Can anyone guide me to a route to take as far as making a basic page in drupal 7 and then having that page load a block with images inside based on URL path.
So I have a content type that is for 1 type of pages and another content type for another type of page. Each content type has 30 pages. I don't want to create 30 pages for 1 page that will have the same content over and over but with a different logo.
http://www.example.com/contenttype1name/%/staticname
I need to make the menu have an argument passed and then based on what is passed go get the correct image.
Sorry if this is confusing. Thanks for your help.
You should look into the views module - it allows you to easily create a view with dynamic parameters (contextual filters) that allow you to easily tackle things like this.
I used contextual filters on views and nodesymlinks along with panels that was already installed.
Modules Used:
Views
Nodesymlinks
Panels
Step 1: admin > Modules > Add Modules/Enable.
Enable Nodesymlinks
Enable Panels and panelizer
Step 2: admin > Structure > Views > Add View.
Make view, name it and check block not page (I used Fields).
Step 3: admin > Structure > Views > your view.
Add filtered Criteria - Content type = your type.
Content should be Published only.
Add contextual filter: title.
Configure contextual filter: Content: Title.
Provide default value. Select Raw Value from URL.
Path component select 2. You can add it where you want in the URL.
Use path alias and check it.
Under More you need to check this box: Transform spaces to dashes in URL.
Check it in Views and save.
Step 4: admin > Content > Add Page.
Add a basic page.
On the bottom of the page you will see: Provide a menu link. You want to check that box. Now you will be able to add all the menu links that you wish this page to show up on. Add links/Paths and titles. Make sure you use argument 2 in your link to be your content on the views block in step 3.
Step 5: admin > config > content > panelizer.
You want to go into this pages panelizer, could be basic or whatever your content type would be. Add your views block and save.
Step 6:
Test it. If it doesn't work then you need to check your titles in argument 2 in the URL. Worked for me. Saved me a ton of time.
Related
How do I extract specific field for display in a taxonomy page?
I have a custom content type called "film" and each film has a Term Reference field called "casting". As expected I can click on a "casting" (tag) it brings me a page where all films are listed wherever this tag is associated. For expample if I click on "Kate Winslet" from movie Titanic, I land on a page http://localhost/mysite/tags/kate-winslet where other movies of Kate Winslet are listed. Up to this point everything is just fine.
I do not want Drupal to pull in and show default fields like just Title and Body in its own display format. Rather I want it so that I can display a photo from each film, year of release and of course the title and trimmed version of the body. I only want to customize the content of this page so that I have the control over What to Show and Where To Show a specific field value.
This is what I tried:
I cloned and put page.tpl.php in my theme's template folder. Renamed it as page--vocabulary--tags.tpl.php. Then I took out the following line of code (<?php print render($page['content']);?>) from my page--vocabulary--tags.tpl.php. The intention was to check whether the overridden template is actually being accessed by Drupal or not. It does!
But I am not been able to extract fields like field_photo or field_release_date from $page['content]. To get an idea about defined variables and how they are placed I used the following line of code:
<pre><?php /*print var_export(get_defined_vars(), TRUE);*/ ?></pre>. But even from there I could not extract a particular field like I mentioned above. The fields look to be somewhere inside $page['content']['system_main']['nodes'], but I don't know how to get to a specific field directly.
I also created a template.php with the following preprocess hook function:
<?php
function introduction_preprocess_page(&$vars) {
if (arg(0) == 'taxonomy' && arg(1) == 'term' && is_numeric(arg(2))) {
$term = taxonomy_term_load(arg(2));
$vars['theme_hook_suggestions'][] = 'page__vocabulary__' . $term->vocabulary_machine_name;
$vars['content'] = $vars['page']['content']['system_main']['nodes'];
}
}
?>
Both <?php print render($content) ?> and <?php print render($page['content']) ?> print the same result but I want something like <?php render($content['photo_field'])?> which I am not been able to.
I am sorry for making this too long. I have just stepped into Drupal. So wanted to make sure that what I am trying to explain matches exactly what I want to accomplish.
You are probably trying the long way to this.
You can use Views module. It allows to create custom listings querying the database, but also override existent ones, like the case of the taxonomy term page listing.
