Is it possible to add all the dates between 1st Jan-31-Dec in MS Sql server using query?
If someone has done it before please guide me to right track.
Thanks
DECLARE #dt Date
SET #dt = '2015-01-01'
WHILE #dt < '2016-01-01'
BEGIN
SELECT #dt
--INSERT .....
SET #dt = DATEADD(DAY, 1, #dt)
END
Of course it depends on your table structure
using loop we can achieve this
Declare #date table(d datetime)
Declare #d datetime, #d1 datetime, #d2 datetime
Declare #inc INT
set #d1='20150101'
set #d2='20151231'
Set #inc = DATEDIFF(D, #d1, #d2)
Set #d = #d1
While #d<=#d2
Begin
Insert into #date values (#d)
set #d=#d+1
End
Select d as DateCol from #date
This should do the trick:
DECLARE #year int = 2015
;WITH N(N)AS
(SELECT 1 FROM(VALUES(1),(1),(1),(1),(1),(1),(1),(1),(1),(1))M(N)),
tally(N)AS(SELECT ROW_NUMBER()OVER(ORDER BY N.N)-1 FROM N,N a,N b,N c,N d,N e,N f)
SELECT top (datediff(d, cast(#year as char(4)), cast(#year + 1 as char(4))))
CAST(DATEADD(d, N, cast(#year as char(4))) as date)
FROM tally
Result:
2015-01-01
2015-01-02
..
..
2015-12-31
Related
In SQL Server, I want to get days from date to date. Example: from 2015/12/28 to 2016/01/02, the result as
2015/12/28
2015/12/29
2015/12/30
2015/12/31
2016/01/01
2016/01/02
DECLARE #STARTDATE DATETIME = '2015-12-28'
DECLARE #ENDDATE DATETIME = '2016-01-02'
SELECT BETWEEN #STARTDATE AND #ENDDATE AS DAYS
Use CTE
DECLARE #STARTDATE DATE = '2015-12-28'
DECLARE #ENDDATE DATE = '2016-01-02'
;WITH CTE AS
(
SELECT #STARTDATE As dt
UNION ALL
SELECT DATEADD(D,1,dt) AS dt
FROM CTE
WHERE dt < #ENDDATE
)
SELECT * FROM CTE
You could build a calendar table, which would probably come in handy down the road. Or you could use a loop.
DECLARE #ENDDATE DATETIME = '2016-01-02'
DECLARE #DAY DATETIME = '2015-12-28'
WHILE #Day <= #ENDDATE
BEGIN
SELECT #DAY
SET #DAY = DATEADD(DD,1,#DAY)
END
Or for all of the days in one result set:
DECLARE #ENDDATE DATETIME = '2016-01-02'
DECLARE #DAY DATETIME = '2015-12-28'
DECLARE #TABLE TABLE (DATE DATETIME)
WHILE #Day <= #ENDDATE
BEGIN
INSERT #TABLE
VALUES (#DAY)
SET #DAY = DATEADD(DD,1,#DAY)
END
SELECT *
FROM #TABLE
You can specify the dates in your WHERE clause. For example, WHERE date >=#STARTDATE AND date <=#ENDDATE. That should return the full date in your results.
using Numbers table
select dateadd(day,n,startdate)
from numbers
where dateadd(day,n,startdate)<=enddate
order by n
Thanks for all for reading my questions, I have fallen a big problem to retrieve date from SQL Server 2012 by providing year, week number and day name.
Suppose I have
Year = 2016
Week number = 1
Day Name ='FRI'
First day of week='SUN'
Expected result:
01-01-2016
How can I do that?
EDIT: I have found similar solution from here but I have no month name.
My suggestion is based on the solution to the question in the link you provided.
