I've got a problem in SQL Server.
"Whate'er is well conceived is clearly said, And the words to say it flow with ease", Nicolas Boileau-Despreaux
Well, I don't think I'll be able to make it clear but I'll try ! And I'd like to apologize for my bad english !
I've got this table :
id ind lvl result date
1 1 a 3 2017-01-31
2 1 a 3 2017-02-28
3 1 a 1 2017-03-31
4 1 a 1 2017-04-30
5 1 a 1 2017-05-31
6 1 b 1 2017-01-31
7 1 b 3 2017-02-28
8 1 b 3 2017-03-31
9 1 b 1 2017-04-30
10 1 b 1 2017-05-31
11 2 a 3 2017-01-31
12 2 a 1 2017-02-28
13 2 a 3 2017-03-31
14 2 a 1 2017-04-30
15 2 a 3 2017-05-31
I'd like to count the number of month the combo {ind, lvl} remain in the result 1 before re-initializing the number of month to 0 if the result is not 1.
Clearly, I need to get something like that :
id ind lvl result date BadResultRemainsFor%Months
1 1 a 3 2017-01-31 0
2 1 a 3 2017-02-28 0
3 1 a 1 2017-03-31 1
4 1 a 1 2017-04-30 2
5 1 a 1 2017-05-31 3
6 1 b 1 2017-01-31 1
7 1 b 3 2017-02-28 0
8 1 b 3 2017-03-31 0
9 1 b 1 2017-04-30 1
10 1 b 1 2017-05-31 2
11 2 a 3 2017-01-31 0
12 2 a 1 2017-02-28 1
13 2 a 3 2017-03-31 0
14 2 a 1 2017-04-30 1
15 2 a 3 2017-05-31 0
So that if I was looking for the number of months the result was 1 for the date 2017-05-31 with the id 1 and the lvl a, I know it's been 3 months.
Assume all the date the the end day of month:
;WITH tb(id,ind,lvl,result,date) AS(
select 1,1,'a',3,'2017-01-31' UNION
select 2,1,'a',3,'2017-02-28' UNION
select 3,1,'a',1,'2017-03-31' UNION
select 4,1,'a',1,'2017-04-30' UNION
select 5,1,'a',1,'2017-05-31' UNION
select 6,1,'b',1,'2017-01-31' UNION
select 7,1,'b',3,'2017-02-28' UNION
select 8,1,'b',3,'2017-03-31' UNION
select 9,1,'b',1,'2017-04-30' UNION
select 10,1,'b',1,'2017-05-31' UNION
select 11,2,'a',3,'2017-01-31' UNION
select 12,2,'a',1,'2017-02-28' UNION
select 13,2,'a',3,'2017-03-31' UNION
select 14,2,'a',1,'2017-04-30' UNION
select 15,2,'a',3,'2017-05-31'
)
SELECT t.id,t.ind,t.lvl,t.result,t.date
,CASE WHEN t.isMatched=1 THEN ROW_NUMBER()OVER(PARTITION BY t.ind,t.lvl,t.id-t.rn ORDER BY t.id) ELSE 0 END
FROM (
SELECT t1.*,c.MonthDiff,CASE WHEN c.MonthDiff=t1.result THEN 1 ELSE 0 END AS isMatched
,CASE WHEN c.MonthDiff=t1.result THEN ROW_NUMBER()OVER(PARTITION BY t1.ind,t1.lvl,CASE WHEN c.MonthDiff=t1.result THEN 1 ELSE 0 END ORDER BY t1.id) ELSE null END AS rn
FROM tb AS t1
LEFT JOIN tb AS t2 ON t1.ind=t2.ind AND t1.lvl=t2.lvl AND t2.id=t1.id-1
CROSS APPLY(VALUES(ISNULL(DATEDIFF(MONTH,t2.date,t1.date),1))) c(MonthDiff)
) AS t
ORDER BY t.id
id ind lvl result date
----------- ----------- ---- ----------- ---------- --------------------
1 1 a 3 2017-01-31 0
2 1 a 3 2017-02-28 0
3 1 a 1 2017-03-31 1
4 1 a 1 2017-04-30 2
5 1 a 1 2017-05-31 3
6 1 b 1 2017-01-31 1
7 1 b 3 2017-02-28 0
8 1 b 3 2017-03-31 0
9 1 b 1 2017-04-30 1
10 1 b 1 2017-05-31 2
11 2 a 3 2017-01-31 0
12 2 a 1 2017-02-28 1
13 2 a 3 2017-03-31 0
14 2 a 1 2017-04-30 1
15 2 a 3 2017-05-31 0
By slightly tweaking your input data and slightly tweaking how we define the requirement, it becomes quite simple to produce the expected results.
