if i give an input of 13, output should be like:
*
**
***
****
***
i've reached only this far:
#include <stdio.h>
int main()
{
int i, j, n = 13;
for(i = 1 ; i <= n ; i++)
{
for ( j = 1; j <= i ; j++)
{
printf("*");
}
t = ((i * (i + 1)) / 2);
printf("\n");
}
printf("%d",t);
return 0;
}
stars should be increasing by 1 in every line, but program will stop when total printed stars reach my inputted number. i am not sure how to start and where to end. i am very new to "for" loops.
You can do something like this
int n,i=1,j,coun=0;
scanf("%d",&n);
while(1)
{
if(i+coun<=n)
{
for(j=0;j<i;j++)
printf("*");
printf("\n");
coun+=i;
}
else
{
for(j=0;j<n-coun;j++)
printf("*");
printf("\n");
break;
}
i++;
}
#include <stdio.h>
int main(){
int i, j, k, n = 13;
for(k = j = i = 1 ; i <= n ; i++, j++){
putchar('*');
if(j==k){
putchar('\n');
j = 0;
++k;
}
}
return 0;
}
Related
I'm trying to print out a hollow, open tent shape using asterisk stars "*". The code uses two for loops, the first for the rows, and the other for the columns.
following is my code:
void printTent(int n)
{
int j = 1;
int i = 1;
if (n == 1) {
printf("*");
} else {
for(i = 0; i < n; i++) {
for(j = 0; j < n; j++) {
printf(" ");
}
if(j == n) {
printf("*");
for(j = 1; j <= n; j++) {
printf(" ");
}
}
}
}
}
int main()
{
printTent(4);
}
Output obtained:
* * * *
Desired output:
*
* *
* *
* *
I don't think you will need that
if (n == 1) {
printf("*");
}
We can take care of that in what you've written in the else part.
For n=4, the number of spaces to be printed at the start of each line is 3, 2, 1 & 0.
You seem to be trying to accomplish that with your first inner loop. But
for(j = 0; j < n; j++) {
printf(" ");
}
will always print n spaces. We need to reduce the number of spaces printed by 1 on each iteration of the outer loop.
Coming to your second loop,
for(j = 1; j <= n; j++) {
printf(" ");
}
This has a similar problem only difference being the incrementation of the number of spaces printed.
Try something like this
void printTentNMMod(int n)
{
int j;
int i;
for(i = 0; i < n; i++) {
for(j = i; j < n; j++) {
printf(" ");
}
printf("*");
if(i!=0)
{
for(j=0; j<2*(i-1)+1; ++j)
{
printf(" ");
}
printf("*");
}
printf("\n");
}
}
Also, you could shorten this to
void printTent(int n)
{
int j;
int i;
for(i = 0; i < n; i++) {
printf("%*c", n-i, '*');
if(i!=0)
{
printf("%*c", 2*i, '*');
}
printf("\n");
}
}
The * in %*c will set the number of places occupied by the character printed by the %c.
I've finished it and I have written annotation.
void printTent(int n)
{
int j = 1;
int i = 1;
if (n == 1) {
printf("*");
}
else {
for (i = 0; i < n; i++) {
for (j = 0; j < n -i; j++) {// you should use n-i instead of n because the number of spaces is decreasing
printf(" ");
}
if (j == n-i) { //
printf("*");
for (j = 1; j <= i * 2 - 1; j++)//this loop outputs spaces between two "*"
{
printf(" ");
}
if (i != 0)//the first line only needs one "*"
printf("*");
printf("\n"); //Line breaks
}
}
}
}
Another way.
#include <stdio.h>
int main() {
int i, j;
int height = 5;
for(i = height; i > 0; i--) {
for(j = 1; j < height * 2; j++) {
if(j == i || j == height * 2 - i)
printf("*");
else
printf(" ");
}
puts("");
}
return 0;
}
Output
*
* *
* *
* *
* *
I'm a freshmen student and we have an activity in intro pro.. We were tasked to create a Christmas tree using a loop...
