Display distinct Badge_ID - sql-server

Question

This is my query having the Current Results as displayed below.
SELECT
Distinct CONVERT(int, Employees_1.Emp_Badge_No) AS Emp_Badge_No,
Employees_1.Emp_LastName, Employees_1.Emp_FirstName, Employees_1.Email,
Employees_1.NT_Name, Employees_1.Dept_key,
Employees_1.Emp_LastName + ',' + Employees_1.Emp_FirstName AS FullName,
dbo.department_vw.DepartmentShortName AS deptname,
Employees_1.active_flag
FROM data_common.dbo.employees_union_vw AS Employees_1
INNER JOIN dbo.department_vw
ON Employees_1.Dept_key = dbo.department_vw.DepartmentKey
Sample data:
I need help to achieve the Expected Results. What will I modify with my existing sql query?
I want to keep all the records even though it is inactive as long as the Emp_Badge_No is not repeated. I only want those duplicate Emp_Badge_No to be remove.
Thanks in advance.

Answer 1

You may want to use ROW_NUMBER for this. Modify the ORDER BY clause depending on which row from the duplicate entry you want to retrieve:
WITH Cte AS(
SELECT
e.Emp_Badge_No,
e.Emp_LastName,
e.Emp_FirstName,
e.Email,
e.NT_Name,
e.Dept_key,
e.Emp_LastName + ',' + e.Emp_FirstName AS FullName,
d.DepartmentShortName AS deptname,
e.active_flag,
rn = ROW_NUMBER() OVER(PARTITION BY e.Emp_Badge_No ORDER BY e.Active)
FROM data_common.dbo.employees_union_vw AS e
INNER JOIN dbo.department_vw d
ON e.Dept_key = d.DepartmentKey
)
SELECT
Emp_Badge_No,
Emp_LastName,
Emp_FirstName,
Email,
NT_Name,
Dept_key,
FullName,
deptname,
active_flag
FROM Cte
WHERE rn = 1
The above will get the Inactive record if there are duplicates. If you want to get the Active records instead, replace rn with:
ROW_NUMBER() OVER(PARTITION BY Emp_Badge_No ORDER BY e.Active DESC)
If you don't care whether it's Active or Inactive, replace rn with:
ROW_NUMBER() OVER(PARTITION BY Emp_Badge_No ORDER BY (SELECT NULL))