adding a 0 char after every even number in an array C - c

I'm trying to create a program in C which, after every even number, will add a "0". But I have a problem. If I insert for example only even numbers (5 or more numbers) the program crashes.
Below is the program I have right now.
I would like some indications or a code sample to point out what I did wrong and how I can fix it.
void main()
{
int *a, i, n, m;
printf("dimensiune=");
scanf_s("%d", &n);
a = (int*)malloc(n*sizeof(int));
for (i = 0; i < n; i++)
{
printf("a[%d]=", i + 1);
scanf_s("%d", &a[i]);
}
for (i = 0; i < n; i++)
{
if (a[i] % 2 == 0)
{
n++;
a = (int*)realloc(a, n*sizeof(int));
for (m = n - 1; m > i;m--)
{
a[m + 1] = a[m];
}
a[i + 1] = 0;
i++;
}
}
printf("\n currently you have %d numbers in this string\n", n);
printf("your string \n");
for (i = 0; i < n; i++)
{
printf("a[%d]=%d\n", i + 1, a[i]);
}
}

Change:
for (m = n - 1; m > i;m--)
{
a[m + 1] = a[m];
}
to:
for (m = n - 1; m > i;m--)
{
a[m] = a[m-1];
}
I've just tested it, it's working for me, should work for you.

I see a problem with this loop:
for (m = n - 1; m > i;m--)
{
a[m + 1] = a[m];
}
When you start the loop, n is the number of element in the loop. During the first iteration, m is the index of the last element of the loop. So, m+1 is after the last element, creating a buffer overflow.

Thanks for all comments I solved the bug replacing void main() with int main(void) + the solution provided by Shady Programmer.

Related

0xC0000374: A heap has been corrupted (parameters: 0x77AAB960)

The code bellow sometimes throws exceptions similar to:
Exception thrown at 0x779CC19E (ntdll.dll) in Matriks.exe: 0xC0000005: Access violation reading location 0x0000001D.
I'm new to C and just learned to use pointers. Any tips ? Are there other problems in my code that are worth criticizing ?
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
main()
{
int *Matrix_01, *Matrix_02;
int a, b, i, n,valid=1;
srand(time(0));
do
{
printf("Insert number of rows: ");
scanf("%d", &a);
printf("Insert number of columns: ");
scanf("%d", &b);
if (a >= 0 && b >= 0)
valid = 0;
else
{
printf("Invalid input!");
system("pause>null & cls");
}
} while (valid == 1);
Matrix_01 = (int *)malloc(a * b * sizeof(int));
Matrix_02 = (int *)malloc(a * b * sizeof(int));
for (i = 0; i < a; i++)
for (n = 0; n < b; n++)
{
Matrix_01[a*i + n] = rand() % 50;
Matrix_02[a*i + n] = rand() % 50;
}
printf("\nFirst Matrix:\n");
for (i = 0; i < a; i++)
{
printf("\n");
for (n = 0; n < b; n++)
{
printf("%4d", Matrix_01[a*i + n]);
}
}
printf("\n\nSecond Matrix:\n");
for (i = 0; i < a; i++)
{
printf("\n");
for (n = 0; n < b; n++)
{
printf("%4d", Matrix_02[a*i + n]);
}
}
printf("\n\nAddition:\n");
for (i = 0; i < a; i++)
{
printf("\n");
for (n = 0; n < b; n++)
{
printf("%4d", Matrix_01[a*i + n]+Matrix_02[a*i + n]);
}
}
printf("\n\nSubtraction:\n");
for (i = 0; i < a; i++)
{
printf("\n");
for (n = 0; n < b; n++)
{
printf("%4d", Matrix_01[a*i + n] - Matrix_02[a*i + n]);
}
}
printf("\n");
system("pause>null");
}
Heap is corrupt in that case means that you wrote out of the valid allocated zones.
Check the min & max values of your index:
i ranges from 0 to a-1
n ranges from 0 to b-1
So a*i + n ranges from 0 to a*(a+1) + b. So it doesn't match the matrix dimensions. If a is bigger than b the memory will get corrupted.
You need to replace this by b*i + n (which ranges from 0 to b*(a-1) + b => a*b
You also want to avoid to allow that a or b is zero when reading the input. Actually, it's better to check if scanf succeeded in scanning one value by checking the return code then check if values are greater than zero (but not equal)
Or use 2D matrixes (or compute pointers on rows once to avoid those computations)