First, we tweak your date values so that the only thing that varies is the month and year - the days are all the same. I've chosen to do that my adding 1 day to each value1. The fact that this produces results which are one month advanced doesn't matter here, since all values are similarly transformed, and so the monthly relationships stay the same.
Then, we introduce a numbers table - here, I've assumed a small fixed table is adequate. If it doesn't fit your needs, you can easily locate examples online for creating a large fixed numbers table that you can use for this query.
And, finally, we recast the problem statement. Instead of trying to count months, we instead ask "what's the smallest number of months, greater of equal to zero, that I need to go back from the current row, to locate a row with a non-1 result?". And so, we produce this query:
declare #t table (id int not null,ind int not null,lvl varchar(13) not null,
result int not null,date date not null)
insert into #t(id,ind,lvl,result,date) values
(1 ,1,'a',3,'20170131'), (2 ,1,'a',3,'20170228'), (3 ,1,'a',1,'20170331'),
(4 ,1,'a',1,'20170430'), (5 ,1,'a',1,'20170531'), (6 ,1,'b',1,'20170131'),
(7 ,1,'b',3,'20170228'), (8 ,1,'b',3,'20170331'), (9 ,1,'b',1,'20170430'),
(10,1,'b',1,'20170531'), (11,2,'a',3,'20170131'), (12,2,'a',1,'20170228'),
(13,2,'a',3,'20170331'), (14,2,'a',1,'20170430'), (15,2,'a',3,'20170531')
;With Tweaked as (
select
*,
DATEADD(day,1,date) as dp1d
from
#t
), Numbers(n) as (
select 0 union all select 1 union all select 2 union all select 3 union all select 4
union all
select 5 union all select 6 union all select 7 union all select 8 union all select 9
)
select
id, ind, lvl, result, date,
COALESCE(
(select MIN(n) from Numbers n1
inner join Tweaked t2
on
t2.ind = t1.ind and
t2.lvl = t1.lvl and
t2.dp1d = DATEADD(month,-n,t1.dp1d)
where
t2.result != 1
),
1) as [BadResultRemainsFor%Months]
from
Tweaked t1
The COALESCE is just there to deal with the edge case, such as for your 1,b data, where there is no previous row with a non-1 result.
Results:
id ind lvl result date BadResultRemainsFor%Months
----------- ----------- ------------- ----------- ---------- --------------------------
1 1 a 3 2017-01-31 0
2 1 a 3 2017-02-28 0
3 1 a 1 2017-03-31 1
4 1 a 1 2017-04-30 2
5 1 a 1 2017-05-31 3
6 1 b 1 2017-01-31 1
7 1 b 3 2017-02-28 0
8 1 b 3 2017-03-31 0
9 1 b 1 2017-04-30 1
10 1 b 1 2017-05-31 2
11 2 a 3 2017-01-31 0
12 2 a 1 2017-02-28 1
13 2 a 3 2017-03-31 0
14 2 a 1 2017-04-30 1
15 2 a 3 2017-05-31 0
1An alternative way to perform the adjustment is to use a DATEADD/DATEDIFF pair to perform a "floor" operation against the dates:
DATEADD(month,DATEDIFF(month,0,date),0) as dp1d
Which resets all of the date values to be the first of their own month rather than the following month. This may fell more "natural" to you, or you may already have such values available in your original data.
