irb(main):001:0> d = OurDomains.find(3)
=> #<OurDomains:0x000000056ea410 #id="2", #internal_domains=["1.com", "2.com", "3.com"], #external_domains=["2.com"]>
Using the above response as an example, could someone give me a guide on how to compare values in the internal_domains and external_domains array please? Specially, I am interested in displaying all the values in internal_domains that corresponds to a value in external_domains in my view.html.erb; that is "2.com" in this case
#internal_domains & #external_domains
Related
As #vadian suggested, I am learning Xcode from Paul Hudson's 100 days of SwiftUI to better understand the basics (even though I am still struggling with time to deliver working GitHub repository search - no it is not for the job I am working on right now).
I am doing a lesson on Arrays, so pretty basic stuff right now and I struggle to map the String from array on the sorted array. I don't get why, but I get the:
Ambiguous use of 'init'
error.
Here's the code:
let cities = ["London", "Tokyo", "Rome", "Budapest"]
print(cities.sorted())
let citiesSorted = cities.sorted()
let citiesSortedString = citiesSorted.map(String.init).joined(separator:", ")
And it's so really strange, since I pulled the similar thing out before in the same Playground but not with the sorted Array:
var schoolScoresString = schoolScores.map(String.init).joined(separator:", ")
print(schoolScoresString)
And yes I tried changing let to var. It didn't help.
cities is already of type [String], so you're passing a String to String.init, which obviously won't work. If you want to join an array of Strings into a single String, remove the map and just call joined on the array.
let citiesSortedString = citiesSorted.joined(separator:", ")
I'm using this json content (I'm open to suggestions on better formatting here):
{"forwardingZones": [{"name": "corp.mycompany.com","dnsServers": ["192.168.0.1","192.168.0.2"]}]}
Note: we may add more items to this list as we scale out, both more IPs and more names, hence the "join(',')" in the end of the code below.
And I'm trying to loop through it to get this result:
corp.mycompany.com=192.168.0.1;192.168.0.2
Using this code:
forward_zones = node['DNS']['forward_zones'].each do |forwarded_zone|
forwarded_zone_name = forwarded_zone['name']
forwarded_zone_dns_servers = forwarded_zone['dns_servers'].join(';')
"#{forwarded_zone_name}=#{forwarded_zone_dns_servers}"
end.join(',')
This is the result that I get:
{"dnsServers"=>["192.168.0.1", "192.168.0.2"], "name"=>"corp.mycompany.com"}
What am i doing wrong...?
x.each returns x. You want x.map.
i am using laravel 5.2 and trying to update records using whereIn('id',[1,2]) but when i try to pass a json value [1,2] to it , i returns
parameterize() must be of the type array, string given. I am mentioning my code below.
$load_id=json_encode($request->chk_load,JSON_NUMERIC_CHECK); // it returns [1,2]
Load::whereIn('id',$load_id)->update(array('status'=>3));
What should i do to fix this error. ?
seems json_encode($request->chk_load,JSON_NUMERIC_CHECK);
returns json string and not an array..
can you elaboarate $request->chk_load is what kind of data it is?
Scala beginner who is trying to store values obtains in a Scala foreach loop but failing miserably.
The basic foreach loop looks like this currently:
order.orderList.foreach((x: OrderRef) => {
val references = x.ref}))
When run this foreach loop will execute twice and return a reference each time. I'm trying to capture the reference value it returns on each run (so two references in either a list or array form so I can access these values later)
I'm really confused about how to go about doing this...
I attempted to retrieve and store the values as an array but when ran, the array list doesn't seem to hold any values.
This was my attempt:
val newArray = Array(order.orderList.foreach((x: OrderRef) => {
val references = x.ref
}))
println(newArray)
Any advice would be much appreciated. If there is a better way to achieve this, please share. Thanks
Use map instead of foreach
order.orderList.map((x: OrderRef) => {x.ref}))
Also val references = x.ref doesn't return anything. It create new local variable and assign value to it.
Agree with answer 1, and I believe the reason is below:
Return of 'foreach' or 'for' should be 'Unit', and 'map' is an with an changed type result like example below:
def map[B](f: (A) ⇒ B): Array[B]
Compare To for and foreach, the prototype should be like this
def foreach(f: (A) ⇒ Unit): Unit
So If you wanna to get an changed data which is maped from your source data, considering more about functions like map, flatMap, and these functions will traverse all datas like for and foreach(except with yield), but with return values.
While working on one application I am getting this error:
can't convert Enumerator into Array
Here is my code, mr_collection is MongoID query.
mr_collection = self.where(query).map_reduce(map, reduce).finalize(finalize).out({:replace => 'mr_results'})
paginator = WillPaginate::Collection.new(page, limit, collection_count)
collection = mr_collection.find(
:sort => sort,
:limit => limit,
:skip => skip
)
paginator.replace(collection)
While getting mr_collection, if I inspect the result mr_collection gives me:
[
{"_id"=>1.0, "value"=>{"s"=>4.2, "p"=>14.95, "pml"=>0.01993}},
{"_id"=>2.0, "value"=>{"s"=>3.7, "p"=>12.9, "pml"=>0.0172}},
{"_id"=>3.0, "value"=>{"s"=>4.2, "p"=>12.9, "pml"=>0.0172}},
{"_id"=>4.0, "value"=>{"s"=>4.0, "p"=>11.95, "pml"=>0.01593}},
{"_id"=>300.0, "value"=>{"s"=>0.0, "p"=>8.95, "pml"=>0.01193}},
]
While getting collection, if I inspect the result collection gives me:
#<Enumerator: []:find({:sort=>[["value.s", :desc], ["value.pml", :asc]], :limit=>10, :skip=>0})>
I am getting error on the line paginator.replace(collection). I'm using Ruby 1.9.3 & Rails 3.2.6.
collection is an Enumerator which obviously can't convert into an Array, which is what replace expects.
Here are the comments from the rubydocs:
Enumerable#find(ifnone = nil) { |e| ... }
Passes each entry in enum to block. Returns the first for which block
is not false. If no object matches, calls ifnone and returns its
result when it is specified, or returns nil otherwise.
If no block is given, an enumerator is returned instead.
Therefore you have two options:
If you want all elements, yield from the Enumerator to an Array.
If you only want the first match, supply a block that determines what the match is.
Hope this helps.
(Moral of the story: always read the docs!)
I have no idea about mongoid having never used it.
But a search has brought to fore an awfully similar question -
Mongoid 3 - access map_reduce results
Unfortunately my environent is not set to test the magic of
collection = mr_collection.send(:documents).sort(sort).limit(limit).skip(skip).to_a
Have you had a look at this link? Hopefully it'll help solve your issue!