i am using 4 for lopp , 2 are working correct rest 2 are showing issue 3 and 4 loop are showing invalid answer

i am using 4 for lopp , 2 are working correct rest 2 are showing issue 3 and 4 loop are showing invalid answer:
#include <stdio.h>
int main(void) {
// your code goes here
int n,arr[n],i,l=0,m=0,u=0,d=0;
printf("enter the value of n");
scanf("%d",&n);
arr[0]=0;
for(i=0;i<n;i++) {
arr[i+1]=arr[i]+10;
}
printf("%d",arr[3]);
for(i=1;i<=n;i=i+4) {
l=arr[i]+l;
}
for(i=2;i<=n;i=i+4) {
u=arr[i]+u;
}
for(i=3;i<=n;i=i+4) {
m=arr[i]+m;
}
/* for(i=4;i<=n;i=i+4) { d=arr[i]+d; } */
printf("\n%d\n",l);
printf("%d\n",u);
printf("%d\n",m);
printf("%d\n",d);
return 0;
}
answer in negative
Among the things wrong in this code
Your decl of arr[n] is based on an indeterminate n value. The array doesn't magically resize when you read n later in your program. n has to be known before the arr decl.
Your loop limits are potentially out of range (and definitely with the first loop).
The scanf call to populate n isn't checked for successful stdin input. Never assume your IO works, especially the 'I' in IO.
Just fixing those:
#include <stdio.h>
int main(void)
{
int n, i, l = 0, m = 0, u = 0, d = 0;
printf("enter the value of n");
if (scanf("%d", &n) == 1 && n > 0)
{
int arr[n];
arr[0] = 0;
for (i = 0; i<(n - 1); i++) {
arr[i + 1] = arr[i] + 10;
}
printf("%d", arr[3]);
for (i = 1; i < n; i += 4) {
l = arr[i] + l;
}
for (i = 2; i < n; i += 4) {
u = arr[i] + u;
}
for (i = 3; i < n; i += 4) {
m = arr[i] + m;
}
printf("\n%d\n", l);
printf("%d\n", u);
printf("%d\n", m);
printf("%d\n", d);
}
return 0;
}
See it live on ideone.com

This is a c program to find next greatest number with same digits. But not passing one test case

This is a C program to find the next greater number with the same digits. This program is working for all given test cases except one. When the input is 472, the expected output is 724. But my output is 247. Can anyone please help me to find the error?
logic I tried to solve this is :
Traverse the given number from rightmost digit, keep traversing till you find a digit which is smaller than the previously traversed digit. For example, if the input number is 534976, we stop at 4 because 4 is smaller than next digit 9. If we do not find such a digit, then output is Not Possible.
Now search the right side of above found digit ‘d’ for the smallest digit greater than ‘d’. For 534976, the right side of 4 contains 976. The smallest digit greater than 4 is 6.
Swap the above found two digits, we get 536974 in above example.
Now sort all digits from position next to ‘d’ to the end of number. The number that we get after sorting is the output. For above example, we sort digits in bold 536974. We get 536479 which is the next greater number for input 534976.
Here is my code:
#include <stdio.h>
#include <stdlib.h>
int main() {
int N, dig[100], i = 0,j, temp, t, s, k, l, min, temp1;
scanf("%d", &N);
while (N > 0) {
dig[i] = N % 10;
i++;
N = N / 10;
}
for (j = 0; j <= i; j++) {
if (dig[j] > dig[j + 1]) {
s = j;
break;
}
}
min = dig[s];
//printf("%d ", min);
for (k = s; k >= 0; k--) {
if (dig[k] <= min) {
min = dig[k];
t = k;
}
}
//printf("%d ", t);
temp = dig[t];
dig[t] = dig[s + 1];
dig[s + 1] = temp;
for (k = 0; k <= s; k++) {
for (l = k + 1; l <= s; l++) {
if (dig[k] < dig[l]) {
temp1 = dig[k];
dig[k] = dig[l];
dig[l] = temp1;
}
}
}
for (k = i - 1; k >= 0; k--) {
printf("%d", dig[k]);
}
}
Your algorithm seems correct, but the loops are incorrect. Some index boundaries are off by one and the comparisons with <= are incorrect. Storing the digits by increasing powers of 10, while more practical is counter-intuitive and complicates the translation of the algorithm into code.
Here is a corrected version, that outputs all greater numbers. You can easily check the output by piping through sort -c to verify order and wc -l to verify that all combinations have been found (there should be at most n! - 1 greater numbers for a number with n digits).
#include <stdio.h>
int main() {
int N, dig[100], i, j, s, t, k, l, temp;
if (scanf("%d", &N) != 1 || N < 0)
return 1;
for (;;) {
for (i = j = 100; N > 0;) {
dig[--i] = N % 10;
N = N / 10;
}
for (s = j - 2; s >= i; s--) {
if (dig[s] < dig[s + 1]) {
break;
}
}
if (s < i) {
/* no greater number with the same digits */
break;
}
t = s + 1;
for (k = t + 1; k < j; k++) {
if (dig[k] < dig[t] && dig[k] > dig[s]) {
t = k;
}
}
temp = dig[t];
dig[t] = dig[s];
dig[s] = temp;
for (k = s + 1; k < j; k++) {
for (l = k + 1; l < j; l++) {
if (dig[k] > dig[l]) {
temp = dig[k];
dig[k] = dig[l];
dig[l] = temp;
}
}
}
N = 0;
for (k = i; k < j; k++) {
N = N * 10 + dig[k];
printf("%d", dig[k]);
}
printf("\n");
}
return 0;
}
Input: 472
Output:
724
742

