (Wrong value)
check1:2
Duplicates : 5 (Wrong value)
Duplicates : 5
Duplicates : 5
check1:0
check1:0
check1:0
check1:0
Duplicates : 1
Duplicates : 1
check1:0
check1:0
check1:2
check1:3
check1:3
check1:3
check1:4
check1:5
check1:5
check1:5
check1:5
check1:6
check1:6
Duplicates : 7 (Wrong value)
From the output it appears that whenever a test case goes through the if statement if(array[check] == ch), the output is incorrect.
I have been staring at the loops in this function for a long and I am still stumped.
Any suggestions as to why that loop is leading to incorrect values? Thank you.

Answer 1

Your logic is too complicated, this simple logic should do it
Count the first value
Start a loop from the second value to the last
Subtract the current value from the previous, if the result is 0 then it's the same value, do not add to the counter otherwise add to the counter.
I wrote a program to show you how
numbers.txt
1 2 3 4 5 6 5 4 5
14 62 48 14
1 3 5 7 9
123 456 789 1234 5678
34 34 34 34 34
1
1 2 2 2 2 2 3 3 4 4 4 4 5 5 6 7 7 7 1 1
program.c
#include <stdlib.h>
#include <stdio.h>
int
main(int argc, char **argv)
{
FILE *file;
char line[100];
file = fopen("numbers.txt", "r");
if (file == NULL)
return -1;
while (fgets(line, sizeof(line), file) != NULL)
{
char *start;
int array[100];
int count;
int value;
int step;
count = 0;
start = line;
while (sscanf(start, "%d%n", array + count, &step) == 1)
{
start += step;
count += 1;
}
fprintf(stderr, "%d ", array[0]);
value = 1;
for (int i = 1 ; i < count ; ++i)
{
value += (array[i] - array[i - 1]) ? 1 : 0;
fprintf(stderr, "%d ", array[i]);
}
fprintf(stderr, " -- %d\n", value);
}
fclose(file);
return 0;
}

Answer 2

You simply need to check the current value to previous value of the array and check if they are equal or not something like this ::
int ans = 1;
for (int i = 1 ; i < n ; i++) { //n is the number of elements in array
if (a[i] != a[i - 1]) {
ans++;
}
}
printf("%d", ans);
I do not exactly understand why you use so many check in your code. What I do in this code is that I check my current element in the array (starting from 1) and compare it with previous element, so if they are not equal you have a unique element in your array (sequentially), and hence I increment the ans which is the number of unique elements sequentially.
Here I start with ans = 1 because I assume that there will be at least 1 element in your array and that will be unique in any case.

Answer 3

I don't know what you are using that much code for.
But for what i understand you want to do, it a simple loop like this:
#include <stdio.h>
int main() {
int array[] = {1,3,5,7,9};
int count = 1;
int i = 0;
for(i=1; i<(sizeof(array)/sizeof(array[0])); i++) { //sizeof(array)/sizeof(array[0]) calculates the length of the array
if(array[i]!=array[i-1]) {
count++;
}
}
printf("%d", count);
}