Compare argv[] to list of allowable elements - c

Question

I want myprogram to take user-entered arguments and see if each argument matches a hard-coded list. I am looking for a better alternative to a long switch statement or a series of if else.
Here is a minimal example of what I'm attempting using enum:
$ ./myprogram blue square
//myprogram.c
#include<stdio.h>
int main(int argc, char ** argv){
//many allowable colors and shapes
enum colors_t {blue, red, /*...*/ green};
enum shape_t {square, circle, /*...*/ triangle};
//how do I check if argv[1] is on the list of colors?
if(COMPARE(argv[1], colors_t)
colors_t user_color = argv[1];
else
printf("%s is not a usable color\n",argv[1]);
//same question with shapes
if(COMPARE(argv[2], shape_t)
shape_t user_shape = argv[2];
else
printf("%s is not a usable shape\n",argv[2]);
return 0;
}
I need help with the COMPARE() function to see if argv[i] matches a member of its corresponding enum list.

Answer 1

One way to do this would be to use qsort and bsearch (well, if you don't mind making sure the array is sorted yourself, you don't need qsort). Something like (using your enum color_t):
struct color_picker {
char const *name;
enum colors_t id;
} acolor[] = { {"blue", blue}, {"red", red}, {"green", green} };
const unsigned acolor_count = sizeof acolor / sizeof acolor[0];
int cmp_color(struct color_picker const *l, struct color_picker const *r)
{
return strcmp(l->name, r->name);
}
int main(int argc, char *argv[])
{
struct color_picker *ptr;
qsort(acolor, acolor_count, sizeof acolor[0], cmp_color);
ptr = bsearch(name, acolor, acolor_count, sizeof acolor[0], cmp_color);
if (NULL == ptr) {
printf("%s is not a usable color\n",argv[1]); }
}
/* the value for `enum color_t` is in `ptr->id` */
return 0;
}
You could also use hash tables here, but there is not support for those in the C standard library, so you'd have to code it yourself, or use some third-party library.