Is it the efficeint program to rotate array in left direction?

#include<stdio.h>
#include<stdlib.h>
main()
{
int i,j,l,m,n;
j=0;
printf("\nenter 5 element single dimension array\n");
printf("enter shift rate\n");
scanf("%d",&n);
/* Here we take input from user that by what times user wants to rotate the array in left. */
int arr[5],arrb[n];
for(i=0;i<=4;i++){
scanf("%d",&arr[i]);
}
/* Here we have taken another array. */
for(i=0;i<=4;i++){
printf("%d",arr[i]);
}
for(i=0;i<n;i++){
arrb[j]=arr[i];
j++;
// These loop will shift array element to left by position which's entered by user.
}
printf("\n");
for(i=0;i<=3;i++){
arr[i]=arr[i+n];
}
for(i=0;i<=4;i++){
if(n==1 && i==4)
break;
if(n==2 && i==3)
break;
if(n==3 && i==2)
break;
printf("%d",arr[i]);
}
//To combine these two arrays. Make it look like single array instead of two
for(i=0;i<n;i++){
printf("%d",arrb[i]);
}
// Final sorted array will get printed here
}
Is it the efficeint program to rotate array in left direction?
Actually, very complicated, and some problems contained:
for(i = 0; i < n; i++)
{
arrb[j] = arr[i];
j++;
}
Why not simply:
for(i = 0; i < n; i++)
{
arrb[i] = arr[i];
}
There is no need for a second variable. Still, if n is greater than five, you get into trouble, as you will access arr out of its bounts (undefined behaviour!). At least, you should check the user input!
for(i = 0; i <=3 ; i++)
{
arr[i] = arr[i + n];
}
Same problem: last accessible index is 4 (four), so n must not exceed 1, or you again access the array out of bounds...
Those many 'if's within the printing loop for the first array cannot be efficient...
You can have it much, much simpler:
int arr[5], arrb[5];
// ^
for(int i = 0; i < 5; ++i)
arrb[i] = arr[(i + n) % 5];
This does not cover negative values of n, though.
arrb[i] = arr[(((i + n) % 5) + 5) % 5];
would be safe even for negative values... All you need now for the output is:
for(int i = 0; i < 5; ++i)
printf("%d ", arrb[i]);
There would be one last point uncovered, though: if user enters for n a value greater than INT_MAX - 4, you get a signed integer overflow, which again is undefined behaviour!
We can again cover this by changing the index formula:
arrb[i] = arr[(5 + i + (n % 5)) % 5];
n % 5 is invariant, so we can move it out of the loop:
n %= 5;
for(int i = 0; i < 5; ++i)
arrb[i] = arr[(5 + i + n) % 5];
Finally, if we make n positive already outside, we can spare the addition in the for loop.
n = ((n % 5) + 5) % 5;
for(int i = 0; i < 5; ++i)
arrb[i] = arr[(i + n) % 5]; // my original formula again...
Last step is especially worth considering for very long running loops.
I think you want to do something like this (you should check that 0 <= n <= 5, too):
int b[5];
int k = 0;
for(i=0; i<5; i++){
if (i < 5 - n)
b[i] = arr[i+n];
else
{
b[i] = arr[k];
k++;
}
}
Array b is used to save the rotated matrix.