Assuming the dates are continously increasing in month, you can use window function like so:
select
t.id, ind, lvl, result, dat,
case when result = 1 then row_number() over (partition by grp order by id) else 0 end x
from (
select t.*,
dense_rank() over (order by e, result) grp
from (
select
t.*,
row_number() over (order by id) - row_number() over (partition by ind, lvl, result order by id) e
from your_table t
order by id) t ) t;
Need help in construct SQL, over an orders table, that holds the Date, SalesID, ItemID and other misc. columns.
Table looks like:
Date SalesID ItemID
13-9-15 6:15:00 56 6
13-9-15 6:00:00 56 6
13-9-15 6:26:00 56 4
13-9-15 6:38:00 34 4
13-9-15 7:05:00 34 2
13-9-15 6:42:00 12 2
13-9-15 7:20:00 12 5
13-9-15 7:34:00 78 5
13-9-15 7:41:00 78 6
What I'd like to have as an additional column is, one counter which is increments each time when new SalesID begins order by date.And the counter column will count until max no is 3.I'm using DENSE_RANK()for the increment column.
Finally what I need:
Date SalesID ItemID Counter
13-9-15 6:00:00 56 6 1
13-9-15 6:15:00 56 6 1
13-9-15 6:26:00 56 4 1
13-9-15 6:38:00 34 4 2
13-9-15 6:42:00 34 2 2
13-9-15 7:05:00 12 2 3
13-9-15 7:20:00 12 5 3
13-9-15 7:34:00 78 5 1
13-9-15 7:41:00 78 6 1
This solution works for sqlserver 2012+. I had to correct invalid data in your example in order to get the correct output
DECLARE #t table(Date datetime, SalesID int, ItemID int)
INSERT #t values
('2015-09-13 6:15:00',56,6),
('2015-09-13 6:00:00',56,6),
('2015-09-13 6:26:00',56,4),
('2015-09-13 6:38:00',34,4),
('2015-09-13 6:42:00',34,2),
('2015-09-13 7:05:00',12,2),
('2015-09-13 7:10:00',12,5),
('2015-09-13 7:34:00',78,5),
('2015-09-13 7:41:00',78,6)
;WITH CTE as
(
SELECT
[Date], [SalesID], [ItemID],
CASE WHEN lag(SalesID) over (order by Date) = SalesID
THEN 0 ELSE 1 END x
FROM #t
)
SELECT
[Date], [SalesID], [ItemID],
(sum(x) over (ORDER BY Date) - 1) % 3 + 1 [Counter]
FROM CTE
Result:
Date SalesID ItemID Counter
2015-09-13 06:00 56 6 1
2015-09-13 06:15 56 6 1
2015-09-13 06:26 56 4 1
2015-09-13 06:38 34 4 2
2015-09-13 06:42 34 2 2
2015-09-13 07:05 12 2 3
2015-09-13 07:10 12 5 3
2015-09-13 07:34 78 5 1
2015-09-13 07:41 78 6 1
This will work for sqlserver 2008:
;WITH CTE as
(
SELECT
[Date],
SalesID,
ItemID,
row_number() over (order by Date)-
row_number() over (partition by SalesID order by Date) x
FROM #t
)
SELECT
[Date],
SalesID,
ItemID,
(dense_rank() over (order by x) - 1) % 3 + 1 [Counter]
FROM CTE
I want to update a table column -Code- with shuffled numbers within its range, with no duplicates and without missing a number from the range.
for example the range is 1-9 and the following is the table:
Id|Name|Code
1 | AC | 2
2 | AB | 1
3 | CB | 5
4 | DE | 9
5 | FE | 3
6 | AE | 4
7 | FD | 6
8 | BD | 7
9 | DC | 8
I want result like in the above example. I am using SQL Server 2008.
