CakePHP 3.x: Create a controller object - cakephp

I am trying to create a list of controller objects
use App\Controller\AccessController;
foreach ($controllerlist as $controllerName){
require_once($path); // path for the controller
$clsobj = new $controllerName ();
$methods = get_class_methods($clsobj);
}
In this way I am getting a class not found error
EX:AccessController not found
but when I hard code the controller name and use it`s work
$clsobj = new AccessController (); // this way its work
Any Idea how to do ?

Related

Cakephp 4.x Passing Variables to Email Template

In CakePHP 4.x I'm having some trouble with the mailer() function, specifically passing variables from my controller to a template.
I need a user to be able to receive an email with a list of items. I'm able to use ajax to send an array to my controller, but I can't get the controller to pass the variables to the email template. I'm getting the email but not the dynamic content and I just can't get it to work via setViewVars.
My controller function:
public function bar(): void
{
if( $this->request->is('ajax') ) {
$this->request->allowMethod('ajax');
$foo = $this->request->getQuery('data');
// data is a stringified array
$mailer = new Mailer("default");
$mailer->viewBuilder()->setTemplate('default','default');
$mailer
->setEmailFormat('html')
->setFrom(['email#email.com' => 'Comparaciones'])
->setTo('email#email.com')
->setSubject('About')
>setViewVars($foo)
->send();
// ->deliver() doesn't work either
}
}
My template:
// standard cakephp default template
$content = explode("\n", $content);
foreach ($content as $line) :
echo '<p> ' . $line . "</p>\n";
endforeach;
I'm probably tripping up with something simple, I just can't get the array into the template. Any help much appreciated!!!

How to pass array value from view to another view Laravel 5.7

I want to get the value from the array I've passed from the first view to another view.
I found this works by using route (not url), but I don't know how to get it without parameter in the controller.
Please help me within the right syntax.
This is the latest code I've tried
$id = $request->id;
if($request->has('download', 'id')){
$pdf = PDF::loadView('pdfview');
return $pdf->download('pdfview.pdf',['id'=>$id])->with('id',$id);}
This is my code *used to download pdf file from a view
Controller
public function pdfview(Request $request)
{
$items = DB::table("items")->get();
view()->share('items',$items);
$id = $request->only(['id']);
if($request->has('download', 'id')){
$pdf = PDF::loadView('pdfview');
return $pdf->download('pdfview.pdf', ['id'=>$id])->with('id', $id);
}
return view('pdfview', ['id'=>$id])->with('id', $id);
}
Route
Route::get('pdfview',array('as'=>'pdfview','uses'=>'MaatwebsiteDemoController#pdfview'));
View
Download PDF
I want to get the $employee->nip value
But it is still Undefined variable: id
Don't really have time to test it. But this thread looks promising.
https://laravel.io/forum/03-14-2016-basics-passing-info-from-one-view-to-another

Trying to write a simple Joomla plugin

Please help, this is my first plugin I'm writing and I'm completely lost. I'm trying to write and update information in a table in a joomla database using my custom giveBadge() function. The functions receives two different variables, the first variable is the $userID and the second one is the digit 300 which I pass at the bottom of the class using giveBadge(300). At the same comparing the $userID in the Joomla database to ensure that the number 300 is given to the current user logged in the Joomla site.
Thanks in advance.
<?php
defined('JPATH_BASE') or die;
class plgUserBadge extends JPlugin
{
public function onUserLogin () {
$user =& JFactory::getUser();
$userID =& user->userID;
return $userID;
}
public function giveBadge ($userID, &$badgeID) {
// Get a db connection.
$db = JFactory::getDbo();
// Create a new query object.
$query = $db->getQuery(true);
// Fields to update.
$fields = array(
'profile_value=\'Updating custom message for user 1001.\'',
'ordering=2');
// Conditions for which records should be updated.
$conditions = array(
'user_id='.$userID,
'profile_key=\'custom.message\'');
$query->update($db->quoteName('#__user_badges'))->set($fields)->where($conditions);
$db->setQuery($query);
try {
$result = $db->query();
} catch (Exception $e) {
// Catch the error.
}es = array(1001, $db->quote('custom.message'), $db->quote('Inserting a record using insert()'), 1);
}
}
giveBadge(300); //attaches to $badgeID
?>
Here is not going well with your code:
You can drop the assign by reference in all your code (&) - you really don't need it, in 99% of the cases.
Use an IDE (for example Eclipse with PDT). At the top of your code you have & user->userID; Any IDE will spot your error and also other things in your code.
Study existing plugins to understand how they work. Here is also the documentation on plugins.
The method onUserLogin() will automatically be called by Joomla when the specific event is triggered (when your plugin is activated). Check with a die("My plugin was called") to see if your plugin is really called
inside onUserLogin() you do all your business logic. You are not supposed to return something, just return true. Right now your method does absolutely nothing. But you can call $this->giveBadge() to move the logic to another method.

