Why can't I get string input? - c

Question

I was trying to simulate stack concept, and this is my code, blasts errors everywhere, from
the very first scanf,
to everywhere referring char* variables,
and eventually the stack pointer (I named it towerIndicator) doesn't change at all.
And then every typed input is somehow screwed: if I type '+314' to add 314 to the stack, it eventually add 3144, if all the problem above were somehow prevented while compiling.
gcc doesn't inform me any usable error message so I don't get where to go at all. Desperately requiring help here.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main() {
const int towerHeight = 32;
int tower[towerHeight];
int towerIndicator = 0;
/*
printf("%i개의 정수를 담을 수 있는 스택을 만들었습니다.\n", towerHeight);
printf("- '+'를 붙여서 정수를 담습니다.\n");
printf("- '-'를 입력해 정수를 빼냅니다.\n");
printf("- '?'를 입력해 스택을 확인합니다.\n");
printf("- '0'를 입력해 작업을 종료합니다.\n");
printf("명령을 입력해주세요.\n================================\n");
*/
char* command;
char* kindOfCommand[1];
char* actualCommand;
while(1) {
printf("> ");
scanf("%s", command);
printf("%s", command);
strncpy(*kindOfCommand, command, 1); kindOfCommand[1] = '\0';puts("#");
strncpy(actualCommand, command+1, strlen(command)-1);puts("$");
switch(**kindOfCommand) {
int i;
case '+':
if(towerIndicator<towerHeight) {
tower[towerIndicator] = atoi(actualCommand);
towerIndicator++;
printf("현재 %i개의 값이 있습니다.\n", towerIndicator);
} else printf("더 이상 넣을 곳이 없습니다.\n");
break;
case '-':
if(towerIndicator>0) {
towerIndicator--;
printf("%i\n", tower[towerIndicator]);
printf("현재 %i개의 값이 있습니다.\n", towerIndicator);
} else printf("더 이상 빼낼 값이 없습니다.\n");
break;
case '?':
default:
printf("[");
for(i=0; i<towerIndicator; i++) {
if(i==towerIndicator) printf("[%i]", tower[i]);
else printf("%i", tower[i]);
if(i!=towerIndicator-1) printf(" ");
}
printf("]\n");
break;
}
if(**kindOfCommand=='0') break;
}
}

Answer 1

There are quite a few modifications required here
loosely fixed may be in for a lot more fixes
// char* command; // <-- initialize this, failure in scanf other wise
char command[120] ;
assuming you are looking for a single character, don't complicate code
// char* kindOfCommand[1]; pointer not required
char kindOfCommand;
since you are using strncpy down somewhere
// char* actualCommand; // <-- initialize this
char actualCommand[126];
and the kindOfCommand code change
// strncpy(kindOfCommand, command, 1);
kindOfCommand = *command;// since you are taking single character
puts("#");
some more at switch
switch( kindOfCommand ) {
and while breaking
if( kindOfCommand == '0' ) break;
Also return before end
return 0;

Answer 2

I applied changes from kkk's answer, and getting input now works well.
char command[11];
char kindOfCommand;
char actualCommand[10];
while(1) {
printf("> ");
scanf("%s", command);
kindOfCommand = *command;
memset(actualCommand,0,sizeof(actualCommand));
strncpy(actualCommand, command+1, strlen(command)-1);
switch(kindOfCommand) { ... }
...
if(kindOfCommand=='0') break;
}
return 0;
}
I needed to solve the input getting screwed. It was because when actualCommand receives a new string from command and it's shorter than previous received string, the last few characters of the string was still remaining in actualCommand. So I put a memset to reset the variable every time the while loop loops. It's not a pointer, so sizeof() could do the work. Otherwise I should've to use strlen() to tell memset the length.