Try this:
DECLARE #t TABLE ( ID INT, Code INT )
INSERT INTO #t
( ID )
VALUES ( 1 ),
( 2 ),
( 3 ),
( 4 ),
( 5 ),
( 6 ),
( 7 ),
( 8 ),
( 9 );
WITH cte
AS ( SELECT * ,
ROW_NUMBER() OVER ( ORDER BY NEWID() ) AS rn
FROM #t
)
UPDATE cte
SET code = rn
SELECT *
FROM #t
Output:
ID Code
1 2
2 7
3 4
4 1
5 6
6 8
7 5
8 9
9 3
If you want to manually set the range then you can set starting number of range and do something like:
DECLARE #start INT = 101
DECLARE #t TABLE ( ID INT, Code INT )
INSERT INTO #t
( ID )
VALUES ( 1 ),
( 2 ),
( 3 ),
( 4 ),
( 5 ),
( 6 ),
( 7 ),
( 8 ),
( 9 );
WITH cte
AS ( SELECT * ,
ROW_NUMBER() OVER ( ORDER BY NEWID() ) AS rn
FROM #t
)
UPDATE cte
SET code = rn + #start - 1
SELECT *
FROM #t
Output:
ID Code
1 104
2 108
3 107
4 105
5 102
6 103
7 106
8 101
9 109
NEWID() will give us a type of random id that you can use it for shuffling
As Giorgu Nakeuri answer you can use ROW_NUMBER() for a range of continuous and always start from 1
So I suggest you to use a query like this for shuffling a non-continues Range with different start point of 1:
;With t as (
SELECT *, ROW_NUMBER() OVER (ORDER BY NEWID()) As rndrn
FROM (
SELECT *, ROW_NUMBER() OVER (ORDER BY Id) As rn
FROM yourTable ) t1)
SELECT Id, Name, (SELECT ti.Id FROM t ti WHERE ti.rn = t.rndrn) As Code
FROM t
ORDER BY Id
Sample Result is:
ID Name Code
2 AB 2
3 CB 8
4 DE 7
5 FE 5
6 AE 6
7 FD 9
8 BD 3
9 DC 11
11 AC 4
I've following table:
Id CreationDate FromEntryNo ToEntryNo
1 2013-01-01 1 4
2 2013-01-03 5 8
3 2013-01-05 9 11
...
I want to split this into multiple rows to have a list with all consecutive EntryNo, something like this:
Id CreationDate FromEntryNo ToEntryNo EntryNo
1 2013-01-01 1 4 1
1 2013-01-01 1 4 2
1 2013-01-01 1 4 3
1 2013-01-01 1 4 4
2 2013-01-03 5 8 5
2 2013-01-03 5 8 6
2 2013-01-03 5 8 7
2 2013-01-03 5 8 8
3 2013-01-05 9 11 9
3 2013-01-05 9 11 10
3 2013-01-05 9 11 11
...
My first attempt is CTE with recursion, but it doesn't work:
with cte as
(select gr.Id, gr.CreationDate, gr.FromEntryNo, gr.ToEntryNo, gr.FromEntryNo as [EntryNo]
from dbo.[Register] gr
union all
select No, CreationDate, FromEntryNo, ToEntryNo, EntryNo + 1 from cte where EntryNo <= ToEntryNo
)
select Id, CreationDate, FromEntryNo, ToEntryNo, EntryNo from cte
<
Any idea how to do this using one SQL query?
with cte as
(select gr.Id, gr.CreationDate, gr.FromEntryNo, gr.ToEntryNo,
gr.FromEntryNo as [EntryNo]
from dbo.[Register] gr
union all
select Id, CreationDate, FromEntryNo,
ToEntryNo, EntryNo + 1
from cte where EntryNo < ToEntryNo
)
select Id, CreationDate, FromEntryNo, ToEntryNo, EntryNo
from cte
ORDER BY Id,EntryNo