Retrieve date from year, week number, day name in SQL Server 2012 - sql-server

Question

Thanks for all for reading my questions, I have fallen a big problem to retrieve date from SQL Server 2012 by providing year, week number and day name.
Suppose I have
Year = 2016
Week number = 1
Day Name ='FRI'
First day of week='SUN'
Expected result:
01-01-2016
How can I do that?
EDIT: I have found similar solution from here but I have no month name.

Answer 1

My suggestion is based on the solution to the question in the link you provided.
Basically, I've created a calendar that holds the dates since January 1st of the year till #x weeks after that, and then queried that calendar:
-- provided data:
DECLARE #Year int = 2016,
#WeekNumber int = 1,
#DayName char(3) = 'Fri';
-- Calculate start date and end date
DECLARE #StartDate date,
#EndDate date;
SELECT #StartDate = CAST('01-01-'+ CAST(#Year as char(4)) as date),
#EndDate = DATEADD(WEEK, #WeekNumber, #StartDate)
-- Create the calendar
;WITH CTE AS
(
SELECT #StartDate as TheDate
UNION ALL
SELECT DATEADD(DAY, 1, TheDate)
FROM CTE
WHERE DATEADD(DAY, 1, TheDate) <= #EndDate
)
-- Finally, query the calendar:
SELECT TheDate
FROM CTE
WHERE DATEPART(WEEK, TheDate) = #WeekNumber
AND YEAR(TheDate) = #Year
AND DATENAME(WEEKDAY, TheDate) LIKE #DayName + '%'
OPTION(MAXRECURSION 0)
results:
TheDate
----------
2016-01-01
Note: This solution will return no rows if the day you specify is mon, since the first week of 2016 starts on Friday.

Answer 2

TRY THIS
DECLARE #Year varchar(4)
DECLARE #WeekDayday varchar(10)
DECLARE #WeekNumber int
SET #Year ='2016'
SET #WeekDayday ='fri'
SET #WeekNumber =1
--used to solve
DECLARE #StartDate datetime
,#EndDate datetime
,#FirstWeek int
SET #StartDate='01-01-'+' '+#Year
SET #EndDate=#StartDate+38
SET #FirstWeek=DATENAME(week,#StartDate)-1
;with AllDates AS
(
SELECT #StartDate AS DateOf, DATENAME(week,#StartDate)-#FirstWeek AS WeekOf, DATENAME(weekday,#StartDate) AS WeekDayOf
UNION ALL
SELECT DateOf+1, DATENAME(week,DateOf+1)-#FirstWeek AS WeekOf, DATENAME(weekday,DateOf+1) AS WeekDayOf
FROM AllDates
WHERE DateOf<#EndDate
)
SELECT
DateOf
FROM AllDates
WHERE WeekOf=#WeekNumber AND WeekDayOf LIKE #WeekDayday+'%'
ORDER BY DateOf

Answer 3

How about improve that answer by evaluate month name by week number:
--given info
DECLARE #Year varchar(4);
DECLARE #MonthName varchar(10);
DECLARE #WeekDayday varchar(10);
DECLARE #WeekNumber int;
SET #Year = '2016';
SET #WeekDayday = 'Tue';
set #WeekNumber = 46;
-- get month number by week
declare #w int = 0;
declare #m int = 1;
while (#w <= #WeekNumber and #m < 13) begin
set #w = datepart(wk, datefromparts(#year, #m, 1));
if (#w <= #WeekNumber and #m < 13) begin
set #m = #m + 1;
end;
end;
set #m = #m -1;
-- get month name
set #MonthName = left(DateName(month ,DateAdd(month ,#m ,0 ) - 1), 3);
--used to solve
DECLARE #StartDate datetime
,#EndDate datetime
,#FirstWeek int
SET #StartDate='01 '+#MonthName+' '+#Year
SET #EndDate=#StartDate+38
SET #FirstWeek=DATENAME(week,#StartDate)-1
;with AllDates AS
(
SELECT #StartDate AS DateOf, DATENAME(week,#StartDate)-#FirstWeek AS WeekOf, DATENAME(weekday,#StartDate) AS WeekDayOf
UNION ALL
SELECT DateOf+1, DATENAME(week,DateOf+1)-#FirstWeek AS WeekOf, DATENAME(weekday,DateOf+1) AS WeekDayOf
FROM AllDates
WHERE DateOf<#EndDate
)
SELECT
DateOf ,WeekOf ,WeekDayOf
FROM AllDates
WHERE datepart(wk, DateOf) = #WeekNumber AND WeekDayOf LIKE #WeekDayday+'%'
ORDER BY DateOf