Basically, I've created a calendar that holds the dates since January 1st of the year till #x weeks after that, and then queried that calendar:
-- provided data:
DECLARE #Year int = 2016,
#WeekNumber int = 1,
#DayName char(3) = 'Fri';
-- Calculate start date and end date
DECLARE #StartDate date,
#EndDate date;
SELECT #StartDate = CAST('01-01-'+ CAST(#Year as char(4)) as date),
#EndDate = DATEADD(WEEK, #WeekNumber, #StartDate)
-- Create the calendar
;WITH CTE AS
(
SELECT #StartDate as TheDate
UNION ALL
SELECT DATEADD(DAY, 1, TheDate)
FROM CTE
WHERE DATEADD(DAY, 1, TheDate) <= #EndDate
)
-- Finally, query the calendar:
SELECT TheDate
FROM CTE
WHERE DATEPART(WEEK, TheDate) = #WeekNumber
AND YEAR(TheDate) = #Year
AND DATENAME(WEEKDAY, TheDate) LIKE #DayName + '%'
OPTION(MAXRECURSION 0)
results:
TheDate
----------
2016-01-01
Note: This solution will return no rows if the day you specify is mon, since the first week of 2016 starts on Friday.
TRY THIS
DECLARE #Year varchar(4)
DECLARE #WeekDayday varchar(10)
DECLARE #WeekNumber int
SET #Year ='2016'
SET #WeekDayday ='fri'
SET #WeekNumber =1
--used to solve
DECLARE #StartDate datetime
,#EndDate datetime
,#FirstWeek int
SET #StartDate='01-01-'+' '+#Year
SET #EndDate=#StartDate+38
SET #FirstWeek=DATENAME(week,#StartDate)-1
;with AllDates AS
(
SELECT #StartDate AS DateOf, DATENAME(week,#StartDate)-#FirstWeek AS WeekOf, DATENAME(weekday,#StartDate) AS WeekDayOf
UNION ALL
SELECT DateOf+1, DATENAME(week,DateOf+1)-#FirstWeek AS WeekOf, DATENAME(weekday,DateOf+1) AS WeekDayOf
FROM AllDates
WHERE DateOf<#EndDate
)
SELECT
DateOf
FROM AllDates
WHERE WeekOf=#WeekNumber AND WeekDayOf LIKE #WeekDayday+'%'
ORDER BY DateOf
How about improve that answer by evaluate month name by week number:
--given info
DECLARE #Year varchar(4);
DECLARE #MonthName varchar(10);
DECLARE #WeekDayday varchar(10);
DECLARE #WeekNumber int;
SET #Year = '2016';
SET #WeekDayday = 'Tue';
set #WeekNumber = 46;
-- get month number by week
declare #w int = 0;
declare #m int = 1;
while (#w <= #WeekNumber and #m < 13) begin
set #w = datepart(wk, datefromparts(#year, #m, 1));
if (#w <= #WeekNumber and #m < 13) begin
set #m = #m + 1;
end;
end;
set #m = #m -1;
-- get month name
set #MonthName = left(DateName(month ,DateAdd(month ,#m ,0 ) - 1), 3);
--used to solve
DECLARE #StartDate datetime
,#EndDate datetime
,#FirstWeek int
SET #StartDate='01 '+#MonthName+' '+#Year
SET #EndDate=#StartDate+38
SET #FirstWeek=DATENAME(week,#StartDate)-1
;with AllDates AS
(
SELECT #StartDate AS DateOf, DATENAME(week,#StartDate)-#FirstWeek AS WeekOf, DATENAME(weekday,#StartDate) AS WeekDayOf
UNION ALL
SELECT DateOf+1, DATENAME(week,DateOf+1)-#FirstWeek AS WeekOf, DATENAME(weekday,DateOf+1) AS WeekDayOf
FROM AllDates
WHERE DateOf<#EndDate
)
SELECT
DateOf ,WeekOf ,WeekDayOf
FROM AllDates
WHERE datepart(wk, DateOf) = #WeekNumber AND WeekDayOf LIKE #WeekDayday+'%'
ORDER BY DateOf
I have a sql table that has the following
ID StartDate EndDate
10 2015-12-01 2016-05-31
15 2016-01-05 2016-07-04
20 2016-02-10 2016-08-09
I need to break down the months like so...
