I'm having a bit of trouble dealing with the output of array formulas in Excel, e.g.:
{=IF(B3:D3>=4;"Something";"")}
What I want to achieve with this snippet is to print "Something" in the target cell if one value of the array is greater or equal to 4. If we assume our array is {1,1,4} the result should be {"","","Something"}, but Excel will only print the first value of the array resulting in a blank cell.
Is there an easy way to make this work?
Also, how do I compare an array against a "static" array? Something like:
Pseudocode
{=IF(B3:D3={1,1,1};"Every value is 1";"")}
Purpose being to determine if every value in B3:D3 is 1 then print something to the target cell.
Is it possible to enter an array/list like {1,1,1} directly into the formula?
I've Googled to no avail, could only find solutions where the "conditional" array was defined in an array somewhere on the sheet or just chaining the value checking with AND statements.
Try this formula:
=IF(COUNTIF($B$3:$D$3,1)=COLUMNS($B$3:$D$3),"Every value is 1","")
First part can be done like this for a cell range:
=IF(MAX(B3:D3)>=4, "Something", "")
or for static array:
=IF(MAX({1,2,3,4})>=4, "Something", "")
Second part to check matching arrays must be done by pressing Ctrl_Shift_Enter when entering the formula:
IF(MIN((B3:D3={8,5,8})+0)>0, "Matches!!", "NOT matching")
Related
I have to make this work in a (always sorted) array that results from splitting a delimited string of sorted whole numbers. Concretely, if my cell contains "1,2,3,5" I need a formula to evaluate to 4. A beneficial side-effect would be to find an implementation that would give the last-number+1, if the original array had only consecutive numbers, i.e., applying the formula to "1,2,3,4,5" would evaluate to 6.
My approach has been to generate a new array that is a perfect sequence and compare it with my original array, to find the first element where the two arrays are not equal.
Creating a perfect sequence of the array like this:
=TRANSPOSE(SEQUENCE(COUNT(arr),1,MIN(arr),1))
So all that would be left to do is compare arr with the sequence above to find the first element that differed, something like:
=COUNTA(IFERROR(FILTER(arr;MATCH(arr; transpose(sequence(count(arr),1,min(arr),1))
;0))))
Sadly, what I have above is not correctly "short-circuiting" at the first non equal value of the arrays. Is COUNTIF the way to go?
If my previous step gets me the index of the element instead of the value, then what remains is to get the value at that index:
INDEX( arr, 1, counta(iferror(filter(arr;match(arr1; transpose(sequence(count(arr),1,min(arr),1))
;0)))) )
Is there a more straight-forward way get the first non-consecutive element? A way that does not involve actual ranges in the spreadsheet?
After some thought, I realized that set-subtracting (i.e. set difference) the original array from the generated sequence always gives me the first missing number.
So my final formula to handle this and the case where all numbers are in sequence is this:
IFERROR(INDEX(FILTER(TRANSPOSE(SEQUENCE(COUNT(SPLIT(G7," ")),1,LEFT(G7,4),1)), ISERROR(MATCH(TRANSPOSE(SEQUENCE(COUNT(split(G7," ")),1,LEFT(G7,4),1)),SPLIT(G7, " "),False))),1,1),RIGHT(G7,4)+1) )
I'm sure there is a better, more concise answer, but this does the job.
I have a list of values that I would like to match against the combination of multiple ranges.
So, for example, my ranges are A1:A100 and B1:B100.
Instead of concatenating A with B in a new column C, i.e.
CONCAT(A1,B1)...CONCAT(A100,B100)
and then matching my value against that new column - I would like to do something like this:
MATCH(value,CONCATENATE(A1:B100),0)
And copy this down a column near my list of values.
I have a feeling this can be done with some sort of array formula...
Yes as an array formula:
=MATCH(value,$A$1:$A$100 & $B$1:$B$100,0)
Being an array formula it must be confirmed with Ctrl-Shift-Enter instead of Enter when exiting edit mode.
Though they may seem similar in approach they are not. CONCATENATE will return a string not an array to the MATCH with all 200 values in one long string. Where the above will return 100 values, each row concatenated, as an array which can be used to search.
One further note, If performance becomes a issue, Array formulas are inherently slower, adding the helper column and using a regular MATCH will improve the responsiveness.
This should work, basically you just need to concatenate it yourself using &
=MATCH(D1,A1:A10&B1:B10,0)
D1 is the value you're trying to look for.
This is an array, so remember to hit Ctrl+Shift+Enter when you input it.
I have been looking around for a while but unable to find an answer to my question.
In Excel, what compact formula can I use to create an array made up of a single element repeated n times, where n is an input (potentially hard-coded)?
For example, something that would look like this (the formula below does not work but gives an idea of what I am looking for):
{={"Constant"}*3}
Note: I am not looking for a VBA-based solution.
EDIT Reading #AxelRichter answer, I see I should also indicate that the formulas below assume Constant is a number. If Constant is text, then this solution will not work.
Volatile:
=ROW(INDIRECT("1:" & Repts))/ROW(INDIRECT("1" & ":" & Repts)) * Constant
non-Volatile:
=ROW(INDEX($1:$65535,1,1):INDEX($1:$65535,Repts,1))/ROW(INDEX($1:$65535,1,1):INDEX($1:$65535,Repts,1))*Constant
If
Constant = 14
Repts = 3
then
Result = {14;14;14}
The first part of the formulas create an array of 1's repeated Repts times. Then we multiply that array by Constant to get the desired result.