Negative numbers are printed

This is a program on sorting integers.
#include <stdio.h>
int main(void) {
int n, i, j, k;
int nmbr[100];
printf("\n How many numbers ? ");
scanf("%d", &n);
printf("\n");
for (i = 0; i < n; ++i) {
printf(" Number %d : ", i + 1);
scanf("%d", &nmbr[i]);
}
for (i = 0; i < n; ++i) {
for (j = 0; j < n; ++j) {
if (nmbr[j] > nmbr[j + 1]) {
k = nmbr[j];
nmbr[j] = nmbr[j + 1];
nmbr[j + 1] = k;
}
}
}
printf("\n Numbers after sorting : \n");
for (i = 0; i < n; ++i) {
printf (" %d", nmbr[i]);
}
return 0;
}
It works fine, but when I enter some number that contains more than 2 digits, the first number that is printed is negative and really big. I don't also get the last integer too. I enter N as 4, then the numbers I entered were 25, 762, 588, and 34. The result I get is:
-1217260830 25 34 588
What seems to be the problem?
You are running the loop as for (j = 0; j < n; ++j) which means j will have values from 0 to n-1 which are valid array indices (or array elements with relevant values).
But, inside that loop you are accessing an element beyond the last. For instance, in
if (nmbr[j] > nmbr[j + 1])
you are accessing nmbr[j + 1]. If the current value of j in n-1, then you are accessing nmbr[n-1 + 1] i.e. nmbr[n] which will be a value outside the array and may contain a garbage value (which might as well be negative!).
If you are trying something like Bubblesort, you might want to run the inner loop like for (j = 0; j < n - 1; ++j).
There are multiple problems in your code:
You do not check the return values of scanf(). If any of these input operations fail, the destination values remain uninitialized, invoking undefined behavior and potentially producing garbage output.
You do not verify that the number of values provided by the user is at most 100. The reading loop will cause a buffer overflow if n is too large.
Your sorting logic is flawed: in the nested loop, you refer to nmbr[j + 1] which is beyond the values read from the user. This invokes undefined behavior: potentially causing a garbage value to appear in the output.
Here is a corrected version:
#include <stdio.h>
int main(void) {
int n, i, j, k;
int nmbr[100];
printf("\n How many numbers ? ");
if (scanf("%d", &n) != 1 || n > 100) {
printf("input error\n");
return 1;
}
printf("\n");
for (i = 0; i < n; ++i) {
printf(" Number %d : ", i + 1);
if (scanf("%d", &nmbr[i]) != 1) {{
printf("input error\n");
return 1;
}
}
for (i = 0; i < n; ++i) {
for (j = 0; j < n - 1; ++j) {
if (nmbr[j] > nmbr[j + 1]) {
k = nmbr[j];
nmbr[j] = nmbr[j + 1];
nmbr[j + 1] = k;
}
}
}
printf("\n Numbers after sorting :\n");
for (i = 0; i < n; ++i) {
printf (" %d", nmbr[i]);
}
printf("\n");
return 0;
}
Your Sorting Logic is wrong. It should be:
for (i = 0; i < n; ++i){
for (j = 0; j < (n-1); ++j){
if (nmbr[j] > nmbr[j + 1]){
k = nmbr[j];
nmbr[j] = nmbr[j + 1];
nmbr[j + 1] = k;
}
}
You are trying to access out of bounds of array, when you iterate in your second loop using j. This is causing the garbage value.
As per your example involving 4 elements, when you try to access j+1, it will try to access nmbr[3+1] in the last iteration of second loop which leads to out of bounds access.
Problem is with the sorting logic as suggested by fellow coders. But It is always good coding habit to initialize the variables. Also use the qualifier if are dealing with positive numbers only.
unsigned int n = 0 , i = 0, j = 0, k = 0;
unsigned int nmbr[100] = {0};
If you would have initialized them, out put of your program would be following, which might help you tracing the problem by yourself.
0 25 34 588

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