I have my code here:
#include<stdio.h>
int main ()
{
int rows,a,b,space;
clrscr();
printf("Enter a number of rows:");
scanf("%d",&rows);
space=rows-1
for(b=space;b>=1;b--)
{
for(a=rows;a>=1;a--)
space--;
printf("");
for(a=2*(rows-b)-1;a>=1;a--)
printf("*",a);
printf("\n");
space = space-1;
}
getche();
return 0;
}
This code was given to us by our professor... the program runs, but the output is wrong. Can you help me?
when i run this program, the output was like this:
*
***
*****
******
*******
You have to find a pattern. Say you want a tree with n rows. Last row is going to have 2n-1 stars. Row before it will have 2n-3 and so on. To print a row, first you print a number of spaces, then a number of stars. For last row, you print 0 spaces and 2n-1 stars. For row before it, you print 1 space and 2n-3 stars and so on.
for(int i = 0; i < n; i++)
{ for(int j = i + 1; j < n; j++)
printf(" ");
for(int j = 0; j <= 2*i; j++)
printf("*");
if(i < n - 1) puts("");
}
The Code is a little bit to messed up for me, but this should work:
#include<stdio.h>
int main() {
/*Variables*/
int rows, starNumber, spaceNumber;
int rowCount, spaceCount, starCount, treeTrunkCount, treeTrunkSpaceCount;
printf("Enter Rows:\n>");
scanf("%d",&rows);
for(rowCount = 1; rowCount <= rows; rowCount++) {
starNumber = rowCount * 2 - 1;
spaceNumber = rowCount + rows - starNumber;
for(spaceCount = 0; spaceCount < spaceNumber; spaceCount++)
printf(" ");
for(starCount = 0; starCount < starNumber; starCount++)
printf("%c",'*');
printf("\n");
}
for(treeTrunkCount = 0; treeTrunkCount < 3; treeTrunkCount++) {
for(treeTrunkSpaceCount = 0; treeTrunkSpaceCount < (rows * 2 + 1)/2; treeTrunkSpaceCount++)
printf(" ");
printf("%c\n",'*');
}
}
This is the simplest solution to your program..
#include <stdio.h>
int main()
{
int i=-1,j=0,rows;
printf("Enter Rows:\n");
scanf("%d",&rows);
while(j++<rows) // Moving pointer for the first '*'
{
printf(" ");
}
printf("*"); // This prints the first '*'
while(++i<rows)
{
for(j=-2;++j<rows-i;) // This loop will print Spaces before '*' on each row
printf(" ");
for(j=0;++j<2*i;) // This loop will print * on each row
{
printf("*");
}
printf("\n"); // This printf will take you to the next Line
}
}
This is the shortest and simplest solution for your question:
#include<stdio.h>
#include<conio.h>
void main(){
int count;
int i,j;
printf("enter the numbers of line");
scanf("%d",&count);
for(i=1;i<=count;i++){
for(j=1;j<=i;j++){
printf("*");
}
printf("\n");
}
getch();
}
You forgot a space between "".
for(a=rows;a>=1;a--)
space--;
printf("");
should be
for(a=rows;a>=1;a--)
space--;
printf(" ");
#include <stdio.h>
int main() {
int n = 50;
for (int i = 0; i <= n; ++i) {
for (int k = i; k < n; ++k)
printf(" ");
for (int j = 0; j < i; ++j)
printf("*");
for (int j = 1; j < i; ++j)
printf("*");
printf("\n");
}
for (int l = 1; l < n/2; ++l) {
for (int i = 1; i < n; ++i)
printf(" ");
printf("[|]\n");
}
return 0;
}
A simple tree can be made up with for loop, Christmas may need more symbol...