And after reading #MacroMarc's comment, the following non-volatile formula shouyld also work for numbers:
=(ROW($A$1:INDEX($A:$A,Repts))>0)*Constant
One could concatenate 1:n empty cells to the "Constant" to create a string array having n items "Constant":
"Constant"&INDEX(XFD:XFD,1):INDEX(XFD:XFD,3)
There 3 is n.
Used in Formula
=INDEX("Constant"&INDEX(XFD:XFD,1):INDEX(XFD:XFD,3),0)
Evaluate Formula shows that it works:
Here column XFD is used because in most cases this column will be empty and a column which is guaranteed to be empty is needed for this solution.
If used
"Constant"&T(ROW($A$1:INDEX($A:$A,3)))
=INDEX("Constant"&T(ROW($A$1:INDEX($A:$A,3))),0)
the need of an empty column disappears. The function ROW returns numbers but the T returns an empty string if its parameter is not text. So empty strings will be concatenated for each 1:3 (n).
Thanks to #MacroMarc for the hint.
Try:
REPT("Constant", SEQUENCE(3,1,1,0))
Or, if the reference is to a dynamic array:
REPT("Constant", SEQUENCE(A1#,1,1,0))
The dynamic array spills, and has your constant repeated one time.
Using SEQUENCE with a step of 0 is a much cleaner way to make an array of constants. You can choose whether you want rows or columns (or both!) as well.
=SEQUENCE(Repts,1,Constant,0)
I will generally use a sequence (like Claire (above) said). But if you want to provide an output of text objects, I would do it this way:
=IF(SEQUENCE(A1,A2,1,0),A3)
Where:
A1 has the number of rows
A2 has the number of columns
A3 has the thing you want repeated into an array
The sequence will create a matrix of 1's, which the IF statement will default to the TRUE expression (being the contents of A3).
So, if you wanted a vertical list of 3 items that says "Constant", this would do it:
=IF(SEQUENCE(3,,1,0),"Constant")
If you would prefer it be arranged horizontally instead of vertically, just amend the SEQUENCE function:
=IF(SEQUENCE(,3,1,0),"Constant")
I need to pass a multiple criteria list (a constant array) via cell reference rather than hard-typing it into my formula.
So, instead of this:
=SUM(SUMIFS(sum_range,criteria_range,{"red","blue"}))
But I would need to use this:
=SUM(SUMIFS(sum_range,criteria_range,$A1)) where $A1 is {"red","blue"}
I understand that one can use a range of cells to pass an array but I really need my condition to come from a single cell.
It seems that passing a constant array via cell reference only passes the first element to the formula (i.e. only "red" is used as a condition) and all the working examples I could find of this (here or here) are hard-typing the condition into the formula.
Any luck anybody ?
EDIT: I should add that my data set includes blank rows so it is not contiguous and in general, I'm looking for a not too convoluted solution that will work most of the time and with as little restrictions and caveats as possible.
Change the "Array" in A1 to a comma delineated list:
blue,purple
No quotes or {}
Change the SUM to SUMPRODUCT and use this as the criteria:
TRIM(MID(SUBSTITUTE(A1,",",REPT(" ",99)),(ROW(INDEX(AAA:AAA,1):INDEX(AAA:AAA,LEN(A1)-LEN(SUBSTITUTE(A1,",",""))+1))-1)*99+1,99))
The $20 should be placed at the max number of choices possible. I just used it here as a placeholder, it can be more without problem but not less or it will skip any more than that.
Based on the formula you provided.
=SUMPRODUCT(SUMIFS(W$12:W$448,$I$12:$I$448,$I474,$J$12:$J$448,$J474,$K$12:$K$448,TRIM(MID(SUBSTITUTE(A1,",",REPT(" ",99)),(ROW(INDEX(AAA:AAA,1):INDEX(AAA:AAA,LEN(A1)-LEN(SUBSTITUTE(A1,",",""))+1))-1)*99+1,99))))
With cell A1 containing {"red","blue"} I then setup a named range Condition to which I assigned =EVALUATE($A1) and now I can pass my condition like so:
=SUM(SUMIFS(W$12:W$448,$I$12:$I$448,$I474,$J$12:$J$448,$J474,$K$12:$K$448,Condition))
I'm trying to perform math within an Excel formula to specify the end of an array. Here is a simple version of what I want to do:
A B C
1 =COUNTA(A1:A5)-1 =SUM(A1:A(1+B1))
2
3
4
5
The first column is my data array. The second column counts the number of entries in that array (so if it isn't full, it returns a value less than 5). The third column sums the array starting with the first value and ending with the last entered value. Obviously with the SUM function it doesn't matter if there are zeroes, but I am trying to use the MATCH function and I don't want it to return a zero just because there are blank entries in the array I'm looking up.
So I want to modify the information within the SUM function to produce a variable array length based on the return value of B1. I hope this is clear. Thanks for any help!
One way is to use INDEX like this
=SUM(A1:INDEX(A:A,B1+1))
you can use the range defined by
A1:INDEX(A:A,B1+1)
in other functions like MATCH
Like this?
=SUM(INDIRECT("A1:A"&(1+B1)))