Once you have the module installed (if it's not yet), particularly the Views UI module, go to /admin/structure/views and scroll to bottom, where disabled views (grayed rows) are. You'll find one called Taxonomy term, described as 'A view to emulate Drupal core's handling of taxonomy/term.'
Click Enable on the right of it and then go to the same place where the Enable link is, click the arrow to unfold and choose Edit.
Once you're in the view edit page, you can manipulate the listing at your convenience, adding/removing fields or whatever you want to do in your particular case. If you are not familiar with Views, I recommend you to learn about it, there is a lot of related content on the web and it is close to essential for Drupal development.
Also, if you want to add more customisation to the page, you can use the same approach with the Panels module, who allows to override system pages (not just listings like Views).
I have a Page and a Block both are created using Views.
I want to display this Block along with the Page i.e. on Left hand side, Page's content will be shown and on the Right hand side this block's content but at the same time I don't want to configure this block from the administrative settings. How can I achieve this ?
You can create 'page' template file for your view and use module_invoke() function to call your block into it.
Page template can use following pattern -
page--[path].html.twig
module_invoke() documentation -
https://api.drupal.org/api/drupal/includes%21module.inc/function/module_invoke/7
Iam new to drupal 7 views.
I have a content type contains title, description fields. I want the content title's to scroll at the top of the page, so that i created a view and it works fine.What is my question is, i want to link a content (eg: 1st content (title) in a scroll) to another website instead of content page, the remaining contents linked to the content page. Is it possible?.If it is possible how it can be done?..
Thanks in advance,
A.John Melchior.
Yes, it's possible.
One way to do it, would be to use the Link module to create a link field in your node.
Use the link field to input the external link value.
In views add the link field, before the title ( order is important ) and exclude it from display
Add the node title field in the views and in the rewrite field output option, use one the link field token as your path.
I'm not looking at the Views UI right now , but you should find at least a couple of ways to redirect content when the node title is clicked. You should have the Rewrite field output and the Output this field as a link.
You could make use of Display Suite coupled with the description above.
Create a link field for your nodes.
Create 2 view modes for your content type via Display Suite. View Mode 1 will show the link field as the first data element, View Mode 2 will show the title as the first element.
Configure your view to show output using Display Suite, configured to show the first record using View Mode 1, all others using View Mode 2.
I use taxonomy terms to address my menus(these taxonomy terms show the structure of my site) so when I create a view I should use the taxonomy path (instead of alias) for the page setting (the only way that I can link the view to my taxonomy address path as far as I know :P ). whenever I see the page URL I can see the alias. now I'm trying to set up a page that has 2 tabs. I have set it up but the problem is when I click in the tab I see the taxonomy path instead of alias ? (for example taxonomy/term/6/digital instead of CCTV/digital However default menu tab still work correctly and show the alias CCTV)
Is there any way to show the alias instead of taxonomy term address ?
I assume that you have a view that is filtering your taxonomy terms. If you render the results as fields, each field can have it's formatter. If you need a custom form of the output, you can define your own formatter or generate one via GUI with help of: custom formatters.
In case that you render your output as rendered entity, you need to find the right template file and use the drupal_get_path_alias() function within it.
As last I would hint you a great module that also might help you: taxonomy menu
CASE:
I've created a content type 'Attorney', and have set a url alias pattern for all attorneys to be 'attorneys/[node:title]'. I'd like to create a view that uses the aliased path to display the information about the attorney. This view should have a 'page' display.
EXAMPLE:
When a user visits 'http://mydomain.com/attorneys/aaron-silber' the view returns data for the Attorney with the name Aaron Silber.
BACKGROUND:
I've searched high and low for a solution to this but can't seem to find one that works for me. Typically I'm asked to create a page view with a url of 'attorneys/%' and add a contextual filter with 'Content: Nid', choosing to provide a default value (type: Raw value from URL, path component 2).
The resources on the web for this case are aweful at best. Lets try to fix it here once and for all.
Thanks!
Use a Views block instead with the visibility set to "Only the listed pages" and supply "attorneys/*" in the textarea. Set the block to display in the main content region. Use the Content: Nid filter with a default value of path component 2, as you were previously attempting.
You can't have an attorney node page and a Views page occupying the same URL.