//Linux C program to print a tree
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <unistd.h>
#include <sys/ioctl.h>
#include <string.h>
int pcenter(char *s) {
struct winsize w;
ioctl(STDOUT_FILENO, TIOCGWINSZ, &w);
int ct = w.ws_col;
int sl = strlen(s) / 2;
printf("%*s%*s\n", ct / 2 + sl, s, ct / 2 - sl, "");
return 0;
}
int ptree(char s, char t, int l, int r) {
int i;
for (i = 1; i <= l; i++) {
int j = 2 * i - 1;
char *p = malloc(j);
memset(p, s, j);
pcenter(p);
free(p);
}
for (i = 1; i <= r; i++) {
int j = 1;
char *p = malloc(j);
memset(p, t, j);
pcenter(p);
free(p);
}
return 0;
}
int main() {
// system("clear");
ptree('*', '|', 10, 5);
return 0;
}
#include<stdio.h>
main()
{
int n,i, j, space=1;
printf("Enter the number of rows: ");
scanf("%d",&n);
space=n-1;
for(i=1;i<=n;i++)
{
for(j=1;j<=space;j++)
{
printf(" ");
}
space--;
for(j=1;j<=2*i-1;j++)
{
printf("*");
}
printf("\n");
}
for(i=1;i<=n-3;i++)
{
for(j=1;j<=10;j++)
{
printf(" ");
}
for(j=1;j<=1;j++)
{
printf("*");
}
for(j=1;j<=1;j++)
{
printf("*");
}
for(j=1;j<=1;j++)
{
printf("*");
}
printf("\n");
}
}
#include<stdio.h>
int main()
{
int i,j,k,l=1,a,b;
for(i=8;i>=0;i--)
{
for(j=0;j<=i;j++)
{
printf(" ");
}
k=0 ;
while(k<l)
{
printf("*");
k=k+1;
}
l=l+2;
printf("\n");
}
i=8;
for(b=0;b<=3;b++)
{
for(a=0;a<=i-1;a++)
{
printf(" ");
}
printf("***");
printf("\n");
}
}
I want to print this pattern like right angled triangle
0
909
89098
7890987
678909876
56789098765
4567890987654
345678909876543
23456789098765432
1234567890987654321
I wrote the following code:
#include <stdio.h>
#include <conio.h>
void main()
{
clrscr();
int i,j,x,z,k,f=1;
for ( i=10;i>=1;i--,f++)
{
for(j=1;j<=f;j++,k--)
{
k=i;
if(k!=10)
{
printf("%d",k);
}
if(k==10)
{
printf("0");
}
}
for(x=1;x<f;x++,z--)
{
z=9;
printf("%d",z);
}
printf("%d/n");
}
getch();
}
What is wrong with this code? When I check manually it seems correct but when compiled gives different pattern
Fairly simple: use two loops, one for counting up and one for counting down. Print literal "0" between the two.
#include <stdio.h>
int main()
{
for (int i = 0; i < 10; i++) {
for (int j = 10 - i; j < 10; j++)
printf("%d", j);
printf("0");
for (int j = 9; j >= 10 - i; j--)
printf("%d", j);
printf("\n");
}
return 0;
}
Like H2CO3's, but since we're only printing single digits why not use putchar():
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
int i, j;
for(i = 0; i < 10; ++i)
{
// Left half.
for(j = 0; j < i; ++j)
putchar('9' - i + j + 1);
// Center zero.
putchar('0');
// Right half.
for(j = 0; j < i; ++j)
putchar('9' - i + j + 1);
putchar('\n');
}
return EXIT_SUCCESS;
}
Modified Code:
Check your errors:
# include<stdio.h>
# include<conio.h>
int main()
{
// clrscr();
int i,j,x,z,k,f=1;
for ( i=10;i>=1;i--,f++)
{
k=i; // K=i should be outside of loop.
for(j=1;j<=f;j++,k++)
{
if(k!=10)
{
printf("%d",k);
}
if(k==10)
{
printf("0");
}
}
z=9; //z=9 should be outside loop.
for(x=1;x<f;x++,z--)
{
printf("%d",z);
}
printf("\n");
}
//getch();
return 0;
}
You are defining k=i inside the for loop(loop which has j) so every time k gets value of i and thus it always get value of i and prints that value and your another condition(if(k==10)) will never be true because every time k takes value of i and i is less than 10 after first iteration of loop and z=9 inside loop so every time loop is executed it is taking value z=9 so it is printing wrong value.