ID StartDate EndDate
10 2015-12-01 2015-12-31
10 2016-01-01 2016-01-31
10 2016-02-01 2016-02-29
10 2016-03-01 2016-03-31
10 2016-04-01 2016-04-30
10 2016-05-01 2016-05-31
15 2016-01-05 2016-02-04
15 2016-02-05 2016-03-04
15 2016-03-05 2016-04-04
15 2016-04-05 2016-05-04
15 2016-05-05 2016-06-04
15 2016-06-05 2016-07-04
etc
I'm new to SQL so an example would be very helpful
Calendar
recommended if you have persistent Calendar/DateRanges table
declare #datebegin date = '20140101'
;with cteCalendar as
(
select
c.period_start,
dateadd(dd, -1, dateadd(mm, 1, c.period_start)) as period_end
from
(
select top 100
dateadd(mm, row_number() over(order by sc.object_id)-1, #datebegin) as period_start
from sys.columns sc
order by period_start
) c
),
cteData as
(
select cast(10 as int) as id, cast('20151201' as date) as StartDate, cast('20160531' as date) as EndDate
union all
select 15, '20160105', '20160704'
union all
select 25, '20160210', '20160809'
),
cteDataEx as
(
select d.id, d.StartDate, d.EndDate, datepart(dd, d.StartDate)-1 as DateOffset
from cteData d
)
select
d.id,
dateadd(dd, d.DateOffset, c.period_start) as StartDate,
dateadd(dd, d.DateOffset, c.period_end) as EndDate
from cteDataEx d
inner join cteCalendar c on c.period_start <= d.EndDate and c.period_end >= d.StartDate
where dateadd(dd, d.DateOffset, c.period_end) <= d.EndDate
order by id, StartDate
Actually I did not notice at the beginning that periods may start and end not at 1st day of month, so had to append some calculations after completion of the whole script. Later I realized that <= >= date filter produces unnecessary last row which overflows original date range high bound. So had to append final filter and after that modification don't like this approach totally )) May be some enhancements can be applied but I'm not interested in. Lots of ways to accomplish this task. Additional information about nature and purpose of periods given may alter relevance and applicability of different approaches
Recursion
no extra data required but recursion can be slow if date ranges can be wide enough.
;with cteData as
(
select cast(10 as int) as id, cast('20151201' as date) as StartDate, cast('20160531' as date) as EndDate
union all
select 15, '20160105', '20160704'
union all
select 25, '20160210', '20160809'
),
ctePeriods as
(
select
d.id,
d.StartDate,
dateadd(dd, -1, dateadd(mm, 1, d.StartDate)) as EndDate,
d.EndDate as _EndDate
from cteData d
union all
select
p.id,
dateadd(mm, 1, p.StartDate),
dateadd(dd, -1, dateadd(mm, 2, p.StartDate)),
p._EndDate
from ctePeriods p
where p.EndDate < p._EndDate
)
select p.id, p.StartDate, p.EndDate
from ctePeriods p
order by id, startdate
this code generate the rage of months, inclute leap year, but I don't undestand your need so explain better
create table #dia_meses
(mes int,
messtr varchar(2),
dia_final varchar(2))
insert into #dia_meses values(1,'01','31')
insert into #dia_meses values(2,'02','29')
insert into #dia_meses values(3,'03','31')
insert into #dia_meses values(4,'04','30')
insert into #dia_meses values(5,'05','31')
insert into #dia_meses values(6,'06','30')
insert into #dia_meses values(7,'07','31')
insert into #dia_meses values(8,'08','31')
insert into #dia_meses values(9,'09','30')
insert into #dia_meses values(10,'10','31')
insert into #dia_meses values(11,'11','30')
insert into #dia_meses values(12,'12','31')
declare #year varchar(4)
declare #contador int
set #year =convert(varchar,DATEPART(YEAR,GETDATE()))
set #contador =convert(varchar,DATEPART(month,GETDATE()))
declare #dataIni datetime
declare #datafim datetime
set #dataIni=(select #year+'-'+messtr+'-01' from #dia_meses where mes=#contador)
--pulo do gato ano bissexto
if(#contador=2)
begin
if(select ISDATE(#year+'-'+messtr+'-'+dia_final) from #dia_meses where mes=#contador)=0
begin
set #datafim=(select #year+'-'+messtr+'-28' from #dia_meses where mes=#contador)
end
else--ano bissexto
begin
set #datafim=(select #year+'-'+messtr+'-'+dia_final from #dia_meses where mes=#contador)
end
end
else
begin
set #datafim=(select #year+'-'+messtr+'-'+dia_final from #dia_meses where mes=#contador)
end
print #dataIni
print #dataFim
This will work on SQL Server 2012 and up; the EOMONTH function does not exist on earlier versions.