How to use find('all') in Views - CakePHP

I searched a lot but I couldn't find on How to use the find('all') in Views as used in Rails, but here I'm getting the error "Undefined property: View::$Menu [APP\Lib\Cake\View\View.php, line 804]"
'Menu' is the model which I'm using to fetch data from the menus table.
I'm using the below code in views:
$this->set('test',$this->Menu->find('all'));
print_r($test);
Inside your Menu model create a method, something like getMenu(). In this method do your find() and get the results you want. Modify the results as you need and like to within the getMenu() method and return the data.
If you need that menu on every page in AppController::beforeFilter() or beforeRender() simply do
$this->set('menu', ClassRegistry::init('Menu')->getMenu());
If you do not need it everywhere you might go better with using requestAction getting the data using this method from the Menus controller that will call getMenu() from the model and return the data. Setting it where you need it would be still better, if you use requestAction you also want to cache it very likely.
TRY TO NOT RETRIEVE DATA WITHIN VIEW FILE. VIOLATION OF MVC RULE
try this in view file:
$menu = ClassRegistry::init('Menu');
pr($menu->find('all'));
In AppHelper ,
Make a below function
function getMenu()
{
App::import('Model', 'Menu');
$this->Menu= &new Menu();
$test = array();
$test = $this->Menu->find('all');
return $test;
}
Use above function in view like :
<?php
$menu = $html->getMenu();
print_r($menu);
?>
Cakephp not allow this .
First create the reference(object) of your model using ClassRegistry::init('Model');
And then call find function from using object
$obj = ClassRegistry::init('Menu');
$test = $obj->find('all');
echo ""; print_r($test); `
This will work.

Passing data from CakePHP component to a helper

I need to share data between a component and helper. I'm converting my self-made payment service formdata generator to a CakePHP plugin and I'd like to be able to fill in the payment data from the controller(using a component) and use a helper to print out the data.
Everything I've tried so far have felt a little too hacky, so let me ask you: Is there any elegant way to pass data from a component to a helper?
edit:
I solved this particular situation by adding the original formadata class instance to ClassRegistry during the component initialization. This way the helper too can access the instance using ClassRegistry.
However, this only works for objects, so the question remains open.
Having a similar problem, I found this solution to work best for me.
You could use the helper's __construct method in pair with $controller->helpers array.
Since the Helper::_construct() is called after the Component::beforeRender, you can modify the $controller->helpers['YourHelperName'] array to pass the data to your helper.
Component code:
<?php
public function beforeRender($controller){
$controller->helpers['YourHelperName']['data'] = array('A'=>1, 'B'=>2);
}
?>
Helper code:
<?php
function __construct($View, $settings){
debug($settings);
/* outputs:
array(
'data' => array(
'A' => (int) 1,
'B' => (int) 2
)
)
*/
}
?>
I am using CakePHP 2.0, so this solution should be tested for earlier versions.
Is there any elegant way to pass data from a component to a helper?
Yes, the same way you pass any data to the helper. In your view.
Inside your component I would do something like the following. The beforeRender() action is a CakePHP component callback.
public function beforeRender(Controller $controller) {
$yourVars = 'some data';
$goHere = 'other stuff';
$controller->set(compact('yourVars', 'goHere'));
}
Then in your view you can pass the data off to your helpers just like normal.
// view or layout *.ctp file
$this->YourHelper->yourMethod($yourVars);
$this->YourHelper->otherMethod($goHere);
In addition to what #Vanja, you can also do this just prior to instantiating a new view in your controller:
// In your controller method
// must be set prior to instantiating view
$this->helpers['YourHelperName']['paramsOrAnyName'] = ['var' => $passed_var];
$_newView = new View($this);
$return_result = $_newView->render($element_to_view, $layout);

Resources