Here's a C# version:
static void DrawNumberTriangle()
{
for (int line = 10; line >=1; line--)
{
for (int number = line; number < 10; number++)
{
System.Console.Write(number);
}
System.Console.Write("0");
for (int number = 9; number > line - 1; number--)
{
System.Console.Write(number);
}
System.Console.WriteLine();
}
}
I'd suggest renaming your i,j,x,z,k,f variables to ones that have meaning like the one's I used. This helps making your code easier to follow.
Rather than output the mid 0 using printf, why not print it using the loops itself.
The following short and simple code can be used:
int main()
{
int m = 10, n, p;
while(m >= 1)
{
for(n = m; n <= 10; n++)
printf("%d", n % 10);
for(p = n - 2; p >= m; p--)
printf("%d", p );
printf("\n");
m--;
}
return 1;
}
For high throughput (though of questionable merit in terms of clarity):
#include <stdio.h>
int main() {
char const digits[] = "1234567890";
char const rdigits[] = "9876543210";
for (int i = 0; i < 30; ++i) {
int k = i % 10;
fputs(digits + 9 - k, stdout);
for (int j = 9; j < i; j += 10) fputs(digits, stdout);
for (int j = 9; j < i; j += 10) fputs(rdigits, stdout);
fwrite(rdigits, 1, k, stdout);
fputs("\n", stdout);
}
}
#include <stdio.h>
void print(int i){
if(i == 10){
putchar('0');
return ;
} else {
printf("%d", i);
print(i+1);
printf("%d", i);
}
}
int main(void){
int i;
for(i = 10; i>0; --i){
print(i);
putchar('\n');
}
return 0;
}
I want to print this pattern like right angled triangle
0
909
89098
7890987
678909876
56789098765
4567890987654
345678909876543
23456789098765432
1234567890987654321
I wrote the following code:
#include <stdio.h>
#include <conio.h>
void main()
{
clrscr();
int i,j,x,z,k,f=1;
for ( i=10;i>=1;i--,f++)
{
for(j=1;j<=f;j++,k--)
{
k=i;
if(k!=10)
{
printf("%d",k);
}
if(k==10)
{
printf("0");
}
}
for(x=1;x<f;x++,z--)
{
z=9;
printf("%d",z);
}
printf("%d/n");
}
getch();
}
What is wrong with this code? When I check manually it seems correct but when compiled gives different pattern
Fairly simple: use two loops, one for counting up and one for counting down. Print literal "0" between the two.
#include <stdio.h>
int main()
{
for (int i = 0; i < 10; i++) {
for (int j = 10 - i; j < 10; j++)
printf("%d", j);
printf("0");
for (int j = 9; j >= 10 - i; j--)
printf("%d", j);
printf("\n");
}
return 0;
}
Like H2CO3's, but since we're only printing single digits why not use putchar():
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
int i, j;
for(i = 0; i < 10; ++i)
{
// Left half.
for(j = 0; j < i; ++j)
putchar('9' - i + j + 1);
// Center zero.
putchar('0');
// Right half.
for(j = 0; j < i; ++j)
putchar('9' - i + j + 1);
putchar('\n');
}
return EXIT_SUCCESS;
}
Modified Code:
Check your errors:
# include<stdio.h>
# include<conio.h>
int main()
{
// clrscr();
int i,j,x,z,k,f=1;
for ( i=10;i>=1;i--,f++)
{
k=i; // K=i should be outside of loop.
