MS SQL REPLACE based on 1 character to the left of the $ - sql-server

Question

I am not a SQL expert so please forgive me if this is SQL 101 :).
In a select statement there are 2 replace functions. They look for a Servername and it's admin share d$ by it's UNC path. Example '\SERVERNAME\d$'
It then replaces '\SERVERNAME\d$' with 'D:'.
Here is the query currently:
select Replace(p.Path,'\\SERVERNAME\d$','D:') as searchpath
,p.path as fullpath
,s.ShareName
,s.SharePath
,p.Member
,p.Access
From Paths As p
Left Outer Join Shares as s on
Replace(p.Path,'\\SERVERNAME\d$','D:') Like s.SharePath + '\%'
Up until now it has always been d$.
Today my needs have changed and I need the query to find ANY servername UNC path admin share regardless of share letter (c$, d$, e$, f$...etc) and replace it with it's respective drive letter (D:, E:, F:... etc).
My thought is replace function could find the $ and look one character to the left of it to get the proper share letter, then use that for the replace. The issue I have, not being a SQL professional, is that I know SQL can likley do what I need it to do...I just don't know how to get there. I've googled and found some examples, but haven't had any luck in getting them to work.
Any help would be greatly appreciated.

Answer 1

You can use a combination of STUFF, PATINDEX, LEN to get what you want.
Sample Query
DECLARE #ReplaceChar VARCHAR(100) = '[prefixcharacters]\\SERVERNAME\d$[postcharacter]'
DECLARE #SearchString VARCHAR(100) = '\\SERVERNAME\_$'
SELECT
STUFF(#ReplaceChar,PATINDEX('%' + #SearchString + '%',#ReplaceChar),LEN(#SearchString),
UPPER(SUBSTRING(#ReplaceChar,PATINDEX('%' + #SearchString + '%',#ReplaceChar) + LEN(#SearchString) - 2,1)) + ':') as searchpath
WHERE PATINDEX('%' + #SearchString + '%',#ReplaceChar) > 0
Output
[prefixcharacters]D:[postcharacter]
Alternate Query
You can shorten the query if you want to get the previous character before $ as per your title. Something like this
DECLARE #ReplaceChar VARCHAR(100) = '[prefixcharacters]\\SERVERNAME\d$[postcharacter]'
DECLARE #SearchString VARCHAR(100) = '\\SERVERNAME\_$'
SELECT
STUFF(#ReplaceChar,
PATINDEX('%'+#SearchString+'%',#ReplaceChar),
LEN(#SearchString),
UPPER(SUBSTRING(#ReplaceChar,CHARINDEX('$',#ReplaceChar) -1,1)) + ':')
WHERE PATINDEX('%'+#SearchString+'%',#ReplaceChar) > 0
In this query
STUFF replaces your pattern with with the character before $ + ':'
Start of pattern is identified by PATINDEX('%'+#SearchString+'%',#ReplaceChar)
D is identified by getting the charindex of '$' and then getting the previous character using SUBSTRING

Answer 2

What about ¸
select Replace(SUBSTRING(p.path, 14, Len(#spath)-14),'$',':') as searchpath
,p.path as fullpath
,s.ShareName
,s.SharePath
,p.Member
,p.Access
From Paths As p
Left Outer Join Shares as s on
Replace(SUBSTRING(p.path, 14, Len(#spath)-14),'$',':') Like s.SharePath + '\%
select as searchpath

Answer 3

DECLARE #str nvarchar (100)
SET #str = '\\SERVERNAME\d$'
IF #str LIKE '\\SERVERNAME\_$'
SET #str = UPPER(SUBSTRING(#str, 14, 1)) + ':'
SELECT #str
Starting from previous, something like
select UPPER(SUBSTRING(p.path, 14, 1)) + ':' as searchpath
,p.path as fullpath
,s.ShareName
,s.SharePath
,p.Member
,p.Access
From Paths As p
Left Outer Join Shares as s on
SUBSTRING(p.path, 14, 1) + ':' Like s.SharePath + '\%'

Answer 4

I am no mysql expert either :)
Based on the logic you mentioned in the last part of the question, I have used concat and substring to get to the drive letter in the column.
Hope this helps
select replace(path, concat(substring(path, 1, locate('$', path) - 2), substring(path, locate('$', path) - 1, 1) , '$'), concat(substring(path, locate('$', path) - 1, 1) , ':')) as searchpath ...
The remaining part of the query would be the same.