DECLARE #table TABLE (ID INT, StartDate DATE, EndDate DATE)
DECLARE #outtable TABLE (ID INT, StartDate DATE, EndDate DATE)
DECLARE #ID INT
DECLARE #StartDate DATE
DECLARE #Date1 DATE
DECLARE #Date2 DATE
DECLARE #EndDate DATE
INSERT INTO #table VALUES
(10,'2015-12-01','2016-05-31')
,(15,'2016-01-05','2016-07-04')
,(20,'2016-02-10','2016-08-09')
DECLARE tablecursor CURSOR FOR
SELECT * FROM #table
OPEN tablecursor
FETCH NEXT FROM tablecursor INTO #ID, #StartDate, #EndDate
WHILE ##FETCH_STATUS = 0
BEGIN
SET #Date1 = #StartDate
SET #Date2 = EOMONTH(#Date1)
WHILE #Date1 < #EndDate
BEGIN
PRINT CONVERT(VARCHAR,#ID) + ' ' + CONVERT(VARCHAR,#Date1) + ' ' + CONVERT(VARCHAR,#Date2)
INSERT INTO #outtable
SELECT #ID, #Date1, #Date2
SET #Date1 = DATEADD(DAY,1,#Date2)
SET #Date2 = EOMONTH(#Date1)
IF #Date2 > #EndDate
BEGIN
SET #Date2 = #EndDate
END
END
FETCH NEXT FROM tablecursor INTO #ID, #StartDate, #EndDate
END
SELECT * FROM #outtable
CLOSE tablecursor
DEALLOCATE tablecursor
I'm trying to create a stored procedure in SQL Server that basically increments the months from a given start date up to a given end date and updates them into a predefined table.
Problem:
Somewhat like this:
Exec MonthRunner #Start ='2014-01-01', #End = '2014-06-01'
Should give me a table like this:
Date
2014-01-01
2014-02-01
2015-03-01
2015-04-01
2015-05-01
2015-06-01
Approach:
A loop programmed using a cursor. Something similar to this:
Create Procedure MonthRunner(#Start date, #End date)
AS
DECLARE #Date date
DECLARE #getid CURSOR
SET #getid = CURSOR FOR
Select (#Start)
Set #getid
OPEN #getid
FETCH NEXT
FROM #getid into #Date
WHILE ##FETCH_STATUS = 0
BEGIN
SET #Date = (Select Dateadd(Month, 1, #Date))
DECLARE #sqlrun varchar(max)
SET #sqlrun= 'Update myTable' + 'Set Date=' + #Date
EXEC #sqlrun
fetch next
from #getid into #Date
END
CLOSE #getid
DEALLOCATE #getid
So far my result is:
Update myTable Set Date='2014-02-01'
But there is no loop and also I don't know how to terminate the loop using the variable #End.
Your help would be greatly appreciated!
Thanks in advance,
Clemens
This can easily be done with a recursive CTE:
;WITH cte AS (
SELECT #Start AS [Month]
UNION ALL
SELECT DATEADD(MONTH, 1, [Month])
FROM cte
WHERE [Month] < #End
)
SELECT [Month]
FROM cte
OPTION (MAXRECURSION 0)
I looped similar to this:
DECLARE #Start date
DECLARE #End date
DECLARE #counter date
set #counter = #Start
while #counter <= #End
begin
print 'The counter is ' + cast(#counter as char)
set #counter = (Select Dateadd(Month, 1, #counter))
end
what do you think about this solution? (of course I have to change the text)
increment months from a starting date to an end date in sp
ALTER PROCEDURE "dbo"."monthIncrementSp"
AS
DECLARE #startDate VARCHAR(50);
DECLARE #endDate VARCHAR(50);
SET #startDate = '01-01-2017';
SET #endDate = '31-12-2017';
SELECT TOP (DATEDIFF(MONTH, CONVERT(DATE, #startDate, 105),CONVERT(DATE, #endDate, 105))+1)
DATEADD(MONTH, ROW_NUMBER() OVER (ORDER BY name)-1, CONVERT(DATE, #startDate, 105))
FROM sys.all_columns
Here's a table-valued function to get the beginning of a month:
CREATE FUNCTION dbo.MonthBegin (
#date DATE = NULL
, #offset INT = 0
)
RETURNS TABLE
AS
RETURN (
SELECT D = DATEADD(m, DATEDIFF(m, 0, #date) + #offset, 0)
);
Alone, this function doesn't quite do what you need. Combine it with a set of integers though and you can have a lot of fun:
DECLARE #seedDate DATE = GETDATE();
SELECT *
FROM dbo.RangeInt(-100, 100) Nums
CROSS APPLY dbo.MonthBegin(#seedDate, Nums.N) Dates;
The above example uses a TVF to generate a set of numbers between -100 and 100 and then passes those numbers to the MonthBegin TVF (along with a seed date). You could also write this to be based off of a numbers table or CTE... whatever is most familiar/comfortable to you.