for(j=1;j<=f;j++,k++)
{
if(k!=10)
{
printf("%d",k);
}
if(k==10)
{
printf("0");
}
}
z=9; //z=9 should be outside loop.
for(x=1;x<f;x++,z--)
{
printf("%d",z);
}
printf("\n");
}
//getch();
return 0;
}
You are defining k=i inside the for loop(loop which has j) so every time k gets value of i and thus it always get value of i and prints that value and your another condition(if(k==10)) will never be true because every time k takes value of i and i is less than 10 after first iteration of loop and z=9 inside loop so every time loop is executed it is taking value z=9 so it is printing wrong value.
Here's a C# version:
static void DrawNumberTriangle()
{
for (int line = 10; line >=1; line--)
{
for (int number = line; number < 10; number++)
{
System.Console.Write(number);
}
System.Console.Write("0");
for (int number = 9; number > line - 1; number--)
{
System.Console.Write(number);
}
System.Console.WriteLine();
}
}
I'd suggest renaming your i,j,x,z,k,f variables to ones that have meaning like the one's I used. This helps making your code easier to follow.
Rather than output the mid 0 using printf, why not print it using the loops itself.
The following short and simple code can be used:
int main()
{
int m = 10, n, p;
while(m >= 1)
{
for(n = m; n <= 10; n++)
printf("%d", n % 10);
for(p = n - 2; p >= m; p--)
printf("%d", p );
printf("\n");
m--;
}
return 1;
}
For high throughput (though of questionable merit in terms of clarity):
#include <stdio.h>
int main() {
char const digits[] = "1234567890";
char const rdigits[] = "9876543210";
for (int i = 0; i < 30; ++i) {
int k = i % 10;
fputs(digits + 9 - k, stdout);
for (int j = 9; j < i; j += 10) fputs(digits, stdout);
for (int j = 9; j < i; j += 10) fputs(rdigits, stdout);
fwrite(rdigits, 1, k, stdout);
fputs("\n", stdout);
}
}
#include <stdio.h>
void print(int i){
if(i == 10){
putchar('0');
return ;
} else {
printf("%d", i);
print(i+1);
printf("%d", i);
}
}
int main(void){
int i;
for(i = 10; i>0; --i){
print(i);
putchar('\n');
}
return 0;
}
I am trying to write a C code that will print a pyramid structure on screen, something like this.
The corresponding code I've written is something like this.
#include <stdio.h>
#include <stdlib.h>
void printArrayFunc(char arr[9][5]) {
int i, j;
printf("=========================================\nprinting the values\n");
for (i = 0; i < 5; i++) {
for (j = 0; j < 9; j++) {
//printf("arr[%d][%d] = %d\n", i,j, arr[i][j]);
if (arr[i][j] == 1)
printf("*");
else
printf(" ");
}
printf("\n");
}
}
int main() {
int i, j;
char arr[9][5] = {
0
};
printf("============================\nfilling the values\n");
for (i = 0; i < 5; i++) {
for (j = 4 - i; j <= 4 + i; j++) {
arr[i][j] = 1;
// printf("arr[%d][%d]= %d\n",i,j,arr[i][j]);
}
//printf("\n");
}
printArrayFunc(arr);
return 0;
}
It is giving an output like
I know I'm doing some silly mistake but at this moment, I'm not able to find what is going wrong. Let me hear your comments on this.
In the function argument:
char arr[9][5]
In the loop:
for (i = 0; i<5; i++) {
for (j = 0; j<9;j++) {
if (arr[i][j] == 1)
You flipped the position of i and j. i should go from 0 to 9, j from 0 to 5.
if (arr[i][j] == 1)
printf("*");
else
printf(" ");
This statement is giving the garbage value in this statement if if condition is true then it print else statement and when else comes true it prints the garbage value.