I need to display dates of all Mondays in the given date range.
For example, if my start date is 01/05/2015 and end date is 31/05/2015, I need to show
04/05/2015
11/05/2015
18/05/2015
25/05/2015
How is it possible?
This procedure is independent from regions and languages.
Please note the first line with SET DATEFIRST 1.
SET DATEFIRST 1; -- First day of the week is set to monday
DECLARE #DateFrom DateTime ='20150601', #DateTo DateTime = '20150630' ;
WITH CTE(dt)
AS
(
SELECT #DateFrom
UNION ALL
SELECT DATEADD(d, 1, dt) FROM CTE
WHERE dt < #DateTo
)
SELECT dt FROM CTE where datepart ("dw", dt) = 1;
Using a CTE it is possible this way..
DECLARE #DateFrom DateTime ='2015-05-01',
#DateTo DateTime = '2015-05-31'
;WITH CTE(dt)
AS
(
SELECT #DateFrom
UNION ALL
SELECT DATEADD(d, 1, dt) FROM CTE
WHERE dt < #DateTo
)
SELECT 'Monday', dt FROM CTE
WHERE DATENAME(dw, dt) In ('Monday')
Refer: Select dates of a day between two dates.
SELECT [Day],[Dt] FROM dbo.fnGetDatesforAday('7/1/2008','8/31/2008','Sunday')
CREATE FUNCTION fnGetDatesforAday
(
-- Add the parameters for the function here
#DtFrom DATETIME,
#DtTo DATETIME,
#DayName VARCHAR(12)
)
RETURNS #DateList TABLE ([Day] varchar(20),Dt datetime)
AS
BEGIN
IF NOT (#DayName = 'Monday' OR #DayName = 'Sunday' OR #DayName = 'Tuesday' OR #DayName = 'Wednesday' OR #DayName = 'Thursday' OR #DayName = 'Friday' OR #DayName = 'Saturday')
BEGIN
--Error Insert the error message and return
INSERT INTO #DateList
SELECT 'Invalid Day',NULL AS DAT
RETURN
END
DECLARE #TotDays INT
DECLARE #CNT INT
SET #TotDays = DATEDIFF(DD,#DTFROM,#DTTO)-- [NO OF DAYS between two dates]
SET #CNT = 0
WHILE #TotDays >= #CNT -- repeat for all days
BEGIN
-- Pick each single day and check for the day needed
IF DATENAME(DW, (#DTTO - #CNT)) = #DAYNAME
BEGIN
INSERT INTO #DateList
SELECT #DAYNAME,(#DTTO - #CNT) AS DAT
END
SET #CNT = #CNT + 1
END
RETURN
END
SET DATEFIRST 7; -- Set's sunday as first day of week, won't work otherwise
DECLARE #StartDate DATE = '06/01/2015'
DECLARE #EndDate DATETIME = '06/30/2015'
DECLARE #TableOfDates TABLE(DateValue DATETIME)
DECLARE #CurrentDate DATETIME
SET #CurrentDate = #startDate
WHILE #CurrentDate <= #endDate
BEGIN
INSERT INTO #TableOfDates(DateValue) VALUES (#CurrentDate)
SET #CurrentDate = DATEADD(DAY, 1, #CurrentDate)
END
SELECT * FROM #TableOfDates WHERE DATEPART(weekday,Datevalue) = 2
Related
I would like to create a function in SQL Server that would return the no of working days after checking the day from the dimension table dimcalender which has all the working days from 2020 up until 2040
My Code:
Create FUNCTION [udf_WorkingDays]
(
-- Add the parameters for the function here
#StartDate DATETIME,
#EndDate DATETIME
)
RETURNS INT
AS
BEGIN
DECLARE #TotalDays INT
SET #StartDate = '2022/06/01'
SET #EndDate = '2022/06/07'
SET #TotalDays = 0
--SET #TotalDays =(
WHILE (#StartDate <= #EndDate)
BEGIN
sum(select WorkingDay
FROM [XS].[dimCalendar]
where [Date] >= #StartDate
and [Date] <= #EndDate)
set #StartDate = DATEADD(day, 1, #StartDate)
--set #TotalDays = dss;)
END;
RETURN #TotalDays
END;
[dimCalendar] is where all UK working days are recorded.
WorkingDay is just a flag to say 0,1 (if its a working day or not.)
TotalDays is a variable that will have total no. of working days that will be returned.
