Update a table column with shuffled numbers within a range - sql-server

Question

I want to update a table column -Code- with shuffled numbers within its range, with no duplicates and without missing a number from the range.
for example the range is 1-9 and the following is the table:
Id|Name|Code
1 | AC | 2
2 | AB | 1
3 | CB | 5
4 | DE | 9
5 | FE | 3
6 | AE | 4
7 | FD | 6
8 | BD | 7
9 | DC | 8
I want result like in the above example. I am using SQL Server 2008.

Answer 1

Try this:
DECLARE #t TABLE ( ID INT, Code INT )
INSERT INTO #t
( ID )
VALUES ( 1 ),
( 2 ),
( 3 ),
( 4 ),
( 5 ),
( 6 ),
( 7 ),
( 8 ),
( 9 );
WITH cte
AS ( SELECT * ,
ROW_NUMBER() OVER ( ORDER BY NEWID() ) AS rn
FROM #t
)
UPDATE cte
SET code = rn
SELECT *
FROM #t
Output:
ID Code
1 2
2 7
3 4
4 1
5 6
6 8
7 5
8 9
9 3
If you want to manually set the range then you can set starting number of range and do something like:
DECLARE #start INT = 101
DECLARE #t TABLE ( ID INT, Code INT )
INSERT INTO #t
( ID )
VALUES ( 1 ),
( 2 ),
( 3 ),
( 4 ),
( 5 ),
( 6 ),
( 7 ),
( 8 ),
( 9 );
WITH cte
AS ( SELECT * ,
ROW_NUMBER() OVER ( ORDER BY NEWID() ) AS rn
FROM #t
)
UPDATE cte
SET code = rn + #start - 1
SELECT *
FROM #t
Output:
ID Code
1 104
2 108
3 107
4 105
5 102
6 103
7 106
8 101
9 109

Answer 2

NEWID() will give us a type of random id that you can use it for shuffling
As Giorgu Nakeuri answer you can use ROW_NUMBER() for a range of continuous and always start from 1
So I suggest you to use a query like this for shuffling a non-continues Range with different start point of 1:
;With t as (
SELECT *, ROW_NUMBER() OVER (ORDER BY NEWID()) As rndrn
FROM (
SELECT *, ROW_NUMBER() OVER (ORDER BY Id) As rn
FROM yourTable ) t1)
SELECT Id, Name, (SELECT ti.Id FROM t ti WHERE ti.rn = t.rndrn) As Code
FROM t
ORDER BY Id
Sample Result is:
ID Name Code
2 AB 2
3 CB 8
4 DE 7
5 FE 5
6 AE 6
7 FD 9
8 BD 3
9 DC 11
11 AC 4