I need to display dates of all Mondays in the given date range.
For example, if my start date is 01/05/2015 and end date is 31/05/2015, I need to show
04/05/2015
11/05/2015
18/05/2015
25/05/2015
How is it possible?
This procedure is independent from regions and languages.
Please note the first line with SET DATEFIRST 1.
SET DATEFIRST 1; -- First day of the week is set to monday
DECLARE #DateFrom DateTime ='20150601', #DateTo DateTime = '20150630' ;
WITH CTE(dt)
AS
(
SELECT #DateFrom
UNION ALL
SELECT DATEADD(d, 1, dt) FROM CTE
WHERE dt < #DateTo
)
SELECT dt FROM CTE where datepart ("dw", dt) = 1;
Using a CTE it is possible this way..
DECLARE #DateFrom DateTime ='2015-05-01',
#DateTo DateTime = '2015-05-31'
;WITH CTE(dt)
AS
(
SELECT #DateFrom
UNION ALL
SELECT DATEADD(d, 1, dt) FROM CTE
WHERE dt < #DateTo
)
SELECT 'Monday', dt FROM CTE
WHERE DATENAME(dw, dt) In ('Monday')
Refer: Select dates of a day between two dates.
SELECT [Day],[Dt] FROM dbo.fnGetDatesforAday('7/1/2008','8/31/2008','Sunday')
CREATE FUNCTION fnGetDatesforAday
(
-- Add the parameters for the function here
#DtFrom DATETIME,
#DtTo DATETIME,
#DayName VARCHAR(12)
)
RETURNS #DateList TABLE ([Day] varchar(20),Dt datetime)
AS
BEGIN
IF NOT (#DayName = 'Monday' OR #DayName = 'Sunday' OR #DayName = 'Tuesday' OR #DayName = 'Wednesday' OR #DayName = 'Thursday' OR #DayName = 'Friday' OR #DayName = 'Saturday')
BEGIN
--Error Insert the error message and return
INSERT INTO #DateList
SELECT 'Invalid Day',NULL AS DAT
RETURN
END
DECLARE #TotDays INT
DECLARE #CNT INT
SET #TotDays = DATEDIFF(DD,#DTFROM,#DTTO)-- [NO OF DAYS between two dates]
SET #CNT = 0
WHILE #TotDays >= #CNT -- repeat for all days
BEGIN
-- Pick each single day and check for the day needed
IF DATENAME(DW, (#DTTO - #CNT)) = #DAYNAME
BEGIN
INSERT INTO #DateList
SELECT #DAYNAME,(#DTTO - #CNT) AS DAT
END
SET #CNT = #CNT + 1
END
RETURN
END
SET DATEFIRST 7; -- Set's sunday as first day of week, won't work otherwise
DECLARE #StartDate DATE = '06/01/2015'
DECLARE #EndDate DATETIME = '06/30/2015'
DECLARE #TableOfDates TABLE(DateValue DATETIME)
DECLARE #CurrentDate DATETIME
SET #CurrentDate = #startDate
WHILE #CurrentDate <= #endDate
BEGIN
INSERT INTO #TableOfDates(DateValue) VALUES (#CurrentDate)
SET #CurrentDate = DATEADD(DAY, 1, #CurrentDate)
END
SELECT * FROM #TableOfDates WHERE DATEPART(weekday,Datevalue) = 2