DECLARE #StartDate DATETIME
DECLARE #EndDate DATETIME
DECLARE #TotalDays INT
DECLARE #DDays INT
SET #StartDate = '2022/06/01'
SET #EndDate = '2022/06/06'
SET #TotalDays = 0
SET #TotalDays = (
SELECT a.toti
FROM (
SELECT SUM(WorkingDay) AS toti
FROM [dimCalendar]
WHERE [Date] >= #StartDate
AND [Date] <= #EndDate
) AS a
)
RETURN #TotalDays;
for example:
--fromdate todate
--2020/10/1 2020/11/01
Output should be like:
--Days dayname
------- ---------------
--2020/10/1 Monday
.. ..
You can use DATENAME to get the WEEKDAY and filter by it:
DATENAME ( WEEKDAY , my_date )
Something like this (the code for generating days is from here)
declare #dt datetime, #dtEnd datetime
set #dt = '2020/10/1'
set #dtEnd = '2020/11/01'
select dateadd(day, number, #dt)
,DATENAME ( WEEKDAY , dateadd(day, number, #dt) )
from
(select number from master.dbo.spt_values
where [type] = 'P'
) n
where dateadd(day, number, #dt) < #dtEnd
AND DATENAME ( WEEKDAY , dateadd(day, number, #dt) ) NOT IN ('Saturday', 'Sunday')
I think this query works well.
declare #result table
(
Days varchar(10),
DayName varchar(20)
)
declare #fromDate date = '2020/10/01'
declare #toDate date = '2020/11/01'
while #fromDate <= #toDate
begin
if DATENAME(weekday, #fromDate) not in ('Saturday', 'Sunday')
begin
insert into #result(Days, DayName)
values(#fromDate, DATENAME(weekday, #fromDate))
end
set #fromDate = DATEADD(day, 1, #fromDate)
end
select *
from #result
I am trying to generate a stock position report as at each month. within my query i have a date variable set at a specific month:
declare #date datetime = CONVERT(DATETIME, '2019-08-13 00:00:00', 121)
declare #lastmonth datetime = (select cast(dateadd(day, -day(getdate()), getdate()) as date))
declare #m int = 0
--**my aim is to ensure that #date = #lastmonth**
while #date<= #lastmonth
Begin
set #m = #m + 1
while #m < 12
Begin
set #date = (select dateadd(mm, #m, #date))
End
End
select
In SQL Server, I want to get days from date to date. Example: from 2015/12/28 to 2016/01/02, the result as
2015/12/28
2015/12/29
2015/12/30
2015/12/31
2016/01/01
2016/01/02
DECLARE #STARTDATE DATETIME = '2015-12-28'
DECLARE #ENDDATE DATETIME = '2016-01-02'
SELECT BETWEEN #STARTDATE AND #ENDDATE AS DAYS
Use CTE
DECLARE #STARTDATE DATE = '2015-12-28'
DECLARE #ENDDATE DATE = '2016-01-02'
;WITH CTE AS
(
SELECT #STARTDATE As dt
UNION ALL
SELECT DATEADD(D,1,dt) AS dt
FROM CTE
WHERE dt < #ENDDATE
)
SELECT * FROM CTE
You could build a calendar table, which would probably come in handy down the road. Or you could use a loop.
DECLARE #ENDDATE DATETIME = '2016-01-02'
DECLARE #DAY DATETIME = '2015-12-28'
WHILE #Day <= #ENDDATE
BEGIN
SELECT #DAY
SET #DAY = DATEADD(DD,1,#DAY)
END
Or for all of the days in one result set:
DECLARE #ENDDATE DATETIME = '2016-01-02'
DECLARE #DAY DATETIME = '2015-12-28'
DECLARE #TABLE TABLE (DATE DATETIME)
WHILE #Day <= #ENDDATE
BEGIN
INSERT #TABLE
VALUES (#DAY)
SET #DAY = DATEADD(DD,1,#DAY)
END
SELECT *
FROM #TABLE
You can specify the dates in your WHERE clause. For example, WHERE date >=#STARTDATE AND date <=#ENDDATE. That should return the full date in your results.
using Numbers table
select dateadd(day,n,startdate)
from numbers
where dateadd(day,n,startdate)<=enddate
order by n
Thanks for all for reading my questions, I have fallen a big problem to retrieve date from SQL Server 2012 by providing year, week number and day name.
Suppose I have
Year = 2016
Week number = 1
Day Name ='FRI'
First day of week='SUN'
Expected result:
01-01-2016
How can I do that?
EDIT: I have found similar solution from here but I have no month name.
My suggestion is based on the solution to the question in the link you provided.
Basically, I've created a calendar that holds the dates since January 1st of the year till #x weeks after that, and then queried that calendar:
-- provided data:
DECLARE #Year int = 2016,
#WeekNumber int = 1,
#DayName char(3) = 'Fri';
-- Calculate start date and end date
DECLARE #StartDate date,
#EndDate date;
SELECT #StartDate = CAST('01-01-'+ CAST(#Year as char(4)) as date),
#EndDate = DATEADD(WEEK, #WeekNumber, #StartDate)
-- Create the calendar
;WITH CTE AS
(
SELECT #StartDate as TheDate
UNION ALL
SELECT DATEADD(DAY, 1, TheDate)
FROM CTE
WHERE DATEADD(DAY, 1, TheDate) <= #EndDate
)
-- Finally, query the calendar:
SELECT TheDate
FROM CTE
WHERE DATEPART(WEEK, TheDate) = #WeekNumber
AND YEAR(TheDate) = #Year
AND DATENAME(WEEKDAY, TheDate) LIKE #DayName + '%'
OPTION(MAXRECURSION 0)
results:
TheDate
----------
2016-01-01
Note: This solution will return no rows if the day you specify is mon, since the first week of 2016 starts on Friday.
TRY THIS
DECLARE #Year varchar(4)
DECLARE #WeekDayday varchar(10)
DECLARE #WeekNumber int
SET #Year ='2016'
SET #WeekDayday ='fri'
SET #WeekNumber =1
--used to solve
DECLARE #StartDate datetime
,#EndDate datetime
,#FirstWeek int
SET #StartDate='01-01-'+' '+#Year
SET #EndDate=#StartDate+38
SET #FirstWeek=DATENAME(week,#StartDate)-1
;with AllDates AS
(
SELECT #StartDate AS DateOf, DATENAME(week,#StartDate)-#FirstWeek AS WeekOf, DATENAME(weekday,#StartDate) AS WeekDayOf
UNION ALL
SELECT DateOf+1, DATENAME(week,DateOf+1)-#FirstWeek AS WeekOf, DATENAME(weekday,DateOf+1) AS WeekDayOf
FROM AllDates
WHERE DateOf<#EndDate
)
SELECT
DateOf
FROM AllDates
WHERE WeekOf=#WeekNumber AND WeekDayOf LIKE #WeekDayday+'%'
ORDER BY DateOf
How about improve that answer by evaluate month name by week number:
--given info
DECLARE #Year varchar(4);
DECLARE #MonthName varchar(10);
DECLARE #WeekDayday varchar(10);
DECLARE #WeekNumber int;
SET #Year = '2016';
SET #WeekDayday = 'Tue';
set #WeekNumber = 46;
-- get month number by week
declare #w int = 0;
declare #m int = 1;
while (#w <= #WeekNumber and #m < 13) begin
set #w = datepart(wk, datefromparts(#year, #m, 1));
if (#w <= #WeekNumber and #m < 13) begin
set #m = #m + 1;
end;
end;
set #m = #m -1;
-- get month name
set #MonthName = left(DateName(month ,DateAdd(month ,#m ,0 ) - 1), 3);
--used to solve
DECLARE #StartDate datetime
,#EndDate datetime
,#FirstWeek int
SET #StartDate='01 '+#MonthName+' '+#Year
SET #EndDate=#StartDate+38
SET #FirstWeek=DATENAME(week,#StartDate)-1
;with AllDates AS
(
SELECT #StartDate AS DateOf, DATENAME(week,#StartDate)-#FirstWeek AS WeekOf, DATENAME(weekday,#StartDate) AS WeekDayOf
UNION ALL
SELECT DateOf+1, DATENAME(week,DateOf+1)-#FirstWeek AS WeekOf, DATENAME(weekday,DateOf+1) AS WeekDayOf
FROM AllDates
WHERE DateOf<#EndDate
)
SELECT
DateOf ,WeekOf ,WeekDayOf
FROM AllDates
WHERE datepart(wk, DateOf) = #WeekNumber AND WeekDayOf LIKE #WeekDayday+'%'